Why does the Rust compiler not optimize code assuming that two mutable references cannot alias?Why can't (or doesn't) the compiler optimize a predictable addition loop into a multiplication?Does clang or gcc take advantage of referencing restrictions for alias analysisWhy can lambdas be better optimized by the compiler than plain functions?Why does the enhanced GCC 6 optimizer break practical C++ code?How to make a Rust mutable reference immutable?Why does creating a mutable reference to a dereferenced mutable reference work?Why can the Rust compiler not optimize Option::take and an “if let” if you print the value?Why can the Rust compiler not optimize away the Err arm of Box::downcast?Why is casting a const reference directly to a mutable reference invalid in Rust?Is it possible to unborrow a mutable reference in rust?

How did the Axis intend to hold the Caucasus?

Should I accept an invitation to give a talk from someone who might review my proposal?

Dual-national, returning to US the day the US Passport expires; can he check in with airline on Dutch passport but reenter with expiring US passport?

Does dual boot harm a laptop battery or reduce its life?

ECDSA: Why is SigningKey shorter than VerifyingKey

Is it safe if the neutral lead is exposed and disconnected?

Is this photo showing a woman standing in the nude before teenagers real?

Is it okay for me to decline a project on ethical grounds?

What container to use to store developer concentrate?

Exploiting the delay when a festival ticket is scanned

How does one get an animal off of the Altar surreptitiously?

Name These Animals

Desktop app status bar: Notification vs error message

Why did I lose on time with 3 pawns vs Knight. Shouldn't it be a draw?

Why isn't there any 9.5 digit multimeter or higher?

Irreducible factors of primitive permutation group representation

Telling manager project isn't worth the effort?

Copying an existing HTML page and use it, is that against any copyright law?

What steps would an amateur scientist have to take in order to get a scientific breakthrough published?

What happens when a flying sword is killed?

reconstruction filter - How does it actually work?

Polyhedra, Polyhedron, Polytopes and Polygon

If Trump gets impeached, how long would Pence be president?

(3 of 11: Akari) What is Pyramid Cult's Favorite Car?



Why does the Rust compiler not optimize code assuming that two mutable references cannot alias?


Why can't (or doesn't) the compiler optimize a predictable addition loop into a multiplication?Does clang or gcc take advantage of referencing restrictions for alias analysisWhy can lambdas be better optimized by the compiler than plain functions?Why does the enhanced GCC 6 optimizer break practical C++ code?How to make a Rust mutable reference immutable?Why does creating a mutable reference to a dereferenced mutable reference work?Why can the Rust compiler not optimize Option::take and an “if let” if you print the value?Why can the Rust compiler not optimize away the Err arm of Box::downcast?Why is casting a const reference directly to a mutable reference invalid in Rust?Is it possible to unborrow a mutable reference in rust?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








8















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question


























  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago

















8















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question


























  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago













8












8








8


2






As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question
















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?







rust compiler-optimization






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago









Shepmaster

174k20 gold badges383 silver badges535 bronze badges




174k20 gold badges383 silver badges535 bronze badges










asked 9 hours ago









AccienteAcciente

554 bronze badges




554 bronze badges















  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago

















  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago
















godbolt.org/z/aEDINX, strange

– Stargateur
8 hours ago






godbolt.org/z/aEDINX, strange

– Stargateur
8 hours ago





3




3





Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

– Lukas Kalbertodt
7 hours ago





Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

– Lukas Kalbertodt
7 hours ago












1 Answer
1






active

oldest

votes


















12














Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



adds:
mov eax, dword ptr [rsi]
add eax, eax
add dword ptr [rdi], eax
ret


Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



This has happened multiple times.



Related Rust issues:




  • Current case



    • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

    • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



  • Previous case



    • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

    • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



  • Other



    • make use of LLVM's scoped noalias metadata #16515

    • Missed optimization: references from pointers aren't treated as noalias #38941

    • noalias is not enough #53105

    • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






share|improve this answer


























    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f57259126%2fwhy-does-the-rust-compiler-not-optimize-code-assuming-that-two-mutable-reference%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    12














    Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



    If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



    adds:
    mov eax, dword ptr [rsi]
    add eax, eax
    add dword ptr [rdi], eax
    ret


    Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



    This has happened multiple times.



    Related Rust issues:




    • Current case



      • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

      • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



    • Previous case



      • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

      • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



    • Other



      • make use of LLVM's scoped noalias metadata #16515

      • Missed optimization: references from pointers aren't treated as noalias #38941

      • noalias is not enough #53105

      • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






    share|improve this answer































      12














      Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



      If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



      adds:
      mov eax, dword ptr [rsi]
      add eax, eax
      add dword ptr [rdi], eax
      ret


      Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



      This has happened multiple times.



      Related Rust issues:




      • Current case



        • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

        • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



      • Previous case



        • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

        • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



      • Other



        • make use of LLVM's scoped noalias metadata #16515

        • Missed optimization: references from pointers aren't treated as noalias #38941

        • noalias is not enough #53105

        • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






      share|improve this answer





























        12












        12








        12







        Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



        If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



        adds:
        mov eax, dword ptr [rsi]
        add eax, eax
        add dword ptr [rdi], eax
        ret


        Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



        This has happened multiple times.



        Related Rust issues:




        • Current case



          • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

          • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



        • Previous case



          • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

          • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



        • Other



          • make use of LLVM's scoped noalias metadata #16515

          • Missed optimization: references from pointers aren't treated as noalias #38941

          • noalias is not enough #53105

          • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






        share|improve this answer















        Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



        If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



        adds:
        mov eax, dword ptr [rsi]
        add eax, eax
        add dword ptr [rdi], eax
        ret


        Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



        This has happened multiple times.



        Related Rust issues:




        • Current case



          • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

          • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



        • Previous case



          • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

          • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



        • Other



          • make use of LLVM's scoped noalias metadata #16515

          • Missed optimization: references from pointers aren't treated as noalias #38941

          • noalias is not enough #53105

          • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 8 hours ago









        ShepmasterShepmaster

        174k20 gold badges383 silver badges535 bronze badges




        174k20 gold badges383 silver badges535 bronze badges





















            Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.







            Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.



















            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f57259126%2fwhy-does-the-rust-compiler-not-optimize-code-assuming-that-two-mutable-reference%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

            Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

            Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її