Irish Snap: Variant RulesName the poker handCounting icons for Innovation splaysEvaluate a Skat-HandClock (card game)Simulate a 'battle' in the playing card game 'Oorlog'Help me cheat at CheatPlay Best Card in EuchreExecute a Superb Shuffle™Was it a Superb Shuffle™️Is this a straight flush?

Mathematical uses of string theory

Did the British navy fail to take into account the ballistics correction due to Coriolis force during WW1 Falkland Islands battle?

Why don't electrons take the shorter path in coils?

Is it safe to remove the bottom chords of a series of garage roof trusses?

What are some interesting features that are common cross-linguistically but don't exist in English?

Sun setting in East!

Why do all fields in a QFT transform like *irreducible* representations of some group?

C++20 constexpr std::copy optimizations for run-time

What to say to a student who has failed?

Defense against attacks using dictionaries

What magic extends life or grants immortality?

Was Switzerland really impossible to invade during WW2?

Middle Mouse turns on Perspective

Can realistic planetary invasion have any meaningful strategy?

How can I watch the 17th (or last, if less) line in files of a folder?

Avoiding racist tropes in fantasy

Sleeping solo in a double sleeping bag

Deck Size Problems in Deckbuilding

Dealing with an extrovert co-worker

Rule based coloured background for labeling in QGIS

Would this system work to purify water?

Accent on í misaligned in bibliography / citation

Cross-referencing enumerate item

If the first law of thermodynamics ensures conservation of energy, why does it allow systems to lose energy?



Irish Snap: Variant Rules


Name the poker handCounting icons for Innovation splaysEvaluate a Skat-HandClock (card game)Simulate a 'battle' in the playing card game 'Oorlog'Help me cheat at CheatPlay Best Card in EuchreExecute a Superb Shuffle™Was it a Superb Shuffle™️Is this a straight flush?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








7












$begingroup$


Introduction



Recently, me and a couple of my friends decided to play some cards, and one of them suggested the game 'Irish Snap', which was the inspiration for this challenge. However, I later learnt that the game has a lot of different rules that you can play with, some of which are listed here. The rules that are in this challenge aren't currently listed on that page, hence the name, 'Variant Rules'



The Challenge



Given an array of 3 cards, output a truthy or falsey value depending on if they make a valid snap in a game of Irish snap.



Input



The input will be an array of 3 numbers, ranging from 1-13 inclusive, with 1 representing an ace, 11 representing a jack, 12 representing a queen and 13 representing a king. The input can be in any order of top, middle, bottom.



Rules



The 4 different criteria for if cards make an Irish snap are:



  • The top and middle cards are the same

  • The top and middle cards have a difference of one

  • The top and bottom cards are the same

  • The top and bottom cards have a difference of one

If any of these criteria are met, you must output a truthy value. As well as this, for the two criteria that require the cards to have a difference of one, it 'wraps around', meaning that an ace and a king are considered to have a difference of one, and vice versa.



Test Cases



Input (Bottom, Middle, Top) -> Output
1 13 7 -> False
1 4 13 -> True
9 3 6 -> False
8 9 7 -> True
2 6 5 -> True
12 5 11 -> True
10 4 8 -> False
12 13 7 -> False
9 7 10 -> True
7 3 1 -> False
4 2 3 -> True









share|improve this question











$endgroup$









  • 1




    $begingroup$
    Can we take the cards seperately? Or take input as top, [middle, bottom]?
    $endgroup$
    – Jo King
    8 hours ago











  • $begingroup$
    sure, you can do both. changed the question to reflect that
    $endgroup$
    – EdgyNerd
    8 hours ago










  • $begingroup$
    Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
    $endgroup$
    – Jo King
    8 hours ago










  • $begingroup$
    Yeah, you can invert the output. Also, added that test case
    $endgroup$
    – EdgyNerd
    8 hours ago

















7












$begingroup$


Introduction



Recently, me and a couple of my friends decided to play some cards, and one of them suggested the game 'Irish Snap', which was the inspiration for this challenge. However, I later learnt that the game has a lot of different rules that you can play with, some of which are listed here. The rules that are in this challenge aren't currently listed on that page, hence the name, 'Variant Rules'



The Challenge



Given an array of 3 cards, output a truthy or falsey value depending on if they make a valid snap in a game of Irish snap.



