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Incrementing add under condition in pandas


Does Python have a ternary conditional operator?Add new keys to a dictionary?Converting a Pandas GroupBy output from Series to DataFrameRenaming columns in pandasAdding new column to existing DataFrame in Python pandasHow can I replace all the NaN values with Zero's in a column of a pandas dataframe“Large data” work flows using pandasChange data type of columns in PandasSelect rows from a DataFrame based on values in a column in pandasWhy is “1000000000000000 in range(1000000000000001)” so fast in Python 3?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








6















For the following pandas dataframe



 servo_in_position second_servo_in_position Expected output
0 0 1 0
1 0 1 0
2 1 2 1
3 0 3 0
4 1 4 2
5 1 4 2
6 0 5 0
7 0 5 0
8 1 6 3
9 0 7 0
10 1 8 4
11 0 9 0
12 1 10 5
13 1 10 5
14 1 10 5
15 0 11 0
16 0 11 0
17 0 11 0
18 1 12 6
19 1 12 6
20 0 13 0
21 0 13 0
22 0 13 0


I want to increment the column "Expected output" only if "servo_in_position" changes from 0 to 1. I want also to assume "Expected output" to be 0 (null) if "servo_in_position" equals to 0.



I tried



input_data['second_servo_in_position']=(input_data.servo_in_position.diff()!=0).cumsum()


but it gives output as in "second_servo_in_position" column, which is not what I wanted.



After that I would like to group and calculate mean using:



print("Mean=nn",input_data.groupby('second_servo_in_position').mean())









share|improve this question
































    6















    For the following pandas dataframe



     servo_in_position second_servo_in_position Expected output
    0 0 1 0
    1 0 1 0
    2 1 2 1
    3 0 3 0
    4 1 4 2
    5 1 4 2
    6 0 5 0
    7 0 5 0
    8 1 6 3
    9 0 7 0
    10 1 8 4
    11 0 9 0
    12 1 10 5
    13 1 10 5
    14 1 10 5
    15 0 11 0
    16 0 11 0
    17 0 11 0
    18 1 12 6
    19 1 12 6
    20 0 13 0
    21 0 13 0
    22 0 13 0


    I want to increment the column "Expected output" only if "servo_in_position" changes from 0 to 1. I want also to assume "Expected output" to be 0 (null) if "servo_in_position" equals to 0.



    I tried



    input_data['second_servo_in_position']=(input_data.servo_in_position.diff()!=0).cumsum()


    but it gives output as in "second_servo_in_position" column, which is not what I wanted.



    After that I would like to group and calculate mean using:



    print("Mean=nn",input_data.groupby('second_servo_in_position').mean())









    share|improve this question




























      6












      6








      6








      For the following pandas dataframe



       servo_in_position second_servo_in_position Expected output
      0 0 1 0
      1 0 1 0
      2 1 2 1
      3 0 3 0
      4 1 4 2
      5 1 4 2
      6 0 5 0
      7 0 5 0
      8 1 6 3
      9 0 7 0
      10 1 8 4
      11 0 9 0
      12 1 10 5
      13 1 10 5
      14 1 10 5
      15 0 11 0
      16 0 11 0
      17 0 11 0
      18 1 12 6
      19 1 12 6
      20 0 13 0
      21 0 13 0
      22 0 13 0


      I want to increment the column "Expected output" only if "servo_in_position" changes from 0 to 1. I want also to assume "Expected output" to be 0 (null) if "servo_in_position" equals to 0.



      I tried



      input_data['second_servo_in_position']=(input_data.servo_in_position.diff()!=0).cumsum()


      but it gives output as in "second_servo_in_position" column, which is not what I wanted.



