Animate flow lines of time-dependent 3D dynamical systemHow can I create a fountain effect?Creating a Dynamic Time Index Slider for List Animate PlotCreate a point on a phase portrait and draw a trajectory flow following the vector lines by time-passingSpeed of flow of time in Dynamic ClockGauges

Heyawacky: Ace of Cups

What is the question mark?

What does 〇〇〇〇 mean when combined with おじさん?

Output with the same length always

What allows us to use imaginary numbers?

Will some rockets really collapse under their own weight?

Expressing a chain of boolean ORs using ILP

Why does "auf der Strecke bleiben" mean "to fall by the wayside"?

Airline power sockets shut down when I plug my computer in. How can I avoid that?

Typesetting "hollow slash"

How to mock ApexTestQueueItem, AsyncApexJob, and ApexTestResult for test coverage?

Meaning of だけはわからない

Why do we use low resistance cables to minimize power losses?

Java methods to add and authenticate users in MySQL

Has there ever been a truly bilingual country prior to the contemporary period?

Is this really better analyzed in G minor than in Bb?

Did Michelle Obama have a staff of 23; and Melania have a staff of 4?

How to render "have ideas above his station" into German

Can I use my OWN published papers' images in my thesis without Copyright infringment

Doesn't the speed of light limit imply the same electron can be annihilated twice?

Has the speed of light ever been measured in vacuum?

Quick destruction of a helium filled airship?

What are some tips and tricks for finding the cheapest flight when luggage and other fees are not revealed until far into the booking process?

Attacking the Hydra



Animate flow lines of time-dependent 3D dynamical system


How can I create a fountain effect?Creating a Dynamic Time Index Slider for List Animate PlotCreate a point on a phase portrait and draw a trajectory flow following the vector lines by time-passingSpeed of flow of time in Dynamic ClockGauges






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4












$begingroup$


I've spent a bunch of time perusing Stack Exchange to try to find an answer and found nothing; hopefully this isn't a duplicate.



I have a time-dependent vector field $Phi_t(x,y,z)=(xlambda^t,ylambda^-t,z+t)$, $lambda>1$ arbitrary; for my example, I'm restricting to the region $[0,1]times[0,1]timesmathbbR$. What I would like to do is:



  • fix some $lambda>1$;

  • generate some number of random initial points;

  • compute / store the orbits of these points over some length of time;

  • plot these orbits in 3D with animation.

I've currently managed to do all of this except animate the flow lines.



Here's my current code:



seeds = RandomReal[-1, 1, 250, 3]; (* 250 random initial points *)
lam = 1.5; (* [Lambda]>1 fixed *)

func[x_, y_, z_, t_] := x lam^t, y lam^(-t), z + t; (* the vector field itself *)
orbit[k_] := Table[func[seeds[[k]], n], n, 0, 9.75, 0.25]; (* function to compute the orbit for a single initial point *)
orbits = orbit[#] & /@ Range[1, Length[seeds], 1]; (* computes orbits for all initial points *)

Graphics3D[
Red, Arrowheads[-.01, .01], Arrow[BezierCurve[orbits[[#]]]] & /@ Range[1, Length[seeds], 1]
, PlotRange -> -1, 1, -1, 1, -1, 1, Boxed -> False, Axes -> True, AxesEdge -> -1, -1, -1, -1, -1, -1, ViewPoint -> 2.6056479300835718`, 2.1387445365836095`, 0.29388887642263006`, ViewVertical -> 0.3985587476649791`, 0.332086389794556`, 0.8549090912915488`, ImageSize -> 400]


Here's the output:
enter image description here



This is okay, but what I'd really like is something that can either



  1. animate one entire flow line a little at a time, then the next flow line a little at a time, etc. (in the same plot); or

  2. animate all flow lines simultaneously, a little at a time.

Can anyone help me with this?



Note: By defining an auxiliary function buildorbits[k_,n_]:=orbits[[k, 1 ;; n]];, I can animate single orbits using a very "hackish-feeling" implementation of ListAnimate. For instance:



enter image description here



; is this really my best option, though?










share|improve this question









$endgroup$













  • $begingroup$
    Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
    $endgroup$
    – Michael E2
    8 hours ago










  • $begingroup$
    @MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
    $endgroup$
    – Michael E2
    7 hours ago










  • $begingroup$
    @MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
    $endgroup$
    – cstover
    7 hours ago

















4












$begingroup$


I've spent a bunch of time perusing Stack Exchange to try to find an answer and found nothing; hopefully this isn't a duplicate.



