LM324 - Issue with output in negative feedbackUnderstanding Op-amp Negative FeedbackWhy is a gyrator negative feedback?Op Amp LM324 Different Source + and -, + and GroundInconsistency/Differenct Voltage Each Output Op Amp LM324high output impedance sensor with voltage outputOp-Amp giving unexpected outputStrange output with a LM7171 opamp (non-inverser amplifier)High side current sensing with LM358Non-inverting op-amp configuration with capacitor

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LM324 - Issue with output in negative feedback

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LM324 - Issue with output in negative feedback


Understanding Op-amp Negative FeedbackWhy is a gyrator negative feedback?Op Amp LM324 Different Source + and -, + and GroundInconsistency/Differenct Voltage Each Output Op Amp LM324high output impedance sensor with voltage outputOp-Amp giving unexpected outputStrange output with a LM7171 opamp (non-inverser amplifier)High side current sensing with LM358Non-inverting op-amp configuration with capacitor






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1












$begingroup$


In my analogue output circuit, ocurrs the following ripple voltage when wired to analogue input of PLC with input resistence of 69.3K.
Ripple Issue



If, I put a resistor in serie, this ripple dissapear.



Why that is? Is a impedance problem?



The schematic of circuit is the next:
Output Schematic



Thanks for your help!!
Regards.









share







New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
    $endgroup$
    – John D
    10 hours ago











  • $begingroup$
    You said you put a resistor in series - where in the circuit?
    $endgroup$
    – Reinderien
    9 hours ago










  • $begingroup$
    What is on the load of the U10A? What does the input and output signal look like?
    $endgroup$
    – Voltage Spike
    9 hours ago










  • $begingroup$
    Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
    $endgroup$
    – Javier Gil Pascual
    9 hours ago











  • $begingroup$
    In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
    $endgroup$
    – Javier Gil Pascual
    9 hours ago


















1












$begingroup$


In my analogue output circuit, ocurrs the following ripple voltage when wired to analogue input of PLC with input resistence of 69.3K.
Ripple Issue



If, I put a resistor in serie, this ripple dissapear.



Why that is? Is a impedance problem?



The schematic of circuit is the next:
Output Schematic



Thanks for your help!!
Regards.









share







New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
    $endgroup$
    – John D
    10 hours ago











  • $begingroup$
    You said you put a resistor in series - where in the circuit?
    $endgroup$
    – Reinderien
    9 hours ago










  • $begingroup$
    What is on the load of the U10A? What does the input and output signal look like?
    $endgroup$
    – Voltage Spike
    9 hours ago










  • $begingroup$
    Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
    $endgroup$
    – Javier Gil Pascual
    9 hours ago











  • $begingroup$
    In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
    $endgroup$
    – Javier Gil Pascual
    9 hours ago














1












1








1





$begingroup$


In my analogue output circuit, ocurrs the following ripple voltage when wired to analogue input of PLC with input resistence of 69.3K.
Ripple Issue



If, I put a resistor in serie, this ripple dissapear.



Why that is? Is a impedance problem?



The schematic of circuit is the next:
Output Schematic



Thanks for your help!!
Regards.









share







New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




In my analogue output circuit, ocurrs the following ripple voltage when wired to analogue input of PLC with input resistence of 69.3K.
Ripple Issue



If, I put a resistor in serie, this ripple dissapear.



Why that is? Is a impedance problem?



The schematic of circuit is the next:
Output Schematic



Thanks for your help!!
Regards.







operational-amplifier





share







New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share







New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







share



share






New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 10 hours ago









Javier Gil PascualJavier Gil Pascual

62 bronze badges




62 bronze badges




New contributor



Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Javier Gil Pascual is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • $begingroup$
    Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
    $endgroup$
    – John D
    10 hours ago











  • $begingroup$
    You said you put a resistor in series - where in the circuit?
    $endgroup$
    – Reinderien
    9 hours ago










  • $begingroup$
    What is on the load of the U10A? What does the input and output signal look like?
    $endgroup$
    – Voltage Spike
    9 hours ago










  • $begingroup$
    Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
    $endgroup$
    – Javier Gil Pascual
    9 hours ago











  • $begingroup$
    In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
    $endgroup$
    – Javier Gil Pascual
    9 hours ago

















  • $begingroup$
    Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
    $endgroup$
    – John D
    10 hours ago











  • $begingroup$
    You said you put a resistor in series - where in the circuit?
    $endgroup$
    – Reinderien
    9 hours ago










  • $begingroup$
    What is on the load of the U10A? What does the input and output signal look like?
    $endgroup$
    – Voltage Spike
    9 hours ago










  • $begingroup$
    Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
    $endgroup$
    – Javier Gil Pascual
    9 hours ago











  • $begingroup$
    In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
    $endgroup$
    – Javier Gil Pascual
    9 hours ago
















$begingroup$
Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
$endgroup$
– John D
10 hours ago





$begingroup$
Probably the load on the op-amp is capacitive enough to cause the amplifier to go unstable.
$endgroup$
– John D
10 hours ago













$begingroup$
You said you put a resistor in series - where in the circuit?
$endgroup$
– Reinderien
9 hours ago




$begingroup$
You said you put a resistor in series - where in the circuit?
$endgroup$
– Reinderien
9 hours ago












$begingroup$
What is on the load of the U10A? What does the input and output signal look like?
$endgroup$
– Voltage Spike
9 hours ago




$begingroup$
What is on the load of the U10A? What does the input and output signal look like?
$endgroup$
– Voltage Spike
9 hours ago












$begingroup$
Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
$endgroup$
– Javier Gil Pascual
9 hours ago





$begingroup$
Resistor in serie is put between U10A:1, before the juction with U10A:2, and the load (analogue input of PLC). @Reinderien
$endgroup$
– Javier Gil Pascual
9 hours ago













$begingroup$
In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
$endgroup$
– Javier Gil Pascual
9 hours ago





$begingroup$
In the load of U10A is connected an analogue PLC input. The signal is an analogue signal generated for a magnetic sensor. @VoltageSpike
$endgroup$
– Javier Gil Pascual
9 hours ago











1 Answer
1






active

oldest

votes


















7














$begingroup$

The effective load on the op-amp is likely capacitive. From the LM324 datasheet:



Capacitive loads which are applied directly to the output of the amplifier reduce the loop stability margin. Values of 50 pF can be accommodated using the worst-case non-inverting unity gain connection. Large closed loop gains or resistive isolation should be used if larger load capacitance must be driven by the amplifier.



It's not too hard to pick up 50pF of stray capacitance when driving an off-board cable or interconnect.



The fact that a series resistor solves the problem is another clue that supports this.






share|improve this answer









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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    $begingroup$

    The effective load on the op-amp is likely capacitive. From the LM324 datasheet:



    Capacitive loads which are applied directly to the output of the amplifier reduce the loop stability margin. Values of 50 pF can be accommodated using the worst-case non-inverting unity gain connection. Large closed loop gains or resistive isolation should be used if larger load capacitance must be driven by the amplifier.



    It's not too hard to pick up 50pF of stray capacitance when driving an off-board cable or interconnect.



    The fact that a series resistor solves the problem is another clue that supports this.






    share|improve this answer









    $endgroup$



















      7














      $begingroup$

      The effective load on the op-amp is likely capacitive. From the LM324 datasheet:



      Capacitive loads which are applied directly to the output of the amplifier reduce the loop stability margin. Values of 50 pF can be accommodated using the worst-case non-inverting unity gain connection. Large closed loop gains or resistive isolation should be used if larger load capacitance must be driven by the amplifier.



      It's not too hard to pick up 50pF of stray capacitance when driving an off-board cable or interconnect.



      The fact that a series resistor solves the problem is another clue that supports this.






      share|improve this answer









      $endgroup$

















        7














        7










        7







        $begingroup$

        The effective load on the op-amp is likely capacitive. From the LM324 datasheet:



        Capacitive loads which are applied directly to the output of the amplifier reduce the loop stability margin. Values of 50 pF can be accommodated using the worst-case non-inverting unity gain connection. Large closed loop gains or resistive isolation should be used if larger load capacitance must be driven by the amplifier.



        It's not too hard to pick up 50pF of stray capacitance when driving an off-board cable or interconnect.



        The fact that a series resistor solves the problem is another clue that supports this.






        share|improve this answer









        $endgroup$



        The effective load on the op-amp is likely capacitive. From the LM324 datasheet:



        Capacitive loads which are applied directly to the output of the amplifier reduce the loop stability margin. Values of 50 pF can be accommodated using the worst-case non-inverting unity gain connection. Large closed loop gains or resistive isolation should be used if larger load capacitance must be driven by the amplifier.



        It's not too hard to pick up 50pF of stray capacitance when driving an off-board cable or interconnect.



        The fact that a series resistor solves the problem is another clue that supports this.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 9 hours ago









        John DJohn D

        13.4k1 gold badge23 silver badges33 bronze badges




        13.4k1 gold badge23 silver badges33 bronze badges
























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