Partitioning values in a sequenceOrdering the elements in a list and separate them into sublists for plottingFinding all partitions of a setPartitioning an image based on featuresPartition list into a given number of sub-listsPartitioning List Into Sublists of Length 2 With The Pairing Being RandomCluster numbers into n partitions so that each partitions sum is closest to total/nEfficient lazy weak compositionsTiming and memory use is critical:fast partitioning of binary sparse arrayVariable iterator in Do Loop (splitting a list)Non-Constant Partitioning of a List with Order AnalysisTotally orderless partition
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Partitioning values in a sequence
Ordering the elements in a list and separate them into sublists for plottingFinding all partitions of a setPartitioning an image based on featuresPartition list into a given number of sub-listsPartitioning List Into Sublists of Length 2 With The Pairing Being RandomCluster numbers into n partitions so that each partitions sum is closest to total/nEfficient lazy weak compositionsTiming and memory use is critical:fast partitioning of binary sparse arrayVariable iterator in Do Loop (splitting a list)Non-Constant Partitioning of a List with Order AnalysisTotally orderless partition
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 4 mins ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
add a comment |
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 4 mins ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 4 mins ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
partitions
edited 4 mins ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
edited 4 mins ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
edited 4 mins ago
user64494
3,65311122
edited 4 mins ago
user64494
3,65311122
edited 4 mins ago
user64494
3,65311122
3,65311122
asked 5 hours ago
Jamie MJamie M
475
asked 5 hours ago
Jamie MJamie M
475
asked 5 hours ago
Jamie MJamie M
475
475
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
edited 4 hours ago
answered 5 hours ago
KagaratschKagaratsch
4,87531348
answered 5 hours ago
KagaratschKagaratsch
4,87531348
answered 5 hours ago
KagaratschKagaratsch
4,87531348
4,87531348
add a comment |
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
answered 1 hour ago
Bob HanlonBob Hanlon
61.9k33598
61.9k33598
add a comment |
add a comment |
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$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago