Naive question about polynomial time reducibilitySuper-linear time complexity lower bounds for any natural problem in NP?Solving NP problems in (usually) Polynomial time?Given a polynomial-time algorithm, can we compute an explicit polynomial time bound just from the program?Proof that any NP problem can be reduced (in P time) to any problem in NPC?What are the implications of the new quasi-polynomial time solution for the Graph Isomorphism problem?What arguments do exist against defining completeness in NP using injective Karp reductions?Should we expect there to be a problem that is PH-hard but not PSPACE-hard?Non-invertible Karp reduction

Naive question about polynomial time reducibility


Super-linear time complexity lower bounds for any natural problem in NP?Solving NP problems in (usually) Polynomial time?Given a polynomial-time algorithm, can we compute an explicit polynomial time bound just from the program?Proof that any NP problem can be reduced (in P time) to any problem in NPC?What are the implications of the new quasi-polynomial time solution for the Graph Isomorphism problem?What arguments do exist against defining completeness in NP using injective Karp reductions?Should we expect there to be a problem that is PH-hard but not PSPACE-hard?Non-invertible Karp reduction













3












$begingroup$



Question:

is it known, whether there is an upper bound on the exponent of the fastest polynomial-time reduction from $mathrm3SAT$ to $mathrmNP$-$mathrmhard$ problems or, can it be proved that for every problem requiring an $Theta(n^k)$ time reduction, there is a problem requiring an $Omega(n^k+1)$ reduction from $mathrm3SAT$?




Additional, secondary question:
Which $mathrmNP$-$mathrmhard$ problem requires the polynomial time reduction from $mathrm3SAT$ with the highest exponent?










share|cite|improve this question









$endgroup$


















    3












    $begingroup$



    Question:

    is it known, whether there is an upper bound on the exponent of the fastest polynomial-time reduction from $mathrm3SAT$ to $mathrmNP$-$mathrmhard$ problems or, can it be proved that for every problem requiring an $Theta(n^k)$ time reduction, there is a problem requiring an $Omega(n^k+1)$ reduction from $mathrm3SAT$?




    Additional, secondary question:
    Which $mathrmNP$-$mathrmhard$ problem requires the polynomial time reduction from $mathrm3SAT$ with the highest exponent?










    share|cite|improve this question









    $endgroup$
















      3












      3








      3





      $begingroup$



      Question:

      is it known, whether there is an upper bound on the exponent of the fastest polynomial-time reduction from $mathrm3SAT$ to $mathrmNP$-$mathrmhard$ problems or, can it be proved that for every problem requiring an $Theta(n^k)$ time reduction, there is a problem requiring an $Omega(n^k+1)$ reduction from $mathrm3SAT$?




      Additional, secondary question:
      Which $mathrmNP$-$mathrmhard$ problem requires the polynomial time reduction from $mathrm3SAT$ with the highest exponent?










      share|cite|improve this question









      $endgroup$





      Question:

      is it known, whether there is an upper bound on the exponent of the fastest polynomial-time reduction from $mathrm3SAT$ to $mathrmNP$-$mathrmhard$ problems or, can it be proved that for every problem requiring an $Theta(n^k)$ time reduction, there is a problem requiring an $Omega(n^k+1)$ reduction from $mathrm3SAT$?




      Additional, secondary question:
      Which $mathrmNP$-$mathrmhard$ problem requires the polynomial time reduction from $mathrm3SAT$ with the highest exponent?







      computational-complexity






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 11 hours ago









      Manfred WeisManfred Weis

      4,9642 gold badges15 silver badges48 bronze badges




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          1 Answer
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          4














          $begingroup$

          It's unlikely there is any upper bound. To see the problem, consider the (artificial) problem



