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How to compare the ls output of two folders to find a missing directory?


Compare two folders for missing filesHow do you compare two folders and copy the difference to a third folder?given a file, find where within a subdirectory it was copied tomerge two image foldersFind differences of ownerships between two home folders?Streaming compare the contents in two directoryMove files that have the same case-insensitive filenameHow should I merge two folders on the same filesystem?Print Folders Missing .txt FiletypeCompare two directories for a certain extension and then move the missing ones to a new directoryCompare two folders for missing files






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















I'm trying to compare a folder with 1400 subfolders to one with a 1.399. I need to know which subfolder is missing.



I tried this:



diff -rq dir1/ dir2/ | grep dir1/ | awk 'print $4' > difference1.txt


But it's been like 6 hours yet and no output. ls in the folders is nearly instant so is there a faster approach than diff?










share|improve this question






















  • Answered in stackoverflow.com/questions/4997693/…

    – GMaster
    8 hours ago











  • @GMaster I'm asking for a faster approach

    – Freedo
    8 hours ago











  • Sounds similar to unix.stackexchange.com/q/524074/117549

    – Jeff Schaller
    7 hours ago

















3















I'm trying to compare a folder with 1400 subfolders to one with a 1.399. I need to know which subfolder is missing.



I tried this:



diff -rq dir1/ dir2/ | grep dir1/ | awk 'print $4' > difference1.txt


But it's been like 6 hours yet and no output. ls in the folders is nearly instant so is there a faster approach than diff?










share|improve this question






















  • Answered in stackoverflow.com/questions/4997693/…

    – GMaster
    8 hours ago











  • @GMaster I'm asking for a faster approach

    – Freedo
    8 hours ago











  • Sounds similar to unix.stackexchange.com/q/524074/117549

    – Jeff Schaller
    7 hours ago













3












3








3








I'm trying to compare a folder with 1400 subfolders to one with a 1.399. I need to know which subfolder is missing.



I tried this:



diff -rq dir1/ dir2/ | grep dir1/ | awk 'print $4' > difference1.txt


But it's been like 6 hours yet and no output. ls in the folders is nearly instant so is there a faster approach than diff?










share|improve this question














I'm trying to compare a folder with 1400 subfolders to one with a 1.399. I need to know which subfolder is missing.



I tried this:



diff -rq dir1/ dir2/ | grep dir1/ | awk 'print $4' > difference1.txt


But it's been like 6 hours yet and no output. ls in the folders is nearly instant so is there a faster approach than diff?







files






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 8 hours ago









FreedoFreedo

4826 silver badges24 bronze badges




4826 silver badges24 bronze badges












  • Answered in stackoverflow.com/questions/4997693/…

    – GMaster
    8 hours ago











  • @GMaster I'm asking for a faster approach

    – Freedo
    8 hours ago











  • Sounds similar to unix.stackexchange.com/q/524074/117549

    – Jeff Schaller
    7 hours ago

















  • Answered in stackoverflow.com/questions/4997693/…

    – GMaster
    8 hours ago











  • @GMaster I'm asking for a faster approach

    – Freedo
    8 hours ago











  • Sounds similar to unix.stackexchange.com/q/524074/117549

    – Jeff Schaller
    7 hours ago
















Answered in stackoverflow.com/questions/4997693/…

– GMaster
8 hours ago





Answered in stackoverflow.com/questions/4997693/…

– GMaster
8 hours ago













@GMaster I'm asking for a faster approach

– Freedo
8 hours ago





@GMaster I'm asking for a faster approach

– Freedo
8 hours ago













Sounds similar to unix.stackexchange.com/q/524074/117549

– Jeff Schaller
7 hours ago





Sounds similar to unix.stackexchange.com/q/524074/117549

– Jeff Schaller
7 hours ago










3 Answers
3






active

oldest

votes


















2














This is a fairly simple task for rsync.



rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'



This does a dry run of rsyncing dir1's contents into dir2, and displays only the lines ending in a slash (the directories), except possibly for the top-level directory itself.



Here's a simple test/demo:



$ # create 1500 folders in dir1:
$ for i in $(jot -w %04d 1500); do mkdir -p dir1/dir-$i; done
$ # clone dir1 to dir2, then remove one directory:
$ rsync -a dir1/ dir2/
$ rmdir dir2/dir-0749/
$ # rsync -n will tell you which one is missing:
$ time rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'
dir-0749/

real 0m0.038s
user 0m0.001s
sys 0m0.041s


If you would like to adapt this technique to also check for folders missing from dir1 but present in dir2, use rsync's --delete option:



$ rmdir dir1/dir-0479/
$ time rsync -nav --delete dir1/ dir2/ | grep '/$' | grep -Fvx './'
deleting dir-0479/
dir-0749/


The deleting ... line tells you that dir-0479 is absent from dir1 but present in dir2.






share|improve this answer






























    1














    Try either
    ls dir1 > file1; ls dir2 > file2; diff file1 file2



    or if you have vimdiff and tree which is the most useful way with sub directories, you could use



    tree dir1 > file1; tree dir2 > fiel2; vimdiff file1 file2



    Though, running ls is much faster than tree which is what you are after.



    If the difference is in a sub-directory in dir1
    eg.



    dir1
    - dir2
    - dir3
    - dir4
    vs

    dir2
    - dir2
    - dir3


    You would need to do



    ls -R dir1 > file1; ls -R dir2 > file2; vimdiff file1 file2






    share|improve this answer










    New contributor



    T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.


























      1














      diff -u <(ls dir1) <(ls dir2)


      This will make sure diff does not look inside the subdirs.



      Or try this if you are brave ;)



      diff -u <(find dir1/ -maxdepth 1 -type d -exec basename ;) <(find dir2/ -maxdepth 1 -type d -exec basename ;)





      share|improve this answer

























      • diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

        – Hannu
        8 hours ago






      • 1





        =) ............

        – Hannu
        8 hours ago











      • comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

        – Freedo
        7 hours ago













      Your Answer








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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      This is a fairly simple task for rsync.



      rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'



      This does a dry run of rsyncing dir1's contents into dir2, and displays only the lines ending in a slash (the directories), except possibly for the top-level directory itself.



      Here's a simple test/demo:



      $ # create 1500 folders in dir1:
      $ for i in $(jot -w %04d 1500); do mkdir -p dir1/dir-$i; done
      $ # clone dir1 to dir2, then remove one directory:
      $ rsync -a dir1/ dir2/
      $ rmdir dir2/dir-0749/
      $ # rsync -n will tell you which one is missing:
      $ time rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'
      dir-0749/

      real 0m0.038s
      user 0m0.001s
      sys 0m0.041s


      If you would like to adapt this technique to also check for folders missing from dir1 but present in dir2, use rsync's --delete option:



      $ rmdir dir1/dir-0479/
      $ time rsync -nav --delete dir1/ dir2/ | grep '/$' | grep -Fvx './'
      deleting dir-0479/
      dir-0749/


      The deleting ... line tells you that dir-0479 is absent from dir1 but present in dir2.






      share|improve this answer



























        2














        This is a fairly simple task for rsync.



        rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'



        This does a dry run of rsyncing dir1's contents into dir2, and displays only the lines ending in a slash (the directories), except possibly for the top-level directory itself.



        Here's a simple test/demo:



        $ # create 1500 folders in dir1:
        $ for i in $(jot -w %04d 1500); do mkdir -p dir1/dir-$i; done
        $ # clone dir1 to dir2, then remove one directory:
        $ rsync -a dir1/ dir2/
        $ rmdir dir2/dir-0749/
        $ # rsync -n will tell you which one is missing:
        $ time rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'
        dir-0749/

        real 0m0.038s
        user 0m0.001s
        sys 0m0.041s


        If you would like to adapt this technique to also check for folders missing from dir1 but present in dir2, use rsync's --delete option:



        $ rmdir dir1/dir-0479/
        $ time rsync -nav --delete dir1/ dir2/ | grep '/$' | grep -Fvx './'
        deleting dir-0479/
        dir-0749/


        The deleting ... line tells you that dir-0479 is absent from dir1 but present in dir2.






        share|improve this answer

























          2












          2








          2







          This is a fairly simple task for rsync.



          rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'



          This does a dry run of rsyncing dir1's contents into dir2, and displays only the lines ending in a slash (the directories), except possibly for the top-level directory itself.



