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What is memelemum?

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6

1

$begingroup$

Here's a ... text? poem? dictionary? list? Something...

e m me mum mele mem mume mumm melee melem meme memum mumele

Given the above, what does 'memelemum' signify, and why that is?

(Okay, I can see that a robot might question whether this "completely describes the problem - and is written using proper grammar". I hereby assure said bot that that is indeed the case.)

enigmatic-puzzle

share|improve this question

asked 8 hours ago

KlaymenDKKlaymenDK

1313

$endgroup$

add a comment | 

6

1

$begingroup$

Here's a ... text? poem? dictionary? list? Something...

e m me mum mele mem mume mumm melee melem meme memum mumele

Given the above, what does 'memelemum' signify, and why that is?

(Okay, I can see that a robot might question whether this "completely describes the problem - and is written using proper grammar". I hereby assure said bot that that is indeed the case.)

enigmatic-puzzle

share|improve this question

asked 8 hours ago

KlaymenDKKlaymenDK

1313

$endgroup$

add a comment | 

$begingroup$

Here's a ... text? poem? dictionary? list? Something...

e m me mum mele mem mume mumm melee melem meme memum mumele

Given the above, what does 'memelemum' signify, and why that is?

(Okay, I can see that a robot might question whether this "completely describes the problem - and is written using proper grammar". I hereby assure said bot that that is indeed the case.)

enigmatic-puzzle

share|improve this question

asked 8 hours ago

KlaymenDKKlaymenDK

1313

$endgroup$

share|improve this question

asked 8 hours ago

KlaymenDKKlaymenDK

1313

share|improve this question

asked 8 hours ago

KlaymenDKKlaymenDK

1313

asked 8 hours ago

KlaymenDKKlaymenDK

1313

asked 8 hours ago

KlaymenDKKlaymenDK

1313

1 Answer
1

active

oldest

votes

4

$begingroup$

I think memelemum signifies

the number 83

because

this is lightly disguised binary where e is 0 and m is 1; for euphony you insert l between instances of e and u between instances of m, except that for reasons I don't quite understand you write mumm instead of mumum. (Perhaps there's a rule that collapses strings of ums or something.)

so

memelemum = memeemm = 1010011 = 83.

share|improve this answer

edited 4 hours ago

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I guess because ROT13(Jr nqq y be h ng zbfg bapr, naq cvpx gur yrsgzbfg cnve? r.t. zzrrrrzz jvyy or zhzryrrrzz?)
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Certainly possible. I don't think we have enough information here to deduce the exact rules with any confidence.
  $endgroup$
  – Gareth McCaughan♦
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  At least there is "melee" also, but yeah $2$ instances are maybe not enough..
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Rot13(Gurer vf h qvivqvat gur svefg bs rirel zz cnve naq y qvivqvat gur svefg bs rirel rr cnve. Ubjrire gung ovanel ahzore vf bayl qrpvzny rvtugl guerr).
  $endgroup$
  – Weather Vane
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @WeatherVane Oops, yes, I erred. Good catch.
  $endgroup$
  – Gareth McCaughan♦
  4 hours ago
  

  
  
  
  

 | 
show 2 more comments

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4

$begingroup$

I think memelemum signifies

the number 83

because

this is lightly disguised binary where e is 0 and m is 1; for euphony you insert l between instances of e and u between instances of m, except that for reasons I don't quite understand you write mumm instead of mumum. (Perhaps there's a rule that collapses strings of ums or something.)

so

memelemum = memeemm = 1010011 = 83.

share|improve this answer

edited 4 hours ago

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I guess because ROT13(Jr nqq y be h ng zbfg bapr, naq cvpx gur yrsgzbfg cnve? r.t. zzrrrrzz jvyy or zhzryrrrzz?)
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Certainly possible. I don't think we have enough information here to deduce the exact rules with any confidence.
  $endgroup$
  – Gareth McCaughan♦
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  At least there is "melee" also, but yeah $2$ instances are maybe not enough..
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Rot13(Gurer vf h qvivqvat gur svefg bs rirel zz cnve naq y qvivqvat gur svefg bs rirel rr cnve. Ubjrire gung ovanel ahzore vf bayl qrpvzny rvtugl guerr).
  $endgroup$
  – Weather Vane
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @WeatherVane Oops, yes, I erred. Good catch.
  $endgroup$
  – Gareth McCaughan♦
  4 hours ago
  

  
  
  
  

 | 
show 2 more comments

4

$begingroup$

I think memelemum signifies

the number 83

because

this is lightly disguised binary where e is 0 and m is 1; for euphony you insert l between instances of e and u between instances of m, except that for reasons I don't quite understand you write mumm instead of mumum. (Perhaps there's a rule that collapses strings of ums or something.)

so

memelemum = memeemm = 1010011 = 83.

share|improve this answer

edited 4 hours ago

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I guess because ROT13(Jr nqq y be h ng zbfg bapr, naq cvpx gur yrsgzbfg cnve? r.t. zzrrrrzz jvyy or zhzryrrrzz?)
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Certainly possible. I don't think we have enough information here to deduce the exact rules with any confidence.
  $endgroup$
  – Gareth McCaughan♦
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  At least there is "melee" also, but yeah $2$ instances are maybe not enough..
  $endgroup$
  – athin
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Rot13(Gurer vf h qvivqvat gur svefg bs rirel zz cnve naq y qvivqvat gur svefg bs rirel rr cnve. Ubjrire gung ovanel ahzore vf bayl qrpvzny rvtugl guerr).
  $endgroup$
  – Weather Vane
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @WeatherVane Oops, yes, I erred. Good catch.
  $endgroup$
  – Gareth McCaughan♦
  4 hours ago
  

  
  
  
  

 | 
show 2 more comments

$begingroup$

I think memelemum signifies

the number 83

because

this is lightly disguised binary where e is 0 and m is 1; for euphony you insert l between instances of e and u between instances of m, except that for reasons I don't quite understand you write mumm instead of mumum. (Perhaps there's a rule that collapses strings of ums or something.)

so

memelemum = memeemm = 1010011 = 83.

share|improve this answer

edited 4 hours ago

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

$endgroup$

share|improve this answer

edited 4 hours ago

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281

answered 6 hours ago

Gareth McCaughan♦Gareth McCaughan

73k3182281