Is the following statement true: two real numbers a and b are equal iff for every ε > 0, |a − b| < ε.Are the following theorems' converses also true?How do I show convergence here?which of the following statement are true?Let $a_n$ be a sequence of real numbers. which one of the following is always true?Is it always true that $f$ is continuous at $c$ given the following conditionsQuick Answer Verification: When are two Norms/Operator Norms EqualThen which of the following statement(s) is(are) true? about uniform convergenceLet $A$ be the set of all functions $f:mathbbRtomathbbR$ that satisfy the following two properties.Which of the following statements are true for $A=tsin(frac1t) $?

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Is the following statement true: two real numbers a and b are equal iff for every ε > 0, |a − b|


Are the following theorems' converses also true?How do I show convergence here?which of the following statement are true?Let $a_n$ be a sequence of real numbers. which one of the following is always true?Is it always true that $f$ is continuous at $c$ given the following conditionsQuick Answer Verification: When are two Norms/Operator Norms EqualThen which of the following statement(s) is(are) true? about uniform convergenceLet $A$ be the set of all functions $f:mathbbRtomathbbR$ that satisfy the following two properties.Which of the following statements are true for $A=tsin(frac1t) $?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


I got that if a and b are equal then |a-b|=0 which is less than ε.
But I'm not sure if the converse also holds.










share|cite|improve this question







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s1234 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$













  • $begingroup$
    otherwise $|a-b| < frac2$ is false
    $endgroup$
    – mathworker21
    8 hours ago










  • $begingroup$
    The only nonnegative real number smaller than every positive numebr is $0$.
    $endgroup$
    – saulspatz
    8 hours ago

















2












$begingroup$


I got that if a and b are equal then |a-b|=0 which is less than ε.
But I'm not sure if the converse also holds.










share|cite|improve this question







New contributor



s1234 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    otherwise $|a-b| < frac2$ is false
    $endgroup$
    – mathworker21
    8 hours ago










  • $begingroup$
    The only nonnegative real number smaller than every positive numebr is $0$.
    $endgroup$
    – saulspatz
    8 hours ago













2












2








2





$begingroup$


I got that if a and b are equal then |a-b|=0 which is less than ε.
But I'm not sure if the converse also holds.










share|cite|improve this question







New contributor



s1234 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




I got that if a and b are equal then |a-b|=0 which is less than ε.
But I'm not sure if the converse also holds.







real-analysis






share|cite|improve this question







New contributor



s1234 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|cite|improve this question







New contributor



s1234 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 8 hours ago









s1234s1234

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  • $begingroup$
    otherwise $|a-b| < frac2$ is false
    $endgroup$
    – mathworker21
    8 hours ago










  • $begingroup$
    The only nonnegative real number smaller than every positive numebr is $0$.
    $endgroup$
    – saulspatz
    8 hours ago
















  • $begingroup$
    otherwise $|a-b| < frac2$ is false
    $endgroup$
    – mathworker21
    8 hours ago










  • $begingroup$
    The only nonnegative real number smaller than every positive numebr is $0$.
    $endgroup$
    – saulspatz
    8 hours ago















$begingroup$
otherwise $|a-b| < frac2$ is false
$endgroup$
– mathworker21
8 hours ago




$begingroup$
otherwise $|a-b| < frac2$ is false
$endgroup$
– mathworker21
8 hours ago












$begingroup$
The only nonnegative real number smaller than every positive numebr is $0$.
$endgroup$
– saulspatz
8 hours ago




$begingroup$
The only nonnegative real number smaller than every positive numebr is $0$.
$endgroup$
– saulspatz
8 hours ago










1 Answer
1






active

oldest

votes


















5













$begingroup$

You are correct. Here is a proof of the converse.



Suppose that $aneq b$.



Then $epsilon:=|a-b|>0$ but we do not have $|a-b|<epsilon$.






share|cite|improve this answer











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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

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    5













    $begingroup$

    You are correct. Here is a proof of the converse.



    Suppose that $aneq b$.



    Then $epsilon:=|a-b|>0$ but we do not have $|a-b|<epsilon$.






    share|cite|improve this answer











    $endgroup$



















      5













      $begingroup$

      You are correct. Here is a proof of the converse.



      Suppose that $aneq b$.



      Then $epsilon:=|a-b|>0$ but we do not have $|a-b|<epsilon$.






      share|cite|improve this answer











      $endgroup$

















        5














        5










        5







        $begingroup$

        You are correct. Here is a proof of the converse.



        Suppose that $aneq b$.



        Then $epsilon:=|a-b|>0$ but we do not have $|a-b|<epsilon$.






        share|cite|improve this answer











        $endgroup$



        You are correct. Here is a proof of the converse.



        Suppose that $aneq b$.



        Then $epsilon:=|a-b|>0$ but we do not have $|a-b|<epsilon$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 7 hours ago

























        answered 8 hours ago









        drhabdrhab

        112k5 gold badges49 silver badges141 bronze badges




        112k5 gold badges49 silver badges141 bronze badges























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