Is it better to use mosfet with gate driver IC or mosfet with lower VGs onHow to drive a high-side N-channel MOSFET with low VGS?Does MOSFET switching gate drive current depend on supply voltage?Using a IR2125 to drive a MOSFET gateLED Matrix Constant Current Driver with MOSFET and NPN TransMOSFET driver for digitally controlled, battery powered boost converterMosfet Gate Driver far from mosfethow to design circuit of high side MOSFET switching with bootstraping and mosfet driver ic?Choosing the correct Gate Driver for a MOSFET in a DC-to-DC ConverterGate Drive Resistor size and/or Gate Driver ICpull-push gate driver for H bridge circuit

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Is it better to use mosfet with gate driver IC or mosfet with lower VGs on


How to drive a high-side N-channel MOSFET with low VGS?Does MOSFET switching gate drive current depend on supply voltage?Using a IR2125 to drive a MOSFET gateLED Matrix Constant Current Driver with MOSFET and NPN TransMOSFET driver for digitally controlled, battery powered boost converterMosfet Gate Driver far from mosfethow to design circuit of high side MOSFET switching with bootstraping and mosfet driver ic?Choosing the correct Gate Driver for a MOSFET in a DC-to-DC ConverterGate Drive Resistor size and/or Gate Driver ICpull-push gate driver for H bridge circuit






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


I am building an RGBW controller for my room. I will be using an ESP32 with 4 MOSFETs for each channel. I want to know which is best for fast switching. Do I need to use a MOSFET driver IC such as ICL7667 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400, or something entirely different?



I'm open for suggestions.



What are the cons and pros for both, since it's only one time investment cost is not the issue.



I will make the PCB so I prefer SMD components.










share|improve this question











$endgroup$













  • $begingroup$
    How much power is each MOSFET delivering?
    $endgroup$
    – Peter Smith
    9 hours ago










  • $begingroup$
    It will be around 2 amps for full brightness each channel
    $endgroup$
    – Uzair Ali
    9 hours ago

















1












$begingroup$


I am building an RGBW controller for my room. I will be using an ESP32 with 4 MOSFETs for each channel. I want to know which is best for fast switching. Do I need to use a MOSFET driver IC such as ICL7667 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400, or something entirely different?



I'm open for suggestions.



What are the cons and pros for both, since it's only one time investment cost is not the issue.



I will make the PCB so I prefer SMD components.










share|improve this question











$endgroup$













  • $begingroup$
    How much power is each MOSFET delivering?
    $endgroup$
    – Peter Smith
    9 hours ago










  • $begingroup$
    It will be around 2 amps for full brightness each channel
    $endgroup$
    – Uzair Ali
    9 hours ago













1












1








1





$begingroup$


I am building an RGBW controller for my room. I will be using an ESP32 with 4 MOSFETs for each channel. I want to know which is best for fast switching. Do I need to use a MOSFET driver IC such as ICL7667 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400, or something entirely different?



I'm open for suggestions.



What are the cons and pros for both, since it's only one time investment cost is not the issue.



I will make the PCB so I prefer SMD components.










share|improve this question











$endgroup$




I am building an RGBW controller for my room. I will be using an ESP32 with 4 MOSFETs for each channel. I want to know which is best for fast switching. Do I need to use a MOSFET driver IC such as ICL7667 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400, or something entirely different?



I'm open for suggestions.



What are the cons and pros for both, since it's only one time investment cost is not the issue.



I will make the PCB so I prefer SMD components.







mosfet pwm esp8266 mosfet-driver






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago









JRE

28.4k7 gold badges53 silver badges91 bronze badges




28.4k7 gold badges53 silver badges91 bronze badges










asked 9 hours ago









Uzair AliUzair Ali

246 bronze badges




246 bronze badges














  • $begingroup$
    How much power is each MOSFET delivering?
    $endgroup$
    – Peter Smith
    9 hours ago










  • $begingroup$
    It will be around 2 amps for full brightness each channel
    $endgroup$
    – Uzair Ali
    9 hours ago
















