Raspberry pi run commands on bootAccess denied when starting systemd serviceNode.Js on raspbian not found with SudoFailed install of Python3.4.3 on Raspberry PiError when attempting to create Python GUI using Tkinter: “no display name and no $DISPLAY environment variable”Default python version and pip problemPython script does not run when called by serviceExecuting multiple scripts on startup in a particular orderRaspberry pi starting shell script at boot not working

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Raspberry pi run commands on boot

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Raspberry pi run commands on boot


Access denied when starting systemd serviceNode.Js on raspbian not found with SudoFailed install of Python3.4.3 on Raspberry PiError when attempting to create Python GUI using Tkinter: “no display name and no $DISPLAY environment variable”Default python version and pip problemPython script does not run when called by serviceExecuting multiple scripts on startup in a particular orderRaspberry pi starting shell script at boot not working






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margin-bottom:0;









1

















I thought that running commands on raspberry pi on boot was the easiest thing in my project. But it seems that it is complex enough not to work.



I've searched a lot on the internet on a simple objective that I couldn't solve yet. All I want to do is to launch chromium normally (not in full-screen mode or any other setting). I also need to start node.js server on boot.



I've followed this website but that didn't help at all.



I kept on seeing gnome-scheduler that is a GUI application that is supposed to run commands on boot. Now this package is deprecated, but I found previous versions at launchpad that I downloaded but I know nothing about how and where to put the downloaded files in order to work.



In the convenience of what I am looking for, I made a python script that is supposed to open a URL in chromium. And the issue should be simplified if I just put the two commands :



  • Run Python (Open URL in Chromium)

  • Start listening on Node.js server

But after using all the methods that were stated at the above tutorial none seem to work. Maybe the problem is that when the raspberry pi is booting other services doesn't seem to load completely.




OS: Raspbian Linux




The method I am working on is SYSTEMD:



import webbrowser
import time

time.sleep(30) #To debug if latency is the problem
webbrowser.open('https://www.google.com')
print("Hey There Log File! I made it till here!")


But this python script doesn't run because when I check the log file it is empty neither anything is printed nor the browser opens why?



Edit:
Write a new Unit file sudo nano /lib/systemd/system/sample.service



Inserting code:



[Unit]
Description=My Sample Service
After=multi-user.target

[Service]
Type=idle
ExecStart=/usr/bin/python3 /home/pi/sample.py

[Install]
WantedBy=multi-user.target


In order to store the script’s text output in a log file, you can change the ExecStart line to:



ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1



The permission on the unit file needs to be set to 644 :



sudo chmod 644 /lib/systemd/system/sample.service



Now the unit file has been defined we can tell systemd to start it during the boot sequence :



sudo systemctl daemon-reload
sudo systemctl enable sample.service


Then reboot raspberry-pi.










share|improve this question









New contributor



Youssof H. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.























  • This tutorial worked well to launch scripts on startup: instructables.com/id/…

    – raspberrypitime
    8 hours ago











  • Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

    – goldilocks
    5 hours ago












  • time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

    – goldilocks
    5 hours ago











  • @goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

    – Youssof H.
    5 hours ago

















1

















I thought that running commands on raspberry pi on boot was the easiest thing in my project. But it seems that it is complex enough not to work.



I've searched a lot on the internet on a simple objective that I couldn't solve yet. All I want to do is to launch chromium normally (not in full-screen mode or any other setting). I also need to start node.js server on boot.



I've followed this website but that didn't help at all.



I kept on seeing gnome-scheduler that is a GUI application that is supposed to run commands on boot. Now this package is deprecated, but I found previous versions at launchpad that I downloaded but I know nothing about how and where to put the downloaded files in order to work.



In the convenience of what I am looking for, I made a python script that is supposed to open a URL in chromium. And the issue should be simplified if I just put the two commands :



  • Run Python (Open URL in Chromium)

  • Start listening on Node.js server

But after using all the methods that were stated at the above tutorial none seem to work. Maybe the problem is that when the raspberry pi is booting other services doesn't seem to load completely.




OS: Raspbian Linux




The method I am working on is SYSTEMD:



import webbrowser
import time

time.sleep(30) #To debug if latency is the problem
webbrowser.open('https://www.google.com')
print("Hey There Log File! I made it till here!")


But this python script doesn't run because when I check the log file it is empty neither anything is printed nor the browser opens why?



