Is a PWM required for regenerative braking on a DC Motor?Half-H bridge or low-side MOSFET for PWM motor controlNon-regenerative braking on a PMSM/BLDC motorPWM inductor currentControlling the “amount” of regenerative braking (variable back torque?)Regenerative braking on an electric bicycleUsing a BLDC motor for regenerative brakingMotor Braking IssueMotor freeweeling and regenerative brаking FOR DUMMIES

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Is a PWM required for regenerative braking on a DC Motor?

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Is a PWM required for regenerative braking on a DC Motor?


Half-H bridge or low-side MOSFET for PWM motor controlNon-regenerative braking on a PMSM/BLDC motorPWM inductor currentControlling the “amount” of regenerative braking (variable back torque?)Regenerative braking on an electric bicycleUsing a BLDC motor for regenerative brakingMotor Braking IssueMotor freeweeling and regenerative brаking FOR DUMMIES






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


The DC Motor is question is here: DC Motor



I was wondering if you use a diode and a switch in a manner shown in the below picture if the motor would exhibit regenerative braking when SW1 is open? (Assuming that the voltage from the motor when braking exceeds the motor power) Is the use of PWM required?





schematic





simulate this circuit – Schematic created using CircuitLab










share|improve this question









New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
    $endgroup$
    – le_top
    8 hours ago











  • $begingroup$
    Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
    $endgroup$
    – le_top
    7 hours ago










  • $begingroup$
    @ie_top I don't know why it works on my end
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    @jjake-freeman I get a certificate error - maybe it is related to the CDN network.
    $endgroup$
    – le_top
    2 hours ago

















2












$begingroup$


The DC Motor is question is here: DC Motor



I was wondering if you use a diode and a switch in a manner shown in the below picture if the motor would exhibit regenerative braking when SW1 is open? (Assuming that the voltage from the motor when braking exceeds the motor power) Is the use of PWM required?





schematic





simulate this circuit – Schematic created using CircuitLab










share|improve this question









New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
    $endgroup$
    – le_top
    8 hours ago











  • $begingroup$
    Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
    $endgroup$
    – le_top
    7 hours ago










  • $begingroup$
    @ie_top I don't know why it works on my end
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    @jjake-freeman I get a certificate error - maybe it is related to the CDN network.
    $endgroup$
    – le_top
    2 hours ago













2












2








2





$begingroup$


The DC Motor is question is here: DC Motor



I was wondering if you use a diode and a switch in a manner shown in the below picture if the motor would exhibit regenerative braking when SW1 is open? (Assuming that the voltage from the motor when braking exceeds the motor power) Is the use of PWM required?





schematic





simulate this circuit – Schematic created using CircuitLab










share|improve this question









New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




The DC Motor is question is here: DC Motor



I was wondering if you use a diode and a switch in a manner shown in the below picture if the motor would exhibit regenerative braking when SW1 is open? (Assuming that the voltage from the motor when braking exceeds the motor power) Is the use of PWM required?





schematic





simulate this circuit – Schematic created using CircuitLab







motor pwm generator braking






share|improve this question









New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 7 hours ago







Jake Freeman













New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 8 hours ago









Jake FreemanJake Freeman

1135 bronze badges




1135 bronze badges




New contributor



Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Jake Freeman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • $begingroup$
    Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
    $endgroup$
    – le_top
    8 hours ago











  • $begingroup$
    Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
    $endgroup$
    – le_top
    7 hours ago










  • $begingroup$
    @ie_top I don't know why it works on my end
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    @jjake-freeman I get a certificate error - maybe it is related to the CDN network.
    $endgroup$
    – le_top
    2 hours ago
















  • $begingroup$
    Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
    $endgroup$
    – le_top
    8 hours ago











  • $begingroup$
    Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
    $endgroup$
    – le_top
    7 hours ago










  • $begingroup$
    @ie_top I don't know why it works on my end
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    @jjake-freeman I get a certificate error - maybe it is related to the CDN network.
    $endgroup$
    – le_top
    2 hours ago















$begingroup$
Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
$endgroup$
– le_top
8 hours ago





$begingroup$
Please explain the relation between your question (title) and the content. You talk about PWM, but in your detail there is no PWM - I guess that the switch is PWM controlled, but you should specify that.
$endgroup$
– le_top
8 hours ago













$begingroup$
Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
$endgroup$
– Jake Freeman
7 hours ago




$begingroup$
Oh yeah, sorry I should add regenerative braking without using PWM since many sources say its require.
$endgroup$
– Jake Freeman
7 hours ago












$begingroup$
Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
$endgroup$
– le_top
7 hours ago