  • $begingroup$
    How much power is each MOSFET delivering?
    $endgroup$
    – Peter Smith
    9 hours ago










  • $begingroup$
    It will be around 2 amps for full brightness each channel
    $endgroup$
    – Uzair Ali
    9 hours ago















$begingroup$
How much power is each MOSFET delivering?
$endgroup$
– Peter Smith
9 hours ago




$begingroup$
How much power is each MOSFET delivering?
$endgroup$
– Peter Smith
9 hours ago












$begingroup$
It will be around 2 amps for full brightness each channel
$endgroup$
– Uzair Ali
9 hours ago




$begingroup$
It will be around 2 amps for full brightness each channel
$endgroup$
– Uzair Ali
9 hours ago










2 Answers
2






active

oldest

votes


















4














$begingroup$


which is best for fast switching do I need to use MOSFET driver IC such as ICL766 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400




You don't want fast switching to drive LED strips! If the FET switches in a couple tens of nanoseconds, you will send very high di/dt currents into your wires which will radiate electromagnetic interference and essentially act like a broadband radio jammer. Remember a signal with 10ns edges has bandwidth extending to hundreds of MHz...



On the contrary, you want slow edges, like 0.5µs - 1µs. This increases switching losses, but your PWM frequency is going to be low anyway, so switching losses, which are proportional to frequency, will be low too. Let's check the math:



Conduction losses = RdsON * I^2 * DutyCycle



For 2 amps and a duty cycle of 1 (100%) a FET with RdsON of 40 mOhms dissipates 0.16W -- you can use a FET with lower RdsON if you want.



Switching losses = V * I * SwitchingTime * Frequency



For 12V, 2A, 500ns, 10kHz losses will be 0.12W.



Note these losses are already a bit high for a SOT23 FET. I'd use a SO8 single or dual FET instead, they have better dissipation and they're pretty cheap.



Say you want to switch an AO3400 in T=500ns, total gate charge is Qg=7nC so gate drive current will be roughly Qg/T = 14mA. For this you don't need a specialized gate drive IC.



  • If you have 5V available, you can use a 74HCT logic gate as voltage translator between your 3V3 micro and a 5V "logic level" MOSFET. It's cheap and it'll work.


  • If you only have 3V3 available and no 5V, and you don't want to bother with a separate 5V supply, then it makes sense to use a FET that is compatible with 3V3 drive. Depending on the gate drive current required, and the output drive capability of your micro, you might want to add a logic gate as a buffer too. 74LVC for example.






share|improve this answer









$endgroup$














  • $begingroup$
    Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
    $endgroup$
    – Jack Creasey
    6 hours ago










  • $begingroup$
    @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
    $endgroup$
    – Russell McMahon
    1 hour ago


















0














$begingroup$

You cannot design ANY switch properly without specifying the load impedance R, C, L. tR and f rate.



Your switch RdsOn only needs to be < 1% of this load R for efficiency and cool operation with our large heatsink. But cost of FET may become a factor.



Vgs should be be 3x Vgsth for old std 2~4V thresold FETs or Vgs = 12V and only >2~2.5x for low Vth =1V FETs e.g. 3.3V. So your uC levels can consider these options for drivers if a boost is needed in Vgs. But remember that Coss increases as RdsOn decreases, which with cable L affects resonant frequency, so switch rise time, Q, and rep rate needs to be specified also.



For Visual RBW controls, you do not need a very fast rep rate compared to a 1MHz SMPS. Maybe 20kHz with PWM ??



When in doubt, datasheet specs for Vgs @ RdsOn ought to be observed for desired low loss and Coss & L cable to load R, ESR, or incremental R for resonance and series Q values. E.g. LED R ~= 0.5/P. Thus 100W = 5 milliohms , 1 W = 0.5 Ohm. And thus choose a switch that is near 1% of this for cool operation. More Ron demands attention to heat sink 1W/sq.in. of Cu area attached to SMD switch or as specified by datasheet.



For EMI reduction, consider a CM choke and X,Y cap as a PI filter to strip. This can be a Toroid or SMD choke. Use an AM radio to determine if you have EMI.



