Why does the Rust compiler not optimize code assuming that two mutable references cannot alias?Why can't (or doesn't) the compiler optimize a predictable addition loop into a multiplication?Does clang or gcc take advantage of referencing restrictions for alias analysisWhy can lambdas be better optimized by the compiler than plain functions?Why does the enhanced GCC 6 optimizer break practical C++ code?How to make a Rust mutable reference immutable?Why does creating a mutable reference to a dereferenced mutable reference work?Why can the Rust compiler not optimize Option::take and an “if let” if you print the value?Why can the Rust compiler not optimize away the Err arm of Box::downcast?Why is casting a const reference directly to a mutable reference invalid in Rust?Is it possible to unborrow a mutable reference in rust?

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Why does the Rust compiler not optimize code assuming that two mutable references cannot alias?


Why can't (or doesn't) the compiler optimize a predictable addition loop into a multiplication?Does clang or gcc take advantage of referencing restrictions for alias analysisWhy can lambdas be better optimized by the compiler than plain functions?Why does the enhanced GCC 6 optimizer break practical C++ code?How to make a Rust mutable reference immutable?Why does creating a mutable reference to a dereferenced mutable reference work?Why can the Rust compiler not optimize Option::take and an “if let” if you print the value?Why can the Rust compiler not optimize away the Err arm of Box::downcast?Why is casting a const reference directly to a mutable reference invalid in Rust?Is it possible to unborrow a mutable reference in rust?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








8















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question


























  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago

















8















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question


























  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago













8












8








8


2






As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?










share|improve this question
















As far as I know, reference/pointer aliasing can hinder the compiler's ability to generate optimized code, since they must ensure the generated binary behaves correctly in the case where the two references/pointers indeed alias. For instance, in the following C code,



void adds(int *a, int *b) 
*a += *b;
*a += *b;



when compiled by clang version 6.0.0-1ubuntu2 (tags/RELEASE_600/final) with the -O3 flag, it emits



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi) # the first time
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi) # the second time
a: c3 retq


Here the code stores back to (%rdi) twice in case int *a and int *b alias.



When we explicitly tell the compiler that these two pointers cannot alias with the restrict keyword:



void adds(int * restrict a, int * restrict b) 
*a += *b;
*a += *b;



Then clang will emit a more optimized version of binary code



0000000000000000 <adds>:
0: 8b 06 mov (%rsi),%eax
2: 01 c0 add %eax,%eax
4: 01 07 add %eax,(%rdi)
6: c3 retq


Since Rust makes sure (except in unsafe code) that two mutable references cannot alias, I would think that the compiler should be able to emit the more optimized version of the code.



When I test with the code below and compile it with rustc 1.35.0 with -C opt-level=3 --emit obj



#![crate_type = "staticlib"]
#[no_mangle]
fn adds(a: &mut i32, b: &mut i32)
*a += *b;
*a += *b;



it generates



0000000000000000 <adds>:
0: 8b 07 mov (%rdi),%eax
2: 03 06 add (%rsi),%eax
4: 89 07 mov %eax,(%rdi)
6: 03 06 add (%rsi),%eax
8: 89 07 mov %eax,(%rdi)
a: c3 retq


This does not take advantage of the guarantee that a and b cannot alias.



Is this because the current Rust compiler is still in development and has not yet incorporated alias analysis to do the optimization?



Is this because there is still a chance that a and b could alias, even in safe Rust?







rust compiler-optimization






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago









Shepmaster

174k20 gold badges383 silver badges535 bronze badges




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asked 9 hours ago









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  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago

















  • godbolt.org/z/aEDINX, strange

    – Stargateur
    8 hours ago







  • 3





    Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

    – Lukas Kalbertodt
    7 hours ago
















godbolt.org/z/aEDINX, strange

– Stargateur
8 hours ago






godbolt.org/z/aEDINX, strange

– Stargateur
8 hours ago





3




3





Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

– Lukas Kalbertodt
7 hours ago





Side remark: "Since Rust makes sure (except in unsafe code) that two mutable references cannot alias" -- it is worth mentioning that even in unsafe code, aliasing mutable references are not allowed and result in undefined behavior. You can have aliasing raw pointers, but unsafe code does not actually allow you to ignore Rust standard rules. It's just a common misconception and thus worth pointing out.

– Lukas Kalbertodt
7 hours ago












1 Answer
1






active

oldest

votes


















12














Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



adds:
mov eax, dword ptr [rsi]
add eax, eax
add dword ptr [rdi], eax
ret


Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



This has happened multiple times.



Related Rust issues:




  • Current case



    • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

    • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



  • Previous case



    • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

    • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



  • Other



    • make use of LLVM's scoped noalias metadata #16515

    • Missed optimization: references from pointers aren't treated as noalias #38941

    • noalias is not enough #53105

    • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






share|improve this answer


























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    1 Answer
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    active

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    12














    Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



    If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



    adds:
    mov eax, dword ptr [rsi]
    add eax, eax
    add dword ptr [rdi], eax
    ret


    Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



    This has happened multiple times.



    Related Rust issues:




    • Current case



      • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

      • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



    • Previous case



      • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

      • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



    • Other



      • make use of LLVM's scoped noalias metadata #16515

      • Missed optimization: references from pointers aren't treated as noalias #38941

      • noalias is not enough #53105

      • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






    share|improve this answer































      12














      Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



      If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



      adds:
      mov eax, dword ptr [rsi]
      add eax, eax
      add dword ptr [rdi], eax
      ret


      Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



      This has happened multiple times.



      Related Rust issues:




      • Current case



        • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

        • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



      • Previous case



        • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

        • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



      • Other



        • make use of LLVM's scoped noalias metadata #16515

        • Missed optimization: references from pointers aren't treated as noalias #38941

        • noalias is not enough #53105

        • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






      share|improve this answer





























        12












        12








        12







        Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



        If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



        adds:
        mov eax, dword ptr [rsi]
        add eax, eax
        add dword ptr [rdi], eax
        ret


        Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



        This has happened multiple times.



        Related Rust issues:




        • Current case



          • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

          • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



        • Previous case



          • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

          • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



        • Other



          • make use of LLVM's scoped noalias metadata #16515

          • Missed optimization: references from pointers aren't treated as noalias #38941

          • noalias is not enough #53105

          • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029






        share|improve this answer















        Rust originally did enable LLVM's noalias attribute, but this caused miscompiled code. When all supported LLVM versions no longer miscompile the code, it will be re-enabled.



        If you add -Zmutable-noalias=yes to the compiler options, you get the expected assembly:



        adds:
        mov eax, dword ptr [rsi]
        add eax, eax
        add dword ptr [rdi], eax
        ret


        Simply put, Rust put the equivalent of C's restrict keyword everywhere, far more prevalent than any usual C program. This exercised corner cases of LLVM more than it was able to handle correctly. It turns out that C and C++ programmers simply don't use restrict as frequently as &mut is used in Rust.



        This has happened multiple times.



        Related Rust issues:




        • Current case



          • Incorrect code generation for nalgebra's Matrix::swap_rows() #54462

          • Re-enable noalias annotations by default once LLVM no longer miscompiles them #54878



        • Previous case



          • Workaround LLVM optimizer bug by not marking &mut pointers as noalias #31545

          • Mark &mut pointers as noalias once LLVM no longer miscompiles them #31681



        • Other



          • make use of LLVM's scoped noalias metadata #16515

          • Missed optimization: references from pointers aren't treated as noalias #38941

          • noalias is not enough #53105

          • mutable noalias: re-enable permanently, only for panic=abort, or stabilize flag? #45029







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 8 hours ago









        ShepmasterShepmaster

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