          Here's a simple test/demo:



          $ # create 1500 folders in dir1:
          $ for i in $(jot -w %04d 1500); do mkdir -p dir1/dir-$i; done
          $ # clone dir1 to dir2, then remove one directory:
          $ rsync -a dir1/ dir2/
          $ rmdir dir2/dir-0749/
          $ # rsync -n will tell you which one is missing:
          $ time rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'
          dir-0749/

          real 0m0.038s
          user 0m0.001s
          sys 0m0.041s


          If you would like to adapt this technique to also check for folders missing from dir1 but present in dir2, use rsync's --delete option:



          $ rmdir dir1/dir-0479/
          $ time rsync -nav --delete dir1/ dir2/ | grep '/$' | grep -Fvx './'
          deleting dir-0479/
          dir-0749/


          The deleting ... line tells you that dir-0479 is absent from dir1 but present in dir2.






          share|improve this answer













          This is a fairly simple task for rsync.



          rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'



          This does a dry run of rsyncing dir1's contents into dir2, and displays only the lines ending in a slash (the directories), except possibly for the top-level directory itself.



          Here's a simple test/demo:



          $ # create 1500 folders in dir1:
          $ for i in $(jot -w %04d 1500); do mkdir -p dir1/dir-$i; done
          $ # clone dir1 to dir2, then remove one directory:
          $ rsync -a dir1/ dir2/
          $ rmdir dir2/dir-0749/
          $ # rsync -n will tell you which one is missing:
          $ time rsync -n -av dir1/ dir2/ | grep '/$' | grep -Fvx './'
          dir-0749/

          real 0m0.038s
          user 0m0.001s
          sys 0m0.041s


          If you would like to adapt this technique to also check for folders missing from dir1 but present in dir2, use rsync's --delete option:



          $ rmdir dir1/dir-0479/
          $ time rsync -nav --delete dir1/ dir2/ | grep '/$' | grep -Fvx './'
          deleting dir-0479/
          dir-0749/


          The deleting ... line tells you that dir-0479 is absent from dir1 but present in dir2.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 6 hours ago









          Jim L.Jim L.

          8262 silver badges5 bronze badges




          8262 silver badges5 bronze badges























              1














              Try either
              ls dir1 > file1; ls dir2 > file2; diff file1 file2



              or if you have vimdiff and tree which is the most useful way with sub directories, you could use



              tree dir1 > file1; tree dir2 > fiel2; vimdiff file1 file2



              Though, running ls is much faster than tree which is what you are after.



              If the difference is in a sub-directory in dir1
              eg.



              dir1
              - dir2
              - dir3
              - dir4
              vs

              dir2
              - dir2
              - dir3


              You would need to do



              ls -R dir1 > file1; ls -R dir2 > file2; vimdiff file1 file2






              share|improve this answer










              New contributor



              T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.























                1














                Try either
                ls dir1 > file1; ls dir2 > file2; diff file1 file2



                or if you have vimdiff and tree which is the most useful way with sub directories, you could use



                tree dir1 > file1; tree dir2 > fiel2; vimdiff file1 file2



                Though, running ls is much faster than tree which is what you are after.



                If the difference is in a sub-directory in dir1
                eg.



                dir1
                - dir2
                - dir3
                - dir4
                vs

                dir2
                - dir2
                - dir3


                You would need to do



                ls -R dir1 > file1; ls -R dir2 > file2; vimdiff file1 file2






                share|improve this answer










                New contributor



                T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





















                  1












                  1








                  1







                  Try either
                  ls dir1 > file1; ls dir2 > file2; diff file1 file2



                  or if you have vimdiff and tree which is the most useful way with sub directories, you could use



                  tree dir1 > file1; tree dir2 > fiel2; vimdiff file1 file2



                  Though, running ls is much faster than tree which is what you are after.