Edit:
Write a new Unit file sudo nano /lib/systemd/system/sample.service



Inserting code:



[Unit]
Description=My Sample Service
After=multi-user.target

[Service]
Type=idle
ExecStart=/usr/bin/python3 /home/pi/sample.py

[Install]
WantedBy=multi-user.target


In order to store the script’s text output in a log file, you can change the ExecStart line to:



ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1



The permission on the unit file needs to be set to 644 :



sudo chmod 644 /lib/systemd/system/sample.service



Now the unit file has been defined we can tell systemd to start it during the boot sequence :



sudo systemctl daemon-reload
sudo systemctl enable sample.service


Then reboot raspberry-pi.










share|improve this question









New contributor



Youssof H. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.























  • This tutorial worked well to launch scripts on startup: instructables.com/id/…

    – raspberrypitime
    8 hours ago











  • Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

    – goldilocks
    5 hours ago












  • time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

    – goldilocks
    5 hours ago











  • @goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

    – Youssof H.
    5 hours ago













1












1








1








I thought that running commands on raspberry pi on boot was the easiest thing in my project. But it seems that it is complex enough not to work.



I've searched a lot on the internet on a simple objective that I couldn't solve yet. All I want to do is to launch chromium normally (not in full-screen mode or any other setting). I also need to start node.js server on boot.



I've followed this website but that didn't help at all.



I kept on seeing gnome-scheduler that is a GUI application that is supposed to run commands on boot. Now this package is deprecated, but I found previous versions at launchpad that I downloaded but I know nothing about how and where to put the downloaded files in order to work.



In the convenience of what I am looking for, I made a python script that is supposed to open a URL in chromium. And the issue should be simplified if I just put the two commands :



  • Run Python (Open URL in Chromium)

  • Start listening on Node.js server

But after using all the methods that were stated at the above tutorial none seem to work. Maybe the problem is that when the raspberry pi is booting other services doesn't seem to load completely.




OS: Raspbian Linux




The method I am working on is SYSTEMD:



import webbrowser
import time

time.sleep(30) #To debug if latency is the problem
webbrowser.open('https://www.google.com')
print("Hey There Log File! I made it till here!")


But this python script doesn't run because when I check the log file it is empty neither anything is printed nor the browser opens why?



Edit:
Write a new Unit file sudo nano /lib/systemd/system/sample.service



Inserting code:



[Unit]
Description=My Sample Service
After=multi-user.target

[Service]
Type=idle
ExecStart=/usr/bin/python3 /home/pi/sample.py

[Install]
WantedBy=multi-user.target


In order to store the script’s text output in a log file, you can change the ExecStart line to:



ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1



The permission on the unit file needs to be set to 644 :



sudo chmod 644 /lib/systemd/system/sample.service



Now the unit file has been defined we can tell systemd to start it during the boot sequence :



sudo systemctl daemon-reload
sudo systemctl enable sample.service


Then reboot raspberry-pi.










share|improve this question









New contributor



Youssof H. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I thought that running commands on raspberry pi on boot was the easiest thing in my project. But it seems that it is complex enough not to work.



I've searched a lot on the internet on a simple objective that I couldn't solve yet. All I want to do is to launch chromium normally (not in full-screen mode or any other setting). I also need to start node.js server on boot.



I've followed this website but that didn't help at all.



I kept on seeing gnome-scheduler that is a GUI application that is supposed to run commands on boot. Now this package is deprecated, but I found previous versions at launchpad that I downloaded but I know nothing about how and where to put the downloaded files in order to work.



In the convenience of what I am looking for, I made a python script that is supposed to open a URL in chromium. And the issue should be simplified if I just put the two commands :



  • Run Python (Open URL in Chromium)

  • Start listening on Node.js server

But after using all the methods that were stated at the above tutorial none seem to work. Maybe the problem is that when the raspberry pi is booting other services doesn't seem to load completely.




OS: Raspbian Linux




The method I am working on is SYSTEMD:



import webbrowser
import time

time.sleep(30) #To debug if latency is the problem
webbrowser.open('https://www.google.com')
print("Hey There Log File! I made it till here!")


But this python script doesn't run because when I check the log file it is empty neither anything is printed nor the browser opens why?



Edit:
Write a new Unit file sudo nano /lib/systemd/system/sample.service



Inserting code:



[Unit]
Description=My Sample Service
After=multi-user.target

[Service]
Type=idle
ExecStart=/usr/bin/python3 /home/pi/sample.py

[Install]
WantedBy=multi-user.target


In order to store the script’s text output in a log file, you can change the ExecStart line to:



ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1



The permission on the unit file needs to be set to 644 :



sudo chmod 644 /lib/systemd/system/sample.service



Now the unit file has been defined we can tell systemd to start it during the boot sequence :



sudo systemctl daemon-reload
sudo systemctl enable sample.service


Then reboot raspberry-pi.







python boot node.js






share|improve this question









New contributor



Youssof H. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









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Check out our Code of Conduct.








share|improve this question




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share|improve this question








edited 4 hours ago







Youssof H.













