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Displaying minutes in HH:MM format

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Displaying minutes in HH:MM format


CodeChef - Please like meHackerEarth Challenge Find Maximum Taste of Fruits“Angry Professor” Python implementationSeven-segment display GUINo more filthy wordsA class to store the number of seconds since midnightAlternating CharactersHackerEarth problem : number of occurrences of a number in the arrayGetting the Sum of Discounted Price






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








10












$begingroup$


This program is a clock that only displays minutes passed since midnight. This program is supposed to be really simple but because of some "aesthetic bug", I wrote quite a lot if-else statements that I think can be simplified.





Format Input



The first line will contain an integer T, the number of test cases.
Each test case will contain an number N, the number displayed by the
strange clock.



Format Output



For each test case, print “Case X: “ (X starts with 1) and then print
what time it is in 24 hours HH:MM format.



Constraints



1 <= T <= 1000



0 <= N <= 1439




#include <stdio.h>

int main()

int T;
scanf("%d", &T);

for (int i = 1; i <= T; i++)

int N;
scanf("%d", &N);

int hours = N / 60;
int minutes = N % 60;

printf("Case #%d: ", i);

if (N < 10)
printf("00:0%dn", N);
else if (N > 10 && N < 60)
printf("00:%dn", N);
else if (N > 60 && N < 600)
if (minutes == 0)
printf("0%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("0%d:0%dn", hours, minutes);
else
printf("0%d:%dn", hours, minutes);

else
if (minutes == 0)
printf("%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("%d:0%dn", hours, minutes);
else
printf("%d:%dn", hours, minutes);













share|improve this question









New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
    $endgroup$
    – Édouard
    13 hours ago










  • $begingroup$
    @Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
    $endgroup$
    – Roland Illig
    3 hours ago










  • $begingroup$
    Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
    $endgroup$
    – Roland Illig
    3 hours ago

















10












$begingroup$


This program is a clock that only displays minutes passed since midnight. This program is supposed to be really simple but because of some "aesthetic bug", I wrote quite a lot if-else statements that I think can be simplified.





Format Input



The first line will contain an integer T, the number of test cases.
Each test case will contain an number N, the number displayed by the
strange clock.



Format Output



For each test case, print “Case X: “ (X starts with 1) and then print
what time it is in 24 hours HH:MM format.



Constraints



1 <= T <= 1000



0 <= N <= 1439




#include <stdio.h>

int main()

int T;
scanf("%d", &T);

for (int i = 1; i <= T; i++)

int N;
scanf("%d", &N);

int hours = N / 60;
int minutes = N % 60;

printf("Case #%d: ", i);

if (N < 10)
printf("00:0%dn", N);
else if (N > 10 && N < 60)
printf("00:%dn", N);
else if (N > 60 && N < 600)
if (minutes == 0)
printf("0%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("0%d:0%dn", hours, minutes);
else
printf("0%d:%dn", hours, minutes);

else
if (minutes == 0)
printf("%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("%d:0%dn", hours, minutes);
else
printf("%d:%dn", hours, minutes);













share|improve this question









New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
    $endgroup$
    – Édouard
    13 hours ago










  • $begingroup$
    @Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
    $endgroup$
    – Roland Illig
    3 hours ago










  • $begingroup$
    Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
    $endgroup$
    – Roland Illig
    3 hours ago













10












10








10





$begingroup$


This program is a clock that only displays minutes passed since midnight. This program is supposed to be really simple but because of some "aesthetic bug", I wrote quite a lot if-else statements that I think can be simplified.





Format Input



The first line will contain an integer T, the number of test cases.
Each test case will contain an number N, the number displayed by the
strange clock.



Format Output



For each test case, print “Case X: “ (X starts with 1) and then print
what time it is in 24 hours HH:MM format.



