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C4_4 Reflection!

The Characters in the String Go Round and RoundASCII Doodling: Laser in a BoxRotate a Chinese checkerboardASCII art reflectionSimulate a Rubik's cubeHexaGolf: RotatagonsSame length, different stringBinary tree rotationsRotate ASCII Art by 45 DegreesIs this skew symmetry?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;

5

$begingroup$

Sorry if this is a dupe.

In this challenge, your task is to input a rectangle ASCII pattern (You may assume only printable characters need to be handled, and you may assume a trailing newline or not), C4_4 symmetrify, and output it.

Here, C4_4 symmetric means symmetric under 90-degree rotation around a corner of the corner character. The corresponding "symmetrify" process is copy and rotate 90-degree clockwise three times, and then put all four copies together. For the precise arrangement, you can look at Test Cases.

Test Cases

Input:
asdf
jkl;

Output:
 ja
 ks
asdfld
jkl;;f
 f;;lkj
 dlfdsa
 sk
 aj

Input:
.O.
..O
OOO

Output:

.O.O..
..OO.O
OOOOO.
.OOOOO
O.OO..
..O.O.

code-golf ascii-art

share|improve this question

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'd suggest to add a test case where the height of the input is strictly greater than its width.
  $endgroup$
  – Arnauld
  11 hours ago
  

  
  
  
  

add a comment
 | 

5

$begingroup$

Sorry if this is a dupe.

In this challenge, your task is to input a rectangle ASCII pattern (You may assume only printable characters need to be handled, and you may assume a trailing newline or not), C4_4 symmetrify, and output it.

Here, C4_4 symmetric means symmetric under 90-degree rotation around a corner of the corner character. The corresponding "symmetrify" process is copy and rotate 90-degree clockwise three times, and then put all four copies together. For the precise arrangement, you can look at Test Cases.

Test Cases

Input:
asdf
jkl;

Output:
 ja
 ks
asdfld
jkl;;f
 f;;lkj
 dlfdsa
 sk
 aj

Input:
.O.
..O
OOO

Output:

.O.O..
..OO.O
OOOOO.
.OOOOO
O.OO..
..O.O.

code-golf ascii-art

share|improve this question

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'd suggest to add a test case where the height of the input is strictly greater than its width.
  $endgroup$
  – Arnauld
  11 hours ago
  

  
  
  
  

add a comment
 | 

$begingroup$

Sorry if this is a dupe.

In this challenge, your task is to input a rectangle ASCII pattern (You may assume only printable characters need to be handled, and you may assume a trailing newline or not), C4_4 symmetrify, and output it.

Here, C4_4 symmetric means symmetric under 90-degree rotation around a corner of the corner character. The corresponding "symmetrify" process is copy and rotate 90-degree clockwise three times, and then put all four copies together. For the precise arrangement, you can look at Test Cases.

Test Cases

Input:
asdf
jkl;

Output:
 ja
 ks
asdfld
jkl;;f
 f;;lkj
 dlfdsa
 sk
 aj

Input:
.O.
..O
OOO

Output:

.O.O..
..OO.O
OOOOO.
.OOOOO
O.OO..
..O.O.

code-golf ascii-art

share|improve this question

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

$endgroup$

Input:
asdf
jkl;

Output:
 ja
 ks
asdfld
jkl;;f
 f;;lkj
 dlfdsa
 sk
 aj

Input:
.O.
..O
OOO

Output:

.O.O..
..OO.O
OOOOO.
.OOOOO
O.OO..
..O.O.

share|improve this question

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

share|improve this question

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

edited 10 hours ago

alephalpha

22.8k33 gold badges3232 silver badges9898 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

asked 12 hours ago

TwilightSparkleTwilightSparkle

73744 silver badges1515 bronze badges

4 Answers
4

active

oldest

votes

5

$begingroup$

Charcoal, 6 bytes

Ａ⟲Ｃ²⁴⁶

Try it online! Link is to verbose version of code. Explanation: Ａ implicitly prints the input, ⟲ performs the rotation, Ｃ signifies to keep copies, and ²⁴⁶ represents the numbers of 45-degree rotations to make. (Charcoal defaults to rotating around the bottom-right corner as desired.)

share|improve this answer

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yet another fastest gun! Yeah, Charcoal is very suitable for this challenge. Have a +1!
  $endgroup$
  – TwilightSparkle
  12 hours ago
  

  
  
  
  

add a comment
 | 

2

$begingroup$

Python 3, 193 bytes

def f(s):q=len(s[0])-len(s);s=[[" "]*len(s[0])]*q+s;s=[[" "]*-q+l for l in s];j=lambda a,b:[x+y for x,y in zip(a,b)];r=lambda x:[*map(list,zip(*x[::-1]))];return j(s,r(s))+j(r(r(r(s))),r(r(s)))

Try it online!

share|improve this answer

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I was not expecting this to happen. Nice work!
  $endgroup$
  – TwilightSparkle
  11 hours ago
  

  
  
  
  

add a comment
 | 

1

$begingroup$

J, 38 bytes

(,|."1@|.)@(,.|:@|.)@((2$_1*>./)@${.])

