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Can't make parabola without including the tip
Macro to draw a parabola with pgf/TikZExample of matrix node in trees in tikzpictureNumerical conditional within tikz keys?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingExtending a Tikz ParabolaHow to prevent pgf/tikz from drawing a circle as an ellipse when using relative coordinates?How to add additional border on the left and add additional boxes in the right corner with a labelLine up nested tikz enviroments or how to get rid of themSine function in pgfplots and MATLAB. Why are different results obtained?How to invert a parabola bend in TikZ
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I am trying to make an absolute value parabola function with TikZ. When I try to create the right and left sides of the parabola(the ones that would be underneath the x-axis in a normal function) I can't without including a bend underneath the x-axis.
taskbegintikzpicture
draw (-10,0)--(10,0);
draw(0,0) parabola bend(-3,6)(-6,0);
draw(0,0) parabola bend(-3,-6)(2,10);
draw(-6,0) parabola bend(-3,-6)(-8,10);
endtikzpicture
tikz-pgf
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment
|
I am trying to make an absolute value parabola function with TikZ. When I try to create the right and left sides of the parabola(the ones that would be underneath the x-axis in a normal function) I can't without including a bend underneath the x-axis.
taskbegintikzpicture
draw (-10,0)--(10,0);
draw(0,0) parabola bend(-3,6)(-6,0);
draw(0,0) parabola bend(-3,-6)(2,10);
draw(-6,0) parabola bend(-3,-6)(-8,10);
endtikzpicture
tikz-pgf
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment
|
I am trying to make an absolute value parabola function with TikZ. When I try to create the right and left sides of the parabola(the ones that would be underneath the x-axis in a normal function) I can't without including a bend underneath the x-axis.
taskbegintikzpicture
draw (-10,0)--(10,0);
draw(0,0) parabola bend(-3,6)(-6,0);
draw(0,0) parabola bend(-3,-6)(2,10);
draw(-6,0) parabola bend(-3,-6)(-8,10);
endtikzpicture
tikz-pgf
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to make an absolute value parabola function with TikZ. When I try to create the right and left sides of the parabola(the ones that would be underneath the x-axis in a normal function) I can't without including a bend underneath the x-axis.
taskbegintikzpicture
draw (-10,0)--(10,0);
draw(0,0) parabola bend(-3,6)(-6,0);
draw(0,0) parabola bend(-3,-6)(2,10);
draw(-6,0) parabola bend(-3,-6)(-8,10);
endtikzpicture
tikz-pgf
tikz-pgf
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 8 hours ago
DiaWaterBender 4u
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
asked 8 hours ago
DiaWaterBender 4uDiaWaterBender 4u
112 bronze badges
112 bronze badges
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
DiaWaterBender 4u is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment
|
add a comment
|
3 Answers
3
active
oldest
votes
Easiest solution is to draw two parabolas, one upside down, and clip them both to just show the parts above your line:
documentclass[border=3.14,tikz]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
beginscope
clip (-5,0) rectangle (5,6);
draw (-4,6) parabola bend (0,-2) (4,6);
draw (-4,-6) parabola bend (0,2) (4,-6);
endscope
endtikzpicture
enddocument
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
add a comment
|
Another simple solution is use the plot function and define parabola accordingly:
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
draw[semithick, red] plot [domain=-2:2] (2*x,abs(x*x-1));
endtikzpicture
enddocument
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated thanabs(x^2)this would be the correct approach.
– Skillmon
6 hours ago
add a comment
|
This is really just for fun. You can make TikZ reflect the parabola (or anything you draw) at the x axis (say) automatically. This can be done by installing a nonlinear transformation, which is in this case particularly simple.
documentclass[tikz,border=3mm]standalone
usepgfmodulenonlineartransformations
makeatletter
defyreflect%
pgfmathsetmacromyyabs(pgf@y)%
pgf@y=myy pt
begindocument
begintikzpicture
beginscope[transform shape nonlinear=true]
pgftransformnonlinearyreflect
draw (-5,0)--(5,0);
draw (-4,6) parabola bend (0,-2) (4,6);
endscope
endtikzpicture
enddocument
As one can see, there are small gaps, so the solution is not as perfect as Skillmon's solution.
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
add a comment
|
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Easiest solution is to draw two parabolas, one upside down, and clip them both to just show the parts above your line:
documentclass[border=3.14,tikz]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
beginscope
clip (-5,0) rectangle (5,6);
draw (-4,6) parabola bend (0,-2) (4,6);
draw (-4,-6) parabola bend (0,2) (4,-6);
endscope
endtikzpicture
enddocument
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
add a comment
|
Easiest solution is to draw two parabolas, one upside down, and clip them both to just show the parts above your line:
documentclass[border=3.14,tikz]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
beginscope
clip (-5,0) rectangle (5,6);
draw (-4,6) parabola bend (0,-2) (4,6);
draw (-4,-6) parabola bend (0,2) (4,-6);
endscope
endtikzpicture
enddocument
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
add a comment
|
Easiest solution is to draw two parabolas, one upside down, and clip them both to just show the parts above your line:
documentclass[border=3.14,tikz]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
beginscope
clip (-5,0) rectangle (5,6);
draw (-4,6) parabola bend (0,-2) (4,6);
draw (-4,-6) parabola bend (0,2) (4,-6);
endscope
endtikzpicture
enddocument
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
Easiest solution is to draw two parabolas, one upside down, and clip them both to just show the parts above your line:
documentclass[border=3.14,tikz]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
beginscope
clip (-5,0) rectangle (5,6);
draw (-4,6) parabola bend (0,-2) (4,6);
draw (-4,-6) parabola bend (0,2) (4,-6);
endscope
endtikzpicture
enddocument
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
edited 7 hours ago
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
answered 7 hours ago
SkillmonSkillmon
28.1k1 gold badge28 silver badges59 bronze badges
28.1k1 gold badge28 silver badges59 bronze badges
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
add a comment
|
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
Approved always very simple solutions. Very good.