Constraints



1 <= T <= 1000



0 <= N <= 1439




#include <stdio.h>

int main()

int T;
scanf("%d", &T);

for (int i = 1; i <= T; i++)

int N;
scanf("%d", &N);

int hours = N / 60;
int minutes = N % 60;

printf("Case #%d: ", i);

if (N < 10)
printf("00:0%dn", N);
else if (N > 10 && N < 60)
printf("00:%dn", N);
else if (N > 60 && N < 600)
if (minutes == 0)
printf("0%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("0%d:0%dn", hours, minutes);
else
printf("0%d:%dn", hours, minutes);

else
if (minutes == 0)
printf("%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("%d:0%dn", hours, minutes);
else
printf("%d:%dn", hours, minutes);













share|improve this question









New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




This program is a clock that only displays minutes passed since midnight. This program is supposed to be really simple but because of some "aesthetic bug", I wrote quite a lot if-else statements that I think can be simplified.





Format Input



The first line will contain an integer T, the number of test cases.
Each test case will contain an number N, the number displayed by the
strange clock.



Format Output



For each test case, print “Case X: “ (X starts with 1) and then print
what time it is in 24 hours HH:MM format.



Constraints



1 <= T <= 1000



0 <= N <= 1439




#include <stdio.h>

int main()

int T;
scanf("%d", &T);

for (int i = 1; i <= T; i++)

int N;
scanf("%d", &N);

int hours = N / 60;
int minutes = N % 60;

printf("Case #%d: ", i);

if (N < 10)
printf("00:0%dn", N);
else if (N > 10 && N < 60)
printf("00:%dn", N);
else if (N > 60 && N < 600)
if (minutes == 0)
printf("0%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("0%d:0%dn", hours, minutes);
else
printf("0%d:%dn", hours, minutes);

else
if (minutes == 0)
printf("%d:00n", hours);
else if (minutes > 0 && minutes < 10)
printf("%d:0%dn", hours, minutes);
else
printf("%d:%dn", hours, minutes);










beginner algorithm c datetime formatting






share|improve this question









New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 2 hours ago









dfhwze

10.6k2 gold badges19 silver badges69 bronze badges




10.6k2 gold badges19 silver badges69 bronze badges






New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked yesterday









Elvan SelvanoElvan Selvano

587 bronze badges




587 bronze badges




New contributor



Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Elvan Selvano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • $begingroup$
    As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
    $endgroup$
    – Édouard
    13 hours ago










  • $begingroup$
    @Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
    $endgroup$
    – Roland Illig
    3 hours ago










  • $begingroup$
    Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
    $endgroup$
    – Roland Illig
    3 hours ago
















  • $begingroup$
    As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
    $endgroup$
    – Édouard
    13 hours ago










  • $begingroup$
    @Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
    $endgroup$
    – Roland Illig
    3 hours ago










  • $begingroup$
    Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
    $endgroup$
    – Roland Illig
    3 hours ago















$begingroup$
As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
$endgroup$
– Édouard
13 hours ago




$begingroup$
As I understand it, N is the number the clock must display, I.e. when N=1439, the clock should display 14:39. You should divide by 100 and not 60.
$endgroup$
– Édouard
13 hours ago












$begingroup$
@Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
$endgroup$
– Roland Illig
3 hours ago




$begingroup$
@Édouard since a day has 1440 minutes, it's more likely that N is the number of minutes since midnight. This crucial information is missing from the instructions, which probably prepares the students to real-life situations, which are very similar.
$endgroup$
– Roland Illig
3 hours ago












$begingroup$
Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
$endgroup$
– Roland Illig
3 hours ago




$begingroup$
Or, the instructions may have included the definition of the "strange clock", and Elvan just didn't post this part.
$endgroup$
– Roland Illig
3 hours ago










2 Answers
2






active

oldest

votes


















15













$begingroup$

Following @Martin R's comment, I'll make my comment above a solution:



printf already supports what you're trying to achieve with your if-then-else jungle:



#include <stdio.h>

int main()

int T;
scanf("%d", &T);

for (int i = 1; i <= T; i++)

int N;
scanf("%d", &N);

int hours = N / 60;
int minutes = N % 60;

printf("Case #%d: %02d:%02dn", i, hours, minutes);




You're also missing to check the return value of scanf. It is used to report errors in the input. What is the purpose of the first scanf?



