Show that there exists an integer that is a power of 5 with the first 4 digits being 2018.Given $2^x=129$, why is it that I can use the natural logarithm to find $x$?Satisfying equality between logarithmic expressionsDividing logarithms without using a calculatorIf $a=blog b$, how does $b$ grow asymptotically?So many logs with different basesComparing functions that have logs in exponentsHow to show that $- log_b x = log_frac1b x$Taking log of a matrix equationhow to simplify a quadratic logarithmic equation equation?

Writing a love interest for my hero

Starring Samurais - Several Scribbled Short Stories

Character theory and Quantum Chemistry

What are the advantages and disadvantages of Preprints.org compared with arXiv?

SQL Server table with 4,000,000 rows is 40GB

What's the biggest difference between these two photos?

RP Automatic Updates

How to progress with CPLEX/Gurobi

Can i say "I will encrypt something" if i hash something?

Where does the expression "triple-A" comes from?

Have there been any countries that voted themselves out of existence?

How much power do LED smart bulb wireless control systems consume when the light is turned off?

Job offer without any details but asking me to withdraw other applications - is it normal?

What is this dollar sign ($) icon in my Menu Bar?

I see your BIDMAS and raise you a BADMIS

Is there a star over my head?

I changed a word from a source, how do I cite it correctly?

Could the government trigger by-elections to regain a majority?

What happens when a caster loses concentration on a banished creature?

Two different colors in an Illustrator stroke / line

Is there a "right" way to interpret a novel? If so, how do we make sure our novel is interpreted correctly?

Why should I always enable compiler warnings?

How can I protect myself in case of a human attack like the murders of the hikers Jespersen and Ueland in Morocco?

How to create a list of dictionaries from a dictionary with lists of different lengths



Show that there exists an integer that is a power of 5 with the first 4 digits being 2018.


Given $2^x=129$, why is it that I can use the natural logarithm to find $x$?Satisfying equality between logarithmic expressionsDividing logarithms without using a calculatorIf $a=blog b$, how does $b$ grow asymptotically?So many logs with different basesComparing functions that have logs in exponentsHow to show that $- log_b x = log_frac1b x$Taking log of a matrix equationhow to simplify a quadratic logarithmic equation equation?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5












$begingroup$


I know the problem can be expressed in the following way. Let $a,b in mathbbZ^+$ such that $2018:times:10^b < 5^a < 2019:times:10^b$



Taking logs, I get $b + log 2018 < a log 5< b + log 2019$.



Not quite sure how else to proceed though.










share|cite|improve this question









$endgroup$













  • $begingroup$
    Note: $5^92=2019....$
    $endgroup$
    – J. W. Tanner
    10 hours ago






  • 5




    $begingroup$
    $5^4364=2.018826153906575ldotscdot 10^3050$.
    $endgroup$
    – Christian Blatter
    10 hours ago


















5












$begingroup$


I know the problem can be expressed in the following way. Let $a,b in mathbbZ^+$ such that $2018:times:10^b < 5^a < 2019:times:10^b$



Taking logs, I get $b + log 2018 < a log 5< b + log 2019$.



Not quite sure how else to proceed though.










share|cite|improve this question









$endgroup$













  • $begingroup$
    Note: $5^92=2019....$
    $endgroup$
    – J. W. Tanner
    10 hours ago






  • 5




    $begingroup$
    $5^4364=2.018826153906575ldotscdot 10^3050$.
    $endgroup$
    – Christian Blatter
    10 hours ago














5












5








5


2



$begingroup$


I know the problem can be expressed in the following way. Let $a,b in mathbbZ^+$ such that $2018:times:10^b < 5^a < 2019:times:10^b$



Taking logs, I get $b + log 2018 < a log 5< b + log 2019$.



Not quite sure how else to proceed though.










share|cite|improve this question









$endgroup$




I know the problem can be expressed in the following way. Let $a,b in mathbbZ^+$ such that $2018:times:10^b < 5^a < 2019:times:10^b$



Taking logs, I get $b + log 2018 < a log 5< b + log 2019$.



