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How can I draw overlapping triangles?
How can I draw several polygons on the same base line using TikZ?Triangles inside Triangles, Fractals to an arbitrary depthTikz: How to indicate/display overlapping linesWriting from middle of the page, upside down and from the right hand side?How can I draw two triangles in a row?Is it possible to delete all “data-curves” which are outside from my diagram? (only the overlapping part)How to draw overlapping nodesRemoving lines in overlapping triangles in TikZFilling shape with horizontal linesHow do I draw the following triangles in latex?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I need a non-equilateral triangle ABC and an equilateral triangle DEF to be overlapping ABC (with all 6 lines showing). Lines AD, BE, and CF need to be perpendicular bisectors (cut in the middle) of the sides of the triangle DEF. Would really appreciate any help with this thank you!
tikz-pgf geometry shapes
New contributor
add a comment
|
I need a non-equilateral triangle ABC and an equilateral triangle DEF to be overlapping ABC (with all 6 lines showing). Lines AD, BE, and CF need to be perpendicular bisectors (cut in the middle) of the sides of the triangle DEF. Would really appreciate any help with this thank you!
tikz-pgf geometry shapes
New contributor
2
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago
add a comment
|
I need a non-equilateral triangle ABC and an equilateral triangle DEF to be overlapping ABC (with all 6 lines showing). Lines AD, BE, and CF need to be perpendicular bisectors (cut in the middle) of the sides of the triangle DEF. Would really appreciate any help with this thank you!
tikz-pgf geometry shapes
New contributor
I need a non-equilateral triangle ABC and an equilateral triangle DEF to be overlapping ABC (with all 6 lines showing). Lines AD, BE, and CF need to be perpendicular bisectors (cut in the middle) of the sides of the triangle DEF. Would really appreciate any help with this thank you!
tikz-pgf geometry shapes
tikz-pgf geometry shapes
New contributor
New contributor
edited 2 hours ago
LianTze Lim
9,7602 gold badges34 silver badges75 bronze badges
9,7602 gold badges34 silver badges75 bronze badges
New contributor
asked 8 hours ago
marmarmarmarmarmar
153 bronze badges
153 bronze badges
New contributor
New contributor
2
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago
add a comment
|
2
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago
2
2
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago
add a comment
|
2 Answers
2
active
oldest
votes
The fact that A, B, and C should lie on the bisectors makes their location unique up to a real parameter for each of them, for which I chose 1.2
, 1.4
and 1.6
, respectively.
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[declare function=a=2;]
draw (-30:a) coordinate[label=-30:$D$] (D) --
(90:a) coordinate[label=90:$E$] (E) --
(210:a) coordinate[label=210:$F$] (F) -- cycle;
draw (-30-60:1.4*a) coordinate[label=-30-60:$B$] (B) --
(90-60:1.6*a) coordinate[label=90-60:$C$] (C) --
(210-60:1.2*a) coordinate[label=210-60:$A$] (A) -- cycle;
draw[dashed] (A) -- (D) (B) -- (E) (C) -- (F);
endtikzpicture
enddocument
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
add a comment
|
Using calc
TikZ library:
documentclass[tikz,border=3mm]standalone
usetikzlibrarycalc
begindocument
begintikzpicture[declare function=a=2;,
every label/.style = circle, inner sep=0pt
]
draw (0,0) coordinate[label=210:$A$] (A) --
(a,0) coordinate[label=330:$B$] (B) --
(60:a) coordinate[label= 90:$C$] (C) -- cycle;
draw ($(A)!0.5!(B)!a/4!90:(A)$) coordinate[label=270:$D$] (D) --
($(B)!0.5!(C)!a/3!90:(B)$) coordinate[label= 30:$E$] (E) --
($(C)!0.5!(A)!a/2!90:(C)$) coordinate[label=120:$F$] (F) -- cycle;
draw[densely dashed,very thin]
(A) -- (E) (B) -- (F) (C) -- (D);
endtikzpicture
enddocument
add a comment
|
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The fact that A, B, and C should lie on the bisectors makes their location unique up to a real parameter for each of them, for which I chose 1.2
, 1.4
and 1.6
, respectively.
