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Difference between sizeof(struct name_of_struct) vs sizeof(name_of_struct)?
What is the difference between #include <filename> and #include “filename”?Regular cast vs. static_cast vs. dynamic_castWhat are the differences between a pointer variable and a reference variable in C++?What are the differences between struct and class in C++?Why isn't sizeof for a struct equal to the sum of sizeof of each member?Difference between 'struct' and 'typedef struct' in C++?C++11 introduced a standardized memory model. What does it mean? And how is it going to affect C++ programming?Why are elementwise additions much faster in separate loops than in a combined loop?What is the difference between 'typedef' and 'using' in C++11?Replacing a 32-bit loop counter with 64-bit introduces crazy performance deviations
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The return values of the subject are the same.
Is there any difference between the two? Even if it is subtle/not important, I'd like to know.
c++
asked 10 hours ago
KunseokKunseok
885
add a comment |
The return values of the subject are the same.
Is there any difference between the two? Even if it is subtle/not important, I'd like to know.
c++
asked 10 hours ago
KunseokKunseok
885
add a comment |
The return values of the subject are the same.
Is there any difference between the two? Even if it is subtle/not important, I'd like to know.
c++
asked 10 hours ago
KunseokKunseok
885
The return values of the subject are the same.
Is there any difference between the two? Even if it is subtle/not important, I'd like to know.
c++
c++
asked 10 hours ago
KunseokKunseok
885
asked 10 hours ago
KunseokKunseok
885
asked 10 hours ago
KunseokKunseok
885
asked 10 hours ago
KunseokKunseok
885
asked 10 hours ago
KunseokKunseok
885
885
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
struct name_of_struct refers unambiguously to a struct/class tagged name_of_struct whereas name_of_struct may be a variable or a function name.
For example, in POSIX, you have both struct stat and a function named stat. When you want to refer to the struct type, you need the struct keyword to disambiguate (+ plain C requires it always -- in plain C, regular identifiers live in a separate namespace from struct tags and struct tags don't leak into the regular identifier namespace like they do in C++ unless you explicitly drag them there with a typedef as in typedef struct tag /*...*/ tag;).
Example:
struct foo char x [256];;
void (*foo)(void);
int structsz() return sizeof(struct foo); //returns 256
int ptrsz() return sizeof(foo); //returns typically 8 or 4
If this seems confusing, it basically exists to maintain backwards compatibility with C.
answered 10 hours ago
PSkocikPSkocik
37.4k65783
2
One additional minor note, thestructandclasskeywords are interchangeable in this context.sizeof(struct foo)andsizeof(class foo)would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.
– Miles Budnek
9 hours ago
1
Furthermorestruct name_of_structi.e. an elaborated type specifier also declaresname_of_struct. This doesn't make a difference in this particular case, since in order to usesizeof,name_of_structmust be defined, and therefore declared prior. But in another case, it can make a difference.
– eerorika
9 hours ago
add a comment |
As far as I know: the difference is c struct notation versus C++ notation.
answered 10 hours ago
Tarick WellingTarick Welling
513219
No, they are both C++.sizeof(name_of_struct)is only C++ i.e. not C, unlessname_of_structis also atypedef.
– eerorika
9 hours ago
add a comment |
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2 Answers
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2 Answers
2
active
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active
oldest
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active
oldest
votes
struct name_of_struct refers unambiguously to a struct/class tagged name_of_struct whereas name_of_struct may be a variable or a function name.
For example, in POSIX, you have both struct stat and a function named stat. When you want to refer to the struct type, you need the struct keyword to disambiguate (+ plain C requires it always -- in plain C, regular identifiers live in a separate namespace from struct tags and struct tags don't leak into the regular identifier namespace like they do in C++ unless you explicitly drag them there with a typedef as in typedef struct tag /*...*/ tag;).
Example:
struct foo char x [256];;
void (*foo)(void);
int structsz() return sizeof(struct foo); //returns 256
int ptrsz() return sizeof(foo); //returns typically 8 or 4
If this seems confusing, it basically exists to maintain backwards compatibility with C.
answered 10 hours ago
PSkocikPSkocik
37.4k65783
2
One additional minor note, thestructandclasskeywords are interchangeable in this context.sizeof(struct foo)andsizeof(class foo)would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.
– Miles Budnek
9 hours ago
1
Furthermorestruct name_of_structi.e. an elaborated type specifier also declaresname_of_struct. This doesn't make a difference in this particular case, since in order to usesizeof,name_of_structmust be defined, and therefore declared prior. But in another case, it can make a difference.
– eerorika
9 hours ago
add a comment |
struct name_of_struct refers unambiguously to a struct/class tagged name_of_struct whereas name_of_struct may be a variable or a function name.
For example, in POSIX, you have both struct stat and a function named stat. When you want to refer to the struct type, you need the struct keyword to disambiguate (+ plain C requires it always -- in plain C, regular identifiers live in a separate namespace from struct tags and struct tags don't leak into the regular identifier namespace like they do in C++ unless you explicitly drag them there with a typedef as in typedef struct tag /*...*/ tag;).
Example:
struct foo char x [256];;
void (*foo)(void);
int structsz() return sizeof(struct foo); //returns 256
int ptrsz() return sizeof(foo); //returns typically 8 or 4
If this seems confusing, it basically exists to maintain backwards compatibility with C.
answered 10 hours ago
PSkocikPSkocik
37.4k65783
2
One additional minor note, thestructandclasskeywords are interchangeable in this context.sizeof(struct foo)andsizeof(class foo)would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.
– Miles Budnek
9 hours ago
1
Furthermorestruct name_of_structi.e. an elaborated type specifier also declaresname_of_struct. This doesn't make a difference in this particular case, since in order to usesizeof,name_of_structmust be defined, and therefore declared prior. But in another case, it can make a difference.
