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What does this value mean in a BJT datasheet?


How to determine BJT switching timeWhat does “Collector Power Dissipation” mean on a transistor datasheetWhat does “Sourced from process <number>” mean in transistor datasheet?BJT vs Mosfet, switching variable current battery powered deviceHelp analyzing this BJT LED driver circuitReading BJT Transistor Datasheets. Two different values for collector emitter voltage?Understanding datasheet audio transformerelectronic switch, understanding on-resistance measurementsWhat does “normalized” mean in this datasheet?Questions About BJTs in My CircuitCan this transistor (2N2222) take 6 V on emitter-base? Am I reading the datasheet incorrectly?






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In the switching characteristics section of a BJT datasheet I often see test conditions like "Ib1=Ib2=1mA". I understand this is base current but what exactly do they mean by Ib1 and Ib2? Example: https://www.mccsemi.com/pdf/Products/MMBT3904(SOT-23).pdf



Thanks in advanced.










share|improve this question











$endgroup$


















    4












    $begingroup$


    In the switching characteristics section of a BJT datasheet I often see test conditions like "Ib1=Ib2=1mA". I understand this is base current but what exactly do they mean by Ib1 and Ib2? Example: https://www.mccsemi.com/pdf/Products/MMBT3904(SOT-23).pdf



    Thanks in advanced.










    share|improve this question











    $endgroup$














      4












      4








      4





      $begingroup$


      In the switching characteristics section of a BJT datasheet I often see test conditions like "Ib1=Ib2=1mA". I understand this is base current but what exactly do they mean by Ib1 and Ib2? Example: https://www.mccsemi.com/pdf/Products/MMBT3904(SOT-23).pdf



      Thanks in advanced.










      share|improve this question











      $endgroup$




      In the switching characteristics section of a BJT datasheet I often see test conditions like "Ib1=Ib2=1mA". I understand this is base current but what exactly do they mean by Ib1 and Ib2? Example: https://www.mccsemi.com/pdf/Products/MMBT3904(SOT-23).pdf



      Thanks in advanced.







      transistors switches bjt datasheet






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      share|improve this question













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      share|improve this question








      edited 9 hours ago







      Jaywalk

















      asked 9 hours ago









      JaywalkJaywalk

      985 bronze badges




      985 bronze badges




















          1 Answer
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          $begingroup$

          It means that the current for charging the Base is the same as the current used to discharge the Base capacitance when they do fall time testing.
          An exemplary circuit to do so is shown in this datasheet.
          enter image description here



          You may also have a look at:



          How to determine BJT switching time






          share|improve this answer









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          • $begingroup$
            Thank you very much. Perfect answer in no time at all.
            $endgroup$
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            9 hours ago










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          9












          $begingroup$

          It means that the current for charging the Base is the same as the current used to discharge the Base capacitance when they do fall time testing.
          An exemplary circuit to do so is shown in this datasheet.
          enter image description here



          You may also have a look at:



          How to determine BJT switching time






          share|improve this answer









          $endgroup$












          • $begingroup$
            Thank you very much. Perfect answer in no time at all.
            $endgroup$
            – Jaywalk
            9 hours ago










          • $begingroup$
            You're welcome! Please accept my answer.
            $endgroup$
            – Daniel K
            9 hours ago















          9












          $begingroup$

          It means that the current for charging the Base is the same as the current used to discharge the Base capacitance when they do fall time testing.
          An exemplary circuit to do so is shown in this datasheet.
          enter image description here



          You may also have a look at:



          How to determine BJT switching time






          share|improve this answer









          $endgroup$












          • $begingroup$
            Thank you very much. Perfect answer in no time at all.
            $endgroup$
            – Jaywalk
            9 hours ago










          • $begingroup$
            You're welcome! Please accept my answer.
            $endgroup$
            – Daniel K
            9 hours ago













          9












          9








          9





          $begingroup$

          It means that the current for charging the Base is the same as the current used to discharge the Base capacitance when they do fall time testing.
          An exemplary circuit to do so is shown in this datasheet.
          enter image description here



          You may also have a look at:



          How to determine BJT switching time






          share|improve this answer









          $endgroup$



          It means that the current for charging the Base is the same as the current used to discharge the Base capacitance when they do fall time testing.
          An exemplary circuit to do so is shown in this datasheet.
          enter image description here



          You may also have a look at:



          How to determine BJT switching time







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 9 hours ago









          Daniel KDaniel K

          4924 bronze badges




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          • $begingroup$
            Thank you very much. Perfect answer in no time at all.
            $endgroup$
            – Jaywalk
            9 hours ago










          • $begingroup$
            You're welcome! Please accept my answer.
            $endgroup$
            – Daniel K
            9 hours ago
















          • $begingroup$
            Thank you very much. Perfect answer in no time at all.
            $endgroup$
            – Jaywalk
            9 hours ago










          • $begingroup$
            You're welcome! Please accept my answer.
            $endgroup$
            – Daniel K
            9 hours ago















          $begingroup$
          Thank you very much. Perfect answer in no time at all.
          $endgroup$
          – Jaywalk
          9 hours ago




          $begingroup$
          Thank you very much. Perfect answer in no time at all.
          $endgroup$
          – Jaywalk
          9 hours ago












          $begingroup$
          You're welcome! Please accept my answer.
          $endgroup$
          – Daniel K
          9 hours ago




          $begingroup$
          You're welcome! Please accept my answer.
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          – Daniel K
          9 hours ago

















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