Reference request: quantifier elimination testdense orders are saturatedAlgebras admitting quantifier elimination“Fraïssé limits” without amalgamationQuantifier elimination vs decidabilityWhere do uncountable models collapse to?Reference request on a notion of independence for families of [real-valued] functionsComplex L^1 spaces; reference requestPreservation results in abstract logicsQuantifier elimination, subgroups of modulesQuantifier elimination in uncountable elementary “Fraïssé classes”

Reference request: quantifier elimination test


dense orders are saturatedAlgebras admitting quantifier elimination“Fraïssé limits” without amalgamationQuantifier elimination vs decidabilityWhere do uncountable models collapse to?Reference request on a notion of independence for families of [real-valued] functionsComplex L^1 spaces; reference requestPreservation results in abstract logicsQuantifier elimination, subgroups of modulesQuantifier elimination in uncountable elementary “Fraïssé classes”













2












$begingroup$


I'm having difficulty finding this result in the standard texts.




Theorem. Let $T$ be a theory in a language $mathcalL$. TFAE:



1) $T$ has quantifier elimination,



2) Whenever $M, N$ are $aleph_1$-saturated models of $T$, $A subset
M$
, $B subset N$ are countable nonempty substructures and $f : A
rightarrow B$
an $mathcalL$-isomorphism, then for any $a in M$
there exists an extension $f' supset f$ with $a$ in the domain of
$f'$ and $f'$ still an $mathcalL$-isomorphism. In addition, for any
$b in N$ there exists an extension $f'' supset f$ with $b$ in the
range of $f''$ and $f''$ still an $mathcalL$-isomorphism.




I'm obtaining this result from these notes by Chatzidakis (see 2.27): http://www.math.ens.fr/~zchatzid/papiers/CUP-MT.pdf. Any suggestions are appreciated.










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
    $endgroup$
    – Thomas Scanlon
    4 hours ago















2












$begingroup$


I'm having difficulty finding this result in the standard texts.




Theorem. Let $T$ be a theory in a language $mathcalL$. TFAE:



1) $T$ has quantifier elimination,



2) Whenever $M, N$ are $aleph_1$-saturated models of $T$, $A subset
M$
, $B subset N$ are countable nonempty substructures and $f : A
rightarrow B$
an $mathcalL$-isomorphism, then for any $a in M$
there exists an extension $f' supset f$ with $a$ in the domain of
$f'$ and $f'$ still an $mathcalL$-isomorphism. In addition, for any
$b in N$ there exists an extension $f'' supset f$ with $b$ in the
range of $f''$ and $f''$ still an $mathcalL$-isomorphism.




I'm obtaining this result from these notes by Chatzidakis (see 2.27): http://www.math.ens.fr/~zchatzid/papiers/CUP-MT.pdf. Any suggestions are appreciated.










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
    $endgroup$
    – Thomas Scanlon
    4 hours ago













2












2








2





$begingroup$


I'm having difficulty finding this result in the standard texts.




Theorem. Let $T$ be a theory in a language $mathcalL$. TFAE:



1) $T$ has quantifier elimination,



2) Whenever $M, N$ are $aleph_1$-saturated models of $T$, $A subset
M$
, $B subset N$ are countable nonempty substructures and $f : A
rightarrow B$
an $mathcalL$-isomorphism, then for any $a in M$
there exists an extension $f' supset f$ with $a$ in the domain of
$f'$ and $f'$ still an $mathcalL$-isomorphism. In addition, for any
$b in N$ there exists an extension $f'' supset f$ with $b$ in the
range of $f''$ and $f''$ still an $mathcalL$-isomorphism.




I'm obtaining this result from these notes by Chatzidakis (see 2.27): http://www.math.ens.fr/~zchatzid/papiers/CUP-MT.pdf. Any suggestions are appreciated.










share|cite|improve this question











$endgroup$




I'm having difficulty finding this result in the standard texts.




Theorem. Let $T$ be a theory in a language $mathcalL$. TFAE:



1) $T$ has quantifier elimination,



2) Whenever $M, N$ are $aleph_1$-saturated models of $T$, $A subset
M$
, $B subset N$ are countable nonempty substructures and $f : A
rightarrow B$
an $mathcalL$-isomorphism, then for any $a in M$
there exists an extension $f' supset f$ with $a$ in the domain of
$f'$ and $f'$ still an $mathcalL$-isomorphism. In addition, for any
$b in N$ there exists an extension $f'' supset f$ with $b$ in the
range of $f''$ and $f''$ still an $mathcalL$-isomorphism.