Bottom line: Compare Ron / R(LED) for loss ratio then decide on FET choices and then Vgs. The P rating of LEDs depends on array voltage and is irrelevant to this. Current and impedance ratio of switch is primary concern. Thus actual load tends to use only a small ratio of rated FET current at max heat sink rating.






share|improve this answer











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    2 Answers
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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    $begingroup$


    which is best for fast switching do I need to use MOSFET driver IC such as ICL766 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400




    You don't want fast switching to drive LED strips! If the FET switches in a couple tens of nanoseconds, you will send very high di/dt currents into your wires which will radiate electromagnetic interference and essentially act like a broadband radio jammer. Remember a signal with 10ns edges has bandwidth extending to hundreds of MHz...



    On the contrary, you want slow edges, like 0.5µs - 1µs. This increases switching losses, but your PWM frequency is going to be low anyway, so switching losses, which are proportional to frequency, will be low too. Let's check the math:



    Conduction losses = RdsON * I^2 * DutyCycle



    For 2 amps and a duty cycle of 1 (100%) a FET with RdsON of 40 mOhms dissipates 0.16W -- you can use a FET with lower RdsON if you want.



    Switching losses = V * I * SwitchingTime * Frequency



    For 12V, 2A, 500ns, 10kHz losses will be 0.12W.



    Note these losses are already a bit high for a SOT23 FET. I'd use a SO8 single or dual FET instead, they have better dissipation and they're pretty cheap.



    Say you want to switch an AO3400 in T=500ns, total gate charge is Qg=7nC so gate drive current will be roughly Qg/T = 14mA. For this you don't need a specialized gate drive IC.



    • If you have 5V available, you can use a 74HCT logic gate as voltage translator between your 3V3 micro and a 5V "logic level" MOSFET. It's cheap and it'll work.


    • If you only have 3V3 available and no 5V, and you don't want to bother with a separate 5V supply, then it makes sense to use a FET that is compatible with 3V3 drive. Depending on the gate drive current required, and the output drive capability of your micro, you might want to add a logic gate as a buffer too. 74LVC for example.






    share|improve this answer









    $endgroup$














    • $begingroup$
      Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
      $endgroup$
      – Jack Creasey
      6 hours ago










    • $begingroup$
      @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
      $endgroup$
      – Russell McMahon
      1 hour ago















    4














    $begingroup$


    which is best for fast switching do I need to use MOSFET driver IC such as ICL766 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400




    You don't want fast switching to drive LED strips! If the FET switches in a couple tens of nanoseconds, you will send very high di/dt currents into your wires which will radiate electromagnetic interference and essentially act like a broadband radio jammer. Remember a signal with 10ns edges has bandwidth extending to hundreds of MHz...



    On the contrary, you want slow edges, like 0.5µs - 1µs. This increases switching losses, but your PWM frequency is going to be low anyway, so switching losses, which are proportional to frequency, will be low too. Let's check the math:



    Conduction losses = RdsON * I^2 * DutyCycle



    For 2 amps and a duty cycle of 1 (100%) a FET with RdsON of 40 mOhms dissipates 0.16W -- you can use a FET with lower RdsON if you want.



    Switching losses = V * I * SwitchingTime * Frequency



    For 12V, 2A, 500ns, 10kHz losses will be 0.12W.



    Note these losses are already a bit high for a SOT23 FET. I'd use a SO8 single or dual FET instead, they have better dissipation and they're pretty cheap.



    Say you want to switch an AO3400 in T=500ns, total gate charge is Qg=7nC so gate drive current will be roughly Qg/T = 14mA. For this you don't need a specialized gate drive IC.



    • If you have 5V available, you can use a 74HCT logic gate as voltage translator between your 3V3 micro and a 5V "logic level" MOSFET. It's cheap and it'll work.