$begingroup$
Your link to the Amazon product (code B00TE42PME ) is not working neither - I do not know if this is a limitation of the platform.
$endgroup$
– le_top
7 hours ago












$begingroup$
@ie_top I don't know why it works on my end
$endgroup$
– Jake Freeman
7 hours ago




$begingroup$
@ie_top I don't know why it works on my end
$endgroup$
– Jake Freeman
7 hours ago












$begingroup$
@jjake-freeman I get a certificate error - maybe it is related to the CDN network.
$endgroup$
– le_top
2 hours ago




$begingroup$
@jjake-freeman I get a certificate error - maybe it is related to the CDN network.
$endgroup$
– le_top
2 hours ago










3 Answers
3






active

oldest

votes


















1














$begingroup$


(Assuming that the voltage from the motor when braking exceeds the motor power)




That's the problem — it doesn't. You need a way to boost the voltage coming from the motor to a level that will actually charge the battery. You can use a separate boost converter, or you can create a more tightly integrated solution that uses the inductance of the motor itself as an element in a boost converter. Either way, it does involve some sort of PWM control in order to regulate the power flow.






share|improve this answer









$endgroup$














  • $begingroup$
    So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
    $endgroup$
    – Jake Freeman
    8 hours ago










  • $begingroup$
    Yes. The diode by itself does nothing for you.
    $endgroup$
    – Dave Tweed
    8 hours ago










  • $begingroup$
    Ok thank you. With the Boost converter I still need the diode though, correct?
    $endgroup$
    – Jake Freeman
    8 hours ago










  • $begingroup$
    Well, in a way. A boost converter will generally contain at least one diode.
    $endgroup$
    – Dave Tweed
    8 hours ago


















2














$begingroup$

The voltage on the terminals of your motor will be a function of its speed and the load.
It will not be higher than your power supply, unless some external force is trying to accellerate the motor.



Regenerative breaking supposes that you get back some energy from the motor while breaking. Therefore the breaking must be performed by applying a load accross the motor. For example, you could "short-circuit" it using a low value/high power resistor. The resistor would force the motor to supply power and transform that power into heat. At the same time the motor slows down.



When we use a resistor to slow the motor down, the energy is lost into heat. We could use that heat and transform it into "electricity", but that is not the most effective way.
It is better to change the resistor with a more complex system that would transform the power. It can for instance be an inductor. In way similar to switched power supplies we can "charge" the inductor and "discharge" it into your power source. It would be applied to your power source in a different path than the one controlling your motor through PWM.



So the diode accross the controlling switch would not do anything while breaking your motor.






share|improve this answer









$endgroup$














  • $begingroup$
    Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
    $endgroup$
    – Jake Freeman
    7 hours ago










  • $begingroup$
    A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
    $endgroup$
    – le_top
    2 hours ago


















0














$begingroup$

Your circuit doesn't provide any braking because the motor is running free when the switch is open, and won't produce higher voltage than the battery unless it is 'over-driven' to higher speed by an external force.



To brake the motor you must put a switch across it, like this:-





schematic





simulate this circuit – Schematic created using CircuitLab



When SW2 is closed it 'shorts out' the motor. While the motor is spinning it acts as generator, producing voltage which pushes current through SW2. The current produces torque which brakes the motor. This is dynamic braking, but not regenerative.



However if PWM is applied to SW2 then each time it opens the collapsing magnetic field in the motor's winding inductance creates a 'back-emf' voltage which tries to keep the current going. The current then takes the only path available to it, through D1 into the battery. As well as charging the battery the back-emf current also produces braking torque in the motor.



If the controller uses PWM to control motor speed then this circuit can be 'free', because it uses the same switches that are used in a half-bridge configuration. The only change required is to keep the 'motor' switch open while applying PWM to the 'brake' switch. Most controllers use MOSFETs which have built-in body diodes, so an external diode is not needed either.






share|improve this answer









$endgroup$

















    Your Answer






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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    $begingroup$


    (Assuming that the voltage from the motor when braking exceeds the motor power)




    That's the problem — it doesn't. You need a way to boost the voltage coming from the motor to a level that will actually charge the battery. You can use a separate boost converter, or you can create a more tightly integrated solution that uses the inductance of the motor itself as an element in a boost converter. Either way, it does involve some sort of PWM control in order to regulate the power flow.






    share|improve this answer









    $endgroup$














    • $begingroup$
      So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Yes. The diode by itself does nothing for you.
      $endgroup$
      – Dave Tweed
      8 hours ago










