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Does this VCO produce a sine wave or square wave
What does RADOM stand for in this datasheet?I need helping understanding this VCO circuitHow do I generate a high frequency sine wave using a PLL? 900 to 950 MHzWhy isn't this VCO responding to my sawtooth waveform?Is a 555/6 suitable for generating a 1-3000Hz square wave from 0-5V control voltageHow to design a cheap sine-wave generator up to 200 MHz?How does VCO in PLL in computer processor work?How does / can this radar wave detector circuit work?
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I'm looking at the datasheet for the analog devices hmc431lp4 voltage controlled oscillator, and I can't tell if its output waveform is a sine wave or square wave. The datasheet doesn't label the oscillator as being harmonic or relaxation. I'm wondering because I am trying to understand a homemade radar system I found online. Do FMCW systems like this project require a sinusoidal RF signal to operate?
Link to datasheet.
Link to project I'm looking at.
radar vco
$endgroup$
add a comment |
$begingroup$
I'm looking at the datasheet for the analog devices hmc431lp4 voltage controlled oscillator, and I can't tell if its output waveform is a sine wave or square wave. The datasheet doesn't label the oscillator as being harmonic or relaxation. I'm wondering because I am trying to understand a homemade radar system I found online. Do FMCW systems like this project require a sinusoidal RF signal to operate?
Link to datasheet.
Link to project I'm looking at.
radar vco
$endgroup$
$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago
add a comment |
$begingroup$
I'm looking at the datasheet for the analog devices hmc431lp4 voltage controlled oscillator, and I can't tell if its output waveform is a sine wave or square wave. The datasheet doesn't label the oscillator as being harmonic or relaxation. I'm wondering because I am trying to understand a homemade radar system I found online. Do FMCW systems like this project require a sinusoidal RF signal to operate?
Link to datasheet.
Link to project I'm looking at.
radar vco
$endgroup$
I'm looking at the datasheet for the analog devices hmc431lp4 voltage controlled oscillator, and I can't tell if its output waveform is a sine wave or square wave. The datasheet doesn't label the oscillator as being harmonic or relaxation. I'm wondering because I am trying to understand a homemade radar system I found online. Do FMCW systems like this project require a sinusoidal RF signal to operate?
Link to datasheet.
Link to project I'm looking at.
radar vco
radar vco
edited 8 hours ago
Saunders
asked 8 hours ago
SaundersSaunders
1609 bronze badges
1609 bronze badges
$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago
add a comment |
$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago
$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This VCO outputs a frequency between 5.5 and 6.1 GHz.
It is sort of "implied" that the output signal will be a sinewave because:
a "decent" square wave at that frequency would need a signal bandwidth of several hundreds of GHz. That's because a square wave relies on harmonic frequencies (multiples of the base frequency) to become "square". Read up on Fourier analysis to understand this
this chip is designed to be used in RF transceivers, usually as a local oscillator for mixing up/down RF signals. This works best using sinewaves as RF designers want one frequency to deal with, not one frequency and all its harmonics (like a square wave would have).
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
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oldest
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active
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votes
$begingroup$
This VCO outputs a frequency between 5.5 and 6.1 GHz.
It is sort of "implied" that the output signal will be a sinewave because:
a "decent" square wave at that frequency would need a signal bandwidth of several hundreds of GHz. That's because a square wave relies on harmonic frequencies (multiples of the base frequency) to become "square". Read up on Fourier analysis to understand this
this chip is designed to be used in RF transceivers, usually as a local oscillator for mixing up/down RF signals. This works best using sinewaves as RF designers want one frequency to deal with, not one frequency and all its harmonics (like a square wave would have).
$endgroup$
add a comment |
$begingroup$
This VCO outputs a frequency between 5.5 and 6.1 GHz.
It is sort of "implied" that the output signal will be a sinewave because:
a "decent" square wave at that frequency would need a signal bandwidth of several hundreds of GHz. That's because a square wave relies on harmonic frequencies (multiples of the base frequency) to become "square". Read up on Fourier analysis to understand this
this chip is designed to be used in RF transceivers, usually as a local oscillator for mixing up/down RF signals. This works best using sinewaves as RF designers want one frequency to deal with, not one frequency and all its harmonics (like a square wave would have).
$endgroup$
add a comment |
$begingroup$
This VCO outputs a frequency between 5.5 and 6.1 GHz.
It is sort of "implied" that the output signal will be a sinewave because:
a "decent" square wave at that frequency would need a signal bandwidth of several hundreds of GHz. That's because a square wave relies on harmonic frequencies (multiples of the base frequency) to become "square". Read up on Fourier analysis to understand this
this chip is designed to be used in RF transceivers, usually as a local oscillator for mixing up/down RF signals. This works best using sinewaves as RF designers want one frequency to deal with, not one frequency and all its harmonics (like a square wave would have).
$endgroup$
This VCO outputs a frequency between 5.5 and 6.1 GHz.
It is sort of "implied" that the output signal will be a sinewave because:
a "decent" square wave at that frequency would need a signal bandwidth of several hundreds of GHz. That's because a square wave relies on harmonic frequencies (multiples of the base frequency) to become "square". Read up on Fourier analysis to understand this
this chip is designed to be used in RF transceivers, usually as a local oscillator for mixing up/down RF signals. This works best using sinewaves as RF designers want one frequency to deal with, not one frequency and all its harmonics (like a square wave would have).
answered 7 hours ago
BimpelrekkieBimpelrekkie
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57.4k2 gold badges57 silver badges131 bronze badges
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$begingroup$
Just added a screenshot from the front page of the datasheet
$endgroup$
– Saunders
8 hours ago
$begingroup$
I don't know the answer but the harmonics figures should give a clue. I notice that it is rated at > 500 W which, I suspect, should be mW.
$endgroup$
– Transistor
7 hours ago
$begingroup$
So because the datasheet includes information on output harmonics the oscillator most likely produces a sinewave?
$endgroup$
– Saunders
7 hours ago
$begingroup$
I would think so. A squarewave wouldn't have any even harmonics, only odd.
$endgroup$
– Transistor
7 hours ago