Using Thread to map a two variable functionNested Map and ApplyUsing MapIndexed only at certain elements of a listHow to use Map inside MapThread?Function output of two lists are only diagonal elementsUse map on a different levelHow to Map a function with HoldAll attributeHow to map a function on a variable listMapping a simple 2 variable function
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Using Thread to map a two variable function
Nested Map and ApplyUsing MapIndexed only at certain elements of a listHow to use Map inside MapThread?Function output of two lists are only diagonal elementsUse map on a different levelHow to Map a function with HoldAll attributeHow to map a function on a variable listMapping a simple 2 variable function
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$begingroup$
I have the following function:
magicFunction[ lst_, val_ ] := Fold[ ((#2 < val) && #1) &, True, lst ]
It works
In[]=:magicFunction[6,7,9]
Out[]= True
I want to Map the function. To do it I use Thread.
If I use Thread for a noname function with the list I want to map, the following is produced:
In[]:= Thread[f[6,7,2,3,1,2,9, 10,5]]
Out[]= f[6,7,9],f[2,3,10],f[1,2,5]
That is exactly what I want to do.
However, when I use magicFunction that is not what I get. If I use magicFunction I should get the following:
Out[]:= magicFunction[6,7,9],magicFunction[2,3,10],magicFunction[1,2,5]
which then evaluates to:
Out[]:= True, True, True
However what I get is the following:
In[]:= Thread[magicFunction[6,7,2,3,1,2,9, 10,5]]
Out[]:= 1,2<9,10,5&&2,3<9,10,5&&6,7<9,10,5
Does anybody know what I m doing wrong?
Thanks in advance!
map
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
I have the following function:
magicFunction[ lst_, val_ ] := Fold[ ((#2 < val) && #1) &, True, lst ]
It works
In[]=:magicFunction[6,7,9]
Out[]= True
I want to Map the function. To do it I use Thread.
If I use Thread for a noname function with the list I want to map, the following is produced:
In[]:= Thread[f[6,7,2,3,1,2,9, 10,5]]
Out[]= f[6,7,9],f[2,3,10],f[1,2,5]
That is exactly what I want to do.
However, when I use magicFunction that is not what I get. If I use magicFunction I should get the following:
Out[]:= magicFunction[6,7,9],magicFunction[2,3,10],magicFunction[1,2,5]
which then evaluates to:
Out[]:= True, True, True
However what I get is the following:
In[]:= Thread[magicFunction[6,7,2,3,1,2,9, 10,5]]
Out[]:= 1,2<9,10,5&&2,3<9,10,5&&6,7<9,10,5
Does anybody know what I m doing wrong?
Thanks in advance!
map
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have the following function:
magicFunction[ lst_, val_ ] := Fold[ ((#2 < val) && #1) &, True, lst ]
It works
In[]=:magicFunction[6,7,9]
Out[]= True
I want to Map the function. To do it I use Thread.
If I use Thread for a noname function with the list I want to map, the following is produced:
In[]:= Thread[f[6,7,2,3,1,2,9, 10,5]]
Out[]= f[6,7,9],f[2,3,10],f[1,2,5]
That is exactly what I want to do.
However, when I use magicFunction that is not what I get. If I use magicFunction I should get the following:
Out[]:= magicFunction[6,7,9],magicFunction[2,3,10],magicFunction[1,2,5]
which then evaluates to:
Out[]:= True, True, True
However what I get is the following:
In[]:= Thread[magicFunction[6,7,2,3,1,2,9, 10,5]]
Out[]:= 1,2<9,10,5&&2,3<9,10,5&&6,7<9,10,5
Does anybody know what I m doing wrong?
Thanks in advance!
map
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have the following function:
magicFunction[ lst_, val_ ] := Fold[ ((#2 < val) && #1) &, True, lst ]
It works
In[]=:magicFunction[6,7,9]
Out[]= True
I want to Map the function. To do it I use Thread.
If I use Thread for a noname function with the list I want to map, the following is produced:
In[]:= Thread[f[6,7,2,3,1,2,9, 10,5]]
Out[]= f[6,7,9],f[2,3,10],f[1,2,5]
That is exactly what I want to do.
However, when I use magicFunction that is not what I get. If I use magicFunction I should get the following:
Out[]:= magicFunction[6,7,9],magicFunction[2,3,10],magicFunction[1,2,5]
which then evaluates to:
Out[]:= True, True, True
However what I get is the following:
In[]:= Thread[magicFunction[6,7,2,3,1,2,9, 10,5]]
Out[]:= 1,2<9,10,5&&2,3<9,10,5&&6,7<9,10,5
Does anybody know what I m doing wrong?
