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$begingroup$
I apologize for the very basic question but I seem to be lacking some fundamental knowledge.
I am using an infra red LED in a circuit and it seems like it is drawing around 15mA at 5v. I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents. I got confused because my understanding of current is that the consumer draws as much as it needs and the only requirement for the power source regarding current is that it must supply at least that. For example if my power source is a 5v 1Ah battery the current flowing would still be 15mA regardless of the higher capability of the battery. I got further more confused by the second part. I thought resistors affect the EMF, not current, how can I calculate what resistance I need in order to limit current to 15mA?
voltage current ohms-law
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
$endgroup$
add a comment |
$begingroup$
I apologize for the very basic question but I seem to be lacking some fundamental knowledge.
I am using an infra red LED in a circuit and it seems like it is drawing around 15mA at 5v. I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents. I got confused because my understanding of current is that the consumer draws as much as it needs and the only requirement for the power source regarding current is that it must supply at least that. For example if my power source is a 5v 1Ah battery the current flowing would still be 15mA regardless of the higher capability of the battery. I got further more confused by the second part. I thought resistors affect the EMF, not current, how can I calculate what resistance I need in order to limit current to 15mA?
voltage current ohms-law
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
$endgroup$
1
$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
1
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago
add a comment |
$begingroup$
I apologize for the very basic question but I seem to be lacking some fundamental knowledge.
I am using an infra red LED in a circuit and it seems like it is drawing around 15mA at 5v. I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents. I got confused because my understanding of current is that the consumer draws as much as it needs and the only requirement for the power source regarding current is that it must supply at least that. For example if my power source is a 5v 1Ah battery the current flowing would still be 15mA regardless of the higher capability of the battery. I got further more confused by the second part. I thought resistors affect the EMF, not current, how can I calculate what resistance I need in order to limit current to 15mA?
voltage current ohms-law
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
$endgroup$
I apologize for the very basic question but I seem to be lacking some fundamental knowledge.
I am using an infra red LED in a circuit and it seems like it is drawing around 15mA at 5v. I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents. I got confused because my understanding of current is that the consumer draws as much as it needs and the only requirement for the power source regarding current is that it must supply at least that. For example if my power source is a 5v 1Ah battery the current flowing would still be 15mA regardless of the higher capability of the battery. I got further more confused by the second part. I thought resistors affect the EMF, not current, how can I calculate what resistance I need in order to limit current to 15mA?
voltage current ohms-law
voltage current ohms-law
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
asked 8 hours ago
php_nub_qqphp_nub_qq
1545
1545
1
$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
1
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago
add a comment |
1
$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
1
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago
1
1
$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
1
1
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I am using an infrared LED in a circuit and it seems like it is drawing around 15 mA at 5 V.
That is unlikely unless it has a built-in resistor.
Figure 1. The I versus V curves for a range of typical LEDs shows that the forward voltage of an IR LED is about 1.25 V at 20 mA. Source: LED IV curves.*
Note that if you were to apply even 2 V to the IR LED that the current would exceed 100 mA and it might not last long. At 5 V a bare IR LED would almost certain die instantaneously.
I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents.
A better explanation would be that you need to limit the current through the LED to a safe value. A resistor is the simplest way of doing this.
I got confused because my understanding of current is that the consumer draws as much as it needs ...
Yes, but the graph is showing us that at 5 V it "needs" a very high current.
... and the only requirement for the power source regarding current is that it must supply at least that.
That's correct (subject to my previous comment).
For example if my power source is a 5 V 1Ah battery the current flowing would still be 15 mA regardless of the higher capability of the battery.
Only if there is a current limiter in the circuit. Again, a resistor would be the normal solution.
I got further more confused by the second part. I thought resistors affect the EMF, not current, ...
The resistor will both limit the current and create a voltage drop.
How can I calculate what resistance I need in order to limit current to 15 mA?
There are many, many sites on the Internet that explain this. The load-line tool below may be of interest.
Figure 2. A loadline graphic calculator for various LEDs on a 5 V supply. Source: Loadline resistance graphic tool.
To use the tool:
- Select your LED colour: IR in your case.
- Select the current you want: 15 mA in your case.
- On the If axis move up to the 15 mA line and move across to the IR curve.
- Select the nearest loadline curve: 270 Ω.
A 270 Ω resistor will limit the current through your IR LED to about 15 mA on a 5 V supply. There will be 1.25 V across your LED and about 3.75 V across your 270 Ω resistor.
answered 7 hours ago
TransistorTransistor
91.8k788198
$endgroup$
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
add a comment |
$begingroup$
Instead of saying the consumer (circuit) draws as much as it needs, it is better to say current will flow as much as is allowed by the circuit.
