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for xml path('') output


SSIS File System Task Copy File Could not find part of the path errorSql Server 2012 Extended Events for Selective Xml Indexing not showing resultsXML Whitespaces/Unwanted CharactersSSIS Package fails to “Transform File and create output file”How to extract xml attribute from a column?Very strange performance with an XML indexHelp with SQL Server and XML columnsHow Plan Explorer Group Operators in Query Columns Tabsp_whoisactive @get_locks parameter xml errorXML Query Question






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4















When I run the following



select t.type
from (values ('Green'),('Blue'),('Red')) as t(type)
for xml path('')


I receive this output



<type>Green</type>
<type>Blue</type>
<type>Red</type>


If I run the following



select t.type + '/'
from (values ('Green'),('Blue'),('Red')) as t(type)
for xml path('')


I receive this output



Green/Blue/Red/


Why does adding the concatenation in the select lead to the removal of the type tags and output on one line in the xml file? Running SQL Server 2012.










share|improve this question




























    4















    When I run the following



    select t.type
    from (values ('Green'),('Blue'),('Red')) as t(type)
    for xml path('')


    I receive this output



    <type>Green</type>
    <type>Blue</type>
    <type>Red</type>


    If I run the following



    select t.type + '/'
    from (values ('Green'),('Blue'),('Red')) as t(type)
    for xml path('')


    I receive this output



    Green/Blue/Red/


    Why does adding the concatenation in the select lead to the removal of the type tags and output on one line in the xml file? Running SQL Server 2012.










    share|improve this question
























      4












      4








      4








      When I run the following



      select t.type
      from (values ('Green'),('Blue'),('Red')) as t(type)
      for xml path('')


      I receive this output



      <type>Green</type>
      <type>Blue</type>
      <type>Red</type>


      If I run the following



      select t.type + '/'
      from (values ('Green'),('Blue'),('Red')) as t(type)
      for xml path('')


      I receive this output



      Green/Blue/Red/


      Why does adding the concatenation in the select lead to the removal of the type tags and output on one line in the xml file? Running SQL Server 2012.










      share|improve this question














      When I run the following



      select t.type
      from (values ('Green'),('Blue'),('Red')) as t(type)
      for xml path('')


      I receive this output



      <type>Green</type>
      <type>Blue</type>
      <type>Red</type>


      If I run the following



      select t.type + '/'
      from (values ('Green'),('Blue'),('Red')) as t(type)
      for xml path('')


      I receive this output



      Green/Blue/Red/


      Why does adding the concatenation in the select lead to the removal of the type tags and output on one line in the xml file? Running SQL Server 2012.







      sql-server t-sql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 8 hours ago









      kevinnwhatkevinnwhat

      9871 silver badge10 bronze badges




      9871 silver badge10 bronze badges




















          1 Answer
          1






          active

          oldest

          votes


















          5














          XML is bonkers



          When you add the concatenated string, you lose the "path element".



          For example if you do this:



          SELECT t.type + '/' AS type
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML PATH('');

          SELECT t.type + '/'
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML PATH('type');


          You get this back:



          <type>Green/</type>
          <type>Blue/</type>
          <type>Red/</type>


          The column name or alias acts as the path element.



          Some other examples that might help



          Using RAW, ELEMENTS



          SELECT t.type + '/'
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML RAW, ELEMENTS;

          SELECT t.type + '/' AS type
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML RAW, ELEMENTS;


          In the first example, you get the generic "row" element name, but in the second you get row/type.



          When using RAW, TYPE:



          SELECT t.type + '/' AS type
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML RAW, TYPE;

          SELECT t.type + '/'
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML RAW, TYPE;


          The first query returns valid-ish XML, the second throws an error because the path element lacks an identifier.



          Using AUTO, the table alias and column name turns into the path:



          SELECT type + '/' AS type
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML AUTO;

          SELECT type
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML AUTO;


          But without an alias, you get a similar error:



          SELECT type + '/'
          FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
          FOR XML AUTO;


          I'd gin up an example with FOR XML EXPLICIT but it would be irresponsible for me to start drinking right now.






          share|improve this answer



























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            1 Answer
            1






            active

            oldest

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            XML is bonkers



            When you add the concatenated string, you lose the "path element".



            For example if you do this:



            SELECT t.type + '/' AS type
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML PATH('');

            SELECT t.type + '/'
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML PATH('type');


            You get this back:



            <type>Green/</type>
            <type>Blue/</type>
            <type>Red/</type>


            The column name or alias acts as the path element.