Not quite sure how else to proceed though.







logarithms






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 10 hours ago









Haikal YeoHaikal Yeo

1,0638 silver badges23 bronze badges




1,0638 silver badges23 bronze badges














  • $begingroup$
    Note: $5^92=2019....$
    $endgroup$
    – J. W. Tanner
    10 hours ago






  • 5




    $begingroup$
    $5^4364=2.018826153906575ldotscdot 10^3050$.
    $endgroup$
    – Christian Blatter
    10 hours ago

















  • $begingroup$
    Note: $5^92=2019....$
    $endgroup$
    – J. W. Tanner
    10 hours ago






  • 5




    $begingroup$
    $5^4364=2.018826153906575ldotscdot 10^3050$.
    $endgroup$
    – Christian Blatter
    10 hours ago
















$begingroup$
Note: $5^92=2019....$
$endgroup$
– J. W. Tanner
10 hours ago




$begingroup$
Note: $5^92=2019....$
$endgroup$
– J. W. Tanner
10 hours ago




5




5




$begingroup$
$5^4364=2.018826153906575ldotscdot 10^3050$.
$endgroup$
– Christian Blatter
10 hours ago





$begingroup$
$5^4364=2.018826153906575ldotscdot 10^3050$.
$endgroup$
– Christian Blatter
10 hours ago











3 Answers
3






active

oldest

votes


















2














$begingroup$

The set $A = a log_10 5 + b : a,b in mathbb Z $ is an additive subgroup of $mathbb R$, and so is either cyclic or dense.



If $A$ were cyclic, then $1 = n (a_0 log_10 5 + b_0)$. Since $log_10 5$ is irrational, we must have $n a_0 =0$ and $n b_0 = 1$, which cannot happen.



Therefore, $A$ is dense and so there is an element of $A$ in the interval $(log_10(2018), log_10(2019))$.






share|cite|improve this answer









$endgroup$














  • $begingroup$
    But what if $a <0$? ;)
    $endgroup$
    – N. S.
    20 mins ago



















8














$begingroup$

Hint Since $log_10(5)$ is irrational, the set $ a log_10(5)-b : a, b in mathbb N$ is dense in $mathbb R$. Therefore, you can find such a number in the interval $(log_10(2018), log_10(2019))$.






share|cite|improve this answer









$endgroup$






















    -4














    $begingroup$

    201882615390657491958528733888359303897206738410754045263963565695705442119457224168899440239407953138581226299365782567442925725493850667127823188129261463991440173793523996779651936654389368686597194439736208695989862156299629602332523464076512669290731774513558552819180354651303963581641490360308535552425419867299337653389070510045424468908107895566363643482640162372352948553283421340038905458554369108404396575106064121414101960663718546239386527523409161552124792218268239338974867937280489575854266372435173446464066145926791484234116593481699639727998774125414871721332982942016722814109084246332819815465119939678154783718052333181096038896636579784807212135999682794464880561777058643610122484366550692964046735317370672168782581592297953410438100999375161197662519910850059633016528523568042285302742062098814548246723733888013653327016324124727737686998618632277442820374655493093729902407403246796933589232379520684294387357381354286158732655143619009740514672918111683766211391182403531198532559980151972513489907217185072196731637657634674068559899298805500983571984624086190968818017889989749154302003358764408667797989976730972834651878998380425225936897264605310688663029535576600866502864768965770091351971521995641025227860905919121596849003861094298243892705486363508792818416683489930886591576035182909921868555205172091169698191585767546957494046847024226730833257159854651007706945782566951387958682409697454133730086314492661919431019883237423708525758459729006177183221902634043244036721957840616924771617991861189108596959612503053521704057188513232970211432467080796220044513875134615739794385874670476886205780889353138817697126168129565683692421875294802472389184825853664308097076451463513926649779788130377406299829608329206810680213500593258029567966685039842829425254271550324266936497912430799186821435764991658842175752107255972699604608610838678647922991780897811201255157892448118302260686546980422098465087256649477365011881596878199059608414801013417027677837816041537974933022551966344978889501537172467203506670958637174099226979184380737481324329743693108262765896755437598412730342468865474573477004619362456714144985785078817902129543526158982694832379771931581941839225962375548217493133113050127913932315166413560509241349541568784192095222792848694381349868462030138524690958834727087880318746593234222439280165442150519813234371751409660250721132893912068388675454902832327537395026029852373100586738988362442544910516664069691179659777362156805235491174484504759330371215949360906031780262687660002512614551478392076625118081138080259140457229066530352113989013066692570397437773702413957231955020804389634415750498870634142816046788045672568297485242527508630207469164390742003932759774267358556602879306918807555750836800249985550904087271797537215843856934114642382854402532562504961847107385321625601211533133161511192639301728105746220687191517987404378034935607228167440448968116089808516638097060020070846318846918229693351291405338045145821917930096557614039198824684717692434787750244140625 = 5 ^ 4346