I'm obtaining this result from these notes by Chatzidakis (see 2.27): http://www.math.ens.fr/~zchatzid/papiers/CUP-MT.pdf. Any suggestions are appreciated.







reference-request lo.logic model-theory






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edited 8 hours ago









YCor

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  • 1




    $begingroup$
    You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
    $endgroup$
    – Thomas Scanlon
    4 hours ago












  • 1




    $begingroup$
    You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
    $endgroup$
    – Thomas Scanlon
    4 hours ago







1




1




$begingroup$
You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
$endgroup$
– Thomas Scanlon
4 hours ago




$begingroup$
You really mean to replace $aleph_1$-saturated by $|mathcal L|^+$-saturated. Also, it suffices to consider just the forth direction. That is, the last sentence beginning "In addition" may be dropped.
$endgroup$
– Thomas Scanlon
4 hours ago










1 Answer
1






active

oldest

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5












$begingroup$

I'm not sure if this formulation with $omega_1$-saturated models is in any of the "main standard" texts. But there is a complete treatment in these course notes by Pillay (see Proposition 2.29).



If you're looking for something in a standard published text, Corollary 3.1.6 of Model Theory: An Introduction (Marker) is along the same lines. It says:




Let $T$ be an $L$-theory. Suppose that for all quantifier-free formulas $phi(barv,w)$, if $M,Nmodels T$, $A$ is a common substructure of $M$ and $N$, $barain A$, and there is $bin M$ such that $Mmodelsphi(bara,b)$, then there is $cin N$ such that $Nmodels phi(bara,c)$. Then $T$ has quantifier elimination.




It is not too difficult to deduce the theorem you quoted from this.






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    5












    $begingroup$

    I'm not sure if this formulation with $omega_1$-saturated models is in any of the "main standard" texts. But there is a complete treatment in these course notes by Pillay (see Proposition 2.29).



    If you're looking for something in a standard published text, Corollary 3.1.6 of Model Theory: An Introduction (Marker) is along the same lines. It says:




    Let $T$ be an $L$-theory. Suppose that for all quantifier-free formulas $phi(barv,w)$, if $M,Nmodels T$, $A$ is a common substructure of $M$ and $N$, $barain A$, and there is $bin M$ such that $Mmodelsphi(bara,b)$, then there is $cin N$ such that $Nmodels phi(bara,c)$. Then $T$ has quantifier elimination.




    It is not too difficult to deduce the theorem you quoted from this.






    share|cite|improve this answer











    $endgroup$

















      5












      $begingroup$

      I'm not sure if this formulation with $omega_1$-saturated models is in any of the "main standard" texts. But there is a complete treatment in these course notes by Pillay (see Proposition 2.29).



      If you're looking for something in a standard published text, Corollary 3.1.6 of Model Theory: An Introduction (Marker) is along the same lines. It says:




      Let $T$ be an $L$-theory. Suppose that for all quantifier-free formulas $phi(barv,w)$, if $M,Nmodels T$, $A$ is a common substructure of $M$ and $N$, $barain A$, and there is $bin M$ such that $Mmodelsphi(bara,b)$, then there is $cin N$ such that $Nmodels phi(bara,c)$. Then $T$ has quantifier elimination.




      It is not too difficult to deduce the theorem you quoted from this.






      share|cite|improve this answer











      $endgroup$















        5












        5








        5





        $begingroup$

        I'm not sure if this formulation with $omega_1$-saturated models is in any of the "main standard" texts. But there is a complete treatment in these course notes by Pillay (see Proposition 2.29).



        If you're looking for something in a standard published text, Corollary 3.1.6 of Model Theory: An Introduction (Marker) is along the same lines. It says:




        Let $T$ be an $L$-theory. Suppose that for all quantifier-free formulas $phi(barv,w)$, if $M,Nmodels T$, $A$ is a common substructure of $M$ and $N$, $barain A$, and there is $bin M$ such that $Mmodelsphi(bara,b)$, then there is $cin N$ such that $Nmodels phi(bara,c)$. Then $T$ has quantifier elimination.




        It is not too difficult to deduce the theorem you quoted from this.






        share|cite|improve this answer











        $endgroup$



        I'm not sure if this formulation with $omega_1$-saturated models is in any of the "main standard" texts. But there is a complete treatment in these course notes by Pillay (see Proposition 2.29).



        If you're looking for something in a standard published text, Corollary 3.1.6 of Model Theory: An Introduction (Marker) is along the same lines. It says:




        Let $T$ be an $L$-theory. Suppose that for all quantifier-free formulas $phi(barv,w)$, if $M,Nmodels T$, $A$ is a common substructure of $M$ and $N$, $barain A$, and there is $bin M$ such that $Mmodelsphi(bara,b)$, then there is $cin N$ such that $Nmodels phi(bara,c)$. Then $T$ has quantifier elimination.




        It is not too difficult to deduce the theorem you quoted from this.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 5 hours ago

























        answered 6 hours ago









        Gabe ConantGabe Conant

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