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The joke office
Who are the guilty parties? #1A false and a true statement in the blue-eyed puzzleFind the number from 10 statementsKnights, Knaves and Normals - the tough oneArt Accident at Airport!Systematically solving a certain logic puzzle: win prize B when the truth of your statements relates to prize AWhich of my friends has a birthday today?Communicating Information about CardsWho is your secret santa?True or Faulse?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Alice and Bob are supposed to get form A at the joke office.
Forms A, B, C, D and E are each at exactly one of the following five switches.
Switch 1:
Here there are form B.
Switch 2:
Here there are form C or E.
Switch 3: Here there are form D.
Switch 4:
Here there are form A, C or E.
Switch 5:
Here there are form A.
Bob is at a loss when he reads
the signs at the counters.
Alice remembers what the janitor
is said: "Exactly one statement on the signs is wrong, the four other statements are true."
Question:
At which switch is form A
available?
logical-deduction liars
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
$endgroup$
add a comment |
$begingroup$
Alice and Bob are supposed to get form A at the joke office.
Forms A, B, C, D and E are each at exactly one of the following five switches.
Switch 1:
Here there are form B.
Switch 2:
Here there are form C or E.
Switch 3: Here there are form D.
Switch 4:
Here there are form A, C or E.
Switch 5:
Here there are form A.
Bob is at a loss when he reads
the signs at the counters.
Alice remembers what the janitor
is said: "Exactly one statement on the signs is wrong, the four other statements are true."
Question:
At which switch is form A
available?
logical-deduction liars
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
$endgroup$
add a comment |
$begingroup$
Alice and Bob are supposed to get form A at the joke office.
Forms A, B, C, D and E are each at exactly one of the following five switches.
Switch 1:
Here there are form B.
Switch 2:
Here there are form C or E.
Switch 3: Here there are form D.
Switch 4:
Here there are form A, C or E.
Switch 5:
Here there are form A.
Bob is at a loss when he reads
the signs at the counters.
Alice remembers what the janitor
is said: "Exactly one statement on the signs is wrong, the four other statements are true."
Question:
At which switch is form A
available?
logical-deduction liars
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
$endgroup$
Alice and Bob are supposed to get form A at the joke office.
Forms A, B, C, D and E are each at exactly one of the following five switches.
Switch 1:
Here there are form B.
Switch 2:
Here there are form C or E.
Switch 3: Here there are form D.
Switch 4:
Here there are form A, C or E.
Switch 5:
Here there are form A.
Bob is at a loss when he reads
the signs at the counters.
Alice remembers what the janitor
is said: "Exactly one statement on the signs is wrong, the four other statements are true."
Question:
At which switch is form A
available?
logical-deduction liars
logical-deduction liars
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
asked 9 hours ago
MattiMatti
1,3671 silver badge22 bronze badges
1,3671 silver badge22 bronze badges
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Notation: (P,Q,R,S,T) denotes that form P is in Switch 1, Q in Switch 2, etc.
If Switch 1 is wrong, then
(?,C/E,D,C/E,A), only choice left for ? is B -> contradiction
If Switch 2 is wrong, then
(B,?,D,C/E,A), only choices left for ? are C and E -> contradiction
If Switch 3 is wrong, then
(B,C/E,?,C/E,A), only choice left for ? is D -> contradiction
If Switch 4 is wrong, then
(B,C/E,D,?,A), only choices left for ? are C and E -> contradiction
If Switch 5 is wrong, then
(B,C/E,D,A/C/E,?), one scenario can be (B,C/E,D,A,C/E) -> possible
Answer
Form A: Switch 4; Wrong Sign: Switch 5
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Form A is available at
Switch 4.
Assume
Switch 1 was incorrect. This means that form B must be somewhere else. But there is no other sign which references form B, so that would mean more than one sign was incorrect (contradiction!). If we assume Switch 3 was incorrect, we’d get the same result. So one of Switches 2, 4, or 5 are wrong. It can’t be 4, because then B or D would have to be there too and those have already been placed. Assuming that Switch 2 was wrong would put A at Switch 2, but then Switch 5 would also be wrong. Therefore Switch 5 must be wrong, so all of the others are right, and since Switch 4 is the only place with mention to A, it must be there.
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
$endgroup$
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Notation: (P,Q,R,S,T) denotes that form P is in Switch 1, Q in Switch 2, etc.
If Switch 1 is wrong, then
(?,C/E,D,C/E,A), only choice left for ? is B -> contradiction
If Switch 2 is wrong, then
(B,?,D,C/E,A), only choices left for ? are C and E -> contradiction
If Switch 3 is wrong, then
(B,C/E,?,C/E,A), only choice left for ? is D -> contradiction
If Switch 4 is wrong, then
(B,C/E,D,?,A), only choices left for ? are C and E -> contradiction
If Switch 5 is wrong, then
(B,C/E,D,A/C/E,?), one scenario can be (B,C/E,D,A,C/E) -> possible
Answer
Form A: Switch 4; Wrong Sign: Switch 5
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Notation: (P,Q,R,S,T) denotes that form P is in Switch 1, Q in Switch 2, etc.