    • If you only have 3V3 available and no 5V, and you don't want to bother with a separate 5V supply, then it makes sense to use a FET that is compatible with 3V3 drive. Depending on the gate drive current required, and the output drive capability of your micro, you might want to add a logic gate as a buffer too. 74LVC for example.






    share|improve this answer









    $endgroup$














    • $begingroup$
      Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
      $endgroup$
      – Jack Creasey
      6 hours ago










    • $begingroup$
      @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
      $endgroup$
      – Russell McMahon
      1 hour ago













    4














    4










    4







    $begingroup$


    which is best for fast switching do I need to use MOSFET driver IC such as ICL766 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400




    You don't want fast switching to drive LED strips! If the FET switches in a couple tens of nanoseconds, you will send very high di/dt currents into your wires which will radiate electromagnetic interference and essentially act like a broadband radio jammer. Remember a signal with 10ns edges has bandwidth extending to hundreds of MHz...



    On the contrary, you want slow edges, like 0.5µs - 1µs. This increases switching losses, but your PWM frequency is going to be low anyway, so switching losses, which are proportional to frequency, will be low too. Let's check the math:



    Conduction losses = RdsON * I^2 * DutyCycle



    For 2 amps and a duty cycle of 1 (100%) a FET with RdsON of 40 mOhms dissipates 0.16W -- you can use a FET with lower RdsON if you want.



    Switching losses = V * I * SwitchingTime * Frequency



    For 12V, 2A, 500ns, 10kHz losses will be 0.12W.



    Note these losses are already a bit high for a SOT23 FET. I'd use a SO8 single or dual FET instead, they have better dissipation and they're pretty cheap.



    Say you want to switch an AO3400 in T=500ns, total gate charge is Qg=7nC so gate drive current will be roughly Qg/T = 14mA. For this you don't need a specialized gate drive IC.



    • If you have 5V available, you can use a 74HCT logic gate as voltage translator between your 3V3 micro and a 5V "logic level" MOSFET. It's cheap and it'll work.


    • If you only have 3V3 available and no 5V, and you don't want to bother with a separate 5V supply, then it makes sense to use a FET that is compatible with 3V3 drive. Depending on the gate drive current required, and the output drive capability of your micro, you might want to add a logic gate as a buffer too. 74LVC for example.






    share|improve this answer









    $endgroup$




    which is best for fast switching do I need to use MOSFET driver IC such as ICL766 with IRFZ44n or is it better to use lower VGS MOSFET such as AO3400




    You don't want fast switching to drive LED strips! If the FET switches in a couple tens of nanoseconds, you will send very high di/dt currents into your wires which will radiate electromagnetic interference and essentially act like a broadband radio jammer. Remember a signal with 10ns edges has bandwidth extending to hundreds of MHz...



    On the contrary, you want slow edges, like 0.5µs - 1µs. This increases switching losses, but your PWM frequency is going to be low anyway, so switching losses, which are proportional to frequency, will be low too. Let's check the math:



    Conduction losses = RdsON * I^2 * DutyCycle



    For 2 amps and a duty cycle of 1 (100%) a FET with RdsON of 40 mOhms dissipates 0.16W -- you can use a FET with lower RdsON if you want.



    Switching losses = V * I * SwitchingTime * Frequency



    For 12V, 2A, 500ns, 10kHz losses will be 0.12W.



    Note these losses are already a bit high for a SOT23 FET. I'd use a SO8 single or dual FET instead, they have better dissipation and they're pretty cheap.



    Say you want to switch an AO3400 in T=500ns, total gate charge is Qg=7nC so gate drive current will be roughly Qg/T = 14mA. For this you don't need a specialized gate drive IC.



    • If you have 5V available, you can use a 74HCT logic gate as voltage translator between your 3V3 micro and a 5V "logic level" MOSFET. It's cheap and it'll work.