    share|cite|improve this answer










    New contributor



    andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    $endgroup$










    • 2




      $begingroup$
      While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
      $endgroup$
      – Ispil
      38 mins ago













    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "69"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/4.0/"u003ecc by-sa 4.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );














    draft saved

    draft discarded
















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3349550%2fshow-that-there-exists-an-integer-that-is-a-power-of-5-with-the-first-4-digits-b%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    $begingroup$

    The set $A = a log_10 5 + b : a,b in mathbb Z $ is an additive subgroup of $mathbb R$, and so is either cyclic or dense.



    If $A$ were cyclic, then $1 = n (a_0 log_10 5 + b_0)$. Since $log_10 5$ is irrational, we must have $n a_0 =0$ and $n b_0 = 1$, which cannot happen.



    Therefore, $A$ is dense and so there is an element of $A$ in the interval $(log_10(2018), log_10(2019))$.






    share|cite|improve this answer









    $endgroup$














    • $begingroup$
      But what if $a <0$? ;)
      $endgroup$
      – N. S.
      20 mins ago
















    2














    $begingroup$

    The set $A = a log_10 5 + b : a,b in mathbb Z $ is an additive subgroup of $mathbb R$, and so is either cyclic or dense.



    If $A$ were cyclic, then $1 = n (a_0 log_10 5 + b_0)$. Since $log_10 5$ is irrational, we must have $n a_0 =0$ and $n b_0 = 1$, which cannot happen.



    Therefore, $A$ is dense and so there is an element of $A$ in the interval $(log_10(2018), log_10(2019))$.






    share|cite|improve this answer









    $endgroup$














    • $begingroup$
      But what if $a <0$? ;)
      $endgroup$
      – N. S.
      20 mins ago














    2














    2










    2







    $begingroup$

    The set $A = a log_10 5 + b : a,b in mathbb Z $ is an additive subgroup of $mathbb R$, and so is either cyclic or dense.



    If $A$ were cyclic, then $1 = n (a_0 log_10 5 + b_0)$. Since $log_10 5$ is irrational, we must have $n a_0 =0$ and $n b_0 = 1$, which cannot happen.



    Therefore, $A$ is dense and so there is an element of $A$ in the interval $(log_10(2018), log_10(2019))$.






    share|cite|improve this answer









    $endgroup$



    The set $A = a log_10 5 + b : a,b in mathbb Z $ is an additive subgroup of $mathbb R$, and so is either cyclic or dense.



    If $A$ were cyclic, then $1 = n (a_0 log_10 5 + b_0)$. Since $log_10 5$ is irrational, we must have $n a_0 =0$ and $n b_0 = 1$, which cannot happen.



    Therefore, $A$ is dense and so there is an element of $A$ in the interval $(log_10(2018), log_10(2019))$.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 9 hours ago









    lhflhf

    174k12 gold badges179 silver badges418 bronze badges




    174k12 gold badges179 silver badges418 bronze badges














    • $begingroup$
      But what if $a <0$? ;)
      $endgroup$
      – N. S.
      20 mins ago

















    • $begingroup$
      But what if $a <0$? ;)
      $endgroup$
      – N. S.
      20 mins ago
















    $begingroup$
    But what if $a <0$? ;)
    $endgroup$
    – N. S.
    20 mins ago