            Some other examples that might help



            Using RAW, ELEMENTS



            SELECT t.type + '/'
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML RAW, ELEMENTS;

            SELECT t.type + '/' AS type
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML RAW, ELEMENTS;


            In the first example, you get the generic "row" element name, but in the second you get row/type.



            When using RAW, TYPE:



            SELECT t.type + '/' AS type
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML RAW, TYPE;

            SELECT t.type + '/'
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML RAW, TYPE;


            The first query returns valid-ish XML, the second throws an error because the path element lacks an identifier.



            Using AUTO, the table alias and column name turns into the path:



            SELECT type + '/' AS type
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML AUTO;

            SELECT type
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML AUTO;


            But without an alias, you get a similar error:



            SELECT type + '/'
            FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
            FOR XML AUTO;


            I'd gin up an example with FOR XML EXPLICIT but it would be irresponsible for me to start drinking right now.






            share|improve this answer





























              5














              XML is bonkers



              When you add the concatenated string, you lose the "path element".



              For example if you do this:



              SELECT t.type + '/' AS type
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML PATH('');

              SELECT t.type + '/'
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML PATH('type');


              You get this back:



              <type>Green/</type>
              <type>Blue/</type>
              <type>Red/</type>


              The column name or alias acts as the path element.



              Some other examples that might help



              Using RAW, ELEMENTS



              SELECT t.type + '/'
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML RAW, ELEMENTS;

              SELECT t.type + '/' AS type
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML RAW, ELEMENTS;


              In the first example, you get the generic "row" element name, but in the second you get row/type.



              When using RAW, TYPE:



              SELECT t.type + '/' AS type
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML RAW, TYPE;

              SELECT t.type + '/'
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML RAW, TYPE;


              The first query returns valid-ish XML, the second throws an error because the path element lacks an identifier.



              Using AUTO, the table alias and column name turns into the path:



              SELECT type + '/' AS type
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML AUTO;

              SELECT type
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML AUTO;


              But without an alias, you get a similar error:



              SELECT type + '/'
              FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
              FOR XML AUTO;


              I'd gin up an example with FOR XML EXPLICIT but it would be irresponsible for me to start drinking right now.






              share|improve this answer



























                5












                5








                5







                XML is bonkers



                When you add the concatenated string, you lose the "path element".



                For example if you do this:



                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML PATH('');

                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML PATH('type');


                You get this back:



                <type>Green/</type>
                <type>Blue/</type>
                <type>Red/</type>


                The column name or alias acts as the path element.



                Some other examples that might help



                Using RAW, ELEMENTS



                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, ELEMENTS;

                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, ELEMENTS;


                In the first example, you get the generic "row" element name, but in the second you get row/type.



                When using RAW, TYPE:



                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, TYPE;

                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, TYPE;


                The first query returns valid-ish XML, the second throws an error because the path element lacks an identifier.



                Using AUTO, the table alias and column name turns into the path:



                SELECT type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;

                SELECT type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;


                But without an alias, you get a similar error:



                SELECT type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;


                I'd gin up an example with FOR XML EXPLICIT but it would be irresponsible for me to start drinking right now.






                share|improve this answer















                XML is bonkers



                When you add the concatenated string, you lose the "path element".



                For example if you do this:



                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML PATH('');

                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML PATH('type');


                You get this back:



                <type>Green/</type>
                <type>Blue/</type>
                <type>Red/</type>


                The column name or alias acts as the path element.



                Some other examples that might help



                Using RAW, ELEMENTS



                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, ELEMENTS;

                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, ELEMENTS;


                In the first example, you get the generic "row" element name, but in the second you get row/type.



                When using RAW, TYPE:



                SELECT t.type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, TYPE;

                SELECT t.type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML RAW, TYPE;


                The first query returns valid-ish XML, the second throws an error because the path element lacks an identifier.



                Using AUTO, the table alias and column name turns into the path:



                SELECT type + '/' AS type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;

                SELECT type
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;


                But without an alias, you get a similar error:



                SELECT type + '/'
                FROM ( VALUES ( 'Green' ), ( 'Blue' ), ( 'Red' )) AS t ( type )
                FOR XML AUTO;


                I'd gin up an example with FOR XML EXPLICIT but it would be irresponsible for me to start drinking right now.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 7 hours ago

























                answered 8 hours ago









                Erik DarlingErik Darling

                24.9k13 gold badges76 silver badges125 bronze badges




                24.9k13 gold badges76 silver badges125 bronze badges



























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