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Why don't “echo -e” commands seem to produce the right output?


How can I see a history of the terminal output, not just commands entered?Why do df and du show different output?Console doesn't show pretty UTF-8 characters in ShellWhy doesn't the `time` command work with any option?What do numbers between parentheses in bash man pages mean: bash(1), ssh_config(5), sshd(8),Troubles piping echo output to xargs script for mv commandCan sharing the output of these bash commands put you into a risk of being compromised?Direct output from a command to a file including the original command, AND print in terminalTurn off WSL Ubuntu echo when typing commands






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5















In the terminal of Ubuntu 18.04 LTS, when I write this command:





echo -e "Hello\n"


Output:



Hellon


But it should print, as the man page says:



Hello


That is, first print Hello, then , then a newline character. Where is the problem?



See these few echo -e commands and their output:



man420@man420-X542UQ:~$ echo -e "HElloaaaaaa\n"
HEllon
man420@man420-X542UQ:~$ echo -e "HEllo\n"
HEllon
man420@man420-X542UQ:~$ echo -3 "HElloa\n"
HEllon









share|improve this question









New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

    – yolin00
    8 hours ago











  • Try it without the quotes.

    – ajgringo619
    8 hours ago

















5















In the terminal of Ubuntu 18.04 LTS, when I write this command:





echo -e "Hello\n"


Output:



Hellon


But it should print, as the man page says:



Hello


That is, first print Hello, then , then a newline character. Where is the problem?



See these few echo -e commands and their output:



man420@man420-X542UQ:~$ echo -e "HElloaaaaaa\n"
HEllon
man420@man420-X542UQ:~$ echo -e "HEllo\n"
HEllon
man420@man420-X542UQ:~$ echo -3 "HElloa\n"
HEllon









share|improve this question









New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

    – yolin00
    8 hours ago











  • Try it without the quotes.

    – ajgringo619
    8 hours ago













5












5








5








In the terminal of Ubuntu 18.04 LTS, when I write this command:





echo -e "Hello\n"


Output:



Hellon


But it should print, as the man page says:



Hello


That is, first print Hello, then , then a newline character. Where is the problem?



See these few echo -e commands and their output:



man420@man420-X542UQ:~$ echo -e "HElloaaaaaa\n"
HEllon
man420@man420-X542UQ:~$ echo -e "HEllo\n"
HEllon
man420@man420-X542UQ:~$ echo -3 "HElloa\n"
HEllon









share|improve this question









New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











In the terminal of Ubuntu 18.04 LTS, when I write this command:





echo -e "Hello\n"


Output:



Hellon


But it should print, as the man page says:



Hello


That is, first print Hello, then , then a newline character. Where is the problem?



See these few echo -e commands and their output:



man420@man420-X542UQ:~$ echo -e "HElloaaaaaa\n"
HEllon
man420@man420-X542UQ:~$ echo -e "HEllo\n"
HEllon
man420@man420-X542UQ:~$ echo -3 "HElloa\n"
HEllon






command-line echo






share|improve this question









New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 8 hours ago









Eliah Kagan

89.4k23 gold badges249 silver badges391 bronze badges




89.4k23 gold badges249 silver badges391 bronze badges






New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 9 hours ago









yolin00yolin00

262 bronze badges




262 bronze badges




New contributor



yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




yolin00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

    – yolin00
    8 hours ago











  • Try it without the quotes.

    – ajgringo619
    8 hours ago

















  • yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

    – yolin00
    8 hours ago











  • Try it without the quotes.

    – ajgringo619
    8 hours ago
















yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

– yolin00
8 hours ago





yes.for first 2 it should output a .and last and n make a backslash escape n(new line).so why it should print Hello

– yolin00
8 hours ago













Try it without the quotes.

– ajgringo619
8 hours ago





Try it without the quotes.

– ajgringo619
8 hours ago










1 Answer
1






active

oldest

votes


















7















Backslashes are treated specially by echo -e, but first they are sometimes treated specially by the shell (which in this case is bash), according to the shell's quoting rules.