    $begingroup$
    But what if $a <0$? ;)
    $endgroup$
    – N. S.
    20 mins ago














    8














    $begingroup$

    Hint Since $log_10(5)$ is irrational, the set $ a log_10(5)-b : a, b in mathbb N$ is dense in $mathbb R$. Therefore, you can find such a number in the interval $(log_10(2018), log_10(2019))$.






    share|cite|improve this answer









    $endgroup$



















      8














      $begingroup$

      Hint Since $log_10(5)$ is irrational, the set $ a log_10(5)-b : a, b in mathbb N$ is dense in $mathbb R$. Therefore, you can find such a number in the interval $(log_10(2018), log_10(2019))$.






      share|cite|improve this answer









      $endgroup$

















        8














        8










        8







        $begingroup$

        Hint Since $log_10(5)$ is irrational, the set $ a log_10(5)-b : a, b in mathbb N$ is dense in $mathbb R$. Therefore, you can find such a number in the interval $(log_10(2018), log_10(2019))$.






        share|cite|improve this answer









        $endgroup$



        Hint Since $log_10(5)$ is irrational, the set $ a log_10(5)-b : a, b in mathbb N$ is dense in $mathbb R$. Therefore, you can find such a number in the interval $(log_10(2018), log_10(2019))$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 10 hours ago









        N. S.N. S.

        109k7 gold badges118 silver badges215 bronze badges




        109k7 gold badges118 silver badges215 bronze badges
























            -4














            $begingroup$

            201882615390657491958528733888359303897206738410754045263963565695705442119457224168899440239407953138581226299365782567442925725493850667127823188129261463991440173793523996779651936654389368686597194439736208695989862156299629602332523464076512669290731774513558552819180354651303963581641490360308535552425419867299337653389070510045424468908107895566363643482640162372352948553283421340038905458554369108404396575106064121414101960663718546239386527523409161552124792218268239338974867937280489575854266372435173446464066145926791484234116593481699639727998774125414871721332982942016722814109084246332819815465119939678154783718052333181096038896636579784807212135999682794464880561777058643610122484366550692964046735317370672168782581592297953410438100999375161197662519910850059633016528523568042285302742062098814548246723733888013653327016324124727737686998618632277442820374655493093729902407403246796933589232379520684294387357381354286158732655143619009740514672918111683766211391182403531198532559980151972513489907217185072196731637657634674068559899298805500983571984624086190968818017889989749154302003358764408667797989976730972834651878998380425225936897264605310688663029535576600866502864768965770091351971521995641025227860905919121596849003861094298243892705486363508792818416683489930886591576035182909921868555205172091169698191585767546957494046847024226730833257159854651007706945782566951387958682409697454133730086314492661919431019883237423708525758459729006177183221902634043244036721957840616924771617991861189108596959612503053521704057188513232970211432467080796220044513875134615739794385874670476886205780889353138817697126168129565683692421875294802472389184825853664308097076451463513926649779788130377406299829608329206810680213500593258029567966685039842829425254271550324266936497912430799186821435764991658842175752107255972699604608610838678647922991780897811201255157892448118302260686546980422098465087256649477365011881596878199059608414801013417027677837816041537974933022551966344978889501537172467203506670958637174099226979184380737481324329743693108262765896755437598412730342468865474573477004619362456714144985785078817902129543526158982694832379771931581941839225962375548217493133113050127913932315166413560509241349541568784192095222792848694381349868462030138524690958834727087880318746593234222439280165442150519813234371751409660250721132893912068388675454902832327537395026029852373100586738988362442544910516664069691179659777362156805235491174484504759330371215949360906031780262687660002512614551478392076625118081138080259140457229066530352113989013066692570397437773702413957231955020804389634415750498870634142816046788045672568297485242527508630207469164390742003932759774267358556602879306918807555750836800249985550904087271797537215843856934114642382854402532562504961847107385321625601211533133161511192639301728105746220687191517987404378034935607228167440448968116089808516638097060020070846318846918229693351291405338045145821917930096557614039198824684717692434787750244140625 = 5 ^ 4346






            share|cite|improve this answer










            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$










            • 2




              $begingroup$
              While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
              $endgroup$
              – Ispil
              38 mins ago















