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Yet another calculator problem
The Laziest SurveyorMath with dinosaursThe Case of the Miscalculating CalculatorA rather curious division machineThe Lazy worker and the Punctual BossSaving The Mayor (Part 2)Yet another simple math problemCalculator BombMaster and Slave versus Bob: easy version
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
This is an easy one, just came out of my mind yesterday, while discussing calculator's architecture with a friend, even if it is not related to architecture itself.
A man walks into his office. He finds the calculator opened on his laptop with 0.33333333333 written on it. Just for fun, he wants to make 1 with just one operation (he's having such a good time). So he tries to divide by 0.33333333333. The calculator output is not 1.
What's the result he got? Why? What's the correct operation to get 1?
EDIT: Just to clarify, let's assume this is google calculator, that one you can use from google search page. Se everyone can "work" on the same calculator. It makes no difference, but this removes the "maybe this doesn't work on my '77 calculator" wild card.
mathematics
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
|
show 9 more comments
$begingroup$
This is an easy one, just came out of my mind yesterday, while discussing calculator's architecture with a friend, even if it is not related to architecture itself.
A man walks into his office. He finds the calculator opened on his laptop with 0.33333333333 written on it. Just for fun, he wants to make 1 with just one operation (he's having such a good time). So he tries to divide by 0.33333333333. The calculator output is not 1.
What's the result he got? Why? What's the correct operation to get 1?
EDIT: Just to clarify, let's assume this is google calculator, that one you can use from google search page. Se everyone can "work" on the same calculator. It makes no difference, but this removes the "maybe this doesn't work on my '77 calculator" wild card.
mathematics
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
1
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
1
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
2
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago
|
show 9 more comments
$begingroup$
This is an easy one, just came out of my mind yesterday, while discussing calculator's architecture with a friend, even if it is not related to architecture itself.
A man walks into his office. He finds the calculator opened on his laptop with 0.33333333333 written on it. Just for fun, he wants to make 1 with just one operation (he's having such a good time). So he tries to divide by 0.33333333333. The calculator output is not 1.
What's the result he got? Why? What's the correct operation to get 1?
EDIT: Just to clarify, let's assume this is google calculator, that one you can use from google search page. Se everyone can "work" on the same calculator. It makes no difference, but this removes the "maybe this doesn't work on my '77 calculator" wild card.
mathematics
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
This is an easy one, just came out of my mind yesterday, while discussing calculator's architecture with a friend, even if it is not related to architecture itself.
A man walks into his office. He finds the calculator opened on his laptop with 0.33333333333 written on it. Just for fun, he wants to make 1 with just one operation (he's having such a good time). So he tries to divide by 0.33333333333. The calculator output is not 1.
What's the result he got? Why? What's the correct operation to get 1?
EDIT: Just to clarify, let's assume this is google calculator, that one you can use from google search page. Se everyone can "work" on the same calculator. It makes no difference, but this removes the "maybe this doesn't work on my '77 calculator" wild card.
mathematics
mathematics
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Miles Davis
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
asked 9 hours ago
Miles DavisMiles Davis
1154 bronze badges
1154 bronze badges
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Miles Davis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
1
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
1
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
2
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago
|
show 9 more comments
1
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
1
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
1
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
2
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago
1
1
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
1
1
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
1
1
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
2
2
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago
|
show 9 more comments
2 Answers
2
active
oldest
votes
$begingroup$
If you type 0.333333333333 (12 3s) into google calculator and press enter, the display shows 0.33333333333 (11 3s). This is what happened before the man found the calculator.
If you then divide that by 0.33333333333 (11 3s), you get 1.00000000001 because internally it still remembers the number at a higher precision than what it displays.
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
$endgroup$
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
add a comment |
$begingroup$
I guess it is a problem with recurring decimal where someone divided 1 by 3.
Probably the calculator holds more decimal places than it shows. ( though i cant remember if i saw so at past) so dividing with displayed number does not work.
Multiplying with 3 may result closer to 1.