How much current a circuit will allow is based on its resistance (or impedance). An LED has a voltage drop, but very little resistance. This small resistance means that more current will flow through it than is healthy.
A resistor is an easy and common way to limit this current. There are many many examples on this site alone on how to do that. Search for "LED current limiting".
To get you started, use Ohm's Law to calculate the resistor you want:
Subtract the LED's voltage drop from your source voltage. This is how much voltage you need to drop across your resistor. Now use the amount of current you want to pass through your LED to calculate (using Ohm's Law) the size of resistor that will do this.
answered 7 hours ago
evildemonicevildemonic
3,10911027
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I am using an infrared LED in a circuit and it seems like it is drawing around 15 mA at 5 V.
That is unlikely unless it has a built-in resistor.
Figure 1. The I versus V curves for a range of typical LEDs shows that the forward voltage of an IR LED is about 1.25 V at 20 mA. Source: LED IV curves.*
Note that if you were to apply even 2 V to the IR LED that the current would exceed 100 mA and it might not last long. At 5 V a bare IR LED would almost certain die instantaneously.
I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents.
A better explanation would be that you need to limit the current through the LED to a safe value. A resistor is the simplest way of doing this.
I got confused because my understanding of current is that the consumer draws as much as it needs ...
Yes, but the graph is showing us that at 5 V it "needs" a very high current.
... and the only requirement for the power source regarding current is that it must supply at least that.
That's correct (subject to my previous comment).
For example if my power source is a 5 V 1Ah battery the current flowing would still be 15 mA regardless of the higher capability of the battery.
Only if there is a current limiter in the circuit. Again, a resistor would be the normal solution.
I got further more confused by the second part. I thought resistors affect the EMF, not current, ...
The resistor will both limit the current and create a voltage drop.
How can I calculate what resistance I need in order to limit current to 15 mA?
There are many, many sites on the Internet that explain this. The load-line tool below may be of interest.
Figure 2. A loadline graphic calculator for various LEDs on a 5 V supply. Source: Loadline resistance graphic tool.
To use the tool:
- Select your LED colour: IR in your case.
- Select the current you want: 15 mA in your case.
- On the If axis move up to the 15 mA line and move across to the IR curve.
- Select the nearest loadline curve: 270 Ω.
A 270 Ω resistor will limit the current through your IR LED to about 15 mA on a 5 V supply. There will be 1.25 V across your LED and about 3.75 V across your 270 Ω resistor.
answered 7 hours ago
TransistorTransistor
91.8k788198
$endgroup$
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
add a comment |
$begingroup$
I am using an infrared LED in a circuit and it seems like it is drawing around 15 mA at 5 V.
That is unlikely unless it has a built-in resistor.
Figure 1. The I versus V curves for a range of typical LEDs shows that the forward voltage of an IR LED is about 1.25 V at 20 mA. Source: LED IV curves.*
Note that if you were to apply even 2 V to the IR LED that the current would exceed 100 mA and it might not last long. At 5 V a bare IR LED would almost certain die instantaneously.
I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents.
A better explanation would be that you need to limit the current through the LED to a safe value. A resistor is the simplest way of doing this.
I got confused because my understanding of current is that the consumer draws as much as it needs ...
Yes, but the graph is showing us that at 5 V it "needs" a very high current.
... and the only requirement for the power source regarding current is that it must supply at least that.
That's correct (subject to my previous comment).
For example if my power source is a 5 V 1Ah battery the current flowing would still be 15 mA regardless of the higher capability of the battery.
Only if there is a current limiter in the circuit. Again, a resistor would be the normal solution.
I got further more confused by the second part. I thought resistors affect the EMF, not current, ...
The resistor will both limit the current and create a voltage drop.
How can I calculate what resistance I need in order to limit current to 15 mA?
There are many, many sites on the Internet that explain this. The load-line tool below may be of interest.
Figure 2. A loadline graphic calculator for various LEDs on a 5 V supply. Source: Loadline resistance graphic tool.
To use the tool:
- Select your LED colour: IR in your case.
- Select the current you want: 15 mA in your case.
- On the If axis move up to the 15 mA line and move across to the IR curve.
- Select the nearest loadline curve: 270 Ω.
A 270 Ω resistor will limit the current through your IR LED to about 15 mA on a 5 V supply. There will be 1.25 V across your LED and about 3.75 V across your 270 Ω resistor.
answered 7 hours ago
TransistorTransistor
91.8k788198
$endgroup$
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
add a comment |
$begingroup$
I am using an infrared LED in a circuit and it seems like it is drawing around 15 mA at 5 V.
That is unlikely unless it has a built-in resistor.