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asked 8 hours ago









Youssof H.Youssof H.

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Check out our Code of Conduct.




New contributor




Youssof H. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • This tutorial worked well to launch scripts on startup: instructables.com/id/…

    – raspberrypitime
    8 hours ago











  • Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

    – goldilocks
    5 hours ago












  • time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

    – goldilocks
    5 hours ago











  • @goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

    – Youssof H.
    5 hours ago

















  • This tutorial worked well to launch scripts on startup: instructables.com/id/…

    – raspberrypitime
    8 hours ago











  • Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

    – goldilocks
    5 hours ago












  • time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

    – goldilocks
    5 hours ago











  • @goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

    – Youssof H.
    5 hours ago
















This tutorial worked well to launch scripts on startup: instructables.com/id/…

– raspberrypitime
8 hours ago





This tutorial worked well to launch scripts on startup: instructables.com/id/…

– raspberrypitime
8 hours ago













Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

– goldilocks
5 hours ago






Welcome -- you need to provide more information: 1) "when I check the log file it is empty " What log file? The code you have posted prints to standard output which means it is probably discarded. 2) "The method I am working on is SYSTEMD:" Then please include the service file you created.

– goldilocks
5 hours ago














time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

– goldilocks
5 hours ago





time.sleep(30) #To debug if latency is the problem It will be if the program does not properly background itself; it will be killed at some point because of that.

– goldilocks
5 hours ago













@goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

– Youssof H.
5 hours ago





@goldilocks The information you want me to give is the same as in the tutorial. And I used time.sleep(30) after realizing that the code doesn't work. But it is a good point of view. Thanks.

– Youssof H.
5 hours ago










2 Answers
2






active

oldest

votes


















1


















If you're expecting a GUI browser to open, the DISPLAY environment variable may need to be explicitly set so that the browser the webbrowser module opens knows where to show itself. Otherwise it would likely not start at all and instead crash, not finding a valid GUI. For a systemd.service, you would do this by adding the line



Environment=DISPLAY=:0


to the [Service] section of the file before the ExecStart. You may instead need to specify the XAUTHORITY environment variable, as described here due to the service running as a different user. In which case the line to add would be



Environment=XAUTHORITY=/home/pi/.Xauthority


where 'pi' is the username the startup X instance runs as.



The reason you may not be seeing the printed log statement is a crash out of the script, the webbrowser has started a command line only browser, like links, and is waiting, or the GUI has not yet started when the python script finally gets to launching the browser.



If the sole purpose of the python script is to open a browser however, I would recommend directly starting the browser instead of relying on a Python script to do that. If you are concerned about the browser starting after node.js or the GUI, systemd service dependencies can be used to ensure it starts after those two using, e.g., Wants=mynodejs.service lines, see here for more details.






share|improve this answer


























  • The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

    – goldilocks
    3 hours ago



















1



















In order to store the script’s text output in a log file, you can change the ExecStart line to: ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1




This is wrong, although I notice there are a few raspberry pi oriented tutorials that claim it will work.



It will not work because > (and 2>&1) are POSIX shell operations, but you are not invoking this via a shell (as you would from the commandline). It's executed by systemd and all that stuff will be passed to the command (/usr/bin/python) as arguments in addition to the script path which probably causes python to exit with an error.



You need to use these directives as explained in man systemd.exec:



StandardOutput=file:/home/pi/sample.log 
StandardError=file:/home/pi/sample.log


You should test this with:



sudo systemctl start sample.service
sudo systemctl status sample.service


The last command is important because the first one alone may not provide you with all the relevant information. If you do this with sample.service as is (ie., don't fix the redirects), you will probably see the python error output.



Note that if you modify the service file after using systemctl enable you should run systemctl daemon-reload. However, you can test it directly without enabling it.






share|improve this answer



























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    2 Answers
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    2 Answers
    2






    active

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    active

    oldest

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    active

    oldest

    votes









    1


















    If you're expecting a GUI browser to open, the DISPLAY environment variable may need to be explicitly set so that the browser the webbrowser module opens knows where to show itself. Otherwise it would likely not start at all and instead crash, not finding a valid GUI. For a systemd.service, you would do this by adding the line



    Environment=DISPLAY=:0


    to the [Service] section of the file before the ExecStart. You may instead need to specify the XAUTHORITY environment variable, as described here due to the service running as a different user. In which case the line to add would be



    Environment=XAUTHORITY=/home/pi/.Xauthority


    where 'pi' is the username the startup X instance runs as.



