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How big would the ice ball have to be to deliver all the water at once?


No! Not the moon!How long does terraforming take if you have to build the planet from asteroids?Asteroid impact. How big does it have to be to globally affect plate tectonics?How long would a planet take to recover from a large asteroid impact?Asteroid flux or: How to make a planet perfect for miningWhat would the effects be of two tidal locked planets have on each other's geography?What (and how long) would it take for all the water from a Great Flood to go away? How much would such an event shape the geography of the world?Likely warning time for extinction event asteroidWhat would be the most efficient way to destroy a comet?Geological aftereffects of an asteroid impact on a large mountain range?






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4












$begingroup$


One popular theory to explain how Earth got its water is that it was delivered by asteroid/comet/etc. The form this theory usually takes is that many small impacts occured over a long time, each delivering a relatively small amount of water until the planet reached its current water content.



But what if 'all the water' was delivered in a single massive event, a single comet or asteroid, a single impact.



What would this event have "looked" like?



Best answers will include details such as size/speed/etc. of the impactor, angle of impact, effects on the geography caused by the impact (impact crater size, or effects on tectonic motion, etc), whether or not the same impact could account for the formation of the moon, etc.



(optional) Bonus question: Since many of us in this community build worlds on different scales, how would these types of impacts change with the size of the planet? In other words, how different would an impact that covers a smaller planet, like Mercury for example, in about 70% water, or how would it be different for a super-earth with double or triple Earth's mass, to be covered by about 70% water in a single impact?










share|improve this question









$endgroup$













  • $begingroup$
    How do you expect us to come with the angle of impact? That's randomly decided.
    $endgroup$
    – L.Dutch
    7 hours ago










  • $begingroup$
    @L.Dutch you could pick one at random?
    $endgroup$
    – Starfish Prime
    7 hours ago










  • $begingroup$
    @StarfishPrime, I hope we are still doing worldbuilding, not lotteries
    $endgroup$
    – L.Dutch
    7 hours ago






  • 2




    $begingroup$
    @L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
    $endgroup$
    – Dalila
    7 hours ago







  • 2




    $begingroup$
    Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
    $endgroup$
    – Alexander
    7 hours ago

















4












$begingroup$


One popular theory to explain how Earth got its water is that it was delivered by asteroid/comet/etc. The form this theory usually takes is that many small impacts occured over a long time, each delivering a relatively small amount of water until the planet reached its current water content.



But what if 'all the water' was delivered in a single massive event, a single comet or asteroid, a single impact.



What would this event have "looked" like?



Best answers will include details such as size/speed/etc. of the impactor, angle of impact, effects on the geography caused by the impact (impact crater size, or effects on tectonic motion, etc), whether or not the same impact could account for the formation of the moon, etc.



(optional) Bonus question: Since many of us in this community build worlds on different scales, how would these types of impacts change with the size of the planet? In other words, how different would an impact that covers a smaller planet, like Mercury for example, in about 70% water, or how would it be different for a super-earth with double or triple Earth's mass, to be covered by about 70% water in a single impact?










share|improve this question









$endgroup$













  • $begingroup$
    How do you expect us to come with the angle of impact? That's randomly decided.
    $endgroup$
    – L.Dutch
    7 hours ago










  • $begingroup$
    @L.Dutch you could pick one at random?
    $endgroup$
    – Starfish Prime
    7 hours ago










  • $begingroup$
    @StarfishPrime, I hope we are still doing worldbuilding, not lotteries
    $endgroup$
    – L.Dutch
    7 hours ago






  • 2




    $begingroup$
    @L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
    $endgroup$
    – Dalila
    7 hours ago







  • 2




    $begingroup$
    Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
    $endgroup$
    – Alexander
    7 hours ago













4












4








4





$begingroup$


One popular theory to explain how Earth got its water is that it was delivered by asteroid/comet/etc. The form this theory usually takes is that many small impacts occured over a long time, each delivering a relatively small amount of water until the planet reached its current water content.



But what if 'all the water' was delivered in a single massive event, a single comet or asteroid, a single impact.



What would this event have "looked" like?



Best answers will include details such as size/speed/etc. of the impactor, angle of impact, effects on the geography caused by the impact (impact crater size, or effects on tectonic motion, etc), whether or not the same impact could account for the formation of the moon, etc.



(optional) Bonus question: Since many of us in this community build worlds on different scales, how would these types of impacts change with the size of the planet? In other words, how different would an impact that covers a smaller planet, like Mercury for example, in about 70% water, or how would it be different for a super-earth with double or triple Earth's mass, to be covered by about 70% water in a single impact?










share|improve this question









$endgroup$




One popular theory to explain how Earth got its water is that it was delivered by asteroid/comet/etc. The form this theory usually takes is that many small impacts occured over a long time, each delivering a relatively small amount of water until the planet reached its current water content.



But what if 'all the water' was delivered in a single massive event, a single comet or asteroid, a single impact.



What would this event have "looked" like?



Best answers will include details such as size/speed/etc. of the impactor, angle of impact, effects on the geography caused by the impact (impact crater size, or effects on tectonic motion, etc), whether or not the same impact could account for the formation of the moon, etc.