If Switch 1 is wrong, then
(?,C/E,D,C/E,A), only choice left for ? is B -> contradiction
If Switch 2 is wrong, then
(B,?,D,C/E,A), only choices left for ? are C and E -> contradiction
If Switch 3 is wrong, then
(B,C/E,?,C/E,A), only choice left for ? is D -> contradiction
If Switch 4 is wrong, then
(B,C/E,D,?,A), only choices left for ? are C and E -> contradiction
If Switch 5 is wrong, then
(B,C/E,D,A/C/E,?), one scenario can be (B,C/E,D,A,C/E) -> possible
Answer
Form A: Switch 4; Wrong Sign: Switch 5
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Notation: (P,Q,R,S,T) denotes that form P is in Switch 1, Q in Switch 2, etc.
If Switch 1 is wrong, then
(?,C/E,D,C/E,A), only choice left for ? is B -> contradiction
If Switch 2 is wrong, then
(B,?,D,C/E,A), only choices left for ? are C and E -> contradiction
If Switch 3 is wrong, then
(B,C/E,?,C/E,A), only choice left for ? is D -> contradiction
If Switch 4 is wrong, then
(B,C/E,D,?,A), only choices left for ? are C and E -> contradiction
If Switch 5 is wrong, then
(B,C/E,D,A/C/E,?), one scenario can be (B,C/E,D,A,C/E) -> possible
Answer
Form A: Switch 4; Wrong Sign: Switch 5
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
$endgroup$
Notation: (P,Q,R,S,T) denotes that form P is in Switch 1, Q in Switch 2, etc.
If Switch 1 is wrong, then
(?,C/E,D,C/E,A), only choice left for ? is B -> contradiction
If Switch 2 is wrong, then
(B,?,D,C/E,A), only choices left for ? are C and E -> contradiction
If Switch 3 is wrong, then
(B,C/E,?,C/E,A), only choice left for ? is D -> contradiction
If Switch 4 is wrong, then
(B,C/E,D,?,A), only choices left for ? are C and E -> contradiction
If Switch 5 is wrong, then
(B,C/E,D,A/C/E,?), one scenario can be (B,C/E,D,A,C/E) -> possible
Answer
Form A: Switch 4; Wrong Sign: Switch 5
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
edited 9 hours ago
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
answered 9 hours ago
Omega KryptonOmega Krypton
10.3k2 gold badges12 silver badges72 bronze badges
10.3k2 gold badges12 silver badges72 bronze badges
add a comment |
add a comment |
$begingroup$
Form A is available at
Switch 4.
Assume
Switch 1 was incorrect. This means that form B must be somewhere else. But there is no other sign which references form B, so that would mean more than one sign was incorrect (contradiction!). If we assume Switch 3 was incorrect, we’d get the same result. So one of Switches 2, 4, or 5 are wrong. It can’t be 4, because then B or D would have to be there too and those have already been placed. Assuming that Switch 2 was wrong would put A at Switch 2, but then Switch 5 would also be wrong. Therefore Switch 5 must be wrong, so all of the others are right, and since Switch 4 is the only place with mention to A, it must be there.
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
$endgroup$
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
add a comment |
$begingroup$
Form A is available at
Switch 4.
Assume
Switch 1 was incorrect. This means that form B must be somewhere else. But there is no other sign which references form B, so that would mean more than one sign was incorrect (contradiction!). If we assume Switch 3 was incorrect, we’d get the same result. So one of Switches 2, 4, or 5 are wrong. It can’t be 4, because then B or D would have to be there too and those have already been placed. Assuming that Switch 2 was wrong would put A at Switch 2, but then Switch 5 would also be wrong. Therefore Switch 5 must be wrong, so all of the others are right, and since Switch 4 is the only place with mention to A, it must be there.
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
$endgroup$
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
add a comment |
$begingroup$
Form A is available at
Switch 4.
Assume
Switch 1 was incorrect. This means that form B must be somewhere else. But there is no other sign which references form B, so that would mean more than one sign was incorrect (contradiction!). If we assume Switch 3 was incorrect, we’d get the same result. So one of Switches 2, 4, or 5 are wrong. It can’t be 4, because then B or D would have to be there too and those have already been placed. Assuming that Switch 2 was wrong would put A at Switch 2, but then Switch 5 would also be wrong. Therefore Switch 5 must be wrong, so all of the others are right, and since Switch 4 is the only place with mention to A, it must be there.
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
$endgroup$
Form A is available at
Switch 4.
Assume
Switch 1 was incorrect. This means that form B must be somewhere else. But there is no other sign which references form B, so that would mean more than one sign was incorrect (contradiction!). If we assume Switch 3 was incorrect, we’d get the same result. So one of Switches 2, 4, or 5 are wrong. It can’t be 4, because then B or D would have to be there too and those have already been placed. Assuming that Switch 2 was wrong would put A at Switch 2, but then Switch 5 would also be wrong. Therefore Switch 5 must be wrong, so all of the others are right, and since Switch 4 is the only place with mention to A, it must be there.
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
edited 9 hours ago
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
answered 9 hours ago
El-GuestEl-Guest
24.1k3 gold badges55 silver badges97 bronze badges
24.1k3 gold badges55 silver badges97 bronze badges
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
add a comment |
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
1
1
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
$begingroup$
you sniped me with only the answer, but i have the full explanation first. let the judge decide! good game!
$endgroup$
– Omega Krypton
9 hours ago
add a comment |
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