Find the number for the question markIQ-test-type question with not satisfying answerWhich number should replace the question mark?Find the missing piece to complete the patternCan you find the value of the question mark$colorred?$Reasoning - Find Missing NumberWhich two numbers replaces the question mark?Can you find the next number in the following series?What is the missing number in the question mark?What is the missing number, can anyone solve this? My original puzzleWhat is the pattern in the question box?
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Spiral Stumper Series: Instructionless Puzzle
Find the number for the question mark
IQ-test-type question with not satisfying answerWhich number should replace the question mark?Find the missing piece to complete the patternCan you find the value of the question mark$colorred?$Reasoning - Find Missing NumberWhich two numbers replaces the question mark?Can you find the next number in the following series?What is the missing number in the question mark?What is the missing number, can anyone solve this? My original puzzleWhat is the pattern in the question box?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;
.everyonelovesstackoverflowposition:absolute;height:1px;width:1px;opacity:0;top:0;left:0;pointer-events:none;
$begingroup$
What is the number for the question mark? (My original puzzle)
3=39
1=3
4=84
5=155
2=14
10=?
pattern
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
$endgroup$
add a comment
|
$begingroup$
What is the number for the question mark? (My original puzzle)
3=39
1=3
4=84
5=155
2=14
10=?
pattern
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
$endgroup$
add a comment
|
$begingroup$
What is the number for the question mark? (My original puzzle)
3=39
1=3
4=84
5=155
2=14
10=?
pattern
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
$endgroup$
What is the number for the question mark? (My original puzzle)
3=39
1=3
4=84
5=155
2=14
10=?
pattern
pattern
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
asked 8 hours ago
Deepthinker101Deepthinker101
19610 bronze badges
19610 bronze badges
add a comment
|
add a comment
|
2 Answers
2
active
oldest
votes
$begingroup$
By noting that each number maps to a multiple of itself:
$3rightarrow3*13$
$1rightarrow1*3$
$4rightarrow4*21$
$5rightarrow5*31$
$2rightarrow2*7$
And that the quotient increases quadratically
$1:3$
$2:7=3+4$
$3:13=7+6$
$4:21=13+8$
$5:31=21+10$
The mapping must be a cubic function.
The above sequence is equal to $n^2+n+1$, where n is the input.
The original sequence is multiplied by $n$ again.
So the function can be described by $n^3+n^2+n$.
So the final answer is $10^3+10^2+10=1110$.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
add a comment
|
$begingroup$
Note that
1 x 3 = 3 (3 is the 2nd odd positive number)
2 x 7 = 14 (7 is the 4th positive odd number)
3 x 13 = 39 (13 is the 7th positive odd number)
4 x 21 = 84 (21 is the 11th positive odd number)
5 x 31 = 155 (31 is the 16th positive odd number)
Note that
The nth odd number is being used, where n forms a pattern of 2, 4, 7, 11, 16 — ie. differences increase by one. Then to continue this pattern, we have 22, 29, 37, 46, 56 — this sequence is the triangular numbers plus 1. (Note the triangular Numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...)
So then the answer ought to be
10 = 1110, as 111 is the 56th positive odd number and 10 x 111 = 1110.
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
$endgroup$
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
add a comment
|
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
By noting that each number maps to a multiple of itself:
$3rightarrow3*13$
$1rightarrow1*3$
$4rightarrow4*21$
$5rightarrow5*31$
$2rightarrow2*7$
And that the quotient increases quadratically
$1:3$
$2:7=3+4$
$3:13=7+6$
$4:21=13+8$
$5:31=21+10$
The mapping must be a cubic function.
The above sequence is equal to $n^2+n+1$, where n is the input.
The original sequence is multiplied by $n$ again.
So the function can be described by $n^3+n^2+n$.
So the final answer is $10^3+10^2+10=1110$.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
add a comment
|
$begingroup$
By noting that each number maps to a multiple of itself:
$3rightarrow3*13$
$1rightarrow1*3$
$4rightarrow4*21$
$5rightarrow5*31$
$2rightarrow2*7$
And that the quotient increases quadratically
$1:3$
$2:7=3+4$
$3:13=7+6$
$4:21=13+8$
$5:31=21+10$
The mapping must be a cubic function.
The above sequence is equal to $n^2+n+1$, where n is the input.
The original sequence is multiplied by $n$ again.
So the function can be described by $n^3+n^2+n$.
So the final answer is $10^3+10^2+10=1110$.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
add a comment
|
$begingroup$
By noting that each number maps to a multiple of itself:
$3rightarrow3*13$
$1rightarrow1*3$
$4rightarrow4*21$
$5rightarrow5*31$
$2rightarrow2*7$
And that the quotient increases quadratically
$1:3$
$2:7=3+4$
$3:13=7+6$
$4:21=13+8$
$5:31=21+10$
The mapping must be a cubic function.
The above sequence is equal to $n^2+n+1$, where n is the input.