(optional) Bonus question: Since many of us in this community build worlds on different scales, how would these types of impacts change with the size of the planet? In other words, how different would an impact that covers a smaller planet, like Mercury for example, in about 70% water, or how would it be different for a super-earth with double or triple Earth's mass, to be covered by about 70% water in a single impact?







science-based planets environment geography geology






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 8 hours ago









DalilaDalila

1,6084 silver badges27 bronze badges




1,6084 silver badges27 bronze badges














  • $begingroup$
    How do you expect us to come with the angle of impact? That's randomly decided.
    $endgroup$
    – L.Dutch
    7 hours ago










  • $begingroup$
    @L.Dutch you could pick one at random?
    $endgroup$
    – Starfish Prime
    7 hours ago










  • $begingroup$
    @StarfishPrime, I hope we are still doing worldbuilding, not lotteries
    $endgroup$
    – L.Dutch
    7 hours ago






  • 2




    $begingroup$
    @L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
    $endgroup$
    – Dalila
    7 hours ago







  • 2




    $begingroup$
    Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
    $endgroup$
    – Alexander
    7 hours ago
















  • $begingroup$
    How do you expect us to come with the angle of impact? That's randomly decided.
    $endgroup$
    – L.Dutch
    7 hours ago










  • $begingroup$
    @L.Dutch you could pick one at random?
    $endgroup$
    – Starfish Prime
    7 hours ago










  • $begingroup$
    @StarfishPrime, I hope we are still doing worldbuilding, not lotteries
    $endgroup$
    – L.Dutch
    7 hours ago






  • 2




    $begingroup$
    @L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
    $endgroup$
    – Dalila
    7 hours ago







  • 2




    $begingroup$
    Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
    $endgroup$
    – Alexander
    7 hours ago















$begingroup$
How do you expect us to come with the angle of impact? That's randomly decided.
$endgroup$
– L.Dutch
7 hours ago




$begingroup$
How do you expect us to come with the angle of impact? That's randomly decided.
$endgroup$
– L.Dutch
7 hours ago












$begingroup$
@L.Dutch you could pick one at random?
$endgroup$
– Starfish Prime
7 hours ago




$begingroup$
@L.Dutch you could pick one at random?
$endgroup$
– Starfish Prime
7 hours ago












$begingroup$
@StarfishPrime, I hope we are still doing worldbuilding, not lotteries
$endgroup$
– L.Dutch
7 hours ago




$begingroup$
@StarfishPrime, I hope we are still doing worldbuilding, not lotteries
$endgroup$
– L.Dutch
7 hours ago




2




2




$begingroup$
@L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
$endgroup$
– Dalila
7 hours ago





$begingroup$
@L.Dutch For all I know, the angle of impact makes no difference, on the other hand it might be crucially important. I only mention it in case it is significant. If it's not, feel free to explain why it's not in your answer, or leave it out of your answer entirely.
$endgroup$
– Dalila
7 hours ago





2




2




$begingroup$
Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
$endgroup$
– Alexander
7 hours ago




$begingroup$
Note to the answers based on the mass hydrosphere - there is more water in Earth's mantle: Water in Earth's mantle
$endgroup$
– Alexander
7 hours ago










3 Answers
3






active

oldest

votes


















7














$begingroup$

Estimates for the mass of the Chicxulub impactor that offed the dinosaurs range from 1015 and 4.6 $times$ 1017 kilograms.



The hydrosphere's mass is currently estimated to be around 1.4 $times$ 1021 kilograms. That is like 10,000 Chicxulubs in terms of orders of magnitude, if we use the upper bound for Chic's mass. Might be more like 100,000 dino-killing asteroids hitting at once, maybe 1,000,000.



For the record, the mass of the hydrosphere is also just one order of magnitude less than that of the Moon (at about 7 $times$ 1022 kg).



The good news is since you are starting with a completely dry planet there is nothing to kill.



The bad news is that the impact will have so much energy that most of that water will become gaseous. It will also be awkwardly hot. The atmosphere and the water will be so hot that a lot of that water and a lot of any atmosphere you had will escape to space.



In the end the world's mountains will have been smoothed to different degrees due to strong, hot-steam winds happening during the months or years it will take for the planet to cool down. In the end you will have an Earth with shallower oceans and a thinner atmosphere. Maybe some life can develop there.




I just remembered something. The megacomet in question is not as massive as the Moon, but it will be coming much faster than the Moon would if it stopped in its tracks. Which reminds me of this other question:



No! Not the moon!



It's about what would happen if the Moon hits us. Consider the effects described in there but with less severity. For example:




  • The impact is also enough to cause ripples on what is left of the crust, tearing it apart. A significant portion of the surface is destroyed; vast chasms open, ejecting lava(...)


  • Most of the water on the surface of the planet becomes gas. A major portion of it escapes into space along with the gods know how much of the atmosphere.