Input



The input will be an array of 3 numbers, ranging from 1-13 inclusive, with 1 representing an ace, 11 representing a jack, 12 representing a queen and 13 representing a king. The input can be in any order of top, middle, bottom.



Rules



The 4 different criteria for if cards make an Irish snap are:



  • The top and middle cards are the same

  • The top and middle cards have a difference of one

  • The top and bottom cards are the same

  • The top and bottom cards have a difference of one

If any of these criteria are met, you must output a truthy value. As well as this, for the two criteria that require the cards to have a difference of one, it 'wraps around', meaning that an ace and a king are considered to have a difference of one, and vice versa.



Test Cases



Input (Bottom, Middle, Top) -> Output
1 13 7 -> False
1 4 13 -> True
9 3 6 -> False
8 9 7 -> True
2 6 5 -> True
12 5 11 -> True
10 4 8 -> False
12 13 7 -> False
9 7 10 -> True
7 3 1 -> False
4 2 3 -> True









share|improve this question











$endgroup$









  • 1




    $begingroup$
    Can we take the cards seperately? Or take input as top, [middle, bottom]?
    $endgroup$
    – Jo King
    8 hours ago











  • $begingroup$
    sure, you can do both. changed the question to reflect that
    $endgroup$
    – EdgyNerd
    8 hours ago










  • $begingroup$
    Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
    $endgroup$
    – Jo King
    8 hours ago










  • $begingroup$
    Yeah, you can invert the output. Also, added that test case
    $endgroup$
    – EdgyNerd
    8 hours ago













7












7








7





$begingroup$


Introduction



Recently, me and a couple of my friends decided to play some cards, and one of them suggested the game 'Irish Snap', which was the inspiration for this challenge. However, I later learnt that the game has a lot of different rules that you can play with, some of which are listed here. The rules that are in this challenge aren't currently listed on that page, hence the name, 'Variant Rules'



The Challenge



Given an array of 3 cards, output a truthy or falsey value depending on if they make a valid snap in a game of Irish snap.



Input



The input will be an array of 3 numbers, ranging from 1-13 inclusive, with 1 representing an ace, 11 representing a jack, 12 representing a queen and 13 representing a king. The input can be in any order of top, middle, bottom.



Rules



The 4 different criteria for if cards make an Irish snap are:



  • The top and middle cards are the same

  • The top and middle cards have a difference of one

  • The top and bottom cards are the same

  • The top and bottom cards have a difference of one

If any of these criteria are met, you must output a truthy value. As well as this, for the two criteria that require the cards to have a difference of one, it 'wraps around', meaning that an ace and a king are considered to have a difference of one, and vice versa.



Test Cases



Input (Bottom, Middle, Top) -> Output
1 13 7 -> False
1 4 13 -> True
9 3 6 -> False
8 9 7 -> True
2 6 5 -> True
12 5 11 -> True
10 4 8 -> False
12 13 7 -> False
9 7 10 -> True
7 3 1 -> False
4 2 3 -> True









share|improve this question











$endgroup$




Introduction



Recently, me and a couple of my friends decided to play some cards, and one of them suggested the game 'Irish Snap', which was the inspiration for this challenge. However, I later learnt that the game has a lot of different rules that you can play with, some of which are listed here. The rules that are in this challenge aren't currently listed on that page, hence the name, 'Variant Rules'



The Challenge



Given an array of 3 cards, output a truthy or falsey value depending on if they make a valid snap in a game of Irish snap.



Input



The input will be an array of 3 numbers, ranging from 1-13 inclusive, with 1 representing an ace, 11 representing a jack, 12 representing a queen and 13 representing a king. The input can be in any order of top, middle, bottom.