I have a time-dependent vector field $Phi_t(x,y,z)=(xlambda^t,ylambda^-t,z+t)$, $lambda>1$ arbitrary; for my example, I'm restricting to the region $[0,1]times[0,1]timesmathbbR$. What I would like to do is:



  • fix some $lambda>1$;

  • generate some number of random initial points;

  • compute / store the orbits of these points over some length of time;

  • plot these orbits in 3D with animation.

I've currently managed to do all of this except animate the flow lines.



Here's my current code:



seeds = RandomReal[-1, 1, 250, 3]; (* 250 random initial points *)
lam = 1.5; (* [Lambda]>1 fixed *)

func[x_, y_, z_, t_] := x lam^t, y lam^(-t), z + t; (* the vector field itself *)
orbit[k_] := Table[func[seeds[[k]], n], n, 0, 9.75, 0.25]; (* function to compute the orbit for a single initial point *)
orbits = orbit[#] & /@ Range[1, Length[seeds], 1]; (* computes orbits for all initial points *)

Graphics3D[
Red, Arrowheads[-.01, .01], Arrow[BezierCurve[orbits[[#]]]] & /@ Range[1, Length[seeds], 1]
, PlotRange -> -1, 1, -1, 1, -1, 1, Boxed -> False, Axes -> True, AxesEdge -> -1, -1, -1, -1, -1, -1, ViewPoint -> 2.6056479300835718`, 2.1387445365836095`, 0.29388887642263006`, ViewVertical -> 0.3985587476649791`, 0.332086389794556`, 0.8549090912915488`, ImageSize -> 400]


Here's the output:
enter image description here



This is okay, but what I'd really like is something that can either



  1. animate one entire flow line a little at a time, then the next flow line a little at a time, etc. (in the same plot); or

  2. animate all flow lines simultaneously, a little at a time.

Can anyone help me with this?



Note: By defining an auxiliary function buildorbits[k_,n_]:=orbits[[k, 1 ;; n]];, I can animate single orbits using a very "hackish-feeling" implementation of ListAnimate. For instance:



enter image description here



; is this really my best option, though?










share|improve this question









$endgroup$













  • $begingroup$
    Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
    $endgroup$
    – Michael E2
    8 hours ago










  • $begingroup$
    @MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
    $endgroup$
    – Michael E2
    7 hours ago










  • $begingroup$
    @MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
    $endgroup$
    – cstover
    7 hours ago













4












4








4


2



$begingroup$


I've spent a bunch of time perusing Stack Exchange to try to find an answer and found nothing; hopefully this isn't a duplicate.



I have a time-dependent vector field $Phi_t(x,y,z)=(xlambda^t,ylambda^-t,z+t)$, $lambda>1$ arbitrary; for my example, I'm restricting to the region $[0,1]times[0,1]timesmathbbR$. What I would like to do is:



  • fix some $lambda>1$;

  • generate some number of random initial points;

  • compute / store the orbits of these points over some length of time;

  • plot these orbits in 3D with animation.

I've currently managed to do all of this except animate the flow lines.



Here's my current code:



seeds = RandomReal[-1, 1, 250, 3]; (* 250 random initial points *)
lam = 1.5; (* [Lambda]>1 fixed *)

func[x_, y_, z_, t_] := x lam^t, y lam^(-t), z + t; (* the vector field itself *)
orbit[k_] := Table[func[seeds[[k]], n], n, 0, 9.75, 0.25]; (* function to compute the orbit for a single initial point *)
orbits = orbit[#] & /@ Range[1, Length[seeds], 1]; (* computes orbits for all initial points *)

Graphics3D[
Red, Arrowheads[-.01, .01], Arrow[BezierCurve[orbits[[#]]]] & /@ Range[1, Length[seeds], 1]
, PlotRange -> -1, 1, -1, 1, -1, 1, Boxed -> False, Axes -> True, AxesEdge -> -1, -1, -1, -1, -1, -1, ViewPoint -> 2.6056479300835718`, 2.1387445365836095`, 0.29388887642263006`, ViewVertical -> 0.3985587476649791`, 0.332086389794556`, 0.8549090912915488`, ImageSize -> 400]


Here's the output:
enter image description here



This is okay, but what I'd really like is something that can either



  1. animate one entire flow line a little at a time, then the next flow line a little at a time, etc. (in the same plot); or

  2. animate all flow lines simultaneously, a little at a time.