Also, I'd change the variable naming. Use minutes instead of N to communicate clearly what you're handling in the variable. You can then write the computation directly in the parameter list of printf, saving you two additional variables.






share|improve this answer











$endgroup$










  • 5




    $begingroup$
    "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
    $endgroup$
    – Reinderien
    yesterday










  • $begingroup$
    Thank you, added it.
    $endgroup$
    – Cornholio
    yesterday










  • $begingroup$
    "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
    $endgroup$
    – JiK
    9 hours ago










  • $begingroup$
    Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
    $endgroup$
    – chux
    49 mins ago



















10













$begingroup$

If your code is checked by an automated process, you will probably fail all test cases because your code prints a #, which was not asked for. You should better remove it. Just print "Case %d" instead of "Case #%d".






share|improve this answer









$endgroup$

















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    15













    $begingroup$

    Following @Martin R's comment, I'll make my comment above a solution:



    printf already supports what you're trying to achieve with your if-then-else jungle:



    #include <stdio.h>

    int main()

    int T;
    scanf("%d", &T);

    for (int i = 1; i <= T; i++)

    int N;
    scanf("%d", &N);

    int hours = N / 60;
    int minutes = N % 60;

    printf("Case #%d: %02d:%02dn", i, hours, minutes);




    You're also missing to check the return value of scanf. It is used to report errors in the input. What is the purpose of the first scanf?



    Also, I'd change the variable naming. Use minutes instead of N to communicate clearly what you're handling in the variable. You can then write the computation directly in the parameter list of printf, saving you two additional variables.






    share|improve this answer











    $endgroup$










    • 5




      $begingroup$
      "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
      $endgroup$
      – Reinderien
      yesterday










    • $begingroup$
      Thank you, added it.
      $endgroup$
      – Cornholio
      yesterday










    • $begingroup$
      "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
      $endgroup$
      – JiK
      9 hours ago










    • $begingroup$
      Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
      $endgroup$
      – chux
      49 mins ago
















    15













    $begingroup$

    Following @Martin R's comment, I'll make my comment above a solution:



    printf already supports what you're trying to achieve with your if-then-else jungle:



    #include <stdio.h>

    int main()

    int T;
    scanf("%d", &T);

    for (int i = 1; i <= T; i++)

    int N;
    scanf("%d", &N);

    int hours = N / 60;
    int minutes = N % 60;

    printf("Case #%d: %02d:%02dn", i, hours, minutes);




    You're also missing to check the return value of scanf. It is used to report errors in the input. What is the purpose of the first scanf?



    Also, I'd change the variable naming. Use minutes instead of N to communicate clearly what you're handling in the variable. You can then write the computation directly in the parameter list of printf, saving you two additional variables.






    share|improve this answer











    $endgroup$










    • 5




      $begingroup$
      "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
      $endgroup$
      – Reinderien
      yesterday










    • $begingroup$
      Thank you, added it.
      $endgroup$
      – Cornholio
      yesterday










    • $begingroup$
      "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
      $endgroup$
      – JiK
      9 hours ago










    • $begingroup$
      Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
      $endgroup$
      – chux
      49 mins ago














    15














    15










    15







    $begingroup$

    Following @Martin R's comment, I'll make my comment above a solution:



    printf already supports what you're trying to achieve with your if-then-else jungle:



    #include <stdio.h>

    int main()

    int T;
    scanf("%d", &T);

    for (int i = 1; i <= T; i++)

    int N;
    scanf("%d", &N);

    int hours = N / 60;
    int minutes = N % 60;

    printf("Case #%d: %02d:%02dn", i, hours, minutes);




    You're also missing to check the return value of scanf. It is used to report errors in the input. What is the purpose of the first scanf?