The argument echo actually sees is Hello\n. Because you have passed -e to echo, it treats backslash escapes specially, and \ is collapsed to a single . The final n is not escaped, so it appears literally.



The reason for this is that, prior to and separately from the operation of echo itself, the shell treats specially in some contexts but not others. Unquoted characters are always treated specially, single-quoted are never treated specially, but the treatment of double-quoted characters, as in the command you ran, is more subtle and complicated.



When the shell encounters double-quoted text in a command, as with "Hello\n", it treats as an escape character when it precedes a character that can itself have special meaning inside double quotes and not otherwise.



  1. Because sometimes has a special meaning inside "", a that immediately precedes another has the effect of quoting that second . So inside double quotes, the first \ are collapsed into .

  2. After those first two characters, there is a third character which is unaffected by those first two and which precedes an n. But n is not a character that is ever treated specially inside double quotes, so the before it is not treated specially in this situation. Thus n stays n.

The effect is that, in double quotes, \n is interpreted as \n.



When echo -e sees \n, the first removes special meaning from the second, so echo prints n literally for that text.



One solution is to remove a . Running echo -e "Hello\n" outputs Hello with an extra newline at the end. A better solution is to use single quotes and write echo -e 'Hellon'. Single quotes are the strongest form of quoting. An even better solution is usually to use printf instead of echo, which in this case would be printf 'Hellonn'.






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    1 Answer
    1






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    active

    oldest

    votes






    active

    oldest

    votes









    7















    Backslashes are treated specially by echo -e, but first they are sometimes treated specially by the shell (which in this case is bash), according to the shell's quoting rules.



    The argument echo actually sees is Hello\n. Because you have passed -e to echo, it treats backslash escapes specially, and \ is collapsed to a single . The final n is not escaped, so it appears literally.



    The reason for this is that, prior to and separately from the operation of echo itself, the shell treats specially in some contexts but not others. Unquoted characters are always treated specially, single-quoted are never treated specially, but the treatment of double-quoted characters, as in the command you ran, is more subtle and complicated.



    When the shell encounters double-quoted text in a command, as with "Hello\n", it treats as an escape character when it precedes a character that can itself have special meaning inside double quotes and not otherwise.



    1. Because sometimes has a special meaning inside "", a that immediately precedes another has the effect of quoting that second . So inside double quotes, the first \ are collapsed into .

    2. After those first two characters, there is a third character which is unaffected by those first two and which precedes an n. But n is not a character that is ever treated specially inside double quotes, so the before it is not treated specially in this situation. Thus n stays n.

    The effect is that, in double quotes, \n is interpreted as \n.



    When echo -e sees \n, the first removes special meaning from the second, so echo prints n literally for that text.



    One solution is to remove a . Running echo -e "Hello\n" outputs Hello with an extra newline at the end. A better solution is to use single quotes and write echo -e 'Hellon'. Single quotes are the strongest form of quoting. An even better solution is usually to use printf instead of echo, which in this case would be printf 'Hellonn'.






    share|improve this answer































      7















      Backslashes are treated specially by echo -e, but first they are sometimes treated specially by the shell (which in this case is bash), according to the shell's quoting rules.



      The argument echo actually sees is Hello\n. Because you have passed -e to echo, it treats backslash escapes specially, and \ is collapsed to a single . The final n is not escaped, so it appears literally.



      The reason for this is that, prior to and separately from the operation of echo itself, the shell treats specially in some contexts but not others. Unquoted characters are always treated specially, single-quoted are never treated specially, but the treatment of double-quoted characters, as in the command you ran, is more subtle and complicated.



      When the shell encounters double-quoted text in a command, as with "Hello\n", it treats as an escape character when it precedes a character that can itself have special meaning inside double quotes and not otherwise.



      1. Because sometimes has a special meaning inside "", a that immediately precedes another has the effect of quoting that second . So inside double quotes, the first \ are collapsed into .