            -4














            $begingroup$

            201882615390657491958528733888359303897206738410754045263963565695705442119457224168899440239407953138581226299365782567442925725493850667127823188129261463991440173793523996779651936654389368686597194439736208695989862156299629602332523464076512669290731774513558552819180354651303963581641490360308535552425419867299337653389070510045424468908107895566363643482640162372352948553283421340038905458554369108404396575106064121414101960663718546239386527523409161552124792218268239338974867937280489575854266372435173446464066145926791484234116593481699639727998774125414871721332982942016722814109084246332819815465119939678154783718052333181096038896636579784807212135999682794464880561777058643610122484366550692964046735317370672168782581592297953410438100999375161197662519910850059633016528523568042285302742062098814548246723733888013653327016324124727737686998618632277442820374655493093729902407403246796933589232379520684294387357381354286158732655143619009740514672918111683766211391182403531198532559980151972513489907217185072196731637657634674068559899298805500983571984624086190968818017889989749154302003358764408667797989976730972834651878998380425225936897264605310688663029535576600866502864768965770091351971521995641025227860905919121596849003861094298243892705486363508792818416683489930886591576035182909921868555205172091169698191585767546957494046847024226730833257159854651007706945782566951387958682409697454133730086314492661919431019883237423708525758459729006177183221902634043244036721957840616924771617991861189108596959612503053521704057188513232970211432467080796220044513875134615739794385874670476886205780889353138817697126168129565683692421875294802472389184825853664308097076451463513926649779788130377406299829608329206810680213500593258029567966685039842829425254271550324266936497912430799186821435764991658842175752107255972699604608610838678647922991780897811201255157892448118302260686546980422098465087256649477365011881596878199059608414801013417027677837816041537974933022551966344978889501537172467203506670958637174099226979184380737481324329743693108262765896755437598412730342468865474573477004619362456714144985785078817902129543526158982694832379771931581941839225962375548217493133113050127913932315166413560509241349541568784192095222792848694381349868462030138524690958834727087880318746593234222439280165442150519813234371751409660250721132893912068388675454902832327537395026029852373100586738988362442544910516664069691179659777362156805235491174484504759330371215949360906031780262687660002512614551478392076625118081138080259140457229066530352113989013066692570397437773702413957231955020804389634415750498870634142816046788045672568297485242527508630207469164390742003932759774267358556602879306918807555750836800249985550904087271797537215843856934114642382854402532562504961847107385321625601211533133161511192639301728105746220687191517987404378034935607228167440448968116089808516638097060020070846318846918229693351291405338045145821917930096557614039198824684717692434787750244140625 = 5 ^ 4346






            share|cite|improve this answer










            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$










            • 2




              $begingroup$
              While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
              $endgroup$
              – Ispil
              38 mins ago