    • If you only have 3V3 available and no 5V, and you don't want to bother with a separate 5V supply, then it makes sense to use a FET that is compatible with 3V3 drive. Depending on the gate drive current required, and the output drive capability of your micro, you might want to add a logic gate as a buffer too. 74LVC for example.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 8 hours ago









    peufeupeufeu

    27.1k2 gold badges39 silver badges79 bronze badges




    27.1k2 gold badges39 silver badges79 bronze badges














    • $begingroup$
      Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
      $endgroup$
      – Jack Creasey
      6 hours ago










    • $begingroup$
      @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
      $endgroup$
      – Russell McMahon
      1 hour ago
















    • $begingroup$
      Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
      $endgroup$
      – Jack Creasey
      6 hours ago










    • $begingroup$
      @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
      $endgroup$
      – Russell McMahon
      1 hour ago















    $begingroup$
    Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
    $endgroup$
    – Jack Creasey
    6 hours ago




    $begingroup$
    Using a simple filter component (a Ferrite core) will significantly lower the FET dissipation and reduce EMI. You should not be trying to manipulate or select for FET turn on/off characteristics. I have a bag (lifetime supply) of ferrites like these: amazon.com/13X8X5mm-toroidal-ferrite-Inductors-Isolators/dp/… …..should be part of every DIY'er toolkit.
    $endgroup$
    – Jack Creasey
    6 hours ago












    $begingroup$
    @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
    $endgroup$
    – Russell McMahon
    1 hour ago




    $begingroup$
    @JackCreasey To be useful to Uzair your comment would ideally say how to use the ferrites (obvious to you, not to him perhaps) and maybe put as a comment it on his question or even make a partial answer from it.
    $endgroup$
    – Russell McMahon
    1 hour ago













    0














    $begingroup$

    You cannot design ANY switch properly without specifying the load impedance R, C, L. tR and f rate.



    Your switch RdsOn only needs to be < 1% of this load R for efficiency and cool operation with our large heatsink. But cost of FET may become a factor.



    Vgs should be be 3x Vgsth for old std 2~4V thresold FETs or Vgs = 12V and only >2~2.5x for low Vth =1V FETs e.g. 3.3V. So your uC levels can consider these options for drivers if a boost is needed in Vgs. But remember that Coss increases as RdsOn decreases, which with cable L affects resonant frequency, so switch rise time, Q, and rep rate needs to be specified also.



    For Visual RBW controls, you do not need a very fast rep rate compared to a 1MHz SMPS. Maybe 20kHz with PWM ??



    When in doubt, datasheet specs for Vgs @ RdsOn ought to be observed for desired low loss and Coss & L cable to load R, ESR, or incremental R for resonance and series Q values. E.g. LED R ~= 0.5/P. Thus 100W = 5 milliohms , 1 W = 0.5 Ohm. And thus choose a switch that is near 1% of this for cool operation. More Ron demands attention to heat sink 1W/sq.in. of Cu area attached to SMD switch or as specified by datasheet.



    For EMI reduction, consider a CM choke and X,Y cap as a PI filter to strip. This can be a Toroid or SMD choke. Use an AM radio to determine if you have EMI.



    Bottom line: Compare Ron / R(LED) for loss ratio then decide on FET choices and then Vgs. The P rating of LEDs depends on array voltage and is irrelevant to this. Current and impedance ratio of switch is primary concern. Thus actual load tends to use only a small ratio of rated FET current at max heat sink rating.






    share|improve this answer











    $endgroup$



















      0














      $begingroup$

      You cannot design ANY switch properly without specifying the load impedance R, C, L. tR and f rate.



      Your switch RdsOn only needs to be < 1% of this load R for efficiency and cool operation with our large heatsink. But cost of FET may become a factor.



      Vgs should be be 3x Vgsth for old std 2~4V thresold FETs or Vgs = 12V and only >2~2.5x for low Vth =1V FETs e.g. 3.3V. So your uC levels can consider these options for drivers if a boost is needed in Vgs. But remember that Coss increases as RdsOn decreases, which with cable L affects resonant frequency, so switch rise time, Q, and rep rate needs to be specified also.



      For Visual RBW controls, you do not need a very fast rep rate compared to a 1MHz SMPS. Maybe 20kHz with PWM ??



      When in doubt, datasheet specs for Vgs @ RdsOn ought to be observed for desired low loss and Coss & L cable to load R, ESR, or incremental R for resonance and series Q values. E.g. LED R ~= 0.5/P. Thus 100W = 5 milliohms , 1 W = 0.5 Ohm. And thus choose a switch that is near 1% of this for cool operation. More Ron demands attention to heat sink 1W/sq.in. of Cu area attached to SMD switch or as specified by datasheet.