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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active
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votes
$begingroup$
If you type 0.333333333333 (12 3s) into google calculator and press enter, the display shows 0.33333333333 (11 3s). This is what happened before the man found the calculator.
If you then divide that by 0.33333333333 (11 3s), you get 1.00000000001 because internally it still remembers the number at a higher precision than what it displays.
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
$endgroup$
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
add a comment |
$begingroup$
If you type 0.333333333333 (12 3s) into google calculator and press enter, the display shows 0.33333333333 (11 3s). This is what happened before the man found the calculator.
If you then divide that by 0.33333333333 (11 3s), you get 1.00000000001 because internally it still remembers the number at a higher precision than what it displays.
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
$endgroup$
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
add a comment |
$begingroup$
If you type 0.333333333333 (12 3s) into google calculator and press enter, the display shows 0.33333333333 (11 3s). This is what happened before the man found the calculator.
If you then divide that by 0.33333333333 (11 3s), you get 1.00000000001 because internally it still remembers the number at a higher precision than what it displays.
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
$endgroup$
If you type 0.333333333333 (12 3s) into google calculator and press enter, the display shows 0.33333333333 (11 3s). This is what happened before the man found the calculator.
If you then divide that by 0.33333333333 (11 3s), you get 1.00000000001 because internally it still remembers the number at a higher precision than what it displays.
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
edited 2 hours ago
Supersonic
5512 silver badges11 bronze badges
5512 silver badges11 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
answered 5 hours ago
hdsdvhdsdv
8381 silver badge10 bronze badges
8381 silver badge10 bronze badges
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
add a comment |
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
$begingroup$
Didn't the OP say in the comments it wasn't to do with precision error?
$endgroup$
– hexomino
3 hours ago
add a comment |
$begingroup$
I guess it is a problem with recurring decimal where someone divided 1 by 3.
Probably the calculator holds more decimal places than it shows. ( though i cant remember if i saw so at past) so dividing with displayed number does not work.
Multiplying with 3 may result closer to 1.
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
$endgroup$
add a comment |
$begingroup$
I guess it is a problem with recurring decimal where someone divided 1 by 3.
Probably the calculator holds more decimal places than it shows. ( though i cant remember if i saw so at past) so dividing with displayed number does not work.
Multiplying with 3 may result closer to 1.
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
$endgroup$
add a comment |
$begingroup$
I guess it is a problem with recurring decimal where someone divided 1 by 3.
Probably the calculator holds more decimal places than it shows. ( though i cant remember if i saw so at past) so dividing with displayed number does not work.
Multiplying with 3 may result closer to 1.
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
$endgroup$
I guess it is a problem with recurring decimal where someone divided 1 by 3.
Probably the calculator holds more decimal places than it shows. ( though i cant remember if i saw so at past) so dividing with displayed number does not work.
Multiplying with 3 may result closer to 1.
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
answered 3 hours ago
Always ConfusedAlways Confused
2602 silver badges15 bronze badges
2602 silver badges15 bronze badges
add a comment |
add a comment |
Miles Davis is a new contributor. Be nice, and check out our Code of Conduct.
Miles Davis is a new contributor. Be nice, and check out our Code of Conduct.
Miles Davis is a new contributor. Be nice, and check out our Code of Conduct.
Miles Davis is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
Are we to assume that the 3s repeat infinitely, or just for 8 digits?
$endgroup$
– Brandon_J
8 hours ago
$begingroup$
Is it because of precision error? If yes, then note that there are many architectures being used which means: different calculators, different results. In particular case, different answers may arise for this puzzle.
$endgroup$
– athin
8 hours ago
1
$begingroup$
@DonThousand Probably "he tries to divide by"?
$endgroup$
– Rand al'Thor
8 hours ago
1
$begingroup$
@DonThousand It means divide "by", sorry
$endgroup$
– Miles Davis
8 hours ago
2
$begingroup$
To problems like this, my default response is xkcd.com/169/
$endgroup$
– Don Thousand
7 hours ago