            -4














            -4










            -4







            $begingroup$

            201882615390657491958528733888359303897206738410754045263963565695705442119457224168899440239407953138581226299365782567442925725493850667127823188129261463991440173793523996779651936654389368686597194439736208695989862156299629602332523464076512669290731774513558552819180354651303963581641490360308535552425419867299337653389070510045424468908107895566363643482640162372352948553283421340038905458554369108404396575106064121414101960663718546239386527523409161552124792218268239338974867937280489575854266372435173446464066145926791484234116593481699639727998774125414871721332982942016722814109084246332819815465119939678154783718052333181096038896636579784807212135999682794464880561777058643610122484366550692964046735317370672168782581592297953410438100999375161197662519910850059633016528523568042285302742062098814548246723733888013653327016324124727737686998618632277442820374655493093729902407403246796933589232379520684294387357381354286158732655143619009740514672918111683766211391182403531198532559980151972513489907217185072196731637657634674068559899298805500983571984624086190968818017889989749154302003358764408667797989976730972834651878998380425225936897264605310688663029535576600866502864768965770091351971521995641025227860905919121596849003861094298243892705486363508792818416683489930886591576035182909921868555205172091169698191585767546957494046847024226730833257159854651007706945782566951387958682409697454133730086314492661919431019883237423708525758459729006177183221902634043244036721957840616924771617991861189108596959612503053521704057188513232970211432467080796220044513875134615739794385874670476886205780889353138817697126168129565683692421875294802472389184825853664308097076451463513926649779788130377406299829608329206810680213500593258029567966685039842829425254271550324266936497912430799186821435764991658842175752107255972699604608610838678647922991780897811201255157892448118302260686546980422098465087256649477365011881596878199059608414801013417027677837816041537974933022551966344978889501537172467203506670958637174099226979184380737481324329743693108262765896755437598412730342468865474573477004619362456714144985785078817902129543526158982694832379771931581941839225962375548217493133113050127913932315166413560509241349541568784192095222792848694381349868462030138524690958834727087880318746593234222439280165442150519813234371751409660250721132893912068388675454902832327537395026029852373100586738988362442544910516664069691179659777362156805235491174484504759330371215949360906031780262687660002512614551478392076625118081138080259140457229066530352113989013066692570397437773702413957231955020804389634415750498870634142816046788045672568297485242527508630207469164390742003932759774267358556602879306918807555750836800249985550904087271797537215843856934114642382854402532562504961847107385321625601211533133161511192639301728105746220687191517987404378034935607228167440448968116089808516638097060020070846318846918229693351291405338045145821917930096557614039198824684717692434787750244140625 = 5 ^ 4346






            share|cite|improve this answer










            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$



            201882615390657491958528733888359303897206738410754045263963565695705442119457224168899440239407953138581226299365782567442925725493850667127823188129261463991440173793523996779651936654389368686597194439736208695989862156299629602332523464076512669290731774513558552819180354651303963581641490360308535552425419867299337653389070510045424468908107895566363643482640162372352948553283421340038905458554369108404396575106064121414101960663718546239386527523409161552124792218268239338974867937280489575854266372435173446464066145926791484234116593481699639727998774125414871721332982942016722814109084246332819815465119939678154783718052333181096038896636579784807212135999682794464880561777058643610122484366550692964046735317370672168782581592297953410438100999375161197662519910850059633016528523568042285302742062098814548246723733888013653327016324124727737686998618632277442820374655493093729902407403246796933589232379520684294387357381354286158732655143619009740514672918111683766211391182403531198532559980151972513489907217185072196731637657634674068559899298805500983571984624086190968818017889989749154302003358764408667797989976730972834651878998380425225936897264605310688663029535576600866502864768965770091351971521995641025227860905919121596849003861094298243892705486363508792818416683489930886591576035182909921868555205172091169698191585767546957494046847024226730833257159854651007706945782566951387958682409697454133730086314492661919431019883237423708525758459729006177183221902634043244036721957840616924771617991861189108596959612503053521704057188513232970211432467080796220044513875134615739794385874670476886205780889353138817697126168129565683692421875294802472389184825853664308097076451463513926649779788130377406299829608329206810680213500593258029567966685039842829425254271550324266936497912430799186821435764991658842175752107255972699604608610838678647922991780897811201255157892448118302260686546980422098465087256649477365011881596878199059608414801013417027677837816041537974933022551966344978889501537172467203506670958637174099226979184380737481324329743693108262765896755437598412730342468865474573477004619362456714144985785078817902129543526158982694832379771931581941839225962375548217493133113050127913932315166413560509241349541568784192095222792848694381349868462030138524690958834727087880318746593234222439280165442150519813234371751409660250721132893912068388675454902832327537395026029852373100586738988362442544910516664069691179659777362156805235491174484504759330371215949360906031780262687660002512614551478392076625118081138080259140457229066530352113989013066692570397437773702413957231955020804389634415750498870634142816046788045672568297485242527508630207469164390742003932759774267358556602879306918807555750836800249985550904087271797537215843856934114642382854402532562504961847107385321625601211533133161511192639301728105746220687191517987404378034935607228167440448968116089808516638097060020070846318846918229693351291405338045145821917930096557614039198824684717692434787750244140625 = 5 ^ 4346







            share|cite|improve this answer










            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            share|cite|improve this answer



            share|cite|improve this answer








            edited 16 mins ago





















            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            answered 49 mins ago









            andrew.punnettandrew.punnett

            933 bronze badges




            933 bronze badges




            New contributor



            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.




