Performance issue in code for reading line and testing for palindromeCheck if the string is palindromeCheck if a string is palindrome or two strings are the opposite of each otherTesting input integers for the palindrome propertyChecking for a palindromeMilliseconds to Time string & Time string to MillisecondsLongest Common Subsequence and Longest Subsequence PalindromeComparing a string using a stackCheck for Palindrome string in JavaLeetcode 125. Valid Palindrome (better performance?)Palindrome-testing Java program for an interviewPalindrome implementations - iterative and recursiveMatch a simple balanced language using a queue

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Performance issue in code for reading line and testing for palindrome


Check if the string is palindromeCheck if a string is palindrome or two strings are the opposite of each otherTesting input integers for the palindrome propertyChecking for a palindromeMilliseconds to Time string & Time string to MillisecondsLongest Common Subsequence and Longest Subsequence PalindromeComparing a string using a stackCheck for Palindrome string in JavaLeetcode 125. Valid Palindrome (better performance?)Palindrome-testing Java program for an interviewPalindrome implementations - iterative and recursiveMatch a simple balanced language using a queue






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


This is some code that determines if a string of characters is a palindrome or not. My professor says that there is a performance issue with the program, but I can't quite put my finger on it. Can someone find out the 'performance' issue?



Initially, I thought maybe the process is slower as it uses two memory containers, as opposed to simply comparing two halves of a single string.



int main()

char c;
bool check = true;
stack<char> cstack;
queue<char> cqueue;
cout << "Enter a string and press return." << endl;
cin.get(c);
while (c != 'n')
cstack.push(c);
cqueue.push(c);
cin.get(c);

while (check && !cqueue.empty())
if (cstack.top() != cqueue.front())
check = false;
cstack.pop();
cqueue.pop();

if (check)
cout << "Yes it is!" << endl;
else
cout << "No it's not." << endl;
return 0;










share|improve this question









New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$











  • $begingroup$
    Is there a way to combine stack top/pop and queue front/pop in a single statement?
    $endgroup$
    – dfhwze
    7 hours ago










  • $begingroup$
    You might want to have a look at this, though in that case the check was case insensitive.
    $endgroup$
    – Incomputable
    4 hours ago






  • 3




    $begingroup$
    As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
    $endgroup$
    – Deduplicator
    4 hours ago

















2












$begingroup$


This is some code that determines if a string of characters is a palindrome or not. My professor says that there is a performance issue with the program, but I can't quite put my finger on it. Can someone find out the 'performance' issue?



Initially, I thought maybe the process is slower as it uses two memory containers, as opposed to simply comparing two halves of a single string.



int main()

char c;
bool check = true;
stack<char> cstack;
queue<char> cqueue;
cout << "Enter a string and press return." << endl;
cin.get(c);
while (c != 'n')
cstack.push(c);
cqueue.push(c);
cin.get(c);

while (check && !cqueue.empty())
if (cstack.top() != cqueue.front())
check = false;
cstack.pop();
cqueue.pop();

if (check)
cout << "Yes it is!" << endl;
else
cout << "No it's not." << endl;
return 0;










share|improve this question









New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$











  • $begingroup$
    Is there a way to combine stack top/pop and queue front/pop in a single statement?
    $endgroup$
    – dfhwze
    7 hours ago










  • $begingroup$
    You might want to have a look at this, though in that case the check was case insensitive.
    $endgroup$
    – Incomputable
    4 hours ago






  • 3




    $begingroup$
    As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
    $endgroup$
    – Deduplicator
    4 hours ago













2












2








2





$begingroup$


This is some code that determines if a string of characters is a palindrome or not. My professor says that there is a performance issue with the program, but I can't quite put my finger on it. Can someone find out the 'performance' issue?