    • $begingroup$
      Ok thank you. With the Boost converter I still need the diode though, correct?
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Well, in a way. A boost converter will generally contain at least one diode.
      $endgroup$
      – Dave Tweed
      8 hours ago















    1














    $begingroup$


    (Assuming that the voltage from the motor when braking exceeds the motor power)




    That's the problem — it doesn't. You need a way to boost the voltage coming from the motor to a level that will actually charge the battery. You can use a separate boost converter, or you can create a more tightly integrated solution that uses the inductance of the motor itself as an element in a boost converter. Either way, it does involve some sort of PWM control in order to regulate the power flow.






    share|improve this answer









    $endgroup$














    • $begingroup$
      So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Yes. The diode by itself does nothing for you.
      $endgroup$
      – Dave Tweed
      8 hours ago










    • $begingroup$
      Ok thank you. With the Boost converter I still need the diode though, correct?
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Well, in a way. A boost converter will generally contain at least one diode.
      $endgroup$
      – Dave Tweed
      8 hours ago













    1














    1










    1







    $begingroup$


    (Assuming that the voltage from the motor when braking exceeds the motor power)




    That's the problem — it doesn't. You need a way to boost the voltage coming from the motor to a level that will actually charge the battery. You can use a separate boost converter, or you can create a more tightly integrated solution that uses the inductance of the motor itself as an element in a boost converter. Either way, it does involve some sort of PWM control in order to regulate the power flow.






    share|improve this answer









    $endgroup$




    (Assuming that the voltage from the motor when braking exceeds the motor power)




    That's the problem — it doesn't. You need a way to boost the voltage coming from the motor to a level that will actually charge the battery. You can use a separate boost converter, or you can create a more tightly integrated solution that uses the inductance of the motor itself as an element in a boost converter. Either way, it does involve some sort of PWM control in order to regulate the power flow.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 8 hours ago









    Dave TweedDave Tweed

    136k11 gold badges174 silver badges298 bronze badges




    136k11 gold badges174 silver badges298 bronze badges














    • $begingroup$
      So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Yes. The diode by itself does nothing for you.
      $endgroup$
      – Dave Tweed
      8 hours ago










    • $begingroup$
      Ok thank you. With the Boost converter I still need the diode though, correct?
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Well, in a way. A boost converter will generally contain at least one diode.
      $endgroup$
      – Dave Tweed
      8 hours ago
















    • $begingroup$
      So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Yes. The diode by itself does nothing for you.
      $endgroup$
      – Dave Tweed
      8 hours ago










    • $begingroup$
      Ok thank you. With the Boost converter I still need the diode though, correct?
      $endgroup$
      – Jake Freeman
      8 hours ago










    • $begingroup$
      Well, in a way. A boost converter will generally contain at least one diode.
      $endgroup$
      – Dave Tweed
      8 hours ago















    $begingroup$
    So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
    $endgroup$
    – Jake Freeman
    8 hours ago




    $begingroup$
    So if I modify the diode branch to include a DC booster to the battery it would charge it correct? Thank you for the answer as well.
    $endgroup$
    – Jake Freeman
    8 hours ago












    $begingroup$
    Yes. The diode by itself does nothing for you.
    $endgroup$
    – Dave Tweed
    8 hours ago




    $begingroup$
    Yes. The diode by itself does nothing for you.
    $endgroup$
    – Dave Tweed
    8 hours ago












    $begingroup$
    Ok thank you. With the Boost converter I still need the diode though, correct?
    $endgroup$
    – Jake Freeman
    8 hours ago




    $begingroup$
    Ok thank you. With the Boost converter I still need the diode though, correct?
    $endgroup$
    – Jake Freeman
    8 hours ago












    $begingroup$
    Well, in a way. A boost converter will generally contain at least one diode.
    $endgroup$
    – Dave Tweed
    8 hours ago




    $begingroup$
    Well, in a way. A boost converter will generally contain at least one diode.
    $endgroup$
    – Dave Tweed
    8 hours ago













    2














    $begingroup$

    The voltage on the terminals of your motor will be a function of its speed and the load.
    It will not be higher than your power supply, unless some external force is trying to accellerate the motor.



    Regenerative breaking supposes that you get back some energy from the motor while breaking. Therefore the breaking must be performed by applying a load accross the motor. For example, you could "short-circuit" it using a low value/high power resistor. The resistor would force the motor to supply power and transform that power into heat. At the same time the motor slows down.