Can anyone help me with this?



Note: By defining an auxiliary function buildorbits[k_,n_]:=orbits[[k, 1 ;; n]];, I can animate single orbits using a very "hackish-feeling" implementation of ListAnimate. For instance:



enter image description here



; is this really my best option, though?










share|improve this question









$endgroup$




I've spent a bunch of time perusing Stack Exchange to try to find an answer and found nothing; hopefully this isn't a duplicate.



I have a time-dependent vector field $Phi_t(x,y,z)=(xlambda^t,ylambda^-t,z+t)$, $lambda>1$ arbitrary; for my example, I'm restricting to the region $[0,1]times[0,1]timesmathbbR$. What I would like to do is:



  • fix some $lambda>1$;

  • generate some number of random initial points;

  • compute / store the orbits of these points over some length of time;

  • plot these orbits in 3D with animation.

I've currently managed to do all of this except animate the flow lines.



Here's my current code:



seeds = RandomReal[-1, 1, 250, 3]; (* 250 random initial points *)
lam = 1.5; (* [Lambda]>1 fixed *)

func[x_, y_, z_, t_] := x lam^t, y lam^(-t), z + t; (* the vector field itself *)
orbit[k_] := Table[func[seeds[[k]], n], n, 0, 9.75, 0.25]; (* function to compute the orbit for a single initial point *)
orbits = orbit[#] & /@ Range[1, Length[seeds], 1]; (* computes orbits for all initial points *)

Graphics3D[
Red, Arrowheads[-.01, .01], Arrow[BezierCurve[orbits[[#]]]] & /@ Range[1, Length[seeds], 1]
, PlotRange -> -1, 1, -1, 1, -1, 1, Boxed -> False, Axes -> True, AxesEdge -> -1, -1, -1, -1, -1, -1, ViewPoint -> 2.6056479300835718`, 2.1387445365836095`, 0.29388887642263006`, ViewVertical -> 0.3985587476649791`, 0.332086389794556`, 0.8549090912915488`, ImageSize -> 400]


Here's the output:
enter image description here



This is okay, but what I'd really like is something that can either



  1. animate one entire flow line a little at a time, then the next flow line a little at a time, etc. (in the same plot); or

  2. animate all flow lines simultaneously, a little at a time.

Can anyone help me with this?



Note: By defining an auxiliary function buildorbits[k_,n_]:=orbits[[k, 1 ;; n]];, I can animate single orbits using a very "hackish-feeling" implementation of ListAnimate. For instance:



enter image description here



; is this really my best option, though?







graphics3d dynamic animation experimental-mathematics






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 8 hours ago









cstovercstover

537 bronze badges




537 bronze badges














  • $begingroup$
    Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
    $endgroup$
    – Michael E2
    8 hours ago










  • $begingroup$
    @MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
    $endgroup$
    – Michael E2
    7 hours ago










  • $begingroup$
    @MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
    $endgroup$
    – cstover
    7 hours ago
















  • $begingroup$
    Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
    $endgroup$
    – Michael E2
    8 hours ago










  • $begingroup$
    @MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
    $endgroup$
    – Michael E2
    7 hours ago










  • $begingroup$
    @MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
    $endgroup$
    – cstover
    7 hours ago















$begingroup$
Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
$endgroup$
– Michael E2
8 hours ago




$begingroup$
Is capital Phi the vector field or the flow? You say vector field, but you never integrate it; instead, it seems to be used to compute the "orbit" (= trajectory?) of the seed points, as if it were the flow.
$endgroup$
– Michael E2
8 hours ago












$begingroup$
@MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
$endgroup$
– cstover
7 hours ago