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[declare function=a=2;]
draw (-30:a) coordinate[label=-30:$D$] (D) --
(90:a) coordinate[label=90:$E$] (E) --
(210:a) coordinate[label=210:$F$] (F) -- cycle;
draw (-30-60:1.4*a) coordinate[label=-30-60:$B$] (B) --
(90-60:1.6*a) coordinate[label=90-60:$C$] (C) --
(210-60:1.2*a) coordinate[label=210-60:$A$] (A) -- cycle;
draw[dashed] (A) -- (D) (B) -- (E) (C) -- (F);
endtikzpicture
enddocument
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
add a comment
|
The fact that A, B, and C should lie on the bisectors makes their location unique up to a real parameter for each of them, for which I chose 1.2
, 1.4
and 1.6
, respectively.
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[declare function=a=2;]
draw (-30:a) coordinate[label=-30:$D$] (D) --
(90:a) coordinate[label=90:$E$] (E) --
(210:a) coordinate[label=210:$F$] (F) -- cycle;
draw (-30-60:1.4*a) coordinate[label=-30-60:$B$] (B) --
(90-60:1.6*a) coordinate[label=90-60:$C$] (C) --
(210-60:1.2*a) coordinate[label=210-60:$A$] (A) -- cycle;
draw[dashed] (A) -- (D) (B) -- (E) (C) -- (F);
endtikzpicture
enddocument
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
add a comment
|
The fact that A, B, and C should lie on the bisectors makes their location unique up to a real parameter for each of them, for which I chose 1.2
, 1.4
and 1.6
, respectively.
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[declare function=a=2;]
draw (-30:a) coordinate[label=-30:$D$] (D) --
(90:a) coordinate[label=90:$E$] (E) --
(210:a) coordinate[label=210:$F$] (F) -- cycle;
draw (-30-60:1.4*a) coordinate[label=-30-60:$B$] (B) --
(90-60:1.6*a) coordinate[label=90-60:$C$] (C) --
(210-60:1.2*a) coordinate[label=210-60:$A$] (A) -- cycle;
draw[dashed] (A) -- (D) (B) -- (E) (C) -- (F);
endtikzpicture
enddocument
The fact that A, B, and C should lie on the bisectors makes their location unique up to a real parameter for each of them, for which I chose 1.2
, 1.4
and 1.6
, respectively.
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[declare function=a=2;]
draw (-30:a) coordinate[label=-30:$D$] (D) --
(90:a) coordinate[label=90:$E$] (E) --
(210:a) coordinate[label=210:$F$] (F) -- cycle;
draw (-30-60:1.4*a) coordinate[label=-30-60:$B$] (B) --
(90-60:1.6*a) coordinate[label=90-60:$C$] (C) --
(210-60:1.2*a) coordinate[label=210-60:$A$] (A) -- cycle;
draw[dashed] (A) -- (D) (B) -- (E) (C) -- (F);
endtikzpicture
enddocument
edited 7 hours ago
answered 8 hours ago
Schrödinger's catSchrödinger's cat
7,25011 silver badges22 bronze badges
7,25011 silver badges22 bronze badges
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
add a comment
|
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
1
1
Bless your heart THANK YOU
– marmarmar
7 hours ago
Bless your heart THANK YOU
– marmarmar
7 hours ago
add a comment
|
Using calc
TikZ library:
documentclass[tikz,border=3mm]standalone
usetikzlibrarycalc
begindocument
begintikzpicture[declare function=a=2;,