– eerorika
9 hours ago
add a comment |
struct name_of_struct refers unambiguously to a struct/class tagged name_of_struct whereas name_of_struct may be a variable or a function name.
For example, in POSIX, you have both struct stat and a function named stat. When you want to refer to the struct type, you need the struct keyword to disambiguate (+ plain C requires it always -- in plain C, regular identifiers live in a separate namespace from struct tags and struct tags don't leak into the regular identifier namespace like they do in C++ unless you explicitly drag them there with a typedef as in typedef struct tag /*...*/ tag;).
Example:
struct foo char x [256];;
void (*foo)(void);
int structsz() return sizeof(struct foo); //returns 256
int ptrsz() return sizeof(foo); //returns typically 8 or 4
If this seems confusing, it basically exists to maintain backwards compatibility with C.
answered 10 hours ago
PSkocikPSkocik
37.4k65783
struct name_of_struct refers unambiguously to a struct/class tagged name_of_struct whereas name_of_struct may be a variable or a function name.
For example, in POSIX, you have both struct stat and a function named stat. When you want to refer to the struct type, you need the struct keyword to disambiguate (+ plain C requires it always -- in plain C, regular identifiers live in a separate namespace from struct tags and struct tags don't leak into the regular identifier namespace like they do in C++ unless you explicitly drag them there with a typedef as in typedef struct tag /*...*/ tag;).
Example:
struct foo char x [256];;
void (*foo)(void);
int structsz() return sizeof(struct foo); //returns 256
int ptrsz() return sizeof(foo); //returns typically 8 or 4
If this seems confusing, it basically exists to maintain backwards compatibility with C.
answered 10 hours ago
PSkocikPSkocik
37.4k65783
edited 9 hours ago
answered 10 hours ago
PSkocikPSkocik
37.4k65783
answered 10 hours ago
PSkocikPSkocik
37.4k65783
answered 10 hours ago
PSkocikPSkocik
37.4k65783
37.4k65783
2
One additional minor note, thestructandclasskeywords are interchangeable in this context.sizeof(struct foo)andsizeof(class foo)would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.
– Miles Budnek
9 hours ago
1
Furthermorestruct name_of_structi.e. an elaborated type specifier also declaresname_of_struct. This doesn't make a difference in this particular case, since in order to usesizeof,name_of_structmust be defined, and therefore declared prior. But in another case, it can make a difference.
– eerorika
9 hours ago
add a comment |
2
One additional minor note, thestructandclasskeywords are interchangeable in this context.sizeof(struct foo)andsizeof(class foo)would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.
– Miles Budnek
9 hours ago
1
Furthermorestruct name_of_structi.e. an elaborated type specifier also declaresname_of_struct. This doesn't make a difference in this particular case, since in order to usesizeof,name_of_structmust be defined, and therefore declared prior. But in another case, it can make a difference.
– eerorika
9 hours ago
2
2
One additional minor note, the
struct and class keywords are interchangeable in this context. sizeof(struct foo) and sizeof(class foo) would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.– Miles Budnek
9 hours ago
One additional minor note, the
struct and class keywords are interchangeable in this context. sizeof(struct foo) and sizeof(class foo) would both work. You don't see the latter very often though, since this mainly comes up in the context of interoperating with C code.– Miles Budnek
9 hours ago
1
1
Furthermore
struct name_of_struct i.e. an elaborated type specifier also declares name_of_struct. This doesn't make a difference in this particular case, since in order to use sizeof, name_of_struct must be defined, and therefore declared prior. But in another case, it can make a difference.– eerorika
9 hours ago
Furthermore
struct name_of_struct i.e. an elaborated type specifier also declares name_of_struct. This doesn't make a difference in this particular case, since in order to use sizeof, name_of_struct must be defined, and therefore declared prior. But in another case, it can make a difference.– eerorika
9 hours ago
add a comment |
As far as I know: the difference is c struct notation versus C++ notation.
answered 10 hours ago
Tarick WellingTarick Welling
513219
No, they are both C++.sizeof(name_of_struct)is only C++ i.e. not C, unlessname_of_structis also atypedef.
– eerorika
9 hours ago
add a comment |
As far as I know: the difference is c struct notation versus C++ notation.
answered 10 hours ago
Tarick WellingTarick Welling
513219
No, they are both C++.sizeof(name_of_struct)is only C++ i.e. not C, unlessname_of_structis also atypedef.
– eerorika
9 hours ago
add a comment |
As far as I know: the difference is c struct notation versus C++ notation.
answered 10 hours ago
Tarick WellingTarick Welling
513219
As far as I know: the difference is c struct notation versus C++ notation.
answered 10 hours ago
Tarick WellingTarick Welling
513219
answered 10 hours ago
Tarick WellingTarick Welling
513219
answered 10 hours ago
Tarick WellingTarick Welling
513219
answered 10 hours ago
Tarick WellingTarick Welling
513219
513219
No, they are both C++.sizeof(name_of_struct)is only C++ i.e. not C, unlessname_of_structis also atypedef.
– eerorika
9 hours ago
add a comment |
No, they are both C++.sizeof(name_of_struct)is only C++ i.e. not C, unlessname_of_structis also atypedef.
– eerorika
9 hours ago
No, they are both C++.
sizeof(name_of_struct) is only C++ i.e. not C, unless name_of_struct is also a typedef.– eerorika
9 hours ago
No, they are both C++.
sizeof(name_of_struct) is only C++ i.e. not C, unless name_of_struct is also a typedef.– eerorika
9 hours ago
add a comment |
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