    The reason you may not be seeing the printed log statement is a crash out of the script, the webbrowser has started a command line only browser, like links, and is waiting, or the GUI has not yet started when the python script finally gets to launching the browser.



    If the sole purpose of the python script is to open a browser however, I would recommend directly starting the browser instead of relying on a Python script to do that. If you are concerned about the browser starting after node.js or the GUI, systemd service dependencies can be used to ensure it starts after those two using, e.g., Wants=mynodejs.service lines, see here for more details.






    share|improve this answer


























    • The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

      – goldilocks
      3 hours ago
















    1


















    If you're expecting a GUI browser to open, the DISPLAY environment variable may need to be explicitly set so that the browser the webbrowser module opens knows where to show itself. Otherwise it would likely not start at all and instead crash, not finding a valid GUI. For a systemd.service, you would do this by adding the line



    Environment=DISPLAY=:0


    to the [Service] section of the file before the ExecStart. You may instead need to specify the XAUTHORITY environment variable, as described here due to the service running as a different user. In which case the line to add would be



    Environment=XAUTHORITY=/home/pi/.Xauthority


    where 'pi' is the username the startup X instance runs as.



    The reason you may not be seeing the printed log statement is a crash out of the script, the webbrowser has started a command line only browser, like links, and is waiting, or the GUI has not yet started when the python script finally gets to launching the browser.



    If the sole purpose of the python script is to open a browser however, I would recommend directly starting the browser instead of relying on a Python script to do that. If you are concerned about the browser starting after node.js or the GUI, systemd service dependencies can be used to ensure it starts after those two using, e.g., Wants=mynodejs.service lines, see here for more details.






    share|improve this answer


























    • The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

      – goldilocks
      3 hours ago














    1














    1










    1









    If you're expecting a GUI browser to open, the DISPLAY environment variable may need to be explicitly set so that the browser the webbrowser module opens knows where to show itself. Otherwise it would likely not start at all and instead crash, not finding a valid GUI. For a systemd.service, you would do this by adding the line



    Environment=DISPLAY=:0


    to the [Service] section of the file before the ExecStart. You may instead need to specify the XAUTHORITY environment variable, as described here due to the service running as a different user. In which case the line to add would be



    Environment=XAUTHORITY=/home/pi/.Xauthority


    where 'pi' is the username the startup X instance runs as.



    The reason you may not be seeing the printed log statement is a crash out of the script, the webbrowser has started a command line only browser, like links, and is waiting, or the GUI has not yet started when the python script finally gets to launching the browser.



    If the sole purpose of the python script is to open a browser however, I would recommend directly starting the browser instead of relying on a Python script to do that. If you are concerned about the browser starting after node.js or the GUI, systemd service dependencies can be used to ensure it starts after those two using, e.g., Wants=mynodejs.service lines, see here for more details.






    share|improve this answer














    If you're expecting a GUI browser to open, the DISPLAY environment variable may need to be explicitly set so that the browser the webbrowser module opens knows where to show itself. Otherwise it would likely not start at all and instead crash, not finding a valid GUI. For a systemd.service, you would do this by adding the line



    Environment=DISPLAY=:0


    to the [Service] section of the file before the ExecStart. You may instead need to specify the XAUTHORITY environment variable, as described here due to the service running as a different user. In which case the line to add would be



    Environment=XAUTHORITY=/home/pi/.Xauthority


    where 'pi' is the username the startup X instance runs as.



    The reason you may not be seeing the printed log statement is a crash out of the script, the webbrowser has started a command line only browser, like links, and is waiting, or the GUI has not yet started when the python script finally gets to launching the browser.



    If the sole purpose of the python script is to open a browser however, I would recommend directly starting the browser instead of relying on a Python script to do that. If you are concerned about the browser starting after node.js or the GUI, systemd service dependencies can be used to ensure it starts after those two using, e.g., Wants=mynodejs.service lines, see here for more details.







    share|improve this answer













    share|improve this answer




    share|improve this answer



    share|improve this answer










    answered 7 hours ago









    FredFred

    3,56111 silver badges23 bronze badges




    3,56111 silver badges23 bronze badges















    • The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

      – goldilocks
      3 hours ago


















    • The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

      – goldilocks
      3 hours ago

















    The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

    – goldilocks
    3 hours ago






    The log print isn't happening because the OP used shell redirection >, 2>&1 in the ExecStart=command, which never invokes a shell (unless that's an explicit part of "command").

