Deleting a point in METAFONTmetafont hash symbolUsing metafont-letters in LaTeXMETAFONT: Error “Can't open display”Including Metafont proofsheets in LaTeX documentsPositioning a vertex directly above another vertex in feynMFTranslation of typefaces into METAFONT (in the case of AMS Euler and others)how much is Metafont used these days?Running Metafont interactivelyMetafont using more than 256 charactersDrawing part of a path in METAFONT
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Deleting a point in METAFONT
metafont hash symbolUsing metafont-letters in LaTeXMETAFONT: Error “Can't open display”Including Metafont proofsheets in LaTeX documentsPositioning a vertex directly above another vertex in feynMFTranslation of typefaces into METAFONT (in the case of AMS Euler and others)how much is Metafont used these days?Running Metafont interactivelyMetafont using more than 256 charactersDrawing part of a path in METAFONT
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
In METAFONT, run interactively, is it possible to give a new value to a point variable?
If you just try to equate a point to a new point, the equation will be inconsistent with other equations. If you try to assign a new value, MF says that :=
is ''improper''. And you can't wipe out z5 by pair z5;
without taking all the other points with you.
metafont
add a comment |
In METAFONT, run interactively, is it possible to give a new value to a point variable?
If you just try to equate a point to a new point, the equation will be inconsistent with other equations. If you try to assign a new value, MF says that :=
is ''improper''. And you can't wipe out z5 by pair z5;
without taking all the other points with you.
metafont
add a comment |
In METAFONT, run interactively, is it possible to give a new value to a point variable?
If you just try to equate a point to a new point, the equation will be inconsistent with other equations. If you try to assign a new value, MF says that :=
is ''improper''. And you can't wipe out z5 by pair z5;
without taking all the other points with you.
metafont
In METAFONT, run interactively, is it possible to give a new value to a point variable?
If you just try to equate a point to a new point, the equation will be inconsistent with other equations. If you try to assign a new value, MF says that :=
is ''improper''. And you can't wipe out z5 by pair z5;
without taking all the other points with you.
metafont
metafont
edited 9 hours ago
Toothrot
asked 10 hours ago
ToothrotToothrot
1,4574 silver badges19 bronze badges
1,4574 silver badges19 bronze badges
add a comment |
add a comment |
1 Answer
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In MetaFont, z5
etc. is just a shorthand for (x5,y5)
. Now (x5,y5):=(...)
wouldn't be allowed, so z5:=(...)
isn't either.
To assign a new value, you can change both parts separably:
To reset z5
to it's initial set and allow new assignments, write
x5:=whatever; y5:=whatever;
Then z5=(3,4)
etc. works again.
add a comment |
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In MetaFont, z5
etc. is just a shorthand for (x5,y5)
. Now (x5,y5):=(...)
wouldn't be allowed, so z5:=(...)
isn't either.
To assign a new value, you can change both parts separably:
To reset z5
to it's initial set and allow new assignments, write
x5:=whatever; y5:=whatever;
Then z5=(3,4)
etc. works again.
add a comment |
In MetaFont, z5
etc. is just a shorthand for (x5,y5)
. Now (x5,y5):=(...)
wouldn't be allowed, so z5:=(...)
isn't either.
To assign a new value, you can change both parts separably:
To reset z5
to it's initial set and allow new assignments, write
x5:=whatever; y5:=whatever;
Then z5=(3,4)
etc. works again.
add a comment |
In MetaFont, z5
etc. is just a shorthand for (x5,y5)
. Now (x5,y5):=(...)
wouldn't be allowed, so z5:=(...)
isn't either.
To assign a new value, you can change both parts separably:
To reset z5
to it's initial set and allow new assignments, write
x5:=whatever; y5:=whatever;
Then z5=(3,4)
etc. works again.
In MetaFont, z5
etc. is just a shorthand for (x5,y5)
. Now (x5,y5):=(...)
wouldn't be allowed, so z5:=(...)
isn't either.
To assign a new value, you can change both parts separably:
To reset z5
to it's initial set and allow new assignments, write
x5:=whatever; y5:=whatever;
Then z5=(3,4)
etc. works again.
answered 9 hours ago
Marcel KrügerMarcel Krüger
14.6k1 gold badge17 silver badges37 bronze badges
14.6k1 gold badge17 silver badges37 bronze badges
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