                  If the difference is in a sub-directory in dir1
                  eg.



                  dir1
                  - dir2
                  - dir3
                  - dir4
                  vs

                  dir2
                  - dir2
                  - dir3


                  You would need to do



                  ls -R dir1 > file1; ls -R dir2 > file2; vimdiff file1 file2






                  share|improve this answer










                  New contributor



                  T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  Try either
                  ls dir1 > file1; ls dir2 > file2; diff file1 file2



                  or if you have vimdiff and tree which is the most useful way with sub directories, you could use



                  tree dir1 > file1; tree dir2 > fiel2; vimdiff file1 file2



                  Though, running ls is much faster than tree which is what you are after.



                  If the difference is in a sub-directory in dir1
                  eg.



                  dir1
                  - dir2
                  - dir3
                  - dir4
                  vs

                  dir2
                  - dir2
                  - dir3


                  You would need to do



                  ls -R dir1 > file1; ls -R dir2 > file2; vimdiff file1 file2







                  share|improve this answer










                  New contributor



                  T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  share|improve this answer



                  share|improve this answer








                  edited 8 hours ago





















                  New contributor



                  T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  answered 8 hours ago









                  T. RocheT. Roche

                  112 bronze badges




                  112 bronze badges




                  New contributor



                  T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.




                  New contributor




                  T. Roche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.























                      1














                      diff -u <(ls dir1) <(ls dir2)


                      This will make sure diff does not look inside the subdirs.



                      Or try this if you are brave ;)



                      diff -u <(find dir1/ -maxdepth 1 -type d -exec basename ;) <(find dir2/ -maxdepth 1 -type d -exec basename ;)





                      share|improve this answer

























                      • diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                        – Hannu
                        8 hours ago






                      • 1





                        =) ............

                        – Hannu
                        8 hours ago











                      • comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                        – Freedo
                        7 hours ago















                      1














                      diff -u <(ls dir1) <(ls dir2)


                      This will make sure diff does not look inside the subdirs.



                      Or try this if you are brave ;)



                      diff -u <(find dir1/ -maxdepth 1 -type d -exec basename ;) <(find dir2/ -maxdepth 1 -type d -exec basename ;)





                      share|improve this answer

























                      • diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                        – Hannu
                        8 hours ago






                      • 1





                        =) ............

                        – Hannu
                        8 hours ago











                      • comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                        – Freedo
                        7 hours ago













                      1












                      1








                      1







                      diff -u <(ls dir1) <(ls dir2)


                      This will make sure diff does not look inside the subdirs.



                      Or try this if you are brave ;)



                      diff -u <(find dir1/ -maxdepth 1 -type d -exec basename ;) <(find dir2/ -maxdepth 1 -type d -exec basename ;)





                      share|improve this answer















                      diff -u <(ls dir1) <(ls dir2)


                      This will make sure diff does not look inside the subdirs.



                      Or try this if you are brave ;)



                      diff -u <(find dir1/ -maxdepth 1 -type d -exec basename ;) <(find dir2/ -maxdepth 1 -type d -exec basename ;)






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 8 hours ago

























                      answered 8 hours ago









                      GMasterGMaster

                      1,9451 gold badge13 silver badges21 bronze badges




                      1,9451 gold badge13 silver badges21 bronze badges












                      • diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                        – Hannu
                        8 hours ago






                      • 1





                        =) ............

                        – Hannu
                        8 hours ago











                      • comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                        – Freedo
                        7 hours ago

















                      • diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                        – Hannu
                        8 hours ago






                      • 1





                        =) ............

                        – Hannu
                        8 hours ago











                      • comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                        – Freedo
                        7 hours ago
















                      diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                      – Hannu
                      8 hours ago





                      diff -u <(cd dir1; find -type d | sort) <(cd dir2; find -type d | sort) ?

                      – Hannu
                      8 hours ago




                      1




                      1





                      =) ............

                      – Hannu
                      8 hours ago





                      =) ............

                      – Hannu
                      8 hours ago













                      comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                      – Freedo
                      7 hours ago





                      comm -23 <(ls /dir1 |sort) <(ls /dir2 |sort) also worked for me and was very fast too

                      – Freedo
                      7 hours ago

















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                      Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її