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Confused with atmospheric pressure equals plastic balloon’s inner pressure
Get an intuition for pressure valuesThe relation between Internal Pressure and flow rate in a balloonHow can a small volume of gas balance the pressure exerted by the whole atmosphere?The Balloon Model for Human VentilationWhy a balloon explodes by itself?Boyle's Law-$ PV= nRT.$ What equation should be used to find pressure if n is not constant, like in an elastic system?Atmospheric pressure changes on plastic bottle containing a liquidCan a balloon be inflated with electrons?Which balloon has the higher pressure and why?About a balloon in a balloon in a balloon in a balloon in a balloon
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science
New contributor
$endgroup$
add a comment |
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science
New contributor
$endgroup$
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago
add a comment |
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science
New contributor
$endgroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science
pressure atmospheric-science
New contributor
New contributor
New contributor
asked 8 hours ago
panic attackpanic attack
1061
1061
New contributor
New contributor
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago
add a comment |
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago
add a comment |
4 Answers
4
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votes
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
$endgroup$
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Hope this helps.
$endgroup$
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
New contributor
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add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
$endgroup$
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
add a comment |
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
$endgroup$
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
add a comment |
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
$endgroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered 8 hours ago
tparkertparker
24.6k151133
24.6k151133
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
add a comment |
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
6 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Hope this helps.
$endgroup$
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Hope this helps.
$endgroup$
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Hope this helps.
$endgroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Hope this helps.
answered 8 hours ago
Bob DBob D
7,6393626
7,6393626
add a comment |
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
New contributor
$endgroup$
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
New contributor
$endgroup$
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
New contributor
$endgroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
New contributor
New contributor
answered 2 hours ago
Adrian HowardAdrian Howard
625
625
New contributor
New contributor
add a comment |
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
$endgroup$
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
$endgroup$
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
$endgroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered 8 hours ago
Solar MikeSolar Mike
23216
23216
add a comment |
add a comment |
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
1 hour ago