Figure 1. The I versus V curves for a range of typical LEDs shows that the forward voltage of an IR LED is about 1.25 V at 20 mA. Source: LED IV curves.*
Note that if you were to apply even 2 V to the IR LED that the current would exceed 100 mA and it might not last long. At 5 V a bare IR LED would almost certain die instantaneously.
I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents.
A better explanation would be that you need to limit the current through the LED to a safe value. A resistor is the simplest way of doing this.
I got confused because my understanding of current is that the consumer draws as much as it needs ...
Yes, but the graph is showing us that at 5 V it "needs" a very high current.
... and the only requirement for the power source regarding current is that it must supply at least that.
That's correct (subject to my previous comment).
For example if my power source is a 5 V 1Ah battery the current flowing would still be 15 mA regardless of the higher capability of the battery.
Only if there is a current limiter in the circuit. Again, a resistor would be the normal solution.
I got further more confused by the second part. I thought resistors affect the EMF, not current, ...
The resistor will both limit the current and create a voltage drop.
How can I calculate what resistance I need in order to limit current to 15 mA?
There are many, many sites on the Internet that explain this. The load-line tool below may be of interest.
Figure 2. A loadline graphic calculator for various LEDs on a 5 V supply. Source: Loadline resistance graphic tool.
To use the tool:
- Select your LED colour: IR in your case.
- Select the current you want: 15 mA in your case.
- On the If axis move up to the 15 mA line and move across to the IR curve.
- Select the nearest loadline curve: 270 Ω.
A 270 Ω resistor will limit the current through your IR LED to about 15 mA on a 5 V supply. There will be 1.25 V across your LED and about 3.75 V across your 270 Ω resistor.
answered 7 hours ago
TransistorTransistor
91.8k788198
$endgroup$
I am using an infrared LED in a circuit and it seems like it is drawing around 15 mA at 5 V.
That is unlikely unless it has a built-in resistor.
Figure 1. The I versus V curves for a range of typical LEDs shows that the forward voltage of an IR LED is about 1.25 V at 20 mA. Source: LED IV curves.*
Note that if you were to apply even 2 V to the IR LED that the current would exceed 100 mA and it might not last long. At 5 V a bare IR LED would almost certain die instantaneously.
I was told today that I am running a chance of burning it since infra red LEDs require 1 to 2 volts as well as I should consider adding a resistor to protect it from higher currents.
A better explanation would be that you need to limit the current through the LED to a safe value. A resistor is the simplest way of doing this.
I got confused because my understanding of current is that the consumer draws as much as it needs ...
Yes, but the graph is showing us that at 5 V it "needs" a very high current.
... and the only requirement for the power source regarding current is that it must supply at least that.
That's correct (subject to my previous comment).
For example if my power source is a 5 V 1Ah battery the current flowing would still be 15 mA regardless of the higher capability of the battery.
Only if there is a current limiter in the circuit. Again, a resistor would be the normal solution.
I got further more confused by the second part. I thought resistors affect the EMF, not current, ...
The resistor will both limit the current and create a voltage drop.
How can I calculate what resistance I need in order to limit current to 15 mA?
There are many, many sites on the Internet that explain this. The load-line tool below may be of interest.
Figure 2. A loadline graphic calculator for various LEDs on a 5 V supply. Source: Loadline resistance graphic tool.
To use the tool:
- Select your LED colour: IR in your case.
- Select the current you want: 15 mA in your case.
- On the If axis move up to the 15 mA line and move across to the IR curve.
- Select the nearest loadline curve: 270 Ω.
A 270 Ω resistor will limit the current through your IR LED to about 15 mA on a 5 V supply. There will be 1.25 V across your LED and about 3.75 V across your 270 Ω resistor.
answered 7 hours ago
TransistorTransistor
91.8k788198
answered 7 hours ago
TransistorTransistor
91.8k788198
answered 7 hours ago
TransistorTransistor
91.8k788198
answered 7 hours ago
TransistorTransistor
91.8k788198
91.8k788198
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So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
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– php_nub_qq
6 hours ago
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Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
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– Transistor
6 hours ago
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Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
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It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
add a comment |
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
So if I had a 1V power source even if it was capable of supplying 100A theoretically it would be safe to connect the LED without a resistor?
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes, it would be safe but pretty useless. Can you see from the graph how much current would flow? I show how to measure it on the video at the bottom of the page. You might also find What is an LED useful.
$endgroup$
– Transistor
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
Yes I think I understand now. I meant more like 1.25V but I typed 1, my bad.
$endgroup$
– php_nub_qq
6 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
$begingroup$
It can work but you can run into problems with variations in the forward voltage, $ V_f $. I've written on this too in Variations in Vf and binning.
$endgroup$
– Transistor
3 hours ago
add a comment |
$begingroup$
Instead of saying the consumer (circuit) draws as much as it needs, it is better to say current will flow as much as is allowed by the circuit.
