Why does matter stays collapsed following the supernova explosion?Why is iron responsible for causing a supernova?Supernova explosion nearbySpeed of blast from supernovaWhat is faster than a supernova explosion?How to form Copper from Calcium in a supernova explosion?“Supernova” is the explosion or the resulting celestial body? Is it incorrect to call the explosion “supernova”?Are there observable changes in a star about to become supernova, minutes or hours before the explosion?Does a kilonova leave a high mass remnant?Is there a possibility that a white dwarf can turn into a neutron star or a black hole?
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Why does matter stays collapsed following the supernova explosion?
Why is iron responsible for causing a supernova?Supernova explosion nearbySpeed of blast from supernovaWhat is faster than a supernova explosion?How to form Copper from Calcium in a supernova explosion?“Supernova” is the explosion or the resulting celestial body? Is it incorrect to call the explosion “supernova”?Are there observable changes in a star about to become supernova, minutes or hours before the explosion?Does a kilonova leave a high mass remnant?Is there a possibility that a white dwarf can turn into a neutron star or a black hole?
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$begingroup$
Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.
Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?
supernova explosion
New contributor
$endgroup$
add a comment |
$begingroup$
Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.
Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?
supernova explosion
New contributor
$endgroup$
$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago
$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago
$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago
1
$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago
2
$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago
add a comment |
$begingroup$
Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.
Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?
supernova explosion
New contributor
$endgroup$
Following a supernova explosion a star will turn into a white dwarf, neutron star, black hole, or just a stellar dust & gas leftover.
Excluding the latter case, why and how does matter stays collapsed, after such an event where matter is burst and scattered in space?
supernova explosion
supernova explosion
New contributor
New contributor
edited 7 hours ago
Riccardo
New contributor
asked 9 hours ago
RiccardoRiccardo
1363 bronze badges
1363 bronze badges
New contributor
New contributor
$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago
$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago
$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago
1
$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago
2
$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago
add a comment |
$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago
$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago
$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago
1
$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago
2
$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago
$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago
$begingroup$
The answer is gravity. White dwarfs are not a possible product of supernovae.
$endgroup$
– Rob Jeffries
8 hours ago
$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago
$begingroup$
It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
$endgroup$
– Steve Linton
8 hours ago
$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago
$begingroup$
Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
$endgroup$
– Riccardo
8 hours ago
1
1
$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago
$begingroup$
@uhoh I meant dust & gas
$endgroup$
– Riccardo
4 hours ago
2
2
$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago
$begingroup$
@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
$endgroup$
– Steve Linton
4 hours ago
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
Found the answer on NASA site
The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!
This means the core survives the blast somehow
New contributor
$endgroup$
add a comment |
$begingroup$
In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.
Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..
$endgroup$
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
add a comment |
$begingroup$
In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.
At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.
This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.
The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.
$endgroup$
add a comment |
$begingroup$
After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.
$endgroup$
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
$begingroup$
I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
add a comment |
$begingroup$
What's missing from the above explanations is what is really going on that causes any kind of explosion at all.
I'm going to steal from xkcd to help with this:
https://what-if.xkcd.com/73/
Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.
Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.
I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.
$endgroup$
add a comment |
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5 Answers
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oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Found the answer on NASA site
The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!
This means the core survives the blast somehow
New contributor
$endgroup$
add a comment |
$begingroup$
Found the answer on NASA site
The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!
This means the core survives the blast somehow
New contributor
$endgroup$
add a comment |
$begingroup$
Found the answer on NASA site
The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!
This means the core survives the blast somehow
New contributor
$endgroup$
Found the answer on NASA site
The collapse happens so quickly that it creates enormous shock waves that cause the outer part of the star to explode!
This means the core survives the blast somehow
New contributor
New contributor
answered 4 hours ago
RiccardoRiccardo
1363 bronze badges
1363 bronze badges
New contributor
New contributor
add a comment |
add a comment |
$begingroup$
In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.
Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..
$endgroup$
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
add a comment |
$begingroup$
In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.
Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..
$endgroup$
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
add a comment |
$begingroup$
In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.
Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..
$endgroup$
In a star, there are two opposing forces which usually balance each other Gravity is a force which induces collapse, while radiation pressure from the fusion reactions within resists the tendency to collapse. Small, sun-like stars, when they have used up most of their hydrogen fuel, will start "burning" helium and become red giants. When the helium runs out they will puff off their outer layers in a nova and collapse to form a white dwarf about the size of Earth. These white dwarfs are amazingly dense and heavy, because most of the mass of the original star has been compressed into a comparatively tiny volume. Further collapse is resisted by a force called electron degeneracy pressure.
Stars much larger than the sun will go on fusing elements beyond helium, building up layers of successively heavier elements until they reach iron. Fusion of elements beyond iron requires an input of energy rather than producing any, and the nuclear fires go out, so deprived of support from radiation pressure the outer layers of the star collapse, producing a supernova explosion. Electron degeneracy pressure is not enough to prevent a more drastic collapse than occurs with much smaller stars. According to the mass of the collapsing star, this will either result in the formation of a neutron star, which is like a gigantic atomic nucleus of incredible density about 6 miles across but containing a mass equivalent to several of our suns, or it will collapse further to form a black hole singularity in which matter enters a state not fully understood by science. Our sun, by the way, is 860,000 miles in diameter..
answered 8 hours ago
Michael WalsbyMichael Walsby
9471 silver badge6 bronze badges
9471 silver badge6 bronze badges
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
add a comment |
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
This doesn't address the question at all.
$endgroup$
– Rob Jeffries
46 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
$begingroup$
Matter stays collapsed because of the immense gravitational fields these supernovae remnants have. I'd have thought that was obvious.
$endgroup$
– Michael Walsby
12 mins ago
add a comment |
$begingroup$
In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.
At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.
This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.
The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.
$endgroup$
add a comment |
$begingroup$
In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.
At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.
This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.
The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.
$endgroup$
add a comment |
$begingroup$
In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.
At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.
This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.
The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.
$endgroup$
In order to "blow something up" you need to release more energy than its binding energy and have a way of trapping that energy so it can't escape in another way.
At the centre of a core collapse supernovae is a 10 km radius, $1.4 M_odot$ ball of (almost) neutrons.
Its gravitational binding energy is $sim GM^2/R = 5times 10^46$ J.
This is almost exactly how much energy is released by the collapse of the core from a much larger size, and since some of that energy goes into dissociating iron nuclei and making neutrons (both endothermic processes) and most of the rest escapes in the form of neutrinos, then there isn't enough energy to unbind the core. A tiny fraction (1%) is transferred to the envelope of the original star, which is enough to overcome its gravitational binding energy.
The case of a type Ia supernova (an exploding white dwarf) is quite different. Here the energy comes from a thermonuclear detonation of all the carbon and oxygen that make up the white dwarf, to form iron peak elements. This exothermic process releases enough energy to unbind the original star and it is completely destroyed.
edited 37 mins ago
answered 47 mins ago
Rob JeffriesRob Jeffries
58.9k4 gold badges122 silver badges193 bronze badges
58.9k4 gold badges122 silver badges193 bronze badges
add a comment |
add a comment |
$begingroup$
After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.
$endgroup$
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
$begingroup$
I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
add a comment |
$begingroup$
After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.
$endgroup$
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
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I think the point of the original question is how this happens, not that it does.
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– Carl Witthoft
2 hours ago
add a comment |
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After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.
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After a supernova explosion, the event might leave a compact object as a neutron star or a blackhole. The object can still accrete materials such as from fall back accretion or its companion star. If the object is a neutron star, it might further collapse into a blackhole.
answered 4 hours ago
Kornpob BhirombhakdiKornpob Bhirombhakdi
1,1312 silver badges9 bronze badges
1,1312 silver badges9 bronze badges
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That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
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– Riccardo
4 hours ago
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I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
add a comment |
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
$begingroup$
I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
$begingroup$
That's the question ! How can the core survive such an explosion that will scatter matter over 11 light years? That's the size of the Crab Nebula....
$endgroup$
– Riccardo
4 hours ago
$begingroup$
I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
$begingroup$
I think the point of the original question is how this happens, not that it does.
$endgroup$
– Carl Witthoft
2 hours ago
add a comment |
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What's missing from the above explanations is what is really going on that causes any kind of explosion at all.
I'm going to steal from xkcd to help with this:
https://what-if.xkcd.com/73/
Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.
Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.
I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.
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add a comment |
$begingroup$
What's missing from the above explanations is what is really going on that causes any kind of explosion at all.
I'm going to steal from xkcd to help with this:
https://what-if.xkcd.com/73/
Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.
Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.
I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.
$endgroup$
add a comment |
$begingroup$
What's missing from the above explanations is what is really going on that causes any kind of explosion at all.
I'm going to steal from xkcd to help with this:
https://what-if.xkcd.com/73/
Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.
Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.
I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.
$endgroup$
What's missing from the above explanations is what is really going on that causes any kind of explosion at all.
I'm going to steal from xkcd to help with this:
https://what-if.xkcd.com/73/
Ultimately, when the star is in it's dying moments, it starts emitting neutrinos. A lot of neutrinos... with a lot of energy. Now, I'm sure you're thinking "what would that do... they don't weigh much of anything". But this is literally like being buried in a football stadium with ants... there are so many neutrinos packing so much energy that they literally cause the outer matter of the star to be blown outwards with large enough energy to carry it away from the gravity well of the remaining matter.
Ah... but how does any matter remain? Because close to the center, the gravity well is deepest, and also close to the center any particle (nucleus/neutron) is being bombarded just about equally in all directions by neutrinos... so the total momentum effectively cancels to zero. Some of the matter is moved a bit... but falls back into the very deep gravity well.
I'm sure it would be a sight to behold... for that brief moment before you were vaporized by neutrinos (and all the other energy) at least.
answered 7 mins ago
Reginald BlueReginald Blue
1243 bronze badges
1243 bronze badges
add a comment |
add a comment |
Riccardo is a new contributor. Be nice, and check out our Code of Conduct.
Riccardo is a new contributor. Be nice, and check out our Code of Conduct.
Riccardo is a new contributor. Be nice, and check out our Code of Conduct.
Riccardo is a new contributor. Be nice, and check out our Code of Conduct.
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The answer is gravity. White dwarfs are not a possible product of supernovae.
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– Rob Jeffries
8 hours ago
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It's the other way. The collapse comes first anf the explosion afterwards. Basically the core of the stay collapses and the outer part falls in to fill the void, gets very hot (partlyu as a result of energy radiated by the collapsing core and partly from its own fall) and fuses explosively.
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– Steve Linton
8 hours ago
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Steve, this is what the question is about. Following the explosion a neutron star or black whole may be left in place. Why does the matter left after the explosion stays collapsed in so dense objects? maybe the nova explosion expels only some part of the collapsing star?
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– Riccardo
8 hours ago
1
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@uhoh I meant dust & gas
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– Riccardo
4 hours ago
2
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@riccardo exactly so. The explosion happens around the collapsed core of the star, blowing the outer layers outwards, but leaving the core, in some cases intact
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– Steve Linton
4 hours ago