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Grep contents before a colon


Why does adding a colon break this grep pattern?grep command giving errorExtend grep to find a match after the first matchHow to grep-inverse-match and exclude “before” and “after” linesgrep all the lines in a file and write line to a file from the pattern matching pointHow to include everything before Colon in Sed/Grep/…?Grep word within a file then copy the fileTo grep for a word before matching patternExtracting string via grep regex assertionsGrep/Awk for Value Between






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I have a text file on Linux where the contents are like below:



help.helloworld.com:latest.world.com
dev.helloworld.com:latest.world.com


I want to grep the contents before the colon like below:



help.helloworld.com
dev.helloworld.com


How can I do that within the terminal?










share|improve this question









New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

    – Kusalananda
    7 hours ago


















2















I have a text file on Linux where the contents are like below:



help.helloworld.com:latest.world.com
dev.helloworld.com:latest.world.com


I want to grep the contents before the colon like below:



help.helloworld.com
dev.helloworld.com


How can I do that within the terminal?










share|improve this question









New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

    – Kusalananda
    7 hours ago














2












2








2


1






I have a text file on Linux where the contents are like below:



help.helloworld.com:latest.world.com
dev.helloworld.com:latest.world.com


I want to grep the contents before the colon like below:



help.helloworld.com
dev.helloworld.com


How can I do that within the terminal?










share|improve this question









New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have a text file on Linux where the contents are like below:



help.helloworld.com:latest.world.com
dev.helloworld.com:latest.world.com


I want to grep the contents before the colon like below:



help.helloworld.com
dev.helloworld.com


How can I do that within the terminal?







text-processing grep






share|improve this question









New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 8 hours ago









terdon

141k34 gold badges290 silver badges469 bronze badges




141k34 gold badges290 silver badges469 bronze badges






New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 8 hours ago









Gabrial JohnasGabrial Johnas

1173 bronze badges




1173 bronze badges




New contributor



Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Gabrial Johnas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

    – Kusalananda
    7 hours ago


















  • The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

    – Kusalananda
    7 hours ago

















The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

– Kusalananda
7 hours ago






The grep utility is used for looking for lines matching regular expressions. You could possibly use it here, but it would be more appropriate to use a tool that extracts data from fields given some delimiter, such as the cut utility.

– Kusalananda
7 hours ago











4 Answers
4






active

oldest

votes


















1
















Requires GNU grep. It would not work with the default grep on
e.g. macOS or any of the other BSDs.




Do you mean like this:



grep -oP '.*(?=:)' file


Output:



help.helloworld.com
dev.helloworld.com





share|improve this answer






















  • 2





    If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

    – terdon
    7 hours ago











  • there is only one colon and its working fine , but thanks for the update

    – Gabrial Johnas
    7 hours ago






  • 2





    Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

    – Kusalananda
    7 hours ago











  • @Kusalananda I edited the question adding your observation.

    – guillermo chamorro
    7 hours ago


















6















Or an alternative:



$ grep -o '^[^:]*' file
help.helloworld.com
dev.helloworld.com


This returns any characters beginning at the start of each line (^) which are no colons ([^:]*).






share|improve this answer
































    6















    Would definitely recommend awk:



    awk -F ':' 'print $1' file


    Uses : as a field separator and prints the first field.






    share|improve this answer
































      5















      This is what cut is for:



      $ cat file
      help.helloworld.com:latest.world.com
      dev.helloworld.com:latest.world.com
      foo:baz:bar
      foo

      $ cut -d: -f1 file
      help.helloworld.com
      dev.helloworld.com
      foo
      foo


      You just set the delimiter to : with -d: and tell it to only print the 1st field (-f1).






      share|improve this answer



























        Your Answer








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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1
















        Requires GNU grep. It would not work with the default grep on
        e.g. macOS or any of the other BSDs.




        Do you mean like this:



        grep -oP '.*(?=:)' file


        Output:



        help.helloworld.com
        dev.helloworld.com





        share|improve this answer






















        • 2





          If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

          – terdon
          7 hours ago











        • there is only one colon and its working fine , but thanks for the update

          – Gabrial Johnas
          7 hours ago






        • 2





          Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

          – Kusalananda
          7 hours ago











        • @Kusalananda I edited the question adding your observation.

          – guillermo chamorro
          7 hours ago















        1
















        Requires GNU grep. It would not work with the default grep on
        e.g. macOS or any of the other BSDs.




        Do you mean like this:



        grep -oP '.*(?=:)' file


        Output:



        help.helloworld.com
        dev.helloworld.com





        share|improve this answer






















        • 2





          If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

          – terdon
          7 hours ago











        • there is only one colon and its working fine , but thanks for the update

          – Gabrial Johnas
          7 hours ago






        • 2





          Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

          – Kusalananda
          7 hours ago











        • @Kusalananda I edited the question adding your observation.

          – guillermo chamorro
          7 hours ago













        1














        1










        1










        Requires GNU grep. It would not work with the default grep on
        e.g. macOS or any of the other BSDs.




        Do you mean like this:



        grep -oP '.*(?=:)' file


        Output:



        help.helloworld.com
        dev.helloworld.com





        share|improve this answer
















        Requires GNU grep. It would not work with the default grep on
        e.g. macOS or any of the other BSDs.




