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Why does matter stays collapsed following the supernova explosion?


Why is iron responsible for causing a supernova?Supernova explosion nearbySpeed of blast from supernovaWhat is faster than a supernova explosion?How to form Copper from Calcium in a supernova explosion?“Supernova” is the explosion or the resulting celestial body? Is it incorrect to call the explosion “supernova”?Are there observable changes in a star about to become supernova, minutes or hours before the explosion?Does a kilonova leave a high mass remnant?Is there a possibility that a white dwarf can turn into a neutron star or a black hole?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.



Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?










share|improve this question









New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    The answer is gravity. White dwarfs are not a possible product of supernovae.
    $endgroup$
    – Rob Jeffries
    8 hours ago










  • $begingroup$
    It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
    $endgroup$
    – Steve Linton
    8 hours ago










  • $begingroup$
    Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
    $endgroup$
    – Riccardo
    8 hours ago






  • 1




    $begingroup$
    @uhoh I meant dust & gas
    $endgroup$
    – Riccardo
    4 hours ago






  • 2




    $begingroup$
    @riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
    $endgroup$
    – Steve Linton
    4 hours ago

















3












$begingroup$


Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.



Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?










share|improve this question









New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    The answer is gravity. White dwarfs are not a possible product of supernovae.
    $endgroup$
    – Rob Jeffries
    8 hours ago










  • $begingroup$
    It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
    $endgroup$
    – Steve Linton
    8 hours ago










  • $begingroup$
    Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
    $endgroup$
    – Riccardo
    8 hours ago






  • 1




    $begingroup$
    @uhoh I meant dust & gas
    $endgroup$
    – Riccardo
    4 hours ago






  • 2




    $begingroup$
    @riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
    $endgroup$
    – Steve Linton
    4 hours ago













3












3








3





$begingroup$


Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.



Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?










share|improve this question









New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.



Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?







supernova explosion






share|improve this question









New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 7 hours ago







Riccardo













New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 9 hours ago









RiccardoRiccardo

1363 bronze badges




1363 bronze badges




New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • $begingroup$
    The answer is gravity. White dwarfs are not a possible product of supernovae.
    $endgroup$
    – Rob Jeffries
    8 hours ago










  • $begingroup$
    It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
    $endgroup$
    – Steve Linton
    8 hours ago










  • $begingroup$
    Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
    $endgroup$
    – Riccardo
    8 hours ago






  • 1




    $begingroup$
    @uhoh I meant dust & gas
    $endgroup$
    – Riccardo
    4 hours ago






  • 2




    $begingroup$
    @riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
    $endgroup$
    – Steve Linton
    4 hours ago
















  • $begingroup$
    The answer is gravity. White dwarfs are not a possible product of supernovae.
    $endgroup$
    – Rob Jeffries
    8 hours ago










  • $begingroup$
    It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
    $endgroup$
    – Steve Linton
    8 hours ago










  • $begingroup$
    Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
    $endgroup$
    – Riccardo
    8 hours ago






  • 1




    $begingroup$
    @uhoh I meant dust & gas
    $endgroup$
    – Riccardo
    4 hours ago






  • 2




    $begingroup$
    @riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
    $endgroup$
    – Steve Linton
    4 hours ago















$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago




$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago












$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago




$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago












$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago




$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago




1




1




$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago




$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago




2




2




$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago




$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago










5 Answers
5






active

oldest

votes


















2













$begingroup$

Found the answer on NASA site




The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!




This means the core survives the blast somehow






share|improve this answer








New contributor



Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$






















    1













    $begingroup$

    In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.



    Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..






    share|improve this answer









    $endgroup$














    • $begingroup$
      This doesn't address the question at all.
      $endgroup$
      – Rob Jeffries
      46 mins ago











    • $begingroup$
      Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
      $endgroup$
      – Michael Walsby
      12 mins ago


















    1













    $begingroup$

    In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.



    At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
    Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.



    This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.



    The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.






    share|improve this answer











    $endgroup$






















      0













      $begingroup$

      After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.






      share|improve this answer









      $endgroup$














      • $begingroup$
        That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
        $endgroup$
        – Riccardo
        4 hours ago











      • $begingroup$
        I think the point of the original question is how this happens, not that it does.
        $endgroup$
        – Carl Witthoft
        2 hours ago


















      0













      $begingroup$

      What's missing from the above explanations is what is really going on that causes any kind of explosion at all.



      I'm going to steal from xkcd to help with this:



      https://what-if.xkcd.com/73/



      Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.



      Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.



      I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.





      share









      $endgroup$

















        Your Answer








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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2













        $begingroup$

        Found the answer on NASA site




        The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!




        This means the core survives the blast somehow






        share|improve this answer








        New contributor



        Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        $endgroup$



















          2













          $begingroup$

          Found the answer on NASA site




          The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!




          This means the core survives the blast somehow






          share|improve this answer








          New contributor



          Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          $endgroup$

















            2














            2










            2







            $begingroup$

            Found the answer on NASA site




            The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!




            This means the core survives the blast somehow






            share|improve this answer








            New contributor



            Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$



            Found the answer on NASA site




            The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!




            This means the core survives the blast somehow







            share|improve this answer








            New contributor



            Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            share|improve this answer



            share|improve this answer






            New contributor



            Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            answered 4 hours ago









            RiccardoRiccardo

            1363 bronze badges




            1363 bronze badges




            New contributor



            Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.




            New contributor




            Riccardo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.




























                1













                $begingroup$

                In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.



                Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..






                share|improve this answer









                $endgroup$














                • $begingroup$
                  This doesn't address the question at all.
                  $endgroup$
                  – Rob Jeffries
                  46 mins ago











                • $begingroup$
                  Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                  $endgroup$
                  – Michael Walsby
                  12 mins ago















                1













                $begingroup$

                In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.



                Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..






                share|improve this answer









                $endgroup$














                • $begingroup$
                  This doesn't address the question at all.
                  $endgroup$
                  – Rob Jeffries
                  46 mins ago











                • $begingroup$
                  Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                  $endgroup$
                  – Michael Walsby
                  12 mins ago













                1














                1










                1







                $begingroup$

                In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.



                Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..






                share|improve this answer









                $endgroup$



                In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.



                Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 8 hours ago









                Michael WalsbyMichael Walsby

                9471 silver badge6 bronze badges




                9471 silver badge6 bronze badges














                • $begingroup$
                  This doesn't address the question at all.
                  $endgroup$
                  – Rob Jeffries
                  46 mins ago











                • $begingroup$
                  Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                  $endgroup$
                  – Michael Walsby
                  12 mins ago
















                • $begingroup$
                  This doesn't address the question at all.
                  $endgroup$
                  – Rob Jeffries
                  46 mins ago











                • $begingroup$
                  Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                  $endgroup$
                  – Michael Walsby
                  12 mins ago















                $begingroup$
                This doesn't address the question at all.
                $endgroup$
                – Rob Jeffries
                46 mins ago





                $begingroup$
                This doesn't address the question at all.
                $endgroup$
                – Rob Jeffries
                46 mins ago













                $begingroup$
                Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                $endgroup$
                – Michael Walsby
                12 mins ago




                $begingroup$
                Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
                $endgroup$
                – Michael Walsby
                12 mins ago











                1













                $begingroup$

                In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.



                At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
                Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.



                This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.



                The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.






                share|improve this answer











                $endgroup$



















                  1













                  $begingroup$

                  In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.



                  At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
                  Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.



                  This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.



                  The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.






                  share|improve this answer











                  $endgroup$

















                    1














                    1










                    1







                    $begingroup$

                    In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.



                    At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
                    Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.



                    This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.



                    The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.






                    share|improve this answer











                    $endgroup$



                    In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.



                    At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
                    Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.



                    This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.



                    The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 37 mins ago

























                    answered 47 mins ago









                    Rob JeffriesRob Jeffries

                    58.9k4 gold badges122 silver badges193 bronze badges




                    58.9k4 gold badges122 silver badges193 bronze badges
























                        0













                        $begingroup$

                        After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.






                        share|improve this answer









                        $endgroup$














                        • $begingroup$
                          That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                          $endgroup$
                          – Riccardo
                          4 hours ago











                        • $begingroup$
                          I think the point of the original question is how this happens, not that it does.
                          $endgroup$
                          – Carl Witthoft
                          2 hours ago















                        0













                        $begingroup$

                        After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.






                        share|improve this answer









                        $endgroup$














                        • $begingroup$
                          That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                          $endgroup$
                          – Riccardo
                          4 hours ago











                        • $begingroup$
                          I think the point of the original question is how this happens, not that it does.
                          $endgroup$
                          – Carl Witthoft
                          2 hours ago













                        0














                        0










                        0







                        $begingroup$

                        After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.






                        share|improve this answer









                        $endgroup$



                        After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.







                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered 4 hours ago









                        Kornpob BhirombhakdiKornpob Bhirombhakdi

                        1,1312 silver badges9 bronze badges




                        1,1312 silver badges9 bronze badges














                        • $begingroup$
                          That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                          $endgroup$
                          – Riccardo
                          4 hours ago











                        • $begingroup$
                          I think the point of the original question is how this happens, not that it does.
                          $endgroup$
                          – Carl Witthoft
                          2 hours ago
















                        • $begingroup$
                          That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                          $endgroup$
                          – Riccardo
                          4 hours ago











                        • $begingroup$
                          I think the point of the original question is how this happens, not that it does.
                          $endgroup$
                          – Carl Witthoft
                          2 hours ago















                        $begingroup$
                        That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                        $endgroup$
                        – Riccardo
                        4 hours ago





                        $begingroup$
                        That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
                        $endgroup$
                        – Riccardo
                        4 hours ago













                        $begingroup$
                        I think the point of the original question is how this happens, not that it does.
                        $endgroup$
                        – Carl Witthoft
                        2 hours ago




                        $begingroup$
                        I think the point of the original question is how this happens, not that it does.
                        $endgroup$
                        – Carl Witthoft
                        2 hours ago











                        0













                        $begingroup$

                        What's missing from the above explanations is what is really going on that causes any kind of explosion at all.



                        I'm going to steal from xkcd to help with this:



                        https://what-if.xkcd.com/73/



                        Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.



                        Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.



                        I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.





                        share









                        $endgroup$



















                          0













                          $begingroup$

                          What's missing from the above explanations is what is really going on that causes any kind of explosion at all.



                          I'm going to steal from xkcd to help with this:



                          https://what-if.xkcd.com/73/



                          Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.



                          Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.



                          I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.





                          share









                          $endgroup$

















                            0














                            0










                            0







                            $begingroup$

                            What's missing from the above explanations is what is really going on that causes any kind of explosion at all.



                            I'm going to steal from xkcd to help with this:



                            https://what-if.xkcd.com/73/



                            Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.



                            Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.



                            I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.





                            share









                            $endgroup$



                            What's missing from the above explanations is what is really going on that causes any kind of explosion at all.



                            I'm going to steal from xkcd to help with this:



                            https://what-if.xkcd.com/73/



                            Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.



                            Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.



                            I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.






                            share











                            share


                            share










                            answered 7 mins ago









                            Reginald BlueReginald Blue

                            1243 bronze badges




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