Initially, I thought maybe the process is slower as it uses two memory containers, as opposed to simply comparing two halves of a single string.



int main()

char c;
bool check = true;
stack<char> cstack;
queue<char> cqueue;
cout << "Enter a string and press return." << endl;
cin.get(c);
while (c != 'n')
cstack.push(c);
cqueue.push(c);
cin.get(c);

while (check && !cqueue.empty())
if (cstack.top() != cqueue.front())
check = false;
cstack.pop();
cqueue.pop();

if (check)
cout << "Yes it is!" << endl;
else
cout << "No it's not." << endl;
return 0;










share|improve this question









New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




This is some code that determines if a string of characters is a palindrome or not. My professor says that there is a performance issue with the program, but I can't quite put my finger on it. Can someone find out the 'performance' issue?



Initially, I thought maybe the process is slower as it uses two memory containers, as opposed to simply comparing two halves of a single string.



int main()

char c;
bool check = true;
stack<char> cstack;
queue<char> cqueue;
cout << "Enter a string and press return." << endl;
cin.get(c);
while (c != 'n')
cstack.push(c);
cqueue.push(c);
cin.get(c);

while (check && !cqueue.empty())
if (cstack.top() != cqueue.front())
check = false;
cstack.pop();
cqueue.pop();

if (check)
cout << "Yes it is!" << endl;
else
cout << "No it's not." << endl;
return 0;







c++ performance beginner strings palindrome






share|improve this question









New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 4 hours ago









Deduplicator

12.9k20 silver badges52 bronze badges




12.9k20 silver badges52 bronze badges






New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 8 hours ago









Avantika PAvantika P

162 bronze badges




162 bronze badges




New contributor



Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Avantika P is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • $begingroup$
    Is there a way to combine stack top/pop and queue front/pop in a single statement?
    $endgroup$
    – dfhwze
    7 hours ago










  • $begingroup$
    You might want to have a look at this, though in that case the check was case insensitive.
    $endgroup$
    – Incomputable
    4 hours ago






  • 3




    $begingroup$
    As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
    $endgroup$
    – Deduplicator
    4 hours ago
















  • $begingroup$
    Is there a way to combine stack top/pop and queue front/pop in a single statement?
    $endgroup$
    – dfhwze
    7 hours ago










  • $begingroup$
    You might want to have a look at this, though in that case the check was case insensitive.
    $endgroup$
    – Incomputable
    4 hours ago






  • 3




    $begingroup$
    As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
    $endgroup$
    – Deduplicator
    4 hours ago















$begingroup$
Is there a way to combine stack top/pop and queue front/pop in a single statement?
$endgroup$
– dfhwze
7 hours ago




$begingroup$
Is there a way to combine stack top/pop and queue front/pop in a single statement?
$endgroup$
– dfhwze
7 hours ago












$begingroup$
You might want to have a look at this, though in that case the check was case insensitive.
$endgroup$
– Incomputable
4 hours ago




$begingroup$
You might want to have a look at this, though in that case the check was case insensitive.
$endgroup$
– Incomputable
4 hours ago




3




3




$begingroup$
As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
$endgroup$
– Deduplicator
4 hours ago




$begingroup$
As an aside, this is nearly a complete program. Consider giving the full program next time in a similar situation (changing this now is inadvisable).
$endgroup$
– Deduplicator
4 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

  1. While it is not quite definitive, it looks like you use using namespace std;.

    That namespace is not designed for wholesale inclusion, being vast and subject to change at the whim of the implementation, aside from providing what is standardised.

    Read "Why is “using namespace std” considered bad practice?" for more detail.


  2. You should desist from using std::endl, as spurious manual flushing flushes any pretense at performance down the drain.

    For those rare cases where it is actually necessary for correctness, use std::flush for explicitness.


  3. You assume reading from std::cin always succeeds. That's generally unsupportable, please handle failure gracefully.


  4. You are reading character-by-character. Each and every read has significant overhead, which you could simply avoid by using std::getline(). Using the proper abstraction is also significantly more readable.


  5. You are storing the input twice, once in a std::queue and once in a std::stack. Even only storing it in just one std::deque (the underlying implementation for both) would be a considerable improvement.


  6. Consider encapsulating the test whether the input is a palindrome into its own reusable function, separate from actually getting it.


  7. Testing whether something is a palindrome seems a favorite passtime of many beginners.

    Thus, there are a myriad posts on how to efficiently and elegantly do that in C++, for example "Check if a string is palindrome or two strings are the opposite of each other".

