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Excluding specific string grep is also including similar strings


grep multiple strings, count lines, echo output for each stringRun `grep` excluding a file in a specific pathExcluding nested directories with grepExcluding multiple patterns with one grep commandREGEX and GREP — Search string including optional and static wordsGrep every string inside specific X stringgrep a string from a specific columnShell Script: Want to delete two consecutive lines matching pattern from specific linegrep -v is not excluding the stringsGrep complete name including dot in pattern






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I am trying to exclude certain entries of URLs (using IPs instead of domain names) in a list with a grep command, specifically to remove all entries starting with https:// and ending with :80. however, entries with https:// and :8080 are also being included.



My grep command is:



egrep -v "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80"


How can I force grep to only exclude :80 and not :8080



An example of the input file contents is:



http://10.10.46.1:80
http://10.10.48.67:8080
http://10.10.48.67:443
https://10.10.46.1:80
https://10.10.48.67:8080
https://10.10.48.67:443









share|improve this question
























  • Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

    – terdon
    9 hours ago

















1















I am trying to exclude certain entries of URLs (using IPs instead of domain names) in a list with a grep command, specifically to remove all entries starting with https:// and ending with :80. however, entries with https:// and :8080 are also being included.



My grep command is:



egrep -v "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80"


How can I force grep to only exclude :80 and not :8080



An example of the input file contents is:



http://10.10.46.1:80
http://10.10.48.67:8080
http://10.10.48.67:443
https://10.10.46.1:80
https://10.10.48.67:8080
https://10.10.48.67:443









share|improve this question
























  • Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

    – terdon
    9 hours ago













1












1








1








I am trying to exclude certain entries of URLs (using IPs instead of domain names) in a list with a grep command, specifically to remove all entries starting with https:// and ending with :80. however, entries with https:// and :8080 are also being included.



My grep command is:



egrep -v "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80"


How can I force grep to only exclude :80 and not :8080



An example of the input file contents is:



http://10.10.46.1:80
http://10.10.48.67:8080
http://10.10.48.67:443
https://10.10.46.1:80
https://10.10.48.67:8080
https://10.10.48.67:443









share|improve this question
















I am trying to exclude certain entries of URLs (using IPs instead of domain names) in a list with a grep command, specifically to remove all entries starting with https:// and ending with :80. however, entries with https:// and :8080 are also being included.



My grep command is:



egrep -v "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80"


How can I force grep to only exclude :80 and not :8080



An example of the input file contents is:



http://10.10.46.1:80
http://10.10.48.67:8080
http://10.10.48.67:443
https://10.10.46.1:80
https://10.10.48.67:8080
https://10.10.48.67:443






text-processing grep






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 9 hours ago







john doe

















asked 9 hours ago









john doejohn doe

856 bronze badges




856 bronze badges












  • Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

    – terdon
    9 hours ago

















  • Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

    – terdon
    9 hours ago
















Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

– terdon
9 hours ago





Can you give us an example of your input file please? Are the IPs the only thing on the line? Are there any characters after the IPs? What characters? A space?

– terdon
9 hours ago










1 Answer
1






active

oldest

votes


















4














Just be a tad more specific in your grep command. If the IPs are the only thing on the line, so the :80 will be the last 3 characters, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80$"


Or, if there can be whitespace after the 80, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80s*$"


If the :80 isn't the last thing on the line, just grep for cases where there is a space after it:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80 "


If the last character isn't a space, adapt to suit your input.






share|improve this answer























  • Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

    – glenn jackman
    8 hours ago











  • Or grep -x -v ...

    – Kusalananda
    2 hours ago













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














Just be a tad more specific in your grep command. If the IPs are the only thing on the line, so the :80 will be the last 3 characters, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80$"


Or, if there can be whitespace after the 80, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80s*$"


If the :80 isn't the last thing on the line, just grep for cases where there is a space after it:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80 "


If the last character isn't a space, adapt to suit your input.






share|improve this answer























  • Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

    – glenn jackman
    8 hours ago











  • Or grep -x -v ...

    – Kusalananda
    2 hours ago















4














Just be a tad more specific in your grep command. If the IPs are the only thing on the line, so the :80 will be the last 3 characters, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80$"


Or, if there can be whitespace after the 80, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80s*$"


If the :80 isn't the last thing on the line, just grep for cases where there is a space after it:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80 "


If the last character isn't a space, adapt to suit your input.






share|improve this answer























  • Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

    – glenn jackman
    8 hours ago











  • Or grep -x -v ...

    – Kusalananda
    2 hours ago













4












4








4







Just be a tad more specific in your grep command. If the IPs are the only thing on the line, so the :80 will be the last 3 characters, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80$"


Or, if there can be whitespace after the 80, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80s*$"


If the :80 isn't the last thing on the line, just grep for cases where there is a space after it:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80 "


If the last character isn't a space, adapt to suit your input.






share|improve this answer













Just be a tad more specific in your grep command. If the IPs are the only thing on the line, so the :80 will be the last 3 characters, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80$"


Or, if there can be whitespace after the 80, use:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80s*$"


If the :80 isn't the last thing on the line, just grep for cases where there is a space after it:



grep -Ev "https://[0-9]1,3.[0-9]1,3.[0-9]1,3.[0-9]1,3:80 "


If the last character isn't a space, adapt to suit your input.







share|improve this answer












share|improve this answer



share|improve this answer










answered 9 hours ago









terdonterdon

139k33 gold badges286 silver badges463 bronze badges




139k33 gold badges286 silver badges463 bronze badges












  • Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

    – glenn jackman
    8 hours ago











  • Or grep -x -v ...

    – Kusalananda
    2 hours ago

















  • Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

    – glenn jackman
    8 hours ago











  • Or grep -x -v ...

    – Kusalananda
    2 hours ago
















Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

– glenn jackman
8 hours ago





Or add a word boundary: ...:80\>" -- gnu.org/software/gnulib/manual/html_node/…

– glenn jackman
8 hours ago













Or grep -x -v ...

– Kusalananda
2 hours ago





Or grep -x -v ...

– Kusalananda
2 hours ago

















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