      2. After those first two characters, there is a third character which is unaffected by those first two and which precedes an n. But n is not a character that is ever treated specially inside double quotes, so the before it is not treated specially in this situation. Thus n stays n.

      The effect is that, in double quotes, \n is interpreted as \n.



      When echo -e sees \n, the first removes special meaning from the second, so echo prints n literally for that text.



      One solution is to remove a . Running echo -e "Hello\n" outputs Hello with an extra newline at the end. A better solution is to use single quotes and write echo -e 'Hellon'. Single quotes are the strongest form of quoting. An even better solution is usually to use printf instead of echo, which in this case would be printf 'Hellonn'.






      share|improve this answer





























        7














        7










        7









        Backslashes are treated specially by echo -e, but first they are sometimes treated specially by the shell (which in this case is bash), according to the shell's quoting rules.



        The argument echo actually sees is Hello\n. Because you have passed -e to echo, it treats backslash escapes specially, and \ is collapsed to a single . The final n is not escaped, so it appears literally.



        The reason for this is that, prior to and separately from the operation of echo itself, the shell treats specially in some contexts but not others. Unquoted characters are always treated specially, single-quoted are never treated specially, but the treatment of double-quoted characters, as in the command you ran, is more subtle and complicated.



        When the shell encounters double-quoted text in a command, as with "Hello\n", it treats as an escape character when it precedes a character that can itself have special meaning inside double quotes and not otherwise.



        1. Because sometimes has a special meaning inside "", a that immediately precedes another has the effect of quoting that second . So inside double quotes, the first \ are collapsed into .

        2. After those first two characters, there is a third character which is unaffected by those first two and which precedes an n. But n is not a character that is ever treated specially inside double quotes, so the before it is not treated specially in this situation. Thus n stays n.

        The effect is that, in double quotes, \n is interpreted as \n.



        When echo -e sees \n, the first removes special meaning from the second, so echo prints n literally for that text.



        One solution is to remove a . Running echo -e "Hello\n" outputs Hello with an extra newline at the end. A better solution is to use single quotes and write echo -e 'Hellon'. Single quotes are the strongest form of quoting. An even better solution is usually to use printf instead of echo, which in this case would be printf 'Hellonn'.






        share|improve this answer















        Backslashes are treated specially by echo -e, but first they are sometimes treated specially by the shell (which in this case is bash), according to the shell's quoting rules.



        The argument echo actually sees is Hello\n. Because you have passed -e to echo, it treats backslash escapes specially, and \ is collapsed to a single . The final n is not escaped, so it appears literally.



        The reason for this is that, prior to and separately from the operation of echo itself, the shell treats specially in some contexts but not others. Unquoted characters are always treated specially, single-quoted are never treated specially, but the treatment of double-quoted characters, as in the command you ran, is more subtle and complicated.



        When the shell encounters double-quoted text in a command, as with "Hello\n", it treats as an escape character when it precedes a character that can itself have special meaning inside double quotes and not otherwise.



        1. Because sometimes has a special meaning inside "", a that immediately precedes another has the effect of quoting that second . So inside double quotes, the first \ are collapsed into .

        2. After those first two characters, there is a third character which is unaffected by those first two and which precedes an n. But n is not a character that is ever treated specially inside double quotes, so the before it is not treated specially in this situation. Thus n stays n.

        The effect is that, in double quotes, \n is interpreted as \n.



        When echo -e sees \n, the first removes special meaning from the second, so echo prints n literally for that text.



        One solution is to remove a . Running echo -e "Hello\n" outputs Hello with an extra newline at the end. A better solution is to use single quotes and write echo -e 'Hellon'. Single quotes are the strongest form of quoting. An even better solution is usually to use printf instead of echo, which in this case would be printf 'Hellonn'.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 4 mins ago









        John Kugelman

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        9167 silver badges9 bronze badges










        answered 8 hours ago









        Eliah KaganEliah Kagan

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