– Sebastiano
7 hours ago
add a comment
|
Another simple solution is use the plot function and define parabola accordingly:
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
draw[semithick, red] plot [domain=-2:2] (2*x,abs(x*x-1));
endtikzpicture
enddocument
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated thanabs(x^2)this would be the correct approach.
– Skillmon
6 hours ago
add a comment
|
Another simple solution is use the plot function and define parabola accordingly:
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
draw[semithick, red] plot [domain=-2:2] (2*x,abs(x*x-1));
endtikzpicture
enddocument
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated thanabs(x^2)this would be the correct approach.
– Skillmon
6 hours ago
add a comment
|
Another simple solution is use the plot function and define parabola accordingly:
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
draw[semithick, red] plot [domain=-2:2] (2*x,abs(x*x-1));
endtikzpicture
enddocument
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
Another simple solution is use the plot function and define parabola accordingly:
documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture
draw (-5,0)--(5,0);
draw[semithick, red] plot [domain=-2:2] (2*x,abs(x*x-1));
endtikzpicture
enddocument
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
answered 6 hours ago
ZarkoZarko
147k8 gold badges84 silver badges194 bronze badges
147k8 gold badges84 silver badges194 bronze badges
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated thanabs(x^2)this would be the correct approach.
– Skillmon
6 hours ago
add a comment
|
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated thanabs(x^2)this would be the correct approach.
– Skillmon
6 hours ago
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated than
abs(x^2) this would be the correct approach.– Skillmon
6 hours ago
This would be much slower, though, and it is dependent on the sample size (in your output one can see kinks in the parabola for instance). For stuff more complicated than
abs(x^2) this would be the correct approach.– Skillmon
6 hours ago
add a comment
|
This is really just for fun. You can make TikZ reflect the parabola (or anything you draw) at the x axis (say) automatically. This can be done by installing a nonlinear transformation, which is in this case particularly simple.
documentclass[tikz,border=3mm]standalone
usepgfmodulenonlineartransformations
makeatletter
defyreflect%
pgfmathsetmacromyyabs(pgf@y)%
pgf@y=myy pt
begindocument
begintikzpicture
beginscope[transform shape nonlinear=true]
pgftransformnonlinearyreflect
draw (-5,0)--(5,0);
draw (-4,6) parabola bend (0,-2) (4,6);
endscope
endtikzpicture
enddocument
As one can see, there are small gaps, so the solution is not as perfect as Skillmon's solution.
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
add a comment
|
This is really just for fun. You can make TikZ reflect the parabola (or anything you draw) at the x axis (say) automatically. This can be done by installing a nonlinear transformation, which is in this case particularly simple.
documentclass[tikz,border=3mm]standalone
usepgfmodulenonlineartransformations
makeatletter
defyreflect%
pgfmathsetmacromyyabs(pgf@y)%
pgf@y=myy pt
begindocument
begintikzpicture
beginscope[transform shape nonlinear=true]
pgftransformnonlinearyreflect
draw (-5,0)--(5,0);
draw (-4,6) parabola bend (0,-2) (4,6);
endscope
endtikzpicture
enddocument
As one can see, there are small gaps, so the solution is not as perfect as Skillmon's solution.
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
add a comment
|
This is really just for fun. You can make TikZ reflect the parabola (or anything you draw) at the x axis (say) automatically. This can be done by installing a nonlinear transformation, which is in this case particularly simple.
documentclass[tikz,border=3mm]standalone
usepgfmodulenonlineartransformations
makeatletter
defyreflect%
pgfmathsetmacromyyabs(pgf@y)%
pgf@y=myy pt
begindocument
begintikzpicture
beginscope[transform shape nonlinear=true]
pgftransformnonlinearyreflect
draw (-5,0)--(5,0);
draw (-4,6) parabola bend (0,-2) (4,6);
endscope
endtikzpicture
enddocument
As one can see, there are small gaps, so the solution is not as perfect as Skillmon's solution.
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
This is really just for fun. You can make TikZ reflect the parabola (or anything you draw) at the x axis (say) automatically. This can be done by installing a nonlinear transformation, which is in this case particularly simple.
documentclass[tikz,border=3mm]standalone
usepgfmodulenonlineartransformations
makeatletter
defyreflect%
pgfmathsetmacromyyabs(pgf@y)%
pgf@y=myy pt
begindocument
begintikzpicture
beginscope[transform shape nonlinear=true]
pgftransformnonlinearyreflect
draw (-5,0)--(5,0);
draw (-4,6) parabola bend (0,-2) (4,6);
endscope
endtikzpicture
enddocument
As one can see, there are small gaps, so the solution is not as perfect as Skillmon's solution.
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
answered 6 hours ago
Schrödinger's catSchrödinger's cat
7,60511 silver badges23 bronze badges
7,60511 silver badges23 bronze badges
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
add a comment
|
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
Please view the picture with 500/100, I feel parabol doesn't cut Ox axis.
– minhthien_2016
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
@minhthien_2016 Yes, this is what is meant by "there are small gaps".
– Schrödinger's cat
4 hours ago
add a comment
|
DiaWaterBender 4u is a new contributor. Be nice, and check out our Code of Conduct.
DiaWaterBender 4u is a new contributor. Be nice, and check out our Code of Conduct.
DiaWaterBender 4u is a new contributor. Be nice, and check out our Code of Conduct.
DiaWaterBender 4u is a new contributor. Be nice, and check out our Code of Conduct.
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