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How to handle async subshell exit


exit shell script from a subshellRunning a “scheduled”/delayed script as sudo on server, via ssh - and right before ssh exitWhere is `exit` defined?How to run subshell commands over SSH?Wait for foreground process to emit string, then send to backgroundSSH connections running in the background don't exit if multiple connections have been started by the same shellHow to Group Commands After '&&' or '||' Branch and Not Invoke Subshell Variable Restriction?Bash find if all env variables are declared, by variable namegrabbing exit code of background process/subshellBackground process of subshell strange behaviour






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















Say I have this:



set -e;

(
docker stop notifier-server
docker rm -f notifier-server
exit 1 # explicitly exit with non-zero
) &

wait;

echo 'we are here now'


will we always get to the echo line, even if the subshell exits with non-zero? I assume so, since it's a backend process/subshell?



What's the right way to look at this?










share|improve this question







New contributor



zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

























    3















    Say I have this:



    set -e;

    (
    docker stop notifier-server
    docker rm -f notifier-server
    exit 1 # explicitly exit with non-zero
    ) &

    wait;

    echo 'we are here now'


    will we always get to the echo line, even if the subshell exits with non-zero? I assume so, since it's a backend process/subshell?



    What's the right way to look at this?










    share|improve this question







    New contributor



    zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      3












      3








      3








      Say I have this:



      set -e;

      (
      docker stop notifier-server
      docker rm -f notifier-server
      exit 1 # explicitly exit with non-zero
      ) &

      wait;

      echo 'we are here now'


      will we always get to the echo line, even if the subshell exits with non-zero? I assume so, since it's a backend process/subshell?



      What's the right way to look at this?










      share|improve this question







      New contributor



      zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Say I have this:



      set -e;

      (
      docker stop notifier-server
      docker rm -f notifier-server
      exit 1 # explicitly exit with non-zero
      ) &

      wait;

      echo 'we are here now'


      will we always get to the echo line, even if the subshell exits with non-zero? I assume so, since it's a backend process/subshell?



      What's the right way to look at this?







      bash shell background-process subshell






      share|improve this question







      New contributor



      zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share|improve this question







      New contributor



      zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share|improve this question




      share|improve this question






      New contributor



      zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      asked 8 hours ago









      zambiazzzzambiazzz

      161 bronze badge




      161 bronze badge




      New contributor



      zambiazzz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor




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      Check out our Code of Conduct.






















          2 Answers
          2






          active

          oldest

          votes


















          2














          It is not related to the process being a background process, it is related to the exit status of the wait command.



          From help wait:




          If ID is not given, waits for all currently active child processes, and the return status is zero.




          $ bash -exc '(sleep 1; exit 1) & wait ; echo done'
          + wait
          + sleep 1
          + exit 1
          + echo done
          done



          If the -n option is supplied, waits for the next job to terminate and returns its exit status.




          $ bash -exc '(sleep 1; exit 1) & wait -n; echo $?:done'
          + wait -n
          + sleep 1
          + exit 1





          share|improve this answer






























            1














            Your code would not terminate the current shell session since no non-zero exit status is returned to it. The result in the calling shell of starting a background job is always zero.



            Would you have used wait "$!" or wait -n ("wait for next job to finish"), then the shell session would have terminated since wait would have returned the exit status of the job that it waited for, which is non-zero.



            See help wait in bash.






            share|improve this answer

























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              It is not related to the process being a background process, it is related to the exit status of the wait command.



              From help wait:




              If ID is not given, waits for all currently active child processes, and the return status is zero.




              $ bash -exc '(sleep 1; exit 1) & wait ; echo done'
              + wait
              + sleep 1
              + exit 1
              + echo done
              done



              If the -n option is supplied, waits for the next job to terminate and returns its exit status.




              $ bash -exc '(sleep 1; exit 1) & wait -n; echo $?:done'
              + wait -n
              + sleep 1
              + exit 1





              share|improve this answer



























                2














                It is not related to the process being a background process, it is related to the exit status of the wait command.



                From help wait:




                If ID is not given, waits for all currently active child processes, and the return status is zero.




                $ bash -exc '(sleep 1; exit 1) & wait ; echo done'
                + wait
                + sleep 1
                + exit 1
                + echo done
                done



                If the -n option is supplied, waits for the next job to terminate and returns its exit status.




                $ bash -exc '(sleep 1; exit 1) & wait -n; echo $?:done'
                + wait -n
                + sleep 1
                + exit 1





                share|improve this answer

























                  2












                  2








                  2







                  It is not related to the process being a background process, it is related to the exit status of the wait command.



                  From help wait:




                  If ID is not given, waits for all currently active child processes, and the return status is zero.




                  $ bash -exc '(sleep 1; exit 1) & wait ; echo done'
                  + wait
                  + sleep 1
                  + exit 1
                  + echo done
                  done



                  If the -n option is supplied, waits for the next job to terminate and returns its exit status.




                  $ bash -exc '(sleep 1; exit 1) & wait -n; echo $?:done'
                  + wait -n
                  + sleep 1
                  + exit 1





                  share|improve this answer













                  It is not related to the process being a background process, it is related to the exit status of the wait command.



                  From help wait:




                  If ID is not given, waits for all currently active child processes, and the return status is zero.




                  $ bash -exc '(sleep 1; exit 1) & wait ; echo done'
                  + wait
                  + sleep 1
                  + exit 1
                  + echo done
                  done



                  If the -n option is supplied, waits for the next job to terminate and returns its exit status.




                  $ bash -exc '(sleep 1; exit 1) & wait -n; echo $?:done'
                  + wait -n
                  + sleep 1
                  + exit 1






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 8 hours ago









                  RalfFriedlRalfFriedl

                  5,8703 gold badges12 silver badges26 bronze badges




                  5,8703 gold badges12 silver badges26 bronze badges























                      1














                      Your code would not terminate the current shell session since no non-zero exit status is returned to it. The result in the calling shell of starting a background job is always zero.



                      Would you have used wait "$!" or wait -n ("wait for next job to finish"), then the shell session would have terminated since wait would have returned the exit status of the job that it waited for, which is non-zero.



                      See help wait in bash.






                      share|improve this answer



























                        1














                        Your code would not terminate the current shell session since no non-zero exit status is returned to it. The result in the calling shell of starting a background job is always zero.



                        Would you have used wait "$!" or wait -n ("wait for next job to finish"), then the shell session would have terminated since wait would have returned the exit status of the job that it waited for, which is non-zero.



                        See help wait in bash.






                        share|improve this answer

























                          1












                          1








                          1







                          Your code would not terminate the current shell session since no non-zero exit status is returned to it. The result in the calling shell of starting a background job is always zero.



                          Would you have used wait "$!" or wait -n ("wait for next job to finish"), then the shell session would have terminated since wait would have returned the exit status of the job that it waited for, which is non-zero.



                          See help wait in bash.






                          share|improve this answer













                          Your code would not terminate the current shell session since no non-zero exit status is returned to it. The result in the calling shell of starting a background job is always zero.



                          Would you have used wait "$!" or wait -n ("wait for next job to finish"), then the shell session would have terminated since wait would have returned the exit status of the job that it waited for, which is non-zero.



                          See help wait in bash.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 8 hours ago









                          KusalanandaKusalananda

                          153k18 gold badges301 silver badges482 bronze badges




                          153k18 gold badges301 silver badges482 bronze badges




















                              zambiazzz is a new contributor. Be nice, and check out our Code of Conduct.









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