Rules



The 4 different criteria for if cards make an Irish snap are:



  • The top and middle cards are the same

  • The top and middle cards have a difference of one

  • The top and bottom cards are the same

  • The top and bottom cards have a difference of one

If any of these criteria are met, you must output a truthy value. As well as this, for the two criteria that require the cards to have a difference of one, it 'wraps around', meaning that an ace and a king are considered to have a difference of one, and vice versa.



Test Cases



Input (Bottom, Middle, Top) -> Output
1 13 7 -> False
1 4 13 -> True
9 3 6 -> False
8 9 7 -> True
2 6 5 -> True
12 5 11 -> True
10 4 8 -> False
12 13 7 -> False
9 7 10 -> True
7 3 1 -> False
4 2 3 -> True






code-golf decision-problem cards






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago







EdgyNerd

















asked 9 hours ago









EdgyNerdEdgyNerd

6161 silver badge8 bronze badges




6161 silver badge8 bronze badges










  • 1




    $begingroup$
    Can we take the cards seperately? Or take input as top, [middle, bottom]?
    $endgroup$
    – Jo King
    8 hours ago











  • $begingroup$
    sure, you can do both. changed the question to reflect that
    $endgroup$
    – EdgyNerd
    8 hours ago










  • $begingroup$
    Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
    $endgroup$
    – Jo King
    8 hours ago










  • $begingroup$
    Yeah, you can invert the output. Also, added that test case
    $endgroup$
    – EdgyNerd
    8 hours ago












  • 1




    $begingroup$
    Can we take the cards seperately? Or take input as top, [middle, bottom]?
    $endgroup$
    – Jo King
    8 hours ago











  • $begingroup$
    sure, you can do both. changed the question to reflect that
    $endgroup$
    – EdgyNerd
    8 hours ago










  • $begingroup$
    Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
    $endgroup$
    – Jo King
    8 hours ago










  • $begingroup$
    Yeah, you can invert the output. Also, added that test case
    $endgroup$
    – EdgyNerd
    8 hours ago







1




1




$begingroup$
Can we take the cards seperately? Or take input as top, [middle, bottom]?
$endgroup$
– Jo King
8 hours ago





$begingroup$
Can we take the cards seperately? Or take input as top, [middle, bottom]?
$endgroup$
– Jo King
8 hours ago













$begingroup$
sure, you can do both. changed the question to reflect that
$endgroup$
– EdgyNerd
8 hours ago




$begingroup$
sure, you can do both. changed the question to reflect that
$endgroup$
– EdgyNerd
8 hours ago












$begingroup$
Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
$endgroup$
– Jo King
8 hours ago




$begingroup$
Can we invert the output, i.e return False for valid snaps and vice versa? How about a test case where both middle and bottom are valid?
$endgroup$
– Jo King
8 hours ago












$begingroup$
Yeah, you can invert the output. Also, added that test case
$endgroup$
– EdgyNerd
8 hours ago




$begingroup$
Yeah, you can invert the output. Also, added that test case
$endgroup$
– EdgyNerd
8 hours ago










10 Answers
10






active

oldest

votes


















4













$begingroup$


Python 3, 38 bytes





lambda x,y,z:x-y,x-z&0,1,12,-1,-12


Try it online!



Returns a non-empty set (truthy) if valid, empty set (falsey) if not. Takes input in order top-middle-bottom, but can be rearranged for same code size.






share|improve this answer









$endgroup$






















    3













    $begingroup$


    05AB1E, 7 bytes



    α12%ß2‹


    Try it online!



    Takes inputs as [middle, bottom], top.



    α # absolute difference
    12% # mod 12
    ß # minimum
    2‹ # less than 2?





    share|improve this answer











    $endgroup$






















      3













      $begingroup$


      Perl 6, 16 bytes





      3>(*-(*|*)+1)%13


      Try it online!



      Anonymous whatever lambda that takes input as top, middle, bottom and returns a Junction that evaluates to True or False






      share|improve this answer











      $endgroup$














      • $begingroup$
        Too bad whitespace is required before <, this was the perfect chance to have a heart smiley.
        $endgroup$
        – Grimy
        8 hours ago


















      2













      $begingroup$


      J, 12 bytes



      1 e.2>12||@-


      Try it online!



