Maxima of Brownian motionExact simulation of SDEStochastic Integration via Skorohod RepresentationWhat is quantum Brownian motion?Tail for the integral of a diffusion processDoes the variance of a continuous time, time homogeneous, Markov process starting from one point necessarily not decrease?Stochastic differential equation associated with an optimal control problemLaw of motion when initial condition is perturbedLaplace transform of a integral function of CIR/CEV processFeller property for Ito diffusion with Lipschitz coefficientsJoint distribution of integrals of diffusion and driving noise
Maxima of Brownian motion
Exact simulation of SDEStochastic Integration via Skorohod RepresentationWhat is quantum Brownian motion?Tail for the integral of a diffusion processDoes the variance of a continuous time, time homogeneous, Markov process starting from one point necessarily not decrease?Stochastic differential equation associated with an optimal control problemLaw of motion when initial condition is perturbedLaplace transform of a integral function of CIR/CEV processFeller property for Ito diffusion with Lipschitz coefficientsJoint distribution of integrals of diffusion and driving noise
$begingroup$
It is well-known that Brownian motion attains infinitely many maxima in each time interval $[0,T]$ a.s..
From a physics perspective it seems reasonable that when the disorder of the path of a particle decreases and the motion becomes more deterministic, then the number of maxima should decrease.
But I could not find anything on that. Now, there were two natural things to look at:
Is there a way to quantify that a Brownian motion with large variance (large disorder) has more maxima than one with little disorder?
Or is there a way to say that a diffusion process
$dX_t = mu (X_t) dt + alpha dB_t $
has "less" maxima when $alpha $ is small compared to $alpha$ large?
I guess it is hard to make this question more precise, since this is not a question of cardinality of maxima but more about finding a suitably chosen measure that could capture such an effect.
pr.probability stochastic-processes probability-distributions stochastic-calculus
asked 8 hours ago
SaschaSascha
541216
$endgroup$
|
show 1 more comment
$begingroup$
It is well-known that Brownian motion attains infinitely many maxima in each time interval $[0,T]$ a.s..
From a physics perspective it seems reasonable that when the disorder of the path of a particle decreases and the motion becomes more deterministic, then the number of maxima should decrease.
But I could not find anything on that. Now, there were two natural things to look at:
Is there a way to quantify that a Brownian motion with large variance (large disorder) has more maxima than one with little disorder?
Or is there a way to say that a diffusion process
$dX_t = mu (X_t) dt + alpha dB_t $
has "less" maxima when $alpha $ is small compared to $alpha$ large?
I guess it is hard to make this question more precise, since this is not a question of cardinality of maxima but more about finding a suitably chosen measure that could capture such an effect.
pr.probability stochastic-processes probability-distributions stochastic-calculus
asked 8 hours ago
SaschaSascha
541216
$endgroup$
1
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago
|
show 1 more comment
$begingroup$
It is well-known that Brownian motion attains infinitely many maxima in each time interval $[0,T]$ a.s..
From a physics perspective it seems reasonable that when the disorder of the path of a particle decreases and the motion becomes more deterministic, then the number of maxima should decrease.
But I could not find anything on that. Now, there were two natural things to look at:
Is there a way to quantify that a Brownian motion with large variance (large disorder) has more maxima than one with little disorder?
Or is there a way to say that a diffusion process
$dX_t = mu (X_t) dt + alpha dB_t $
has "less" maxima when $alpha $ is small compared to $alpha$ large?
I guess it is hard to make this question more precise, since this is not a question of cardinality of maxima but more about finding a suitably chosen measure that could capture such an effect.
pr.probability stochastic-processes probability-distributions stochastic-calculus
asked 8 hours ago
SaschaSascha
541216
$endgroup$
It is well-known that Brownian motion attains infinitely many maxima in each time interval $[0,T]$ a.s..
From a physics perspective it seems reasonable that when the disorder of the path of a particle decreases and the motion becomes more deterministic, then the number of maxima should decrease.
But I could not find anything on that. Now, there were two natural things to look at:
Is there a way to quantify that a Brownian motion with large variance (large disorder) has more maxima than one with little disorder?
Or is there a way to say that a diffusion process
$dX_t = mu (X_t) dt + alpha dB_t $
has "less" maxima when $alpha $ is small compared to $alpha$ large?