every label/.style = circle, inner sep=0pt
]
draw (0,0) coordinate[label=210:$A$] (A) --
(a,0) coordinate[label=330:$B$] (B) --
(60:a) coordinate[label= 90:$C$] (C) -- cycle;
draw ($(A)!0.5!(B)!a/4!90:(A)$) coordinate[label=270:$D$] (D) --
($(B)!0.5!(C)!a/3!90:(B)$) coordinate[label= 30:$E$] (E) --
($(C)!0.5!(A)!a/2!90:(C)$) coordinate[label=120:$F$] (F) -- cycle;
draw[densely dashed,very thin]
(A) -- (E) (B) -- (F) (C) -- (D);
endtikzpicture
enddocument
add a comment
|
Using calc
TikZ library:
documentclass[tikz,border=3mm]standalone
usetikzlibrarycalc
begindocument
begintikzpicture[declare function=a=2;,
every label/.style = circle, inner sep=0pt
]
draw (0,0) coordinate[label=210:$A$] (A) --
(a,0) coordinate[label=330:$B$] (B) --
(60:a) coordinate[label= 90:$C$] (C) -- cycle;
draw ($(A)!0.5!(B)!a/4!90:(A)$) coordinate[label=270:$D$] (D) --
($(B)!0.5!(C)!a/3!90:(B)$) coordinate[label= 30:$E$] (E) --
($(C)!0.5!(A)!a/2!90:(C)$) coordinate[label=120:$F$] (F) -- cycle;
draw[densely dashed,very thin]
(A) -- (E) (B) -- (F) (C) -- (D);
endtikzpicture
enddocument
add a comment
|
Using calc
TikZ library:
documentclass[tikz,border=3mm]standalone
usetikzlibrarycalc
begindocument
begintikzpicture[declare function=a=2;,
every label/.style = circle, inner sep=0pt
]
draw (0,0) coordinate[label=210:$A$] (A) --
(a,0) coordinate[label=330:$B$] (B) --
(60:a) coordinate[label= 90:$C$] (C) -- cycle;
draw ($(A)!0.5!(B)!a/4!90:(A)$) coordinate[label=270:$D$] (D) --
($(B)!0.5!(C)!a/3!90:(B)$) coordinate[label= 30:$E$] (E) --
($(C)!0.5!(A)!a/2!90:(C)$) coordinate[label=120:$F$] (F) -- cycle;
draw[densely dashed,very thin]
(A) -- (E) (B) -- (F) (C) -- (D);
endtikzpicture
enddocument
Using calc
TikZ library:
documentclass[tikz,border=3mm]standalone
usetikzlibrarycalc
begindocument
begintikzpicture[declare function=a=2;,
every label/.style = circle, inner sep=0pt
]
draw (0,0) coordinate[label=210:$A$] (A) --
(a,0) coordinate[label=330:$B$] (B) --
(60:a) coordinate[label= 90:$C$] (C) -- cycle;
draw ($(A)!0.5!(B)!a/4!90:(A)$) coordinate[label=270:$D$] (D) --
($(B)!0.5!(C)!a/3!90:(B)$) coordinate[label= 30:$E$] (E) --
($(C)!0.5!(A)!a/2!90:(C)$) coordinate[label=120:$F$] (F) -- cycle;
draw[densely dashed,very thin]
(A) -- (E) (B) -- (F) (C) -- (D);
endtikzpicture
enddocument
answered 2 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
147k8 gold badges84 silver badges194 bronze badges
add a comment
|
add a comment
|
marmarmar is a new contributor. Be nice, and check out our Code of Conduct.
marmarmar is a new contributor. Be nice, and check out our Code of Conduct.
marmarmar is a new contributor. Be nice, and check out our Code of Conduct.
marmarmar is a new contributor. Be nice, and check out our Code of Conduct.
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2
Hi, welcome. Can you add a hand-drawn drawing of the desired result?
– AndréC
8 hours ago
someone got it spot on in the comments but will do in the future!
– marmarmar
7 hours ago