$begingroup$
@MichaelE2 - When I said vector field, I mean vector field in the sense of a map from $mathbbR^m$ to $mathbbR^n$ for some $m,ngeq 1$. I'm not sure if this is standard terminology, but to me as far as I'm concerned: For each $t_0$, $Phi_t_0$ ($Phi$ evaluated at time $t=t_0$) is a "vector field," and the family $t_0inmathbbR$ is a "flow".
$endgroup$
– cstover
7 hours ago












$begingroup$
A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
$endgroup$
– Michael E2
7 hours ago




$begingroup$
A "flow" is a function $Phi_t(x,y,z)$ that gives the position at time $t$ of the particle that started at the point $(x,y,z)$. Formally, it is a vector field in the way that coordinates are vectors. The flow of a vector field $F$ satisfies $partial_t Phi_t = F$ at all $(x,y,z)$ and $t$ if $F=F(x,y,z,t)$ is time-dependent. So that a "flow" is related to a "vector field," and I think it is traditional to keep the terms separated. I was asking whether your vector field was more like the flow $Phi$ or the vector field $F$. I think you're saying it's the flow. Thanks.
$endgroup$
– Michael E2
7 hours ago












$begingroup$
@MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
$endgroup$
– cstover
7 hours ago




$begingroup$
@MichaelE2 - I think you're right. Thanks for explaining! I appreciate any chance to clear up gaps in my understanding.
$endgroup$
– cstover
7 hours ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

You can use ParametricPlot3D to get smoother orbits:



SeedRandom[1]
seeds = RandomReal[-1, 1, 50, 3];

Animate[ParametricPlot3D[Evaluate[func[seeds[[#]], t] & /@ Range[Length@seeds]],
t, 0, tmax,
BoxRatios -> 1,
PlotStyle -> Arrowheads[Medium],
ImageSize->400,
PlotRange -> -60, 60, -1, 1, -10, 10] /. Line -> Arrow,
tmax, .1, 10]


enter image description here






share|improve this answer











$endgroup$














  • $begingroup$
    That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, I will update with a version that shows subsets of orbits sequentially.
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    Thank you kindly!
    $endgroup$
    – cstover
    6 hours ago


















3












$begingroup$

Not exactly what was asked, but another way to visualize the flow, based on How can I create a fountain effect?:



DynamicModule[x0, y0, z0, last = 0, lam = 1.5, n = 500, colors, 
replace,
last = Clock[Infinity];
x0, y0, z0 = RandomReal[-1, 1, 3, n];
colors = RandomColor[n];

Graphics3D[
GraphicsComplex[
Dynamic@
With[t = Clock[Infinity],
With[dt = (t - last)/2, With[dl = lam^dt,
last = t;
x0 = x0*dl; y0 = y0/dl; z0 = z0 + dt; (* integration of velocity *)
replace = Pick[Range@n, UnitStep[z0 - 1], 1];
With[pick = UnitStep[z0 - 1],
x0[[replace]] = RandomReal[-1, 1, Length@replace];
y0[[replace]] = RandomReal[-1, 1, Length@replace];
z0[[replace]] = RandomReal[-1, -1 + dt, Length@replace]
];
Transpose@x0, y0, z0
]]],
Point[Range@n, VertexColors -> colors]
], PlotRange -> -2, 2, -2, 2, -1, 1, Axes -> True,
AxesLabel -> x, y, z
],

Initialization :> (x0, y0, z0 = RandomReal[-1, 1, 3, n])
]


enter image description here



The integration is based on the ODE for $Phi$, which is autonomous and linear and can be done by scalings and translation:
$$d over dt,(x,y,z) = (x log lambda, -y log lambda, 1)$$






share|improve this answer









$endgroup$










  • 1




    $begingroup$
    That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
    $endgroup$
    – cstover
    3 hours ago










  • $begingroup$
    Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
    $endgroup$
    – CA Trevillian
    2 hours ago










  • $begingroup$
    @CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
    $endgroup$
    – Michael E2
    1 hour ago













Your Answer








StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f203839%2fanimate-flow-lines-of-time-dependent-3d-dynamical-system%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$

You can use ParametricPlot3D to get smoother orbits:



SeedRandom[1]
seeds = RandomReal[-1, 1, 50, 3];

Animate[ParametricPlot3D[Evaluate[func[seeds[[#]], t] & /@ Range[Length@seeds]],
t, 0, tmax,
BoxRatios -> 1,
PlotStyle -> Arrowheads[Medium],
ImageSize->400,
PlotRange -> -60, 60, -1, 1, -10, 10] /. Line -> Arrow,
tmax, .1, 10]


enter image description here






share|improve this answer











$endgroup$














  • $begingroup$
    That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, I will update with a version that shows subsets of orbits sequentially.
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    Thank you kindly!
    $endgroup$
    – cstover
    6 hours ago















4












$begingroup$

You can use ParametricPlot3D to get smoother orbits:



SeedRandom[1]
seeds = RandomReal[-1, 1, 50, 3];

Animate[ParametricPlot3D[Evaluate[func[seeds[[#]], t] & /@ Range[Length@seeds]],
t, 0, tmax,
BoxRatios -> 1,
PlotStyle -> Arrowheads[Medium],
ImageSize->400,
PlotRange -> -60, 60, -1, 1, -10, 10] /. Line -> Arrow,
tmax, .1, 10]


enter image description here






share|improve this answer











$endgroup$














  • $begingroup$
    That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, I will update with a version that shows subsets of orbits sequentially.
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    Thank you kindly!
    $endgroup$
    – cstover
    6 hours ago













4












4








4





$begingroup$

You can use ParametricPlot3D to get smoother orbits:



SeedRandom[1]
seeds = RandomReal[-1, 1, 50, 3];

Animate[ParametricPlot3D[Evaluate[func[seeds[[#]], t] & /@ Range[Length@seeds]],
t, 0, tmax,
BoxRatios -> 1,
PlotStyle -> Arrowheads[Medium],
ImageSize->400,
PlotRange -> -60, 60, -1, 1, -10, 10] /. Line -> Arrow,
tmax, .1, 10]


enter image description here






share|improve this answer











$endgroup$



You can use ParametricPlot3D to get smoother orbits:



SeedRandom[1]
seeds = RandomReal[-1, 1, 50, 3];

Animate[ParametricPlot3D[Evaluate[func[seeds[[#]], t] & /@ Range[Length@seeds]],
t, 0, tmax,
BoxRatios -> 1,
PlotStyle -> Arrowheads[Medium],
ImageSize->400,
PlotRange -> -60, 60, -1, 1, -10, 10] /. Line -> Arrow,
tmax, .1, 10]


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 7 hours ago

























answered 7 hours ago









kglrkglr

211k10 gold badges242 silver badges484 bronze badges




211k10 gold badges242 silver badges484 bronze badges














  • $begingroup$
    That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, I will update with a version that shows subsets of orbits sequentially.
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    Thank you kindly!
    $endgroup$
    – cstover
    6 hours ago
















  • $begingroup$
    That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
    $endgroup$
    – cstover
    7 hours ago










  • $begingroup$
    @cstover, I will update with a version that shows subsets of orbits sequentially.
    $endgroup$
    – kglr
    7 hours ago










  • $begingroup$
    Thank you kindly!
    $endgroup$
    – cstover
    6 hours ago















$begingroup$
That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
$endgroup$
– cstover
7 hours ago




$begingroup$
That's amazing! I tried for a while to use built-in functions such as ParametricPlot3D, but I never could get the arguments quite right. Okay, follow-up question: Is there a way to use this this implementation to animate as all of orbit 1, followed by all of orbit 2, followed by....?
$endgroup$
– cstover
7 hours ago












$begingroup$
@cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
$endgroup$
– kglr
7 hours ago




$begingroup$
@cstover, do you want to keep or remove orbit 1 in the picture when orbit 2 is rendered?
$endgroup$
– kglr
7 hours ago












$begingroup$
I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
$endgroup$
– cstover
7 hours ago




$begingroup$
I would like to keep orbit 1 when orbit 2 is rendered, and keep both when orbit 3 is rendered, etc. But, if it's not too much trouble, I would appreciate seeing how to do one version with them kept and one with them erased...just to become a better programmer.
$endgroup$
– cstover
7 hours ago