    Also, I'd change the variable naming. Use minutes instead of N to communicate clearly what you're handling in the variable. You can then write the computation directly in the parameter list of printf, saving you two additional variables.






    share|improve this answer











    $endgroup$



    Following @Martin R's comment, I'll make my comment above a solution:



    printf already supports what you're trying to achieve with your if-then-else jungle:



    #include <stdio.h>

    int main()

    int T;
    scanf("%d", &T);

    for (int i = 1; i <= T; i++)

    int N;
    scanf("%d", &N);

    int hours = N / 60;
    int minutes = N % 60;

    printf("Case #%d: %02d:%02dn", i, hours, minutes);




    You're also missing to check the return value of scanf. It is used to report errors in the input. What is the purpose of the first scanf?



    Also, I'd change the variable naming. Use minutes instead of N to communicate clearly what you're handling in the variable. You can then write the computation directly in the parameter list of printf, saving you two additional variables.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited yesterday

























    answered yesterday









    CornholioCornholio

    7762 silver badges10 bronze badges




    7762 silver badges10 bronze badges










    • 5




      $begingroup$
      "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
      $endgroup$
      – Reinderien
      yesterday










    • $begingroup$
      Thank you, added it.
      $endgroup$
      – Cornholio
      yesterday










    • $begingroup$
      "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
      $endgroup$
      – JiK
      9 hours ago










    • $begingroup$
      Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
      $endgroup$
      – chux
      49 mins ago













    • 5




      $begingroup$
      "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
      $endgroup$
      – Reinderien
      yesterday










    • $begingroup$
      Thank you, added it.
      $endgroup$
      – Cornholio
      yesterday










    • $begingroup$
      "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
      $endgroup$
      – JiK
      9 hours ago










    • $begingroup$
      Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
      $endgroup$
      – chux
      49 mins ago








    5




    5




    $begingroup$
    "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
    $endgroup$
    – Reinderien
    yesterday




    $begingroup$
    "saving you two additional variables" - in this case, I think the separated variables are actually a good idea. They shouldn't incur a performance drop, and they help to self-document the code.
    $endgroup$
    – Reinderien
    yesterday












    $begingroup$
    Thank you, added it.
    $endgroup$
    – Cornholio
    yesterday




    $begingroup$
    Thank you, added it.
    $endgroup$
    – Cornholio
    yesterday












    $begingroup$
    "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
    $endgroup$
    – JiK
    9 hours ago




    $begingroup$
    "Use minutes instead of N to communicate clearly what you're handling in the variable." The symbol N is explicitly defined in the problem statement. However, the word minutes could mean either N or the "minutes" field in the output.
    $endgroup$
    – JiK
    9 hours ago












    $begingroup$
    Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
    $endgroup$
    – chux
    49 mins ago





    $begingroup$
    Note that with input like -61, Output of -01:00 might be preferred over this answer's "-01:-01". Yet with "0 <= N <= 1439" and "minutes passed since midnight", we might not worry about yesterday.
    $endgroup$
    – chux
    49 mins ago














    10













    $begingroup$

    If your code is checked by an automated process, you will probably fail all test cases because your code prints a #, which was not asked for. You should better remove it. Just print "Case %d" instead of "Case #%d".






    share|improve this answer









    $endgroup$



















      10













      $begingroup$

      If your code is checked by an automated process, you will probably fail all test cases because your code prints a #, which was not asked for. You should better remove it. Just print "Case %d" instead of "Case #%d".






      share|improve this answer









      $endgroup$

















        10














        10










        10







        $begingroup$

        If your code is checked by an automated process, you will probably fail all test cases because your code prints a #, which was not asked for. You should better remove it. Just print "Case %d" instead of "Case #%d".






        share|improve this answer









        $endgroup$



        If your code is checked by an automated process, you will probably fail all test cases because your code prints a #, which was not asked for. You should better remove it. Just print "Case %d" instead of "Case #%d".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        Roland IlligRoland Illig

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