    The important points are avoiding expensive copies, and only comparing each element once.


  8. If you want one of two values, conditional on some expression, consider the conditional operator expr ? true_expr : false_expr. It is designed for that.


  9. return 0; is implicit for main(). Make of that what you will.






share|improve this answer









$endgroup$




















    2












    $begingroup$

    I see two improvement points in the code.



    1. It is better to use getLine() and store the input in char* instead of reading each char and appending to a stack

    2. It is more than enough to iterate till half of the string as the remaining half is checked in the first half iteration cstack.top() != cqueue.front()





    share|improve this answer









    $endgroup$















      Your Answer






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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3












      $begingroup$

      1. While it is not quite definitive, it looks like you use using namespace std;.

        That namespace is not designed for wholesale inclusion, being vast and subject to change at the whim of the implementation, aside from providing what is standardised.

        Read "Why is “using namespace std” considered bad practice?" for more detail.


      2. You should desist from using std::endl, as spurious manual flushing flushes any pretense at performance down the drain.

        For those rare cases where it is actually necessary for correctness, use std::flush for explicitness.


      3. You assume reading from std::cin always succeeds. That's generally unsupportable, please handle failure gracefully.


      4. You are reading character-by-character. Each and every read has significant overhead, which you could simply avoid by using std::getline(). Using the proper abstraction is also significantly more readable.


      5. You are storing the input twice, once in a std::queue and once in a std::stack. Even only storing it in just one std::deque (the underlying implementation for both) would be a considerable improvement.


      6. Consider encapsulating the test whether the input is a palindrome into its own reusable function, separate from actually getting it.


      7. Testing whether something is a palindrome seems a favorite passtime of many beginners.

        Thus, there are a myriad posts on how to efficiently and elegantly do that in C++, for example "Check if a string is palindrome or two strings are the opposite of each other".

        The important points are avoiding expensive copies, and only comparing each element once.


      8. If you want one of two values, conditional on some expression, consider the conditional operator expr ? true_expr : false_expr. It is designed for that.


      9. return 0; is implicit for main(). Make of that what you will.






      share|improve this answer









      $endgroup$

















        3












        $begingroup$

        1. While it is not quite definitive, it looks like you use using namespace std;.

          That namespace is not designed for wholesale inclusion, being vast and subject to change at the whim of the implementation, aside from providing what is standardised.

          Read "Why is “using namespace std” considered bad practice?" for more detail.


        2. You should desist from using std::endl, as spurious manual flushing flushes any pretense at performance down the drain.

          For those rare cases where it is actually necessary for correctness, use std::flush for explicitness.


        3. You assume reading from std::cin always succeeds. That's generally unsupportable, please handle failure gracefully.


        4. You are reading character-by-character. Each and every read has significant overhead, which you could simply avoid by using std::getline(). Using the proper abstraction is also significantly more readable.


        5. You are storing the input twice, once in a std::queue and once in a std::stack. Even only storing it in just one std::deque (the underlying implementation for both) would be a considerable improvement.


        6. Consider encapsulating the test whether the input is a palindrome into its own reusable function, separate from actually getting it.


        7. Testing whether something is a palindrome seems a favorite passtime of many beginners.

          Thus, there are a myriad posts on how to efficiently and elegantly do that in C++, for example "Check if a string is palindrome or two strings are the opposite of each other".

          The important points are avoiding expensive copies, and only comparing each element once.


        8. If you want one of two values, conditional on some expression, consider the conditional operator expr ? true_expr : false_expr. It is designed for that.


        9. return 0; is implicit for main(). Make of that what you will.






        share|improve this answer









        $endgroup$















          3












          3








          3





          $begingroup$

          1. While it is not quite definitive, it looks like you use using namespace std;.

            That namespace is not designed for wholesale inclusion, being vast and subject to change at the whim of the implementation, aside from providing what is standardised.

            Read "Why is “using namespace std” considered bad practice?" for more detail.


          2. You should desist from using std::endl, as spurious manual flushing flushes any pretense at performance down the drain.

            For those rare cases where it is actually necessary for correctness, use std::flush for explicitness.