$begingroup$
@cstover, I will update with a version that shows subsets of orbits sequentially.
$endgroup$
– kglr
7 hours ago




$begingroup$
@cstover, I will update with a version that shows subsets of orbits sequentially.
$endgroup$
– kglr
7 hours ago












$begingroup$
Thank you kindly!
$endgroup$
– cstover
6 hours ago




$begingroup$
Thank you kindly!
$endgroup$
– cstover
6 hours ago













3












$begingroup$

Not exactly what was asked, but another way to visualize the flow, based on How can I create a fountain effect?:



DynamicModule[x0, y0, z0, last = 0, lam = 1.5, n = 500, colors, 
replace,
last = Clock[Infinity];
x0, y0, z0 = RandomReal[-1, 1, 3, n];
colors = RandomColor[n];

Graphics3D[
GraphicsComplex[
Dynamic@
With[t = Clock[Infinity],
With[dt = (t - last)/2, With[dl = lam^dt,
last = t;
x0 = x0*dl; y0 = y0/dl; z0 = z0 + dt; (* integration of velocity *)
replace = Pick[Range@n, UnitStep[z0 - 1], 1];
With[pick = UnitStep[z0 - 1],
x0[[replace]] = RandomReal[-1, 1, Length@replace];
y0[[replace]] = RandomReal[-1, 1, Length@replace];
z0[[replace]] = RandomReal[-1, -1 + dt, Length@replace]
];
Transpose@x0, y0, z0
]]],
Point[Range@n, VertexColors -> colors]
], PlotRange -> -2, 2, -2, 2, -1, 1, Axes -> True,
AxesLabel -> x, y, z
],

Initialization :> (x0, y0, z0 = RandomReal[-1, 1, 3, n])
]


enter image description here



The integration is based on the ODE for $Phi$, which is autonomous and linear and can be done by scalings and translation:
$$d over dt,(x,y,z) = (x log lambda, -y log lambda, 1)$$






share|improve this answer









$endgroup$










  • 1




    $begingroup$
    That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
    $endgroup$
    – cstover
    3 hours ago










  • $begingroup$
    Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
    $endgroup$
    – CA Trevillian
    2 hours ago










  • $begingroup$
    @CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
    $endgroup$
    – Michael E2
    1 hour ago















3












$begingroup$

Not exactly what was asked, but another way to visualize the flow, based on How can I create a fountain effect?:



DynamicModule[x0, y0, z0, last = 0, lam = 1.5, n = 500, colors, 
replace,
last = Clock[Infinity];
x0, y0, z0 = RandomReal[-1, 1, 3, n];
colors = RandomColor[n];

Graphics3D[
GraphicsComplex[
Dynamic@
With[t = Clock[Infinity],
With[dt = (t - last)/2, With[dl = lam^dt,
last = t;
x0 = x0*dl; y0 = y0/dl; z0 = z0 + dt; (* integration of velocity *)
replace = Pick[Range@n, UnitStep[z0 - 1], 1];
With[pick = UnitStep[z0 - 1],
x0[[replace]] = RandomReal[-1, 1, Length@replace];
y0[[replace]] = RandomReal[-1, 1, Length@replace];
z0[[replace]] = RandomReal[-1, -1 + dt, Length@replace]
];
Transpose@x0, y0, z0
]]],
Point[Range@n, VertexColors -> colors]
], PlotRange -> -2, 2, -2, 2, -1, 1, Axes -> True,
AxesLabel -> x, y, z
],

Initialization :> (x0, y0, z0 = RandomReal[-1, 1, 3, n])
]


enter image description here



The integration is based on the ODE for $Phi$, which is autonomous and linear and can be done by scalings and translation:
$$d over dt,(x,y,z) = (x log lambda, -y log lambda, 1)$$






share|improve this answer









$endgroup$










  • 1




    $begingroup$
    That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
    $endgroup$
    – cstover
    3 hours ago










  • $begingroup$
    Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
    $endgroup$
    – CA Trevillian
    2 hours ago










  • $begingroup$
    @CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
    $endgroup$
    – Michael E2
    1 hour ago













3












3








3





$begingroup$

Not exactly what was asked, but another way to visualize the flow, based on How can I create a fountain effect?:



DynamicModule[x0, y0, z0, last = 0, lam = 1.5, n = 500, colors, 
replace,
last = Clock[Infinity];
x0, y0, z0 = RandomReal[-1, 1, 3, n];
colors = RandomColor[n];

Graphics3D[
GraphicsComplex[
Dynamic@
With[t = Clock[Infinity],
With[dt = (t - last)/2, With[dl = lam^dt,
last = t;
x0 = x0*dl; y0 = y0/dl; z0 = z0 + dt; (* integration of velocity *)
replace = Pick[Range@n, UnitStep[z0 - 1], 1];
With[pick = UnitStep[z0 - 1],
x0[[replace]] = RandomReal[-1, 1, Length@replace];
y0[[replace]] = RandomReal[-1, 1, Length@replace];
z0[[replace]] = RandomReal[-1, -1 + dt, Length@replace]
];
Transpose@x0, y0, z0
]]],
Point[Range@n, VertexColors -> colors]
], PlotRange -> -2, 2, -2, 2, -1, 1, Axes -> True,
AxesLabel -> x, y, z
],

Initialization :> (x0, y0, z0 = RandomReal[-1, 1, 3, n])
]


enter image description here



The integration is based on the ODE for $Phi$, which is autonomous and linear and can be done by scalings and translation:
$$d over dt,(x,y,z) = (x log lambda, -y log lambda, 1)$$






share|improve this answer









$endgroup$



Not exactly what was asked, but another way to visualize the flow, based on How can I create a fountain effect?:



DynamicModule[x0, y0, z0, last = 0, lam = 1.5, n = 500, colors, 
replace,
last = Clock[Infinity];
x0, y0, z0 = RandomReal[-1, 1, 3, n];
colors = RandomColor[n];

Graphics3D[
GraphicsComplex[
Dynamic@
With[t = Clock[Infinity],
With[dt = (t - last)/2, With[dl = lam^dt,
last = t;
x0 = x0*dl; y0 = y0/dl; z0 = z0 + dt; (* integration of velocity *)
replace = Pick[Range@n, UnitStep[z0 - 1], 1];
With[pick = UnitStep[z0 - 1],
x0[[replace]] = RandomReal[-1, 1, Length@replace];
y0[[replace]] = RandomReal[-1, 1, Length@replace];
z0[[replace]] = RandomReal[-1, -1 + dt, Length@replace]
];
Transpose@x0, y0, z0
]]],
Point[Range@n, VertexColors -> colors]
], PlotRange -> -2, 2, -2, 2, -1, 1, Axes -> True,
AxesLabel -> x, y, z
],

Initialization :> (x0, y0, z0 = RandomReal[-1, 1, 3, n])
]


enter image description here



The integration is based on the ODE for $Phi$, which is autonomous and linear and can be done by scalings and translation:
$$d over dt,(x,y,z) = (x log lambda, -y log lambda, 1)$$







share|improve this answer












share|improve this answer



share|improve this answer










answered 6 hours ago









Michael E2Michael E2

158k13 gold badges216 silver badges514 bronze badges




158k13 gold badges216 silver badges514 bronze badges










  • 1




    $begingroup$
    That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
    $endgroup$
    – cstover
    3 hours ago










  • $begingroup$
    Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
    $endgroup$
    – CA Trevillian
    2 hours ago










  • $begingroup$
    @CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
    $endgroup$
    – Michael E2
    1 hour ago












  • 1




    $begingroup$
    That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
    $endgroup$
    – cstover
    3 hours ago










  • $begingroup$
    Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
    $endgroup$
    – CA Trevillian
    2 hours ago










  • $begingroup$
    @CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
    $endgroup$
    – Michael E2
    1 hour ago







1




1




$begingroup$
That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
$endgroup$
– cstover
3 hours ago




$begingroup$
That's really neat! While this may not be the question I asked, it's a hugely rewarding answer that I think will help me learn a lot! Thank you so much!
$endgroup$
– cstover
3 hours ago












$begingroup$
Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
$endgroup$
– CA Trevillian
2 hours ago