Thanks in advance!
map
map
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
edited 7 hours ago
Carl Woll
89.6k3 gold badges117 silver badges229 bronze badges
89.6k3 gold badges117 silver badges229 bronze badges
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
asked 8 hours ago
MavatanetMavatanet
511 bronze badge
511 bronze badge
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mavatanet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Your issue is that magicFunction evaluated before Thread could do anything. One idea to avoid this is to use Unevaluated:
Thread[Unevaluated @ magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
Another idea is to add an argument restriction to your magicFunction. Since Less only makes sense for numeric quantities, you can use:
Clear[magicFunction]
magicFunction[lst_, val_?NumericQ] := Fold[((#2<val)&)&,True,lst]
Then:
Thread[magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
$endgroup$
add a comment |
$begingroup$
You can use MapThread:
MapThread[magicFunction, 6, 7, 2, 3, 1, 2, 9, 10, 5]
True, True, True
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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active
oldest
votes
$begingroup$
Your issue is that magicFunction evaluated before Thread could do anything. One idea to avoid this is to use Unevaluated:
Thread[Unevaluated @ magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
Another idea is to add an argument restriction to your magicFunction. Since Less only makes sense for numeric quantities, you can use:
Clear[magicFunction]
magicFunction[lst_, val_?NumericQ] := Fold[((#2<val)&)&,True,lst]
Then:
Thread[magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
$endgroup$
add a comment |
$begingroup$
Your issue is that magicFunction evaluated before Thread could do anything. One idea to avoid this is to use Unevaluated:
Thread[Unevaluated @ magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
Another idea is to add an argument restriction to your magicFunction. Since Less only makes sense for numeric quantities, you can use:
Clear[magicFunction]
magicFunction[lst_, val_?NumericQ] := Fold[((#2<val)&)&,True,lst]
Then:
Thread[magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
$endgroup$
add a comment |
$begingroup$
Your issue is that magicFunction evaluated before Thread could do anything. One idea to avoid this is to use Unevaluated:
Thread[Unevaluated @ magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
Another idea is to add an argument restriction to your magicFunction. Since Less only makes sense for numeric quantities, you can use:
Clear[magicFunction]
magicFunction[lst_, val_?NumericQ] := Fold[((#2<val)&)&,True,lst]
Then:
Thread[magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
$endgroup$
Your issue is that magicFunction evaluated before Thread could do anything. One idea to avoid this is to use Unevaluated:
Thread[Unevaluated @ magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
Another idea is to add an argument restriction to your magicFunction. Since Less only makes sense for numeric quantities, you can use:
Clear[magicFunction]
magicFunction[lst_, val_?NumericQ] := Fold[((#2<val)&)&,True,lst]
Then:
Thread[magicFunction[6,7,2,3,1,2,9,10,5]]
True, True, True
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
answered 7 hours ago
Carl WollCarl Woll
89.6k3 gold badges117 silver badges229 bronze badges
89.6k3 gold badges117 silver badges229 bronze badges
add a comment |
add a comment |
$begingroup$
You can use MapThread:
MapThread[magicFunction, 6, 7, 2, 3, 1, 2, 9, 10, 5]
True, True, True
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
$endgroup$
add a comment |
$begingroup$
You can use MapThread:
MapThread[magicFunction, 6, 7, 2, 3, 1, 2, 9, 10, 5]
True, True, True
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
$endgroup$
add a comment |
$begingroup$
You can use MapThread:
MapThread[magicFunction, 6, 7, 2, 3, 1, 2, 9, 10, 5]
True, True, True
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
$endgroup$
You can use MapThread:
MapThread[magicFunction, 6, 7, 2, 3, 1, 2, 9, 10, 5]
True, True, True
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
edited 7 hours ago
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
answered 8 hours ago
kglrkglr
215k10 gold badges246 silver badges492 bronze badges
215k10 gold badges246 silver badges492 bronze badges
add a comment |
add a comment |
Mavatanet is a new contributor. Be nice, and check out our Code of Conduct.
Mavatanet is a new contributor. Be nice, and check out our Code of Conduct.
Mavatanet is a new contributor. Be nice, and check out our Code of Conduct.
Mavatanet is a new contributor. Be nice, and check out our Code of Conduct.
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