      Taking bottom middle as left arg, top as right arg.



      original answer taking input as one list




      J, 24 bytes



      1 e.2>#:@3 5(12||@-/)@#]


      Try it online!




      • #:@3 5 The numbers 3 and 5 in binary are 0 1 1 and 1 0 1 which are the masks for the middle/top and bottom/top cards respectively


      • (12||@-/)@# We filter the input with those masks, take the abs value of the
        resulting differences, then the remainder when divided by 12 (for the ace-king case)


      • 1 e.2> are either of the resulting numbers less than 2, ie, 0 or 1?





      share|improve this answer











      $endgroup$






















        2













        $begingroup$

        JavaScript (ES6), 29 bytes



        Takes input as ([bottom, middle])(top).



        The output is inverted.





        a=>c=>a.every(n=>(n-c)/2%6|0)


        Try it online!




        JavaScript (ES6),  37  30 bytes



        Saved 1 byte thanks to @Grimy



        Takes input as ([bottom, middle])(top).





        a=>c=>a.some(n=>(n-=c)*n%72<2)


        Try it online!






        share|improve this answer











        $endgroup$














        • $begingroup$
          %144 could be %72
          $endgroup$
          – Grimy
          8 hours ago










        • $begingroup$
          @Grimy Thanks! FWIW, %13 would also work.
          $endgroup$
          – Arnauld
          8 hours ago


















        1













        $begingroup$


        Perl 5 -ap, 31 bytes





        $t=<>}improve this answer



        share=abs($t-$_)%12<2for@F


        Try it online!



        Input:



        bottom middle
        top


        Actually, the order of the middle and bottom doesn't matter.



        Output:



        0 for false; 1 for true






        share=abs($t-$_)%12<2for@F


        Try it online!



        Input:



        bottom middle
        top


        Actually, the order of the middle and bottom doesn't matter.



        Output:



        0 for false; 1 for true






        shareimprove this answer









        $endgroup$




        Perl 5 -ap, 31 bytes





        $t=<>{$|=abs($t-$_)%12<2for@F


        Try it online!



        Input:



        bottom middle
        top


        Actually, the order of the middle and bottom doesn't matter.



        Output:



        0 for false; 1 for true







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 5 hours ago









        XcaliXcali

        6,6841 gold badge7 silver badges23 bronze badges




        6,6841 gold badge7 silver badges23 bronze badges
























            1













            $begingroup$


            Pyth, 12 11 bytes



            Takes input as [bottom, top, middle] or [middle, top, bottom] (both work).
            Outputs [] (Falsy in Pyth) if there's no valid snap, a non-empty array otherwise.



            f>2%.aT12.+


            Try it online!



            If a consistent truthy/falsy value is required, add .A in front for +2 bytes. Then output will be True or False.



            Explanation



             f # Filter on lambda T:
            >2 # 2 >
            .aT # abs(T)
            % 12 # % 12
            .+ # the list of deltas (difference between consecutive elements)

            .A (if required)# Any truthy values in the above list?


            Edit: -1 with a different approach






            share|improve this answer











            $endgroup$



















              1













              $begingroup$


              Pyth, 12 11 bytes



              Takes input as [bottom, top, middle] or [middle, top, bottom] (both work).
              Outputs [] (Falsy in Pyth) if there's no valid snap, a non-empty array otherwise.



              f>2%.aT12.+


              Try it online!



              If a consistent truthy/falsy value is required, add .A in front for +2 bytes. Then output will be True or False.



              Explanation



               f # Filter on lambda T:
              >2 # 2 >
              .aT # abs(T)
              % 12 # % 12
              .+ # the list of deltas (difference between consecutive elements)

              .A (if required)# Any truthy values in the above list?


              Edit: -1 with a different approach






              share|improve this answer











              $endgroup$

















                1














                1










                1







                $begingroup$


                Pyth, 12 11 bytes



                Takes input as [bottom, top, middle] or [middle, top, bottom] (both work).
                Outputs [] (Falsy in Pyth) if there's no valid snap, a non-empty array otherwise.



                f>2%.aT12.+


                Try it online!