    When we use a resistor to slow the motor down, the energy is lost into heat. We could use that heat and transform it into "electricity", but that is not the most effective way.
    It is better to change the resistor with a more complex system that would transform the power. It can for instance be an inductor. In way similar to switched power supplies we can "charge" the inductor and "discharge" it into your power source. It would be applied to your power source in a different path than the one controlling your motor through PWM.



    So the diode accross the controlling switch would not do anything while breaking your motor.






    share|improve this answer









    $endgroup$














    • $begingroup$
      Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
      $endgroup$
      – Jake Freeman
      7 hours ago










    • $begingroup$
      A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
      $endgroup$
      – le_top
      2 hours ago















    2














    $begingroup$

    The voltage on the terminals of your motor will be a function of its speed and the load.
    It will not be higher than your power supply, unless some external force is trying to accellerate the motor.



    Regenerative breaking supposes that you get back some energy from the motor while breaking. Therefore the breaking must be performed by applying a load accross the motor. For example, you could "short-circuit" it using a low value/high power resistor. The resistor would force the motor to supply power and transform that power into heat. At the same time the motor slows down.



    When we use a resistor to slow the motor down, the energy is lost into heat. We could use that heat and transform it into "electricity", but that is not the most effective way.
    It is better to change the resistor with a more complex system that would transform the power. It can for instance be an inductor. In way similar to switched power supplies we can "charge" the inductor and "discharge" it into your power source. It would be applied to your power source in a different path than the one controlling your motor through PWM.



    So the diode accross the controlling switch would not do anything while breaking your motor.






    share|improve this answer









    $endgroup$














    • $begingroup$
      Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
      $endgroup$
      – Jake Freeman
      7 hours ago










    • $begingroup$
      A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
      $endgroup$
      – le_top
      2 hours ago













    2














    2










    2







    $begingroup$

    The voltage on the terminals of your motor will be a function of its speed and the load.
    It will not be higher than your power supply, unless some external force is trying to accellerate the motor.



    Regenerative breaking supposes that you get back some energy from the motor while breaking. Therefore the breaking must be performed by applying a load accross the motor. For example, you could "short-circuit" it using a low value/high power resistor. The resistor would force the motor to supply power and transform that power into heat. At the same time the motor slows down.



    When we use a resistor to slow the motor down, the energy is lost into heat. We could use that heat and transform it into "electricity", but that is not the most effective way.
    It is better to change the resistor with a more complex system that would transform the power. It can for instance be an inductor. In way similar to switched power supplies we can "charge" the inductor and "discharge" it into your power source. It would be applied to your power source in a different path than the one controlling your motor through PWM.



    So the diode accross the controlling switch would not do anything while breaking your motor.






    share|improve this answer









    $endgroup$



    The voltage on the terminals of your motor will be a function of its speed and the load.
    It will not be higher than your power supply, unless some external force is trying to accellerate the motor.



    Regenerative breaking supposes that you get back some energy from the motor while breaking. Therefore the breaking must be performed by applying a load accross the motor. For example, you could "short-circuit" it using a low value/high power resistor. The resistor would force the motor to supply power and transform that power into heat. At the same time the motor slows down.



    When we use a resistor to slow the motor down, the energy is lost into heat. We could use that heat and transform it into "electricity", but that is not the most effective way.
    It is better to change the resistor with a more complex system that would transform the power. It can for instance be an inductor. In way similar to switched power supplies we can "charge" the inductor and "discharge" it into your power source. It would be applied to your power source in a different path than the one controlling your motor through PWM.



    So the diode accross the controlling switch would not do anything while breaking your motor.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 7 hours ago









    le_tople_top

    1,3054 silver badges13 bronze badges




    1,3054 silver badges13 bronze badges














    • $begingroup$
      Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
      $endgroup$
      – Jake Freeman
      7 hours ago










    • $begingroup$
      A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
      $endgroup$
      – le_top
      2 hours ago
















    • $begingroup$
      Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
      $endgroup$
      – Jake Freeman
      7 hours ago










    • $begingroup$
      A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
      $endgroup$
      – le_top
      2 hours ago















    $begingroup$
    Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
    $endgroup$
    – Jake Freeman
    7 hours ago




    $begingroup$
    Ok thank you. Would the idea of using a booster work as mentioned by Dave Tweed
    $endgroup$
    – Jake Freeman
    7 hours ago












    $begingroup$
    A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
    $endgroup$
    – le_top
    2 hours ago




    $begingroup$
    A separate boost converter used as a load is an interesting idea, but I can not guarantee it will work - I do not have the experience with that.
    $endgroup$
    – le_top
    2 hours ago











    0














    $begingroup$

    Your circuit doesn't provide any braking because the motor is running free when the switch is open, and won't produce higher voltage than the battery unless it is 'over-driven' to higher speed by an external force.