Try it online!

No doubt it can be golfed much further.

share|improve this answer

edited 11 hours ago

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

$endgroup$

add a comment
 | 

1

$begingroup$

JavaScript (ES6),  178  173 bytes

Takes input as an array of strings. Returns a string.

m=>(g=x=>~y?(Y=y<w?y:W-y,X=x<w?x:W-x,Z=y<w^x<w?Y:X,(m[Z-z*d]||0)[(X^Y^Z)+!z*d]||' ')+[`
`[x-W]]+g(x<W?x+1:!y--):'')(0,w=m[0].length,h=m.length,d=w-h,(z=d>0)?0:w=h,y=W=w*2-1)

Try it online!

share|improve this answer

edited 11 hours ago

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

$endgroup$

add a comment
 | 

Your Answer

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5

$begingroup$

Charcoal, 6 bytes

Ａ⟲Ｃ²⁴⁶

Try it online! Link is to verbose version of code. Explanation: Ａ implicitly prints the input, ⟲ performs the rotation, Ｃ signifies to keep copies, and ²⁴⁶ represents the numbers of 45-degree rotations to make. (Charcoal defaults to rotating around the bottom-right corner as desired.)

share|improve this answer

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yet another fastest gun! Yeah, Charcoal is very suitable for this challenge. Have a +1!
  $endgroup$
  – TwilightSparkle
  12 hours ago
  

  
  
  
  

add a comment
 | 

5

$begingroup$

Charcoal, 6 bytes

Ａ⟲Ｃ²⁴⁶

Try it online! Link is to verbose version of code. Explanation: Ａ implicitly prints the input, ⟲ performs the rotation, Ｃ signifies to keep copies, and ²⁴⁶ represents the numbers of 45-degree rotations to make. (Charcoal defaults to rotating around the bottom-right corner as desired.)

share|improve this answer

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yet another fastest gun! Yeah, Charcoal is very suitable for this challenge. Have a +1!
  $endgroup$
  – TwilightSparkle
  12 hours ago
  

  
  
  
  

add a comment
 | 

$begingroup$

Charcoal, 6 bytes

Ａ⟲Ｃ²⁴⁶

Try it online! Link is to verbose version of code. Explanation: Ａ implicitly prints the input, ⟲ performs the rotation, Ｃ signifies to keep copies, and ²⁴⁶ represents the numbers of 45-degree rotations to make. (Charcoal defaults to rotating around the bottom-right corner as desired.)

share|improve this answer

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

$endgroup$

Ａ⟲Ｃ²⁴⁶

share|improve this answer

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

answered 12 hours ago

NeilNeil

89.5k88 gold badges4646 silver badges188188 bronze badges

2

$begingroup$

Python 3, 193 bytes

def f(s):q=len(s[0])-len(s);s=[[" "]*len(s[0])]*q+s;s=[[" "]*-q+l for l in s];j=lambda a,b:[x+y for x,y in zip(a,b)];r=lambda x:[*map(list,zip(*x[::-1]))];return j(s,r(s))+j(r(r(r(s))),r(r(s)))

Try it online!

share|improve this answer

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I was not expecting this to happen. Nice work!
  $endgroup$
  – TwilightSparkle
  11 hours ago
  

  
  
  
  

add a comment
 | 

2

$begingroup$

Python 3, 193 bytes

def f(s):q=len(s[0])-len(s);s=[[" "]*len(s[0])]*q+s;s=[[" "]*-q+l for l in s];j=lambda a,b:[x+y for x,y in zip(a,b)];r=lambda x:[*map(list,zip(*x[::-1]))];return j(s,r(s))+j(r(r(r(s))),r(r(s)))

Try it online!

share|improve this answer

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I was not expecting this to happen. Nice work!
  $endgroup$
  – TwilightSparkle
  11 hours ago
  

  
  