        Do you mean like this:



        grep -oP '.*(?=:)' file


        Output:



        help.helloworld.com
        dev.helloworld.com






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 7 hours ago

























        answered 8 hours ago









        guillermo chamorroguillermo chamorro

        6231 silver badge12 bronze badges




        6231 silver badge12 bronze badges










        • 2





          If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

          – terdon
          7 hours ago











        • there is only one colon and its working fine , but thanks for the update

          – Gabrial Johnas
          7 hours ago






        • 2





          Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

          – Kusalananda
          7 hours ago











        • @Kusalananda I edited the question adding your observation.

          – guillermo chamorro
          7 hours ago












        • 2





          If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

          – terdon
          7 hours ago











        • there is only one colon and its working fine , but thanks for the update

          – Gabrial Johnas
          7 hours ago






        • 2





          Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

          – Kusalananda
          7 hours ago











        • @Kusalananda I edited the question adding your observation.

          – guillermo chamorro
          7 hours ago







        2




        2





        If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

        – terdon
        7 hours ago





        If there are two or more colons on the line, this will print everything until the last one, so not what the OP needs. Try echo foo:bar:baz | grep -oP '.*(?=:)'. This will work for the OP's example, but not for the general case as described in the question.

        – terdon
        7 hours ago













        there is only one colon and its working fine , but thanks for the update

        – Gabrial Johnas
        7 hours ago





        there is only one colon and its working fine , but thanks for the update

        – Gabrial Johnas
        7 hours ago




        2




        2





        Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

        – Kusalananda
        7 hours ago





        Also requires GNU grep. It would not work with the default grep on e.g. macOS or any of the other BSDs.

        – Kusalananda
        7 hours ago













        @Kusalananda I edited the question adding your observation.

        – guillermo chamorro
        7 hours ago





        @Kusalananda I edited the question adding your observation.

        – guillermo chamorro
        7 hours ago













        6















        Or an alternative:



        $ grep -o '^[^:]*' file
        help.helloworld.com
        dev.helloworld.com


        This returns any characters beginning at the start of each line (^) which are no colons ([^:]*).






        share|improve this answer





























          6















          Or an alternative:



          $ grep -o '^[^:]*' file
          help.helloworld.com
          dev.helloworld.com


          This returns any characters beginning at the start of each line (^) which are no colons ([^:]*).






          share|improve this answer



























            6














            6










            6









            Or an alternative:



            $ grep -o '^[^:]*' file
            help.helloworld.com
            dev.helloworld.com


            This returns any characters beginning at the start of each line (^) which are no colons ([^:]*).






            share|improve this answer













            Or an alternative:



            $ grep -o '^[^:]*' file
            help.helloworld.com
            dev.helloworld.com


            This returns any characters beginning at the start of each line (^) which are no colons ([^:]*).







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 8 hours ago









            FreddyFreddy

            6,9481 gold badge6 silver badges24 bronze badges




            6,9481 gold badge6 silver badges24 bronze badges
























                6















                Would definitely recommend awk:



                awk -F ':' 'print $1' file


                Uses : as a field separator and prints the first field.






                share|improve this answer





























                  6















                  Would definitely recommend awk:



                  awk -F ':' 'print $1' file


                  Uses : as a field separator and prints the first field.






                  share|improve this answer



























                    6














                    6










                    6









                    Would definitely recommend awk:



                    awk -F ':' 'print $1' file


                    Uses : as a field separator and prints the first field.






                    share|improve this answer













                    Would definitely recommend awk:



                    awk -F ':' 'print $1' file


                    Uses : as a field separator and prints the first field.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 7 hours ago









                    CentimaneCentimane

                    3,3031 gold badge13 silver badges36 bronze badges




                    3,3031 gold badge13 silver badges36 bronze badges
























                        5















                        This is what cut is for:



                        $ cat file
                        help.helloworld.com:latest.world.com
                        dev.helloworld.com:latest.world.com
                        foo:baz:bar
                        foo

                        $ cut -d: -f1 file
                        help.helloworld.com
                        dev.helloworld.com
                        foo
                        foo


                        You just set the delimiter to : with -d: and tell it to only print the 1st field (-f1).






                        share|improve this answer





























                          5















                          This is what cut is for:



                          $ cat file
                          help.helloworld.com:latest.world.com
                          dev.helloworld.com:latest.world.com
                          foo:baz:bar
                          foo

                          $ cut -d: -f1 file
                          help.helloworld.com
                          dev.helloworld.com
                          foo
                          foo


                          You just set the delimiter to : with -d: and tell it to only print the 1st field (-f1).






                          share|improve this answer



























                            5














                            5










                            5









                            This is what cut is for:



                            $ cat file
                            help.helloworld.com:latest.world.com
                            dev.helloworld.com:latest.world.com
                            foo:baz:bar
                            foo

                            $ cut -d: -f1 file
                            help.helloworld.com
                            dev.helloworld.com
                            foo
                            foo


                            You just set the delimiter to : with -d: and tell it to only print the 1st field (-f1).






                            share|improve this answer













                            This is what cut is for:



                            $ cat file
                            help.helloworld.com:latest.world.com
                            dev.helloworld.com:latest.world.com
                            foo:baz:bar
                            foo

                            $ cut -d: -f1 file
                            help.helloworld.com
                            dev.helloworld.com
                            foo
                            foo


                            You just set the delimiter to : with -d: and tell it to only print the 1st field (-f1).







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 7 hours ago









                            terdonterdon

                            141k34 gold badges290 silver badges469 bronze badges




                            141k34 gold badges290 silver badges469 bronze badges























                                Gabrial Johnas is a new contributor. Be nice, and check out our Code of Conduct.









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