    To brake the motor you must put a switch across it, like this:-





    schematic





    simulate this circuit – Schematic created using CircuitLab



    When SW2 is closed it 'shorts out' the motor. While the motor is spinning it acts as generator, producing voltage which pushes current through SW2. The current produces torque which brakes the motor. This is dynamic braking, but not regenerative.



    However if PWM is applied to SW2 then each time it opens the collapsing magnetic field in the motor's winding inductance creates a 'back-emf' voltage which tries to keep the current going. The current then takes the only path available to it, through D1 into the battery. As well as charging the battery the back-emf current also produces braking torque in the motor.



    If the controller uses PWM to control motor speed then this circuit can be 'free', because it uses the same switches that are used in a half-bridge configuration. The only change required is to keep the 'motor' switch open while applying PWM to the 'brake' switch. Most controllers use MOSFETs which have built-in body diodes, so an external diode is not needed either.






    share|improve this answer









    $endgroup$



















      0














      $begingroup$

      Your circuit doesn't provide any braking because the motor is running free when the switch is open, and won't produce higher voltage than the battery unless it is 'over-driven' to higher speed by an external force.



      To brake the motor you must put a switch across it, like this:-





      schematic





      simulate this circuit – Schematic created using CircuitLab



      When SW2 is closed it 'shorts out' the motor. While the motor is spinning it acts as generator, producing voltage which pushes current through SW2. The current produces torque which brakes the motor. This is dynamic braking, but not regenerative.



      However if PWM is applied to SW2 then each time it opens the collapsing magnetic field in the motor's winding inductance creates a 'back-emf' voltage which tries to keep the current going. The current then takes the only path available to it, through D1 into the battery. As well as charging the battery the back-emf current also produces braking torque in the motor.



      If the controller uses PWM to control motor speed then this circuit can be 'free', because it uses the same switches that are used in a half-bridge configuration. The only change required is to keep the 'motor' switch open while applying PWM to the 'brake' switch. Most controllers use MOSFETs which have built-in body diodes, so an external diode is not needed either.






      share|improve this answer









      $endgroup$

















        0














        0










        0







        $begingroup$

        Your circuit doesn't provide any braking because the motor is running free when the switch is open, and won't produce higher voltage than the battery unless it is 'over-driven' to higher speed by an external force.



        To brake the motor you must put a switch across it, like this:-





        schematic





        simulate this circuit – Schematic created using CircuitLab



        When SW2 is closed it 'shorts out' the motor. While the motor is spinning it acts as generator, producing voltage which pushes current through SW2. The current produces torque which brakes the motor. This is dynamic braking, but not regenerative.



        However if PWM is applied to SW2 then each time it opens the collapsing magnetic field in the motor's winding inductance creates a 'back-emf' voltage which tries to keep the current going. The current then takes the only path available to it, through D1 into the battery. As well as charging the battery the back-emf current also produces braking torque in the motor.



        If the controller uses PWM to control motor speed then this circuit can be 'free', because it uses the same switches that are used in a half-bridge configuration. The only change required is to keep the 'motor' switch open while applying PWM to the 'brake' switch. Most controllers use MOSFETs which have built-in body diodes, so an external diode is not needed either.






        share|improve this answer









        $endgroup$



        Your circuit doesn't provide any braking because the motor is running free when the switch is open, and won't produce higher voltage than the battery unless it is 'over-driven' to higher speed by an external force.



        To brake the motor you must put a switch across it, like this:-





        schematic





        simulate this circuit – Schematic created using CircuitLab



        When SW2 is closed it 'shorts out' the motor. While the motor is spinning it acts as generator, producing voltage which pushes current through SW2. The current produces torque which brakes the motor. This is dynamic braking, but not regenerative.



        However if PWM is applied to SW2 then each time it opens the collapsing magnetic field in the motor's winding inductance creates a 'back-emf' voltage which tries to keep the current going. The current then takes the only path available to it, through D1 into the battery. As well as charging the battery the back-emf current also produces braking torque in the motor.



        If the controller uses PWM to control motor speed then this circuit can be 'free', because it uses the same switches that are used in a half-bridge configuration. The only change required is to keep the 'motor' switch open while applying PWM to the 'brake' switch. Most controllers use MOSFETs which have built-in body diodes, so an external diode is not needed either.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 1 hour ago









        Bruce AbbottBruce Abbott

        29.5k1 gold badge24 silver badges42 bronze badges




        29.5k1 gold badge24 silver badges42 bronze badges
























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