The original sequence is multiplied by $n$ again.
So the function can be described by $n^3+n^2+n$.
So the final answer is $10^3+10^2+10=1110$.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
By noting that each number maps to a multiple of itself:
$3rightarrow3*13$
$1rightarrow1*3$
$4rightarrow4*21$
$5rightarrow5*31$
$2rightarrow2*7$
And that the quotient increases quadratically
$1:3$
$2:7=3+4$
$3:13=7+6$
$4:21=13+8$
$5:31=21+10$
The mapping must be a cubic function.
The above sequence is equal to $n^2+n+1$, where n is the input.
The original sequence is multiplied by $n$ again.
So the function can be described by $n^3+n^2+n$.
So the final answer is $10^3+10^2+10=1110$.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
answered 1 hour ago
Matthew JensenMatthew Jensen
3114 bronze badges
3114 bronze badges
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Matthew Jensen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
add a comment
|
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
It looks like this is it!
$endgroup$
– Duck
1 hour ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
Congratulations
$endgroup$
– Deepthinker101
14 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
$begingroup$
This was the mathematical way to do what I described in words. Congratulations!
$endgroup$
– El-Guest
7 mins ago
add a comment
|
$begingroup$
Note that
1 x 3 = 3 (3 is the 2nd odd positive number)
2 x 7 = 14 (7 is the 4th positive odd number)
3 x 13 = 39 (13 is the 7th positive odd number)
4 x 21 = 84 (21 is the 11th positive odd number)
5 x 31 = 155 (31 is the 16th positive odd number)
Note that
The nth odd number is being used, where n forms a pattern of 2, 4, 7, 11, 16 — ie. differences increase by one. Then to continue this pattern, we have 22, 29, 37, 46, 56 — this sequence is the triangular numbers plus 1. (Note the triangular Numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...)
So then the answer ought to be
10 = 1110, as 111 is the 56th positive odd number and 10 x 111 = 1110.
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
$endgroup$
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
add a comment
|
$begingroup$
Note that
1 x 3 = 3 (3 is the 2nd odd positive number)
2 x 7 = 14 (7 is the 4th positive odd number)
3 x 13 = 39 (13 is the 7th positive odd number)
4 x 21 = 84 (21 is the 11th positive odd number)
5 x 31 = 155 (31 is the 16th positive odd number)
Note that
The nth odd number is being used, where n forms a pattern of 2, 4, 7, 11, 16 — ie. differences increase by one. Then to continue this pattern, we have 22, 29, 37, 46, 56 — this sequence is the triangular numbers plus 1. (Note the triangular Numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...)
So then the answer ought to be
10 = 1110, as 111 is the 56th positive odd number and 10 x 111 = 1110.
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
$endgroup$
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
add a comment
|
$begingroup$
Note that
1 x 3 = 3 (3 is the 2nd odd positive number)
2 x 7 = 14 (7 is the 4th positive odd number)
3 x 13 = 39 (13 is the 7th positive odd number)
4 x 21 = 84 (21 is the 11th positive odd number)
5 x 31 = 155 (31 is the 16th positive odd number)
Note that
The nth odd number is being used, where n forms a pattern of 2, 4, 7, 11, 16 — ie. differences increase by one. Then to continue this pattern, we have 22, 29, 37, 46, 56 — this sequence is the triangular numbers plus 1. (Note the triangular Numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...)
So then the answer ought to be
10 = 1110, as 111 is the 56th positive odd number and 10 x 111 = 1110.
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
$endgroup$
Note that
1 x 3 = 3 (3 is the 2nd odd positive number)
2 x 7 = 14 (7 is the 4th positive odd number)
3 x 13 = 39 (13 is the 7th positive odd number)
4 x 21 = 84 (21 is the 11th positive odd number)
5 x 31 = 155 (31 is the 16th positive odd number)
Note that
The nth odd number is being used, where n forms a pattern of 2, 4, 7, 11, 16 — ie. differences increase by one. Then to continue this pattern, we have 22, 29, 37, 46, 56 — this sequence is the triangular numbers plus 1. (Note the triangular Numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55...)
So then the answer ought to be
10 = 1110, as 111 is the 56th positive odd number and 10 x 111 = 1110.
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
edited 8 mins ago
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
answered 8 hours ago
El-GuestEl-Guest
26.4k3 gold badges63 silver badges108 bronze badges
26.4k3 gold badges63 silver badges108 bronze badges
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
add a comment
|
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
You are probably on the right track, but maybe insisting on primes isn't necessary?
$endgroup$
– Bass
5 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
Yes, it looks like you’re right — this fits better I think. Thanks for the heads up, @Bass
$endgroup$
– El-Guest
4 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
No not the right answer
$endgroup$
– Deepthinker101
2 hours ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
$begingroup$
As it turns out, my process IS right, I’m just a dumdum.
$endgroup$
– El-Guest
8 mins ago
add a comment
|
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