    – goldilocks
    3 hours ago














    1



















    In order to store the script’s text output in a log file, you can change the ExecStart line to: ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1




    This is wrong, although I notice there are a few raspberry pi oriented tutorials that claim it will work.



    It will not work because > (and 2>&1) are POSIX shell operations, but you are not invoking this via a shell (as you would from the commandline). It's executed by systemd and all that stuff will be passed to the command (/usr/bin/python) as arguments in addition to the script path which probably causes python to exit with an error.



    You need to use these directives as explained in man systemd.exec:



    StandardOutput=file:/home/pi/sample.log 
    StandardError=file:/home/pi/sample.log


    You should test this with:



    sudo systemctl start sample.service
    sudo systemctl status sample.service


    The last command is important because the first one alone may not provide you with all the relevant information. If you do this with sample.service as is (ie., don't fix the redirects), you will probably see the python error output.



    Note that if you modify the service file after using systemctl enable you should run systemctl daemon-reload. However, you can test it directly without enabling it.






    share|improve this answer






























      1



















      In order to store the script’s text output in a log file, you can change the ExecStart line to: ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1




      This is wrong, although I notice there are a few raspberry pi oriented tutorials that claim it will work.



      It will not work because > (and 2>&1) are POSIX shell operations, but you are not invoking this via a shell (as you would from the commandline). It's executed by systemd and all that stuff will be passed to the command (/usr/bin/python) as arguments in addition to the script path which probably causes python to exit with an error.



      You need to use these directives as explained in man systemd.exec:



      StandardOutput=file:/home/pi/sample.log 
      StandardError=file:/home/pi/sample.log


      You should test this with:



      sudo systemctl start sample.service
      sudo systemctl status sample.service


      The last command is important because the first one alone may not provide you with all the relevant information. If you do this with sample.service as is (ie., don't fix the redirects), you will probably see the python error output.



      Note that if you modify the service file after using systemctl enable you should run systemctl daemon-reload. However, you can test it directly without enabling it.






      share|improve this answer




























        1














        1










        1










        In order to store the script’s text output in a log file, you can change the ExecStart line to: ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1




        This is wrong, although I notice there are a few raspberry pi oriented tutorials that claim it will work.



        It will not work because > (and 2>&1) are POSIX shell operations, but you are not invoking this via a shell (as you would from the commandline). It's executed by systemd and all that stuff will be passed to the command (/usr/bin/python) as arguments in addition to the script path which probably causes python to exit with an error.



        You need to use these directives as explained in man systemd.exec:



        StandardOutput=file:/home/pi/sample.log 
        StandardError=file:/home/pi/sample.log


        You should test this with:



        sudo systemctl start sample.service
        sudo systemctl status sample.service


        The last command is important because the first one alone may not provide you with all the relevant information. If you do this with sample.service as is (ie., don't fix the redirects), you will probably see the python error output.



        Note that if you modify the service file after using systemctl enable you should run systemctl daemon-reload. However, you can test it directly without enabling it.






        share|improve this answer















        In order to store the script’s text output in a log file, you can change the ExecStart line to: ExecStart=/usr/bin/python /home/pi/sample.py > /home/pi/sample.log 2>&1




        This is wrong, although I notice there are a few raspberry pi oriented tutorials that claim it will work.



        It will not work because > (and 2>&1) are POSIX shell operations, but you are not invoking this via a shell (as you would from the commandline). It's executed by systemd and all that stuff will be passed to the command (/usr/bin/python) as arguments in addition to the script path which probably causes python to exit with an error.



        You need to use these directives as explained in man systemd.exec:



        StandardOutput=file:/home/pi/sample.log 
        StandardError=file:/home/pi/sample.log


        You should test this with:



        sudo systemctl start sample.service
        sudo systemctl status sample.service


        The last command is important because the first one alone may not provide you with all the relevant information. If you do this with sample.service as is (ie., don't fix the redirects), you will probably see the python error output.



        Note that if you modify the service file after using systemctl enable you should run systemctl daemon-reload. However, you can test it directly without enabling it.







        share|improve this answer













        share|improve this answer




        share|improve this answer



        share|improve this answer










        answered 4 hours ago









        goldilocksgoldilocks

        46.9k11 gold badges68 silver badges184 bronze badges




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