I guess it is hard to make this question more precise, since this is not a question of cardinality of maxima but more about finding a suitably chosen measure that could capture such an effect.
pr.probability stochastic-processes probability-distributions stochastic-calculus
pr.probability stochastic-processes probability-distributions stochastic-calculus
asked 8 hours ago
SaschaSascha
541216
asked 8 hours ago
SaschaSascha
541216
asked 8 hours ago
SaschaSascha
541216
asked 8 hours ago
SaschaSascha
541216
asked 8 hours ago
SaschaSascha
541216
541216
1
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago
|
show 1 more comment
1
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago
1
1
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago
|
show 1 more comment
1 Answer
1
active
oldest
votes
$begingroup$
A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $alpha B_cdot$, and if the drift is nice enough to have absolute continuity, the same holds for your drifted diffusion.
This however changes when you move from BM to fractional BM, which I would suggest is the right frame for your question. There, the change in regularity is reflected in the Hausdorff dimension of the set of zeros. See
https://projecteuclid.org/download/pdfview_1/euclid.ecp/1522375381 for details.
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
$endgroup$
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
add a comment |
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1 Answer
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1 Answer
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$begingroup$
A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $alpha B_cdot$, and if the drift is nice enough to have absolute continuity, the same holds for your drifted diffusion.
This however changes when you move from BM to fractional BM, which I would suggest is the right frame for your question. There, the change in regularity is reflected in the Hausdorff dimension of the set of zeros. See
https://projecteuclid.org/download/pdfview_1/euclid.ecp/1522375381 for details.
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
$endgroup$
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
add a comment |
$begingroup$
A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $alpha B_cdot$, and if the drift is nice enough to have absolute continuity, the same holds for your drifted diffusion.
This however changes when you move from BM to fractional BM, which I would suggest is the right frame for your question. There, the change in regularity is reflected in the Hausdorff dimension of the set of zeros. See
https://projecteuclid.org/download/pdfview_1/euclid.ecp/1522375381 for details.
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
$endgroup$
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
add a comment |
$begingroup$
A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $alpha B_cdot$, and if the drift is nice enough to have absolute continuity, the same holds for your drifted diffusion.
This however changes when you move from BM to fractional BM, which I would suggest is the right frame for your question. There, the change in regularity is reflected in the Hausdorff dimension of the set of zeros. See
https://projecteuclid.org/download/pdfview_1/euclid.ecp/1522375381 for details.
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
$endgroup$
A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $alpha B_cdot$, and if the drift is nice enough to have absolute continuity, the same holds for your drifted diffusion.
This however changes when you move from BM to fractional BM, which I would suggest is the right frame for your question. There, the change in regularity is reflected in the Hausdorff dimension of the set of zeros. See
https://projecteuclid.org/download/pdfview_1/euclid.ecp/1522375381 for details.
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
answered 7 hours ago
ofer zeitouniofer zeitouni
5,46011432
5,46011432
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
add a comment |
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
$begingroup$
thank you, I appreciate it very much that you tried to make sense out of my question.
$endgroup$
– Sascha
7 hours ago
add a comment |
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1
$begingroup$
This doesn't really match my intuition. If we drop the drift term (so $mu = 0$), then increasing the variance really just stretches the Brownian motion vertically, which in my book has no effect on the "number" of maxima.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge mhmm, but you would agree that if a particle that performs a deterministic walk has a more "straight motion" whereas a disordered motion has more change of direction and therefore more maxima? Perhaps there is a better to capture this behaviour?-I just wanted to present two starting ideas to model such an effect (which may be wrong?)
$endgroup$
– Sascha
7 hours ago
$begingroup$
Sure, but in this case I think that's just the difference between $alpha = 0$ and $alpha ne 0$. It's more of an abrupt "phase transition", to abuse physics terminology, than a continuous change.
$endgroup$
– Nate Eldredge
7 hours ago
$begingroup$
@NateEldredge I understand, but maybe if you look at fractal dimensions, one could see something like that?-Sorry, I am just trying to bounce ideas. I am sorry that my question is not purely technical.
$endgroup$
– Sascha
7 hours ago
$begingroup$
Fractal dimension won't do it, as that's also invariant under scaling. The graph of a Brownian motion has Hausdorff dimension $3/2$ a.s. for every $alpha ne 0$. I don't know off the top of my head whether the $3/2$-dimensional Hausdorff measure is zero or nonzero; if it's nonzero, then of course it will scale with $alpha$ in an appropriate way.
$endgroup$
– Nate Eldredge
7 hours ago