      After that I would like to group and calculate mean using:



      print("Mean=nn",input_data.groupby('second_servo_in_position').mean())









      share|improve this question
















      For the following pandas dataframe



       servo_in_position second_servo_in_position Expected output
      0 0 1 0
      1 0 1 0
      2 1 2 1
      3 0 3 0
      4 1 4 2
      5 1 4 2
      6 0 5 0
      7 0 5 0
      8 1 6 3
      9 0 7 0
      10 1 8 4
      11 0 9 0
      12 1 10 5
      13 1 10 5
      14 1 10 5
      15 0 11 0
      16 0 11 0
      17 0 11 0
      18 1 12 6
      19 1 12 6
      20 0 13 0
      21 0 13 0
      22 0 13 0


      I want to increment the column "Expected output" only if "servo_in_position" changes from 0 to 1. I want also to assume "Expected output" to be 0 (null) if "servo_in_position" equals to 0.



      I tried



      input_data['second_servo_in_position']=(input_data.servo_in_position.diff()!=0).cumsum()


      but it gives output as in "second_servo_in_position" column, which is not what I wanted.



      After that I would like to group and calculate mean using:



      print("Mean=nn",input_data.groupby('second_servo_in_position').mean())






      python pandas






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 8 hours ago









      Scott Boston

      64.7k7 gold badges38 silver badges62 bronze badges




      64.7k7 gold badges38 silver badges62 bronze badges










      asked 9 hours ago









      TomaszTomasz

      638 bronze badges




      638 bronze badges

























          5 Answers
          5






          active

          oldest

          votes


















          7














          Use cumsum and mask:



          df['E_output'] = df['servo_in_position'].diff().eq(1).cumsum()
          .mask(df['servo_in_position'] == 0, 0)


          Output:



           servo_in_position second_servo_in_position Expected output E_output
          0 0 1 0 0
          1 0 1 0 0
          2 1 2 1 1
          3 0 3 0 0
          4 1 4 2 2
          5 1 4 2 2
          6 0 5 0 0
          7 0 5 0 0
          8 1 6 3 3
          9 0 7 0 0
          10 1 8 4 4
          11 0 9 0 0
          12 1 10 5 5
          13 1 10 5 5
          14 1 10 5 5
          15 0 11 0 0
          16 0 11 0 0
          17 0 11 0 0
          18 1 12 6 6
          19 1 12 6 6
          20 0 13 0 0
          21 0 13 0 0
          22 0 13 0 0





          share|improve this answer
































            6














            Try np.where:



            df['Expected_output'] = np.where(df.servo_in_position.eq(1),
            df.servo_in_position.diff().eq(1).cumsum(),
            0)





            share|improve this answer
































              6














              Using cumsum and arithmetic.




              u = df['servo_in_position']

              (u.eq(1) & u.shift().ne(1)).cumsum() * u




              0 0
              1 0
              2 1
              3 0
              4 2
              5 2
              6 0
              7 0
              8 3
              9 0
              10 4
              11 0
              12 5
              13 5
              14 5
              15 0
              16 0
              17 0
              18 6
              19 6
              20 0
              21 0
              22 0
              Name: servo_in_position, dtype: int64





              share|improve this answer
































                5














                That is cumsum and mul



                df.servo_in_position.diff().eq(1).cumsum().mul(df.servo_in_position.eq(1),axis=0)





                share|improve this answer
































                  3














                  Fast with Numba



                  from numba import njit

                  @njit
                  def f(u):
                  out = np.zeros(len(u), np.int64)
                  a = out[0] = u[0]
                  for i in range(1, len(u)):
                  if u[i] == 1:
                  if u[i - 1] == 0:
                  a += 1
                  out[i] = a
                  return out

                  f(df.servo_in_position.to_numpy())

                  array([0, 0, 1, 0, 2, 2, 0, 0, 3, 0, 4, 0, 5, 5, 5, 0, 0, 0, 6, 6, 0, 0, 0])





                  share|improve this answer



























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                    5 Answers
                    5






                    active

                    oldest

                    votes








                    5 Answers
                    5






                    active

                    oldest

                    votes









                    active

                    oldest

                    votes






                    active

                    oldest

                    votes









                    7














                    Use cumsum and mask:



                    df['E_output'] = df['servo_in_position'].diff().eq(1).cumsum()
                    .mask(df['servo_in_position'] == 0, 0)


