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How is the 'rate law' and 'order' for the ozone decomposition reaction can be defined?

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2

$begingroup$

How is the 'rate law' and 'order' for the following reaction can be defined?

$$ce2O3 -> 3O2$$

"The expression that correlates the rate of reaction with concentration of reactants is known as rate law for that reaction."
So the rate law only include the concentration of reactants, not products.
But the rate law for this reaction is:

$$r = k[ceO3]^2[ceO2]^-1$$

where $k$ is rate constant.

"Order of a reaction is the number of reactant molecules whose concentration determines the rate expression."

Order for this reaction w.r.t. ozone is 2 and that w.r.t. oxygen is -1. But why we are considering oxygen, being a product of this irreversible reaction. This also means that the rate of this reaction will decrease with the increase in concentration of oxygen.

Now it seems that, this is a reversible reaction. But chemical kinetics is studied for only irreversible reaction?

physical-chemistry kinetics

share|improve this question

edited 9 hours ago

andselisk♦

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asked 9 hours ago

ApurvaApurva

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$endgroup$

add a comment | 

2

$begingroup$

How is the 'rate law' and 'order' for the following reaction can be defined?

$$ce2O3 -> 3O2$$

"The expression that correlates the rate of reaction with concentration of reactants is known as rate law for that reaction."
So the rate law only include the concentration of reactants, not products.
But the rate law for this reaction is:

$$r = k[ceO3]^2[ceO2]^-1$$

where $k$ is rate constant.

"Order of a reaction is the number of reactant molecules whose concentration determines the rate expression."

Order for this reaction w.r.t. ozone is 2 and that w.r.t. oxygen is -1. But why we are considering oxygen, being a product of this irreversible reaction. This also means that the rate of this reaction will decrease with the increase in concentration of oxygen.

Now it seems that, this is a reversible reaction. But chemical kinetics is studied for only irreversible reaction?

physical-chemistry kinetics

share|improve this question

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

$endgroup$

add a comment | 

$begingroup$

How is the 'rate law' and 'order' for the following reaction can be defined?

$$ce2O3 -> 3O2$$

"The expression that correlates the rate of reaction with concentration of reactants is known as rate law for that reaction."
So the rate law only include the concentration of reactants, not products.
But the rate law for this reaction is:

$$r = k[ceO3]^2[ceO2]^-1$$

where $k$ is rate constant.

"Order of a reaction is the number of reactant molecules whose concentration determines the rate expression."

Order for this reaction w.r.t. ozone is 2 and that w.r.t. oxygen is -1. But why we are considering oxygen, being a product of this irreversible reaction. This also means that the rate of this reaction will decrease with the increase in concentration of oxygen.

Now it seems that, this is a reversible reaction. But chemical kinetics is studied for only irreversible reaction?

physical-chemistry kinetics

share|improve this question

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

$endgroup$

share|improve this question

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

share|improve this question

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

edited 9 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

asked 9 hours ago

ApurvaApurva

7444 bronze badges

1 Answer
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4

$begingroup$

Chemical kinetic describes both reversible and irreversible reactions.

The reaction scheme and rate expression do not refer to the same thing. The reaction scheme is an overall one whereas the rate equation refers to a particular multi-step reaction. Two examples are given below:

Ozone can be destroyed by UV light in the $240$ to $pu320 nm$ region with the scheme $(ceM$ is an inert gas needed to take away excess energy):

$$
beginalign
ceO3 &->[$hν$] O2 + O \
ceO3 + O + M &-> O2 + O2 + M \
hline
ce2 O3 &-> 3 O2
endalign
$$

Similarly, oxygen molecules can react with short wavelength UV as

$$
beginalign
ceO2 &->[$hν$][$(<pu242 nm)$] O + O & \
ceO + O2 + M &-> O3 + M &|cdot 2 \
hline
ce3 O2 &-> 2 O3
endalign
$$

which also gives a similar net reaction. This is the Chapman mechanism and is very important in atmospheric chemistry.

share|improve this answer

edited 6 hours ago

andselisk♦

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answered 6 hours ago

porphyrinporphyrin

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$endgroup$

add a comment | 

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4

$begingroup$

Chemical kinetic describes both reversible and irreversible reactions.

The reaction scheme and rate expression do not refer to the same thing. The reaction scheme is an overall one whereas the rate equation refers to a particular multi-step reaction. Two examples are given below:

Ozone can be destroyed by UV light in the $240$ to $pu320 nm$ region with the scheme $(ceM$ is an inert gas needed to take away excess energy):

$$
beginalign
ceO3 &->[$hν$] O2 + O \
ceO3 + O + M &-> O2 + O2 + M \
hline
ce2 O3 &-> 3 O2
endalign
$$

Similarly, oxygen molecules can react with short wavelength UV as

$$
beginalign
ceO2 &->[$hν$][$(<pu242 nm)$] O + O & \
ceO + O2 + M &-> O3 + M &|cdot 2 \
hline
ce3 O2 &-> 2 O3
endalign
$$

which also gives a similar net reaction. This is the Chapman mechanism and is very important in atmospheric chemistry.

share|improve this answer

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges

$endgroup$

add a comment | 

4

$begingroup$

Chemical kinetic describes both reversible and irreversible reactions.

The reaction scheme and rate expression do not refer to the same thing. The reaction scheme is an overall one whereas the rate equation refers to a particular multi-step reaction. Two examples are given below:

Ozone can be destroyed by UV light in the $240$ to $pu320 nm$ region with the scheme $(ceM$ is an inert gas needed to take away excess energy):

$$
beginalign
ceO3 &->[$hν$] O2 + O \
ceO3 + O + M &-> O2 + O2 + M \
hline
ce2 O3 &-> 3 O2
endalign
$$

Similarly, oxygen molecules can react with short wavelength UV as

$$
beginalign
ceO2 &->[$hν$][$(<pu242 nm)$] O + O & \
ceO + O2 + M &-> O3 + M &|cdot 2 \
hline
ce3 O2 &-> 2 O3
endalign
$$

which also gives a similar net reaction. This is the Chapman mechanism and is very important in atmospheric chemistry.

share|improve this answer

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges

$endgroup$

add a comment | 

$begingroup$

Chemical kinetic describes both reversible and irreversible reactions.

The reaction scheme and rate expression do not refer to the same thing. The reaction scheme is an overall one whereas the rate equation refers to a particular multi-step reaction. Two examples are given below:

Ozone can be destroyed by UV light in the $240$ to $pu320 nm$ region with the scheme $(ceM$ is an inert gas needed to take away excess energy):

$$
beginalign
ceO3 &->[$hν$] O2 + O \
ceO3 + O + M &-> O2 + O2 + M \
hline
ce2 O3 &-> 3 O2
endalign
$$

Similarly, oxygen molecules can react with short wavelength UV as

$$
beginalign
ceO2 &->[$hν$][$(<pu242 nm)$] O + O & \
ceO + O2 + M &-> O3 + M &|cdot 2 \
hline
ce3 O2 &-> 2 O3
endalign
$$

which also gives a similar net reaction. This is the Chapman mechanism and is very important in atmospheric chemistry.

share|improve this answer

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges

$endgroup$

share|improve this answer

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

edited 6 hours ago

andselisk♦

21.6k77 gold badges7575 silver badges144144 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges

answered 6 hours ago

porphyrinporphyrin

19.3k11 gold badge3333 silver badges5959 bronze badges