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How can I remove rest of file from string for all files?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;

4

1

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Input file 2.

ccc
aergddd
dasdvsdb

Output file 1.

aaa
bbb
ccc
ddfbbd 

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited 7 hours ago

αғsнιη

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asked 8 hours ago

genderbeegenderbee

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add a comment
 | 

4

1

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Input file 2.

ccc
aergddd
dasdvsdb

Output file 1.

aaa
bbb
ccc
ddfbbd 

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

add a comment
 | 

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Input file 2.

ccc
aergddd
dasdvsdb

Output file 1.

aaa
bbb
ccc
ddfbbd 

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

aaa
bbb
ccc
ddfbbd dddaaa
eee

ccc
aergddd
dasdvsdb

aaa
bbb
ccc
ddfbbd 

ccc
aerg

share|improve this question

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

share|improve this question

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

edited 7 hours ago

αғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

asked 8 hours ago

genderbeegenderbee

14077 bronze badges

3 Answers
3

active

oldest

votes

6

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited 7 hours ago

dessert

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answered 7 hours ago

glenn jackmanglenn jackman

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add a comment
 | 

2

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

share|improve this answer

answered 7 hours ago

αғsнιηαғsнιη

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add a comment
 | 

2

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

• -i: modify the file in-place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.

More about Perl flags can be found here.

share|improve this answer

edited 6 hours ago

dessert

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answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, so a true equivalent would be [Nn]* – nice, thanks!
  
  – dessert
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  1 hour ago
  

  
  
  
  

add a comment
 | 

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6

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited 7 hours ago

dessert

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answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

add a comment
 | 

6

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited 7 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

add a comment
 | 

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited 7 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

share|improve this answer

edited 7 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

edited 7 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

edited 7 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

answered 7 hours ago

glenn jackmanglenn jackman

13.3k2626 silver badges4646 bronze badges

2

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

share|improve this answer

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

add a comment
 | 

2

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

share|improve this answer

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

add a comment
 | 

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

share|improve this answer

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

share|improve this answer

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

answered 7 hours ago

αғsнιηαғsнιη

25.9k2323 gold badges105105 silver badges167167 bronze badges

2

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

• -i: modify the file in-place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.

More about Perl flags can be found here.

share|improve this answer

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, so a true equivalent would be [Nn]* – nice, thanks!
  
  – dessert
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  1 hour ago
  

  
  
  
  

add a comment
 | 

2

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

• -i: modify the file in-place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.

More about Perl flags can be found here.

share|improve this answer

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, so a true equivalent would be [Nn]* – nice, thanks!
  
  – dessert
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  1 hour ago
  

  
  
  
  

add a comment
 | 

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

• -i: modify the file in-place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.

More about Perl flags can be found here.

share|improve this answer

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

perl -i -0777 -pe 's/ddd[sS]*//' file

share|improve this answer

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

edited 6 hours ago

dessert

29.2k77 gold badges8787 silver badges121121 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges

answered 6 hours ago

user3140225user3140225

2,16688 silver badges2222 bronze badges