                    Output:



                     servo_in_position second_servo_in_position Expected output E_output
                    0 0 1 0 0
                    1 0 1 0 0
                    2 1 2 1 1
                    3 0 3 0 0
                    4 1 4 2 2
                    5 1 4 2 2
                    6 0 5 0 0
                    7 0 5 0 0
                    8 1 6 3 3
                    9 0 7 0 0
                    10 1 8 4 4
                    11 0 9 0 0
                    12 1 10 5 5
                    13 1 10 5 5
                    14 1 10 5 5
                    15 0 11 0 0
                    16 0 11 0 0
                    17 0 11 0 0
                    18 1 12 6 6
                    19 1 12 6 6
                    20 0 13 0 0
                    21 0 13 0 0
                    22 0 13 0 0





                    share|improve this answer





























                      7














                      Use cumsum and mask:



                      df['E_output'] = df['servo_in_position'].diff().eq(1).cumsum()
                      .mask(df['servo_in_position'] == 0, 0)


                      Output:



                       servo_in_position second_servo_in_position Expected output E_output
                      0 0 1 0 0
                      1 0 1 0 0
                      2 1 2 1 1
                      3 0 3 0 0
                      4 1 4 2 2
                      5 1 4 2 2
                      6 0 5 0 0
                      7 0 5 0 0
                      8 1 6 3 3
                      9 0 7 0 0
                      10 1 8 4 4
                      11 0 9 0 0
                      12 1 10 5 5
                      13 1 10 5 5
                      14 1 10 5 5
                      15 0 11 0 0
                      16 0 11 0 0
                      17 0 11 0 0
                      18 1 12 6 6
                      19 1 12 6 6
                      20 0 13 0 0
                      21 0 13 0 0
                      22 0 13 0 0





                      share|improve this answer



























                        7












                        7








                        7







                        Use cumsum and mask:



                        df['E_output'] = df['servo_in_position'].diff().eq(1).cumsum()
                        .mask(df['servo_in_position'] == 0, 0)


                        Output:



                         servo_in_position second_servo_in_position Expected output E_output
                        0 0 1 0 0
                        1 0 1 0 0
                        2 1 2 1 1
                        3 0 3 0 0
                        4 1 4 2 2
                        5 1 4 2 2
                        6 0 5 0 0
                        7 0 5 0 0
                        8 1 6 3 3
                        9 0 7 0 0
                        10 1 8 4 4
                        11 0 9 0 0
                        12 1 10 5 5
                        13 1 10 5 5
                        14 1 10 5 5
                        15 0 11 0 0
                        16 0 11 0 0
                        17 0 11 0 0
                        18 1 12 6 6
                        19 1 12 6 6
                        20 0 13 0 0
                        21 0 13 0 0
                        22 0 13 0 0





                        share|improve this answer













                        Use cumsum and mask:



                        df['E_output'] = df['servo_in_position'].diff().eq(1).cumsum()
                        .mask(df['servo_in_position'] == 0, 0)


                        Output:



                         servo_in_position second_servo_in_position Expected output E_output
                        0 0 1 0 0
                        1 0 1 0 0
                        2 1 2 1 1
                        3 0 3 0 0
                        4 1 4 2 2
                        5 1 4 2 2
                        6 0 5 0 0
                        7 0 5 0 0
                        8 1 6 3 3
                        9 0 7 0 0
                        10 1 8 4 4
                        11 0 9 0 0
                        12 1 10 5 5
                        13 1 10 5 5
                        14 1 10 5 5
                        15 0 11 0 0
                        16 0 11 0 0
                        17 0 11 0 0
                        18 1 12 6 6
                        19 1 12 6 6
                        20 0 13 0 0
                        21 0 13 0 0
                        22 0 13 0 0






                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered 9 hours ago









                        Scott BostonScott Boston

                        64.7k7 gold badges38 silver badges62 bronze badges




                        64.7k7 gold badges38 silver badges62 bronze badges


























                            6














                            Try np.where:



                            df['Expected_output'] = np.where(df.servo_in_position.eq(1),
                            df.servo_in_position.diff().eq(1).cumsum(),
                            0)





                            share|improve this answer





























                              6














                              Try np.where:



                              df['Expected_output'] = np.where(df.servo_in_position.eq(1),
                              df.servo_in_position.diff().eq(1).cumsum(),
                              0)





                              share|improve this answer



























                                6












                                6








                                6







                                Try np.where:



                                df['Expected_output'] = np.where(df.servo_in_position.eq(1),
                                df.servo_in_position.diff().eq(1).cumsum(),
                                0)





                                share|improve this answer













                                Try np.where:



                                df['Expected_output'] = np.where(df.servo_in_position.eq(1),
                                df.servo_in_position.diff().eq(1).cumsum(),
                                0)






                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered 9 hours ago









                                Quang HoangQuang Hoang

                                14.4k2 gold badges14 silver badges24 bronze badges




                                14.4k2 gold badges14 silver badges24 bronze badges
























                                    6














                                    Using cumsum and arithmetic.




                                    u = df['servo_in_position']

                                    (u.eq(1) & u.shift().ne(1)).cumsum() * u




                                    0 0
                                    1 0
                                    2 1
                                    3 0
                                    4 2
                                    5 2
                                    6 0
                                    7 0
                                    8 3
                                    9 0
                                    10 4
                                    11 0
                                    12 5
                                    13 5
                                    14 5
                                    15 0
                                    16 0
                                    17 0
                                    18 6
                                    19 6
                                    20 0
                                    21 0
                                    22 0
                                    Name: servo_in_position, dtype: int64





                                    share|improve this answer





























                                      6














                                      Using cumsum and arithmetic.




                                      u = df['servo_in_position']

                                      (u.eq(1) & u.shift().ne(1)).cumsum() * u




                                      0 0
                                      1 0
                                      2 1
                                      3 0
                                      4 2
                                      5 2
                                      6 0
                                      7 0
                                      8 3
                                      9 0
                                      10 4
                                      11 0
                                      12 5
                                      13 5
                                      14 5
                                      15 0
                                      16 0
                                      17 0
                                      18 6
                                      19 6
                                      20 0
                                      21 0
                                      22 0
                                      Name: servo_in_position, dtype: int64





                                      share|improve this answer



























                                        6












                                        6








                                        6







                                        Using cumsum and arithmetic.




                                        u = df['servo_in_position']

                                        (u.eq(1) & u.shift().ne(1)).cumsum() * u




                                        0 0
                                        1 0
                                        2 1
                                        3 0
                                        4 2
                                        5 2
                                        6 0
                                        7 0
                                        8 3
                                        9 0
                                        10 4
                                        11 0
                                        12 5
                                        13 5
                                        14 5
                                        15 0
                                        16 0
                                        17 0
                                        18 6
                                        19 6
                                        20 0
                                        21 0
                                        22 0
                                        Name: servo_in_position, dtype: int64





                                        share|improve this answer













                                        Using cumsum and arithmetic.




                                        u = df['servo_in_position']

                                        (u.eq(1) & u.shift().ne(1)).cumsum() * u




                                        0 0
                                        1 0
                                        2 1
                                        3 0
                                        4 2
                                        5 2
                                        6 0
                                        7 0
                                        8 3
                                        9 0
                                        10 4
                                        11 0
                                        12 5
                                        13 5
                                        14 5
                                        15 0
                                        16 0
                                        17 0
                                        18 6
                                        19 6
                                        20 0
                                        21 0
                                        22 0
                                        Name: servo_in_position, dtype: int64






                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered 9 hours ago









                                        user3483203user3483203

                                        36.7k8 gold badges31 silver badges60 bronze badges




                                        36.7k8 gold badges31 silver badges60 bronze badges
























                                            5














                                            That is cumsum and mul



                                            df.servo_in_position.diff().eq(1).cumsum().mul(df.servo_in_position.eq(1),axis=0)