            New contributor




            andrew.punnett is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.












            • 2




              $begingroup$
              While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
              $endgroup$
              – Ispil
              38 mins ago












            • 2




              $begingroup$
              While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
              $endgroup$
              – Ispil
              38 mins ago







            2




            2




            $begingroup$
            While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
            $endgroup$
            – Ispil
            38 mins ago




            $begingroup$
            While an exact answer does answer the question, exactly how you worked that out would probably be more useful to the person asking the question.
            $endgroup$
            – Ispil
            38 mins ago


















            draft saved

            draft discarded















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3349550%2fshow-that-there-exists-an-integer-that-is-a-power-of-5-with-the-first-4-digits-b%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

            Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

            Tom Holland Mục lục Đầu đời và giáo dục | Sự nghiệp | Cuộc sống cá nhân | Phim tham gia | Giải thưởng và đề cử | Chú thích | Liên kết ngoài | Trình đơn chuyển hướngProfile“Person Details for Thomas Stanley Holland, "England and Wales Birth Registration Index, 1837-2008" — FamilySearch.org”"Meet Tom Holland... the 16-year-old star of The Impossible""Schoolboy actor Tom Holland finds himself in Oscar contention for role in tsunami drama"“Naomi Watts on the Prince William and Harry's reaction to her film about the late Princess Diana”lưu trữ"Holland and Pflueger Are West End's Two New 'Billy Elliots'""I'm so envious of my son, the movie star! British writer Dominic Holland's spent 20 years trying to crack Hollywood - but he's been beaten to it by a very unlikely rival"“Richard and Margaret Povey of Jersey, Channel Islands, UK: Information about Thomas Stanley Holland”"Tom Holland to play Billy Elliot""New Billy Elliot leaving the garage"Billy Elliot the Musical - Tom Holland - Billy"A Tale of four Billys: Tom Holland""The Feel Good Factor""Thames Christian College schoolboys join Myleene Klass for The Feelgood Factor""Government launches £600,000 arts bursaries pilot""BILLY's Chapman, Holland, Gardner & Jackson-Keen Visit Prime Minister""Elton John 'blown away' by Billy Elliot fifth birthday" (video with John's interview and fragments of Holland's performance)"First News interviews Arrietty's Tom Holland"“33rd Critics' Circle Film Awards winners”“National Board of Review Current Awards”Bản gốc"Ron Howard Whaling Tale 'In The Heart Of The Sea' Casts Tom Holland"“'Spider-Man' Finds Tom Holland to Star as New Web-Slinger”lưu trữ“Captain America: Civil War (2016)”“Film Review: ‘Captain America: Civil War’”lưu trữ“‘Captain America: Civil War’ review: Choose your own avenger”lưu trữ“The Lost City of Z reviews”“Sony Pictures and Marvel Studios Find Their 'Spider-Man' Star and Director”“‘Mary Magdalene’, ‘Current War’ & ‘Wind River’ Get 2017 Release Dates From Weinstein”“Lionsgate Unleashing Daisy Ridley & Tom Holland Starrer ‘Chaos Walking’ In Cannes”“PTA's 'Master' Leads Chicago Film Critics Nominations, UPDATED: Houston and Indiana Critics Nominations”“Nominaciones Goya 2013 Telecinco Cinema – ENG”“Jameson Empire Film Awards: Martin Freeman wins best actor for performance in The Hobbit”“34th Annual Young Artist Awards”Bản gốc“Teen Choice Awards 2016—Captain America: Civil War Leads Second Wave of Nominations”“BAFTA Film Award Nominations: ‘La La Land’ Leads Race”“Saturn Awards Nominations 2017: 'Rogue One,' 'Walking Dead' Lead”Tom HollandTom HollandTom HollandTom Hollandmedia.gettyimages.comWorldCat Identities300279794no20130442900000 0004 0355 42791085670554170004732cb16706349t(data)XX5557367