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Please let me know why 2/16 has a remainder of 2. Thanks
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Please let me know why 2/16 has a remainder of 2. Thanks
When the roulette has hit 5 reds why shouldn't I bet to black?Find the pattern - puzzleAny other prime numbers that satisfy this condition?Helping 7th grade with math question… I'm stumped.Roulette System that I know can't work but don't understand Why?Division Without DivisionFigure out what to multiply a number by to get it to double after x times.Determine minimum selling price based on cost and feesTwo cars one $10$mph faster than other start at same point and travel in opposite directions.How to arrange 80 people given the following constraints?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I would like to know why this division 2/16 has a remainder of 2.
I understand remainders from this division 10/6 = 1 remainder is 4.
But I can't figure out why 2/16 has a remainder of 2.
Thanks
recreational-mathematics
asked 8 hours ago
NataNata
211 bronze badge
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Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
I would like to know why this division 2/16 has a remainder of 2.
I understand remainders from this division 10/6 = 1 remainder is 4.
But I can't figure out why 2/16 has a remainder of 2.
Thanks
recreational-mathematics
asked 8 hours ago
NataNata
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago
add a comment |
$begingroup$
I would like to know why this division 2/16 has a remainder of 2.
I understand remainders from this division 10/6 = 1 remainder is 4.
But I can't figure out why 2/16 has a remainder of 2.
Thanks
recreational-mathematics
asked 8 hours ago
NataNata
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I would like to know why this division 2/16 has a remainder of 2.
I understand remainders from this division 10/6 = 1 remainder is 4.
But I can't figure out why 2/16 has a remainder of 2.
Thanks
recreational-mathematics
recreational-mathematics
asked 8 hours ago
NataNata
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
NataNata
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
NataNata
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
NataNata
211 bronze badge
asked 8 hours ago
NataNata
211 bronze badge
211 bronze badge
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Nata is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago
add a comment |
1
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago
1
1
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
$16$ goes into $2$ a total of $0$ times. Therefore the quotient is $0$ and the remainder is $2$. This happens whenever the dividend is smaller than the divisor.
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
$endgroup$
add a comment |
$begingroup$
$2/16 = 0 .... 2$
In other words,
$2 = 16 * 0 +2$
Intuitively, doing this division asks you to make choice of a largest number, which, after being multiplied by the divisor (in this case, 16) must not exceed the number being divided (in this case, 2); (so this choice has to be $0$ other wise you exceed $2$). Now whatever remains is the remainder (in this case, 2).
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
$endgroup$
add a comment |
$begingroup$
If $a < b$, then $a mod b = a$. In particular, $2 mod 16 = 2$.
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
$endgroup$
add a comment |
$begingroup$
You can say that $2/16$ has a remainder of 2 because $2=16.0+2$ which is essentially the remainder.
It would also be correct to say that it has a remainder of $-14$ (I know that this is strange but it is true and this fact is helpful to know for some questions, although not of much help for this one) and in fact this is used in some proofs of modular arithmetic in number theory. Just a side fact!
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$16$ goes into $2$ a total of $0$ times. Therefore the quotient is $0$ and the remainder is $2$. This happens whenever the dividend is smaller than the divisor.
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
$endgroup$
add a comment |
$begingroup$
$16$ goes into $2$ a total of $0$ times. Therefore the quotient is $0$ and the remainder is $2$. This happens whenever the dividend is smaller than the divisor.
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
$endgroup$
add a comment |
$begingroup$
$16$ goes into $2$ a total of $0$ times. Therefore the quotient is $0$ and the remainder is $2$. This happens whenever the dividend is smaller than the divisor.
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
$endgroup$
$16$ goes into $2$ a total of $0$ times. Therefore the quotient is $0$ and the remainder is $2$. This happens whenever the dividend is smaller than the divisor.