How much current a circuit will allow is based on its resistance (or impedance). An LED has a voltage drop, but very little resistance. This small resistance means that more current will flow through it than is healthy.
A resistor is an easy and common way to limit this current. There are many many examples on this site alone on how to do that. Search for "LED current limiting".
To get you started, use Ohm's Law to calculate the resistor you want:
Subtract the LED's voltage drop from your source voltage. This is how much voltage you need to drop across your resistor. Now use the amount of current you want to pass through your LED to calculate (using Ohm's Law) the size of resistor that will do this.
answered 7 hours ago
evildemonicevildemonic
3,10911027
$endgroup$
add a comment |
$begingroup$
Instead of saying the consumer (circuit) draws as much as it needs, it is better to say current will flow as much as is allowed by the circuit.
How much current a circuit will allow is based on its resistance (or impedance). An LED has a voltage drop, but very little resistance. This small resistance means that more current will flow through it than is healthy.
A resistor is an easy and common way to limit this current. There are many many examples on this site alone on how to do that. Search for "LED current limiting".
To get you started, use Ohm's Law to calculate the resistor you want:
Subtract the LED's voltage drop from your source voltage. This is how much voltage you need to drop across your resistor. Now use the amount of current you want to pass through your LED to calculate (using Ohm's Law) the size of resistor that will do this.
answered 7 hours ago
evildemonicevildemonic
3,10911027
$endgroup$
add a comment |
$begingroup$
Instead of saying the consumer (circuit) draws as much as it needs, it is better to say current will flow as much as is allowed by the circuit.
How much current a circuit will allow is based on its resistance (or impedance). An LED has a voltage drop, but very little resistance. This small resistance means that more current will flow through it than is healthy.
A resistor is an easy and common way to limit this current. There are many many examples on this site alone on how to do that. Search for "LED current limiting".
To get you started, use Ohm's Law to calculate the resistor you want:
Subtract the LED's voltage drop from your source voltage. This is how much voltage you need to drop across your resistor. Now use the amount of current you want to pass through your LED to calculate (using Ohm's Law) the size of resistor that will do this.
answered 7 hours ago
evildemonicevildemonic
3,10911027
$endgroup$
Instead of saying the consumer (circuit) draws as much as it needs, it is better to say current will flow as much as is allowed by the circuit.
How much current a circuit will allow is based on its resistance (or impedance). An LED has a voltage drop, but very little resistance. This small resistance means that more current will flow through it than is healthy.
A resistor is an easy and common way to limit this current. There are many many examples on this site alone on how to do that. Search for "LED current limiting".
To get you started, use Ohm's Law to calculate the resistor you want:
Subtract the LED's voltage drop from your source voltage. This is how much voltage you need to drop across your resistor. Now use the amount of current you want to pass through your LED to calculate (using Ohm's Law) the size of resistor that will do this.
answered 7 hours ago
evildemonicevildemonic
3,10911027
edited 7 hours ago
answered 7 hours ago
evildemonicevildemonic
3,10911027
answered 7 hours ago
evildemonicevildemonic
3,10911027
answered 7 hours ago
evildemonicevildemonic
3,10911027
3,10911027
add a comment |
add a comment |
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$begingroup$
There are literally hundreds of posts here of how to calculate a series resistor for a LED. Looks these up. IR or not IR does not matter.
$endgroup$
– Eugene Sh.
8 hours ago
1
$begingroup$
@EugeneSh. The point of the question is more about understanding whats going on, than just about calculating a series resistor for a LED. And the question is a good real world example why beginners sometimes get confused.
$endgroup$
– Rev1.0
7 hours ago
$begingroup$
I would rephrase like this: A consumer will draw the amount of current it demands at a particular voltage. Most consumers of power, especially engineered devices with internal power supply circuitry, are designed to be relatively insensitive to small changes in voltage. A "5V" USB device is engineered to draw similar amounts of current at 4.8 or 5.2 volts. Diodes (including) LEDs, are an extreme exception. A diode's current-voltage relation is exponential, so a small change in voltage results in a HUGE change in current. (This kills the LED.)
$endgroup$
– Glenn Willen
6 hours ago
$begingroup$
In principle if you had a perfect LED and a perfect power supply, you could power an LED with just a regulated voltage. We never do this, because (1) LEDs are not perfect (each one is slightly different); (2) power supplies are not perfect (it's hard to regulate to the precision required); (3) all your components change slightly with temperature. So regulating voltage accurately enough to control LED brightness without destroying the LED is impractical, and instead we have to focus on regulating the current. The cheapest way to do this is to add a resistor.
$endgroup$
– Glenn Willen
6 hours ago