          $text3SATpad = phi #^ : phi in text3SAT$,



          where $#$ is some new symbol. $text3SATpad$ is in $mathsfNP$, and there is an obvious $O(n^100)$-time reduction from $text3SAT$ to $text3SATpad$. But it's doubtful there's even an $O(n^99)$-time reduction. Otherwise, one could solve $text3SAT$ in $2^O(n^.99)$ time (unlikely, as this violates the Exponential Time Hypothesis), as follows:



          1. On input $phi$ of length $n$, run the reduction producing string $y$. The key point here is that $|y| leq O(n^99)$.


          2. If $y$ is not of the form $psi #^$, reject.


          3. Otherwise, since $|psi #^| leq O(n^99)$, it must be that $|psi| leq O(n^.99)$. Now decide if $psi in text3SAT$ in $2^O(n^.99)$ time, using a naive brute-force algorithm. This gives the correct answer about satisfiability of $phi$.


          Perhaps one can even prove the impossibility conditioned only on $mathsfP neq mathsfNP$ (rather than on E.T.H.), by a Ladner's Theorem-type argument...






          share|cite|improve this answer









          $endgroup$










          • 3




            $begingroup$
            Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
            $endgroup$
            – Emil Jeřábek
            4 hours ago










          • $begingroup$
            Seems possible, yes.
            $endgroup$
            – Ryan O'Donnell
            4 hours ago












          Your Answer








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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

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          active

          oldest

          votes









          4














          $begingroup$

          It's unlikely there is any upper bound. To see the problem, consider the (artificial) problem



          $text3SATpad = phi #^ : phi in text3SAT$,



          where $#$ is some new symbol. $text3SATpad$ is in $mathsfNP$, and there is an obvious $O(n^100)$-time reduction from $text3SAT$ to $text3SATpad$. But it's doubtful there's even an $O(n^99)$-time reduction. Otherwise, one could solve $text3SAT$ in $2^O(n^.99)$ time (unlikely, as this violates the Exponential Time Hypothesis), as follows:



          1. On input $phi$ of length $n$, run the reduction producing string $y$. The key point here is that $|y| leq O(n^99)$.


          2. If $y$ is not of the form $psi #^$, reject.


          3. Otherwise, since $|psi #^| leq O(n^99)$, it must be that $|psi| leq O(n^.99)$. Now decide if $psi in text3SAT$ in $2^O(n^.99)$ time, using a naive brute-force algorithm. This gives the correct answer about satisfiability of $phi$.


          Perhaps one can even prove the impossibility conditioned only on $mathsfP neq mathsfNP$ (rather than on E.T.H.), by a Ladner's Theorem-type argument...






          share|cite|improve this answer









          $endgroup$










          • 3




            $begingroup$
            Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
            $endgroup$
            – Emil Jeřábek
            4 hours ago










          • $begingroup$
            Seems possible, yes.
            $endgroup$
            – Ryan O'Donnell
            4 hours ago















          4














          $begingroup$

          It's unlikely there is any upper bound. To see the problem, consider the (artificial) problem



          $text3SATpad = phi #^ : phi in text3SAT$,



          where $#$ is some new symbol. $text3SATpad$ is in $mathsfNP$, and there is an obvious $O(n^100)$-time reduction from $text3SAT$ to $text3SATpad$. But it's doubtful there's even an $O(n^99)$-time reduction. Otherwise, one could solve $text3SAT$ in $2^O(n^.99)$ time (unlikely, as this violates the Exponential Time Hypothesis), as follows:



          1. On input $phi$ of length $n$, run the reduction producing string $y$. The key point here is that $|y| leq O(n^99)$.


          2. If $y$ is not of the form $psi #^$, reject.


          3. Otherwise, since $|psi #^| leq O(n^99)$, it must be that $|psi| leq O(n^.99)$. Now decide if $psi in text3SAT$ in $2^O(n^.99)$ time, using a naive brute-force algorithm. This gives the correct answer about satisfiability of $phi$.