          3. You assume reading from std::cin always succeeds. That's generally unsupportable, please handle failure gracefully.


          4. You are reading character-by-character. Each and every read has significant overhead, which you could simply avoid by using std::getline(). Using the proper abstraction is also significantly more readable.


          5. You are storing the input twice, once in a std::queue and once in a std::stack. Even only storing it in just one std::deque (the underlying implementation for both) would be a considerable improvement.


          6. Consider encapsulating the test whether the input is a palindrome into its own reusable function, separate from actually getting it.


          7. Testing whether something is a palindrome seems a favorite passtime of many beginners.

            Thus, there are a myriad posts on how to efficiently and elegantly do that in C++, for example "Check if a string is palindrome or two strings are the opposite of each other".

            The important points are avoiding expensive copies, and only comparing each element once.


          8. If you want one of two values, conditional on some expression, consider the conditional operator expr ? true_expr : false_expr. It is designed for that.


          9. return 0; is implicit for main(). Make of that what you will.






          share|improve this answer









          $endgroup$



          1. While it is not quite definitive, it looks like you use using namespace std;.

            That namespace is not designed for wholesale inclusion, being vast and subject to change at the whim of the implementation, aside from providing what is standardised.

            Read "Why is “using namespace std” considered bad practice?" for more detail.


          2. You should desist from using std::endl, as spurious manual flushing flushes any pretense at performance down the drain.

            For those rare cases where it is actually necessary for correctness, use std::flush for explicitness.


          3. You assume reading from std::cin always succeeds. That's generally unsupportable, please handle failure gracefully.


          4. You are reading character-by-character. Each and every read has significant overhead, which you could simply avoid by using std::getline(). Using the proper abstraction is also significantly more readable.


          5. You are storing the input twice, once in a std::queue and once in a std::stack. Even only storing it in just one std::deque (the underlying implementation for both) would be a considerable improvement.


          6. Consider encapsulating the test whether the input is a palindrome into its own reusable function, separate from actually getting it.


          7. Testing whether something is a palindrome seems a favorite passtime of many beginners.

            Thus, there are a myriad posts on how to efficiently and elegantly do that in C++, for example "Check if a string is palindrome or two strings are the opposite of each other".

            The important points are avoiding expensive copies, and only comparing each element once.


          8. If you want one of two values, conditional on some expression, consider the conditional operator expr ? true_expr : false_expr. It is designed for that.


          9. return 0; is implicit for main(). Make of that what you will.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          DeduplicatorDeduplicator

          12.9k20 silver badges52 bronze badges




          12.9k20 silver badges52 bronze badges























              2












              $begingroup$

              I see two improvement points in the code.



              1. It is better to use getLine() and store the input in char* instead of reading each char and appending to a stack

              2. It is more than enough to iterate till half of the string as the remaining half is checked in the first half iteration cstack.top() != cqueue.front()





              share|improve this answer









              $endgroup$

















                2












                $begingroup$

                I see two improvement points in the code.



                1. It is better to use getLine() and store the input in char* instead of reading each char and appending to a stack

                2. It is more than enough to iterate till half of the string as the remaining half is checked in the first half iteration cstack.top() != cqueue.front()





                share|improve this answer









                $endgroup$















                  2












                  2








                  2





                  $begingroup$

                  I see two improvement points in the code.



                  1. It is better to use getLine() and store the input in char* instead of reading each char and appending to a stack

                  2. It is more than enough to iterate till half of the string as the remaining half is checked in the first half iteration cstack.top() != cqueue.front()





                  share|improve this answer









                  $endgroup$



                  I see two improvement points in the code.



                  1. It is better to use getLine() and store the input in char* instead of reading each char and appending to a stack

                  2. It is more than enough to iterate till half of the string as the remaining half is checked in the first half iteration cstack.top() != cqueue.front()






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 7 hours ago









                  Ramanathan GanesanRamanathan Ganesan

                  4394 silver badges5 bronze badges




                  4394 silver badges5 bronze badges




















                      Avantika P is a new contributor. Be nice, and check out our Code of Conduct.









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                      Avantika P is a new contributor. Be nice, and check out our Code of Conduct.














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