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
answered 8 hours ago
Matt SamuelMatt Samuel
40.8k6 gold badges38 silver badges71 bronze badges
40.8k6 gold badges38 silver badges71 bronze badges
add a comment |
add a comment |
$begingroup$
$2/16 = 0 .... 2$
In other words,
$2 = 16 * 0 +2$
Intuitively, doing this division asks you to make choice of a largest number, which, after being multiplied by the divisor (in this case, 16) must not exceed the number being divided (in this case, 2); (so this choice has to be $0$ other wise you exceed $2$). Now whatever remains is the remainder (in this case, 2).
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
$endgroup$
add a comment |
$begingroup$
$2/16 = 0 .... 2$
In other words,
$2 = 16 * 0 +2$
Intuitively, doing this division asks you to make choice of a largest number, which, after being multiplied by the divisor (in this case, 16) must not exceed the number being divided (in this case, 2); (so this choice has to be $0$ other wise you exceed $2$). Now whatever remains is the remainder (in this case, 2).
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
$endgroup$
add a comment |
$begingroup$
$2/16 = 0 .... 2$
In other words,
$2 = 16 * 0 +2$
Intuitively, doing this division asks you to make choice of a largest number, which, after being multiplied by the divisor (in this case, 16) must not exceed the number being divided (in this case, 2); (so this choice has to be $0$ other wise you exceed $2$). Now whatever remains is the remainder (in this case, 2).
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
$endgroup$
$2/16 = 0 .... 2$
In other words,
$2 = 16 * 0 +2$
Intuitively, doing this division asks you to make choice of a largest number, which, after being multiplied by the divisor (in this case, 16) must not exceed the number being divided (in this case, 2); (so this choice has to be $0$ other wise you exceed $2$). Now whatever remains is the remainder (in this case, 2).
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
answered 8 hours ago
Book Book BookBook Book Book
4997 bronze badges
4997 bronze badges
add a comment |
add a comment |
$begingroup$
If $a < b$, then $a mod b = a$. In particular, $2 mod 16 = 2$.
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
$endgroup$
add a comment |
$begingroup$
If $a < b$, then $a mod b = a$. In particular, $2 mod 16 = 2$.
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
$endgroup$
add a comment |
$begingroup$
If $a < b$, then $a mod b = a$. In particular, $2 mod 16 = 2$.
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
$endgroup$
If $a < b$, then $a mod b = a$. In particular, $2 mod 16 = 2$.
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
answered 8 hours ago
Geoffrey TrangGeoffrey Trang
3288 bronze badges
3288 bronze badges
add a comment |
add a comment |
$begingroup$
You can say that $2/16$ has a remainder of 2 because $2=16.0+2$ which is essentially the remainder.
It would also be correct to say that it has a remainder of $-14$ (I know that this is strange but it is true and this fact is helpful to know for some questions, although not of much help for this one) and in fact this is used in some proofs of modular arithmetic in number theory. Just a side fact!
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
You can say that $2/16$ has a remainder of 2 because $2=16.0+2$ which is essentially the remainder.
It would also be correct to say that it has a remainder of $-14$ (I know that this is strange but it is true and this fact is helpful to know for some questions, although not of much help for this one) and in fact this is used in some proofs of modular arithmetic in number theory. Just a side fact!
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
You can say that $2/16$ has a remainder of 2 because $2=16.0+2$ which is essentially the remainder.
It would also be correct to say that it has a remainder of $-14$ (I know that this is strange but it is true and this fact is helpful to know for some questions, although not of much help for this one) and in fact this is used in some proofs of modular arithmetic in number theory. Just a side fact!
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
You can say that $2/16$ has a remainder of 2 because $2=16.0+2$ which is essentially the remainder.
It would also be correct to say that it has a remainder of $-14$ (I know that this is strange but it is true and this fact is helpful to know for some questions, although not of much help for this one) and in fact this is used in some proofs of modular arithmetic in number theory. Just a side fact!
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
answered 8 hours ago
rockin numbersrockin numbers
83 bronze badges
83 bronze badges
New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
rockin numbers is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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1
$begingroup$
$2 = 0cdot 16 + 2$.
$endgroup$
– Randall
8 hours ago
$begingroup$
or $2div16="0$ with remainder $2"$
$endgroup$
– J. W. Tanner
8 hours ago