$begingroup$
Michael, wow! Several +1s for the self-link to your previous work (especially the gravity hose, WOW!) and for this answer also. So this can be a constructive comment, please, can you elaborate on how much the RAM usage is impacted with depictions such as these? Very exquisite work.
$endgroup$
– CA Trevillian
2 hours ago












$begingroup$
@CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
$endgroup$
– Michael E2
1 hour ago




$begingroup$
@CATrevillian Thanks. The graphics take up about 60K for the colors and 12-13K for the coordinates. The coordinate data gets copied at each step, plus 4K for the computation of replace, and the arrays x0, y0, z0 are partially overwritten (but not copied, I think) at each step and stay packed (I think). If GraphicsComplex & VertexColors are efficient, then it's conceivable that only the 13K of coordinate data needs to be shipped to the GPU at each step since the basic graphics structure does not change (but I don't know anything about how GPUs actually work).
$endgroup$
– Michael E2
1 hour ago

















draft saved

draft discarded
















































Thanks for contributing an answer to Mathematica Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f203839%2fanimate-flow-lines-of-time-dependent-3d-dynamical-system%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

Tom Holland Mục lục Đầu đời và giáo dục | Sự nghiệp | Cuộc sống cá nhân | Phim tham gia | Giải thưởng và đề cử | Chú thích | Liên kết ngoài | Trình đơn chuyển hướngProfile“Person Details for Thomas Stanley Holland, "England and Wales Birth Registration Index, 1837-2008" — FamilySearch.org”"Meet Tom Holland... the 16-year-old star of The Impossible""Schoolboy actor Tom Holland finds himself in Oscar contention for role in tsunami drama"“Naomi Watts on the Prince William and Harry's reaction to her film about the late Princess Diana”lưu trữ"Holland and Pflueger Are West End's Two New 'Billy Elliots'""I'm so envious of my son, the movie star! British writer Dominic Holland's spent 20 years trying to crack Hollywood - but he's been beaten to it by a very unlikely rival"“Richard and Margaret Povey of Jersey, Channel Islands, UK: Information about Thomas Stanley Holland”"Tom Holland to play Billy Elliot""New Billy Elliot leaving the garage"Billy Elliot the Musical - Tom Holland - Billy"A Tale of four Billys: Tom Holland""The Feel Good Factor""Thames Christian College schoolboys join Myleene Klass for The Feelgood Factor""Government launches £600,000 arts bursaries pilot""BILLY's Chapman, Holland, Gardner & Jackson-Keen Visit Prime Minister""Elton John 'blown away' by Billy Elliot fifth birthday" (video with John's interview and fragments of Holland's performance)"First News interviews Arrietty's Tom Holland"“33rd Critics' Circle Film Awards winners”“National Board of Review Current Awards”Bản gốc"Ron Howard Whaling Tale 'In The Heart Of The Sea' Casts Tom Holland"“'Spider-Man' Finds Tom Holland to Star as New Web-Slinger”lưu trữ“Captain America: Civil War (2016)”“Film Review: ‘Captain America: Civil War’”lưu trữ“‘Captain America: Civil War’ review: Choose your own avenger”lưu trữ“The Lost City of Z reviews”“Sony Pictures and Marvel Studios Find Their 'Spider-Man' Star and Director”“‘Mary Magdalene’, ‘Current War’ & ‘Wind River’ Get 2017 Release Dates From Weinstein”“Lionsgate Unleashing Daisy Ridley & Tom Holland Starrer ‘Chaos Walking’ In Cannes”“PTA's 'Master' Leads Chicago Film Critics Nominations, UPDATED: Houston and Indiana Critics Nominations”“Nominaciones Goya 2013 Telecinco Cinema – ENG”“Jameson Empire Film Awards: Martin Freeman wins best actor for performance in The Hobbit”“34th Annual Young Artist Awards”Bản gốc“Teen Choice Awards 2016—Captain America: Civil War Leads Second Wave of Nominations”“BAFTA Film Award Nominations: ‘La La Land’ Leads Race”“Saturn Awards Nominations 2017: 'Rogue One,' 'Walking Dead' Lead”Tom HollandTom HollandTom HollandTom Hollandmedia.gettyimages.comWorldCat Identities300279794no20130442900000 0004 0355 42791085670554170004732cb16706349t(data)XX5557367