                                            share|improve this answer





























                                              5














                                              That is cumsum and mul



                                              df.servo_in_position.diff().eq(1).cumsum().mul(df.servo_in_position.eq(1),axis=0)





                                              share|improve this answer



























                                                5












                                                5








                                                5







                                                That is cumsum and mul



                                                df.servo_in_position.diff().eq(1).cumsum().mul(df.servo_in_position.eq(1),axis=0)





                                                share|improve this answer













                                                That is cumsum and mul



                                                df.servo_in_position.diff().eq(1).cumsum().mul(df.servo_in_position.eq(1),axis=0)






                                                share|improve this answer












                                                share|improve this answer



                                                share|improve this answer










                                                answered 9 hours ago









                                                WeNYoBenWeNYoBen

                                                150k8 gold badges53 silver badges84 bronze badges




                                                150k8 gold badges53 silver badges84 bronze badges
























                                                    3














                                                    Fast with Numba



                                                    from numba import njit

                                                    @njit
                                                    def f(u):
                                                    out = np.zeros(len(u), np.int64)
                                                    a = out[0] = u[0]
                                                    for i in range(1, len(u)):
                                                    if u[i] == 1:
                                                    if u[i - 1] == 0:
                                                    a += 1
                                                    out[i] = a
                                                    return out

                                                    f(df.servo_in_position.to_numpy())

                                                    array([0, 0, 1, 0, 2, 2, 0, 0, 3, 0, 4, 0, 5, 5, 5, 0, 0, 0, 6, 6, 0, 0, 0])





                                                    share|improve this answer





























                                                      3














                                                      Fast with Numba



                                                      from numba import njit

                                                      @njit
                                                      def f(u):
                                                      out = np.zeros(len(u), np.int64)
                                                      a = out[0] = u[0]
                                                      for i in range(1, len(u)):
                                                      if u[i] == 1:
                                                      if u[i - 1] == 0:
                                                      a += 1
                                                      out[i] = a
                                                      return out

                                                      f(df.servo_in_position.to_numpy())

                                                      array([0, 0, 1, 0, 2, 2, 0, 0, 3, 0, 4, 0, 5, 5, 5, 0, 0, 0, 6, 6, 0, 0, 0])





                                                      share|improve this answer



























                                                        3












                                                        3








                                                        3







                                                        Fast with Numba



                                                        from numba import njit

                                                        @njit
                                                        def f(u):
                                                        out = np.zeros(len(u), np.int64)
                                                        a = out[0] = u[0]
                                                        for i in range(1, len(u)):
                                                        if u[i] == 1:
                                                        if u[i - 1] == 0:
                                                        a += 1
                                                        out[i] = a
                                                        return out

                                                        f(df.servo_in_position.to_numpy())

                                                        array([0, 0, 1, 0, 2, 2, 0, 0, 3, 0, 4, 0, 5, 5, 5, 0, 0, 0, 6, 6, 0, 0, 0])





                                                        share|improve this answer













                                                        Fast with Numba



                                                        from numba import njit

                                                        @njit
                                                        def f(u):
                                                        out = np.zeros(len(u), np.int64)
                                                        a = out[0] = u[0]
                                                        for i in range(1, len(u)):
                                                        if u[i] == 1:
                                                        if u[i - 1] == 0:
                                                        a += 1
                                                        out[i] = a
                                                        return out

                                                        f(df.servo_in_position.to_numpy())

                                                        array([0, 0, 1, 0, 2, 2, 0, 0, 3, 0, 4, 0, 5, 5, 5, 0, 0, 0, 6, 6, 0, 0, 0])






                                                        share|improve this answer












                                                        share|improve this answer



                                                        share|improve this answer










                                                        answered 7 hours ago









                                                        piRSquaredpiRSquared

                                                        174k26 gold badges188 silver badges343 bronze badges




                                                        174k26 gold badges188 silver badges343 bronze badges






























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