                If a consistent truthy/falsy value is required, add .A in front for +2 bytes. Then output will be True or False.



                Explanation



                 f # Filter on lambda T:
                >2 # 2 >
                .aT # abs(T)
                % 12 # % 12
                .+ # the list of deltas (difference between consecutive elements)

                .A (if required)# Any truthy values in the above list?


                Edit: -1 with a different approach






                share|improve this answer











                $endgroup$




                Pyth, 12 11 bytes



                Takes input as [bottom, top, middle] or [middle, top, bottom] (both work).
                Outputs [] (Falsy in Pyth) if there's no valid snap, a non-empty array otherwise.



                f>2%.aT12.+


                Try it online!



                If a consistent truthy/falsy value is required, add .A in front for +2 bytes. Then output will be True or False.



                Explanation



                 f # Filter on lambda T:
                >2 # 2 >
                .aT # abs(T)
                % 12 # % 12
                .+ # the list of deltas (difference between consecutive elements)

                .A (if required)# Any truthy values in the above list?


                Edit: -1 with a different approach







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 5 hours ago

























                answered 5 hours ago









                ar4093ar4093

                1714 bronze badges




                1714 bronze badges
























                    1













                    $begingroup$


                    Jelly, 6 bytes



                    ạ%12ṠƑ


                    Try it online!






                    share|improve this answer









                    $endgroup$



















                      1













                      $begingroup$


                      Jelly, 6 bytes



                      ạ%12ṠƑ


                      Try it online!






                      share|improve this answer









                      $endgroup$

















                        1














                        1










                        1







                        $begingroup$


                        Jelly, 6 bytes



                        ạ%12ṠƑ


                        Try it online!






                        share|improve this answer









                        $endgroup$




                        Jelly, 6 bytes



                        ạ%12ṠƑ


                        Try it online!







                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered 4 hours ago









                        Erik the OutgolferErik the Outgolfer

                        35.8k4 gold badges30 silver badges111 bronze badges




                        35.8k4 gold badges30 silver badges111 bronze badges
























                            1













                            $begingroup$


                            Charcoal, 12 bytes



                            ›²⌊﹪↔⁻E²NN¹²


                            Try it online! Port of @Grimy's answer. Takes input as three separate values bottom, middle, top, and outputs using Charcoal's default Boolean format of - for true, nothing for false. Explanation:



                             ² Literal 2
                            › Is greater than
                            ⌊ Minimum of
                            ↔ Absolute value of (vectorised)
                            E²N First two numeric inputs as a list ([bottom, middle])
                            ⁻ Minus (vectorised)
                            N Third input (top)
                            ﹪ Modulo (vectorised)
                            ¹² Literal 12





                            share|improve this answer









                            $endgroup$



















                              1













                              $begingroup$


                              Charcoal, 12 bytes



                              ›²⌊﹪↔⁻E²NN¹²


                              Try it online! Port of @Grimy's answer. Takes input as three separate values bottom, middle, top, and outputs using Charcoal's default Boolean format of - for true, nothing for false. Explanation:



                               ² Literal 2
                              › Is greater than
                              ⌊ Minimum of
                              ↔ Absolute value of (vectorised)
                              E²N First two numeric inputs as a list ([bottom, middle])
                              ⁻ Minus (vectorised)
                              N Third input (top)
                              ﹪ Modulo (vectorised)
                              ¹² Literal 12





                              share|improve this answer









                              $endgroup$

















                                1














                                1










                                1







                                $begingroup$


                                Charcoal, 12 bytes



                                ›²⌊﹪↔⁻E²NN¹²


                                Try it online! Port of @Grimy's answer. Takes input as three separate values bottom, middle, top, and outputs using Charcoal's default Boolean format of - for true, nothing for false. Explanation:



                                 ² Literal 2
                                › Is greater than
                                ⌊ Minimum of
                                ↔ Absolute value of (vectorised)
                                E²N First two numeric inputs as a list ([bottom, middle])
                                ⁻ Minus (vectorised)
                                N Third input (top)
                                ﹪ Modulo (vectorised)
                                ¹² Literal 12