      For EMI reduction, consider a CM choke and X,Y cap as a PI filter to strip. This can be a Toroid or SMD choke. Use an AM radio to determine if you have EMI.



      Bottom line: Compare Ron / R(LED) for loss ratio then decide on FET choices and then Vgs. The P rating of LEDs depends on array voltage and is irrelevant to this. Current and impedance ratio of switch is primary concern. Thus actual load tends to use only a small ratio of rated FET current at max heat sink rating.






      share|improve this answer











      $endgroup$

















        0














        0










        0







        $begingroup$

        You cannot design ANY switch properly without specifying the load impedance R, C, L. tR and f rate.



        Your switch RdsOn only needs to be < 1% of this load R for efficiency and cool operation with our large heatsink. But cost of FET may become a factor.



        Vgs should be be 3x Vgsth for old std 2~4V thresold FETs or Vgs = 12V and only >2~2.5x for low Vth =1V FETs e.g. 3.3V. So your uC levels can consider these options for drivers if a boost is needed in Vgs. But remember that Coss increases as RdsOn decreases, which with cable L affects resonant frequency, so switch rise time, Q, and rep rate needs to be specified also.



        For Visual RBW controls, you do not need a very fast rep rate compared to a 1MHz SMPS. Maybe 20kHz with PWM ??



        When in doubt, datasheet specs for Vgs @ RdsOn ought to be observed for desired low loss and Coss & L cable to load R, ESR, or incremental R for resonance and series Q values. E.g. LED R ~= 0.5/P. Thus 100W = 5 milliohms , 1 W = 0.5 Ohm. And thus choose a switch that is near 1% of this for cool operation. More Ron demands attention to heat sink 1W/sq.in. of Cu area attached to SMD switch or as specified by datasheet.



        For EMI reduction, consider a CM choke and X,Y cap as a PI filter to strip. This can be a Toroid or SMD choke. Use an AM radio to determine if you have EMI.



        Bottom line: Compare Ron / R(LED) for loss ratio then decide on FET choices and then Vgs. The P rating of LEDs depends on array voltage and is irrelevant to this. Current and impedance ratio of switch is primary concern. Thus actual load tends to use only a small ratio of rated FET current at max heat sink rating.






        share|improve this answer











        $endgroup$



        You cannot design ANY switch properly without specifying the load impedance R, C, L. tR and f rate.



        Your switch RdsOn only needs to be < 1% of this load R for efficiency and cool operation with our large heatsink. But cost of FET may become a factor.



        Vgs should be be 3x Vgsth for old std 2~4V thresold FETs or Vgs = 12V and only >2~2.5x for low Vth =1V FETs e.g. 3.3V. So your uC levels can consider these options for drivers if a boost is needed in Vgs. But remember that Coss increases as RdsOn decreases, which with cable L affects resonant frequency, so switch rise time, Q, and rep rate needs to be specified also.



        For Visual RBW controls, you do not need a very fast rep rate compared to a 1MHz SMPS. Maybe 20kHz with PWM ??



        When in doubt, datasheet specs for Vgs @ RdsOn ought to be observed for desired low loss and Coss & L cable to load R, ESR, or incremental R for resonance and series Q values. E.g. LED R ~= 0.5/P. Thus 100W = 5 milliohms , 1 W = 0.5 Ohm. And thus choose a switch that is near 1% of this for cool operation. More Ron demands attention to heat sink 1W/sq.in. of Cu area attached to SMD switch or as specified by datasheet.



        For EMI reduction, consider a CM choke and X,Y cap as a PI filter to strip. This can be a Toroid or SMD choke. Use an AM radio to determine if you have EMI.



        Bottom line: Compare Ron / R(LED) for loss ratio then decide on FET choices and then Vgs. The P rating of LEDs depends on array voltage and is irrelevant to this. Current and impedance ratio of switch is primary concern. Thus actual load tends to use only a small ratio of rated FET current at max heat sink rating.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 4 hours ago

























        answered 6 hours ago









        Sunnyskyguy EE75Sunnyskyguy EE75

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