  
  

add a comment
 | 

$begingroup$

Python 3, 193 bytes

def f(s):q=len(s[0])-len(s);s=[[" "]*len(s[0])]*q+s;s=[[" "]*-q+l for l in s];j=lambda a,b:[x+y for x,y in zip(a,b)];r=lambda x:[*map(list,zip(*x[::-1]))];return j(s,r(s))+j(r(r(r(s))),r(r(s)))

Try it online!

share|improve this answer

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

$endgroup$

def f(s):q=len(s[0])-len(s);s=[[" "]*len(s[0])]*q+s;s=[[" "]*-q+l for l in s];j=lambda a,b:[x+y for x,y in zip(a,b)];r=lambda x:[*map(list,zip(*x[::-1]))];return j(s,r(s))+j(r(r(r(s))),r(r(s)))

share|improve this answer

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

answered 11 hours ago

HyperNeutrinoHyperNeutrino

20.6k44 gold badges4141 silver badges155155 bronze badges

1

$begingroup$

J, 38 bytes

(,|."1@|.)@(,.|:@|.)@((2$_1*>./)@${.])

Try it online!

No doubt it can be golfed much further.

share|improve this answer

edited 11 hours ago

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

$endgroup$

add a comment
 | 

1

$begingroup$

J, 38 bytes

(,|."1@|.)@(,.|:@|.)@((2$_1*>./)@${.])

Try it online!

No doubt it can be golfed much further.

share|improve this answer

edited 11 hours ago

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

$endgroup$

add a comment
 | 

$begingroup$

J, 38 bytes

(,|."1@|.)@(,.|:@|.)@((2$_1*>./)@${.])

Try it online!

No doubt it can be golfed much further.

share|improve this answer

edited 11 hours ago

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

$endgroup$

(,|."1@|.)@(,.|:@|.)@((2$_1*>./)@${.])

share|improve this answer

edited 11 hours ago

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

answered 11 hours ago

Galen IvanovGalen Ivanov

9,70711 gold badge1414 silver badges4040 bronze badges

1

$begingroup$

JavaScript (ES6),  178  173 bytes

Takes input as an array of strings. Returns a string.

m=>(g=x=>~y?(Y=y<w?y:W-y,X=x<w?x:W-x,Z=y<w^x<w?Y:X,(m[Z-z*d]||0)[(X^Y^Z)+!z*d]||' ')+[`
`[x-W]]+g(x<W?x+1:!y--):'')(0,w=m[0].length,h=m.length,d=w-h,(z=d>0)?0:w=h,y=W=w*2-1)

Try it online!

share|improve this answer

edited 11 hours ago

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

$endgroup$

add a comment
 | 

1

$begingroup$

JavaScript (ES6),  178  173 bytes

Takes input as an array of strings. Returns a string.

m=>(g=x=>~y?(Y=y<w?y:W-y,X=x<w?x:W-x,Z=y<w^x<w?Y:X,(m[Z-z*d]||0)[(X^Y^Z)+!z*d]||' ')+[`
`[x-W]]+g(x<W?x+1:!y--):'')(0,w=m[0].length,h=m.length,d=w-h,(z=d>0)?0:w=h,y=W=w*2-1)

Try it online!

share|improve this answer

edited 11 hours ago

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

$endgroup$

add a comment
 | 

$begingroup$

JavaScript (ES6),  178  173 bytes

Takes input as an array of strings. Returns a string.

m=>(g=x=>~y?(Y=y<w?y:W-y,X=x<w?x:W-x,Z=y<w^x<w?Y:X,(m[Z-z*d]||0)[(X^Y^Z)+!z*d]||' ')+[`
`[x-W]]+g(x<W?x+1:!y--):'')(0,w=m[0].length,h=m.length,d=w-h,(z=d>0)?0:w=h,y=W=w*2-1)

Try it online!

share|improve this answer

edited 11 hours ago

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

$endgroup$

m=>(g=x=>~y?(Y=y<w?y:W-y,X=x<w?x:W-x,Z=y<w^x<w?Y:X,(m[Z-z*d]||0)[(X^Y^Z)+!z*d]||' ')+[`
`[x-W]]+g(x<W?x+1:!y--):'')(0,w=m[0].length,h=m.length,d=w-h,(z=d>0)?0:w=h,y=W=w*2-1)

share|improve this answer

edited 11 hours ago

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges

answered 11 hours ago

ArnauldArnauld

94.3k77 gold badges111111 silver badges383383 bronze badges