          Perhaps one can even prove the impossibility conditioned only on $mathsfP neq mathsfNP$ (rather than on E.T.H.), by a Ladner's Theorem-type argument...






          share|cite|improve this answer









          $endgroup$










          • 3




            $begingroup$
            Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
            $endgroup$
            – Emil Jeřábek
            4 hours ago










          • $begingroup$
            Seems possible, yes.
            $endgroup$
            – Ryan O'Donnell
            4 hours ago













          4














          4










          4







          $begingroup$

          It's unlikely there is any upper bound. To see the problem, consider the (artificial) problem



          $text3SATpad = phi #^ : phi in text3SAT$,



          where $#$ is some new symbol. $text3SATpad$ is in $mathsfNP$, and there is an obvious $O(n^100)$-time reduction from $text3SAT$ to $text3SATpad$. But it's doubtful there's even an $O(n^99)$-time reduction. Otherwise, one could solve $text3SAT$ in $2^O(n^.99)$ time (unlikely, as this violates the Exponential Time Hypothesis), as follows:



          1. On input $phi$ of length $n$, run the reduction producing string $y$. The key point here is that $|y| leq O(n^99)$.


          2. If $y$ is not of the form $psi #^$, reject.


          3. Otherwise, since $|psi #^| leq O(n^99)$, it must be that $|psi| leq O(n^.99)$. Now decide if $psi in text3SAT$ in $2^O(n^.99)$ time, using a naive brute-force algorithm. This gives the correct answer about satisfiability of $phi$.


          Perhaps one can even prove the impossibility conditioned only on $mathsfP neq mathsfNP$ (rather than on E.T.H.), by a Ladner's Theorem-type argument...






          share|cite|improve this answer









          $endgroup$



          It's unlikely there is any upper bound. To see the problem, consider the (artificial) problem



          $text3SATpad = phi #^ : phi in text3SAT$,



          where $#$ is some new symbol. $text3SATpad$ is in $mathsfNP$, and there is an obvious $O(n^100)$-time reduction from $text3SAT$ to $text3SATpad$. But it's doubtful there's even an $O(n^99)$-time reduction. Otherwise, one could solve $text3SAT$ in $2^O(n^.99)$ time (unlikely, as this violates the Exponential Time Hypothesis), as follows:



          1. On input $phi$ of length $n$, run the reduction producing string $y$. The key point here is that $|y| leq O(n^99)$.


          2. If $y$ is not of the form $psi #^$, reject.


          3. Otherwise, since $|psi #^| leq O(n^99)$, it must be that $|psi| leq O(n^.99)$. Now decide if $psi in text3SAT$ in $2^O(n^.99)$ time, using a naive brute-force algorithm. This gives the correct answer about satisfiability of $phi$.


          Perhaps one can even prove the impossibility conditioned only on $mathsfP neq mathsfNP$ (rather than on E.T.H.), by a Ladner's Theorem-type argument...







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 5 hours ago









          Ryan O'DonnellRyan O'Donnell

          5,0991 gold badge21 silver badges42 bronze badges




          5,0991 gold badge21 silver badges42 bronze badges










          • 3




            $begingroup$
            Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
            $endgroup$
            – Emil Jeřábek
            4 hours ago










          • $begingroup$
            Seems possible, yes.
            $endgroup$
            – Ryan O'Donnell
            4 hours ago












          • 3




            $begingroup$
            Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
            $endgroup$
            – Emil Jeřábek
            4 hours ago










          • $begingroup$
            Seems possible, yes.
            $endgroup$
            – Ryan O'Donnell
            4 hours ago







          3




          3




          $begingroup$
          Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
          $endgroup$
          – Emil Jeřábek
          4 hours ago




          $begingroup$
          Can’t you prove it unconditionally using the nondeterministic time hierarchy theorem?
          $endgroup$
          – Emil Jeřábek
          4 hours ago












          $begingroup$
          Seems possible, yes.
          $endgroup$
          – Ryan O'Donnell
          4 hours ago




          $begingroup$
          Seems possible, yes.
          $endgroup$
          – Ryan O'Donnell
          4 hours ago


















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