                                share|improve this answer









                                $endgroup$




                                Charcoal, 12 bytes



                                ›²⌊﹪↔⁻E²NN¹²


                                Try it online! Port of @Grimy's answer. Takes input as three separate values bottom, middle, top, and outputs using Charcoal's default Boolean format of - for true, nothing for false. Explanation:



                                 ² Literal 2
                                › Is greater than
                                ⌊ Minimum of
                                ↔ Absolute value of (vectorised)
                                E²N First two numeric inputs as a list ([bottom, middle])
                                ⁻ Minus (vectorised)
                                N Third input (top)
                                ﹪ Modulo (vectorised)
                                ¹² Literal 12






                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered 1 hour ago









                                NeilNeil

                                87.8k8 gold badges46 silver badges185 bronze badges




                                87.8k8 gold badges46 silver badges185 bronze badges
























                                    0













                                    $begingroup$


                                    C (gcc), 47 43 bytes





                                    f(b,m,t)1<<t-b)&0x80101003;


                                    Try it online!






                                    share|improve this answer











                                    $endgroup$



















                                      0













                                      $begingroup$


                                      C (gcc), 47 43 bytes





                                      f(b,m,t)1<<t-b)&0x80101003;


                                      Try it online!






                                      share|improve this answer











                                      $endgroup$

















                                        0














                                        0










                                        0







                                        $begingroup$


                                        C (gcc), 47 43 bytes





                                        f(b,m,t)1<<t-b)&0x80101003;


                                        Try it online!






                                        share|improve this answer











                                        $endgroup$




                                        C (gcc), 47 43 bytes





                                        f(b,m,t)1<<t-b)&0x80101003;


                                        Try it online!







                                        share|improve this answer














                                        share|improve this answer



                                        share|improve this answer








                                        edited 3 hours ago

























                                        answered 3 hours ago









                                        G. SliepenG. Sliepen

                                        4302 silver badges5 bronze badges




                                        4302 silver badges5 bronze badges






























                                            draft saved

                                            draft discarded
















































                                            If this is an answer to a challenge…



                                            • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


                                            • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
                                              Explanations of your answer make it more interesting to read and are very much encouraged.


                                            • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.


                                            More generally…



                                            • …Please make sure to answer the question and provide sufficient detail.


                                            • …Avoid asking for help, clarification or responding to other answers (use comments instead).




                                            draft saved


                                            draft discarded














                                            StackExchange.ready(
                                            function ()
                                            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodegolf.stackexchange.com%2fquestions%2f190599%2firish-snap-variant-rules%23new-answer', 'question_page');

                                            );

                                            Post as a guest















                                            Required, but never shown





















































                                            Required, but never shown














                                            Required, but never shown












                                            Required, but never shown







                                            Required, but never shown

































                                            Required, but never shown














                                            Required, but never shown












                                            Required, but never shown







                                            Required, but never shown







                                            Popular posts from this blog

                                            Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

                                            Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

                                            François Viète Contents Biography Work and thought Bibliography See also Notes Further reading External links Navigation menup. 21Google Bookspp. 75–77Google BooksDe thou (from University of Saint Andrews)ArchivedGoogle BooksGoogle BooksGoogle BooksGoogle booksGoogle Bookscc-parthenay.frL'histoire universelle (fr)Universal History (en)ArchivedAdsabs.harvard.eduPagesperso-orange.frArchive.orgChikara Sasaki. Descartes' mathematical thought p.259Google BooksGoogle BooksGoogle Bookspp. 152 and onwardGoogle BooksGoogle BooksScribd.comGoogle Books1257-7979Google BooksGoogle BooksGoogle BooksGoogle BooksGoogle BooksGoogle BooksGallica.bnf.frGoogle BooksGoogle Books"François Viète"Francois Viète: Father of Modern Algebraic NotationThe Lawyer and the GamblerAbout TarporleySite de Jean-Paul GuichardL'algèbre nouvelle"About the Harmonicon"cb120511976(data)1188044800000 0001 0913 5903n82164680ola2013766880073431702w6vt1sb70287374827140948071409480