And so on.






share|improve this answer











$endgroup$














  • $begingroup$
    In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
    $endgroup$
    – Dalila
    7 hours ago











  • $begingroup$
    @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
    $endgroup$
    – Renan
    7 hours ago






  • 1




    $begingroup$
    keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
    $endgroup$
    – John
    4 hours ago


















6














$begingroup$

So, lets say there's about $1.8*10^21$kg of water on the surface of the earth (this excludes hydrates and stuff in the mantle, but the surface stuff seems like the bit most likely to be deposited by impacts after earth's formation).



Given the density of ice, $2750kg/m^3$, that much water would form a solid sphere about 545.5km in radius. That's Quite Big, by the way... the Chixulub impactor that kicked off the Cretaceous-Paleogene extinction event wasn't likely to have been bigger than 81km across. It is at least smaller than the Theia impact believed to have created our moon, which was believed to have been about 6000km across. There are theories suggesting that much of the Earth's water did arrive during the Theia impact. I won't go into the Theia impact here, but instead consider only a single delivery of ice, probably after the moon was formed and the Hadean era ended (otherwise subsequent bombardments might have blown the water away into space).



Lets assume it is hitting crystalline rock, there being no water or sedimentary minerals on a waterless world. You can now throw these handy figures and assumptions into the Earth Impact Effects Program. I picked a conservative impact velocity of 11km/s (it is a bit unlikely for it to be lower than this, and at this speed it is more likely that some of the delivered water will stay) and a 45 degree impact angle (other angles don't make much difference, which isn't entirely surprising). Summary for those of you too lazy to follow the link and fill in the form for yourself:



  • Initial crater 283km deep, 800km across. Given that Earth's crust is no more than 90km deep, that means the mantle is very definitely exposed. The hole will fill in with ejecta, of which there is quite a lot... it'll end up about 3km deep.

  • Final crater diameter: 1920km, once the surrounding land has finished falling into the initial hole. This is bigger than the biggest hypothesised impact structures ever found, MAPCIS.

  • Despite the impact energy being measure in exatonnes, the calculator doesn't suggest that you'll get a really interesting superheated fireball as the impactor vapourises. I'm slightly dubious on this, but as I'm not an expert on banging rocks together and the authors of the application are, I'll defer to them. Certainly, the behaviour of objects undergoing a hypervelocity collision is unintuitive. This increases the chance that some of the water will actually survive the impact and stay put.

  • Debris from the impact (like, lumps of the stuff, not just dust) will fall over 5000km from ground zero.

The sedate impact velocity is required to minimise the chances of massive post-impact heating. Hopefully the impact pressures are low enough (relatively speaking) and the energy release spread out over a long enough period of time that what you get is a huge explosion of rock and steam that boils and buries an area larger than North America, rather than a multi-thousand-degree fireball that propels debris out of earth's orbit and generates large quantities of light gases that can escape the atmosphere. If the latter occurred, you'd need to deliver even more water, and then the impact energies would be even higher and more volatiles would be lost... and so on. You can see why many smaller impacts are preferred.






share|improve this answer











$endgroup$






















    4














    $begingroup$

    If you want to have the total hydrosphere being delivered on a single impact, let's first check the mass




    The total mass of Earth's hydrosphere is about $1.4 cdot 10^18$ tonnes




    That means $1.4 cdot 10^21$ kg.



    As references, Mimas has a mass of $3 cdot 10^19$ kg, while Enceladus has a mass of $1.0 cdot 10^20$ kg.



    That's a major impact. As a consequence of the impact, most of the water would be vaporized, and such a vast amount of vapor in the Earth atmosphere would be bad: it would mean a huge greenhouse effect, probably turning the planet into a twin Venus.



    Just based on the mass it's impossible to estimate the angle of impact, while the impact velocity would be at least in the order of 10 km/s.






    share|improve this answer











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      3 Answers
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      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7














      $begingroup$

      Estimates for the mass of the Chicxulub impactor that offed the dinosaurs range from 1015 and 4.6 $times$ 1017 kilograms.



      The hydrosphere's mass is currently estimated to be around 1.4 $times$ 1021 kilograms. That is like 10,000 Chicxulubs in terms of orders of magnitude, if we use the upper bound for Chic's mass. Might be more like 100,000 dino-killing asteroids hitting at once, maybe 1,000,000.



      For the record, the mass of the hydrosphere is also just one order of magnitude less than that of the Moon (at about 7 $times$ 1022 kg).



      The good news is since you are starting with a completely dry planet there is nothing to kill.



      The bad news is that the impact will have so much energy that most of that water will become gaseous. It will also be awkwardly hot. The atmosphere and the water will be so hot that a lot of that water and a lot of any atmosphere you had will escape to space.



      In the end the world's mountains will have been smoothed to different degrees due to strong, hot-steam winds happening during the months or years it will take for the planet to cool down. In the end you will have an Earth with shallower oceans and a thinner atmosphere. Maybe some life can develop there.




      I just remembered something. The megacomet in question is not as massive as the Moon, but it will be coming much faster than the Moon would if it stopped in its tracks. Which reminds me of this other question:



      No! Not the moon!



      It's about what would happen if the Moon hits us. Consider the effects described in there but with less severity. For example:




      • The impact is also enough to cause ripples on what is left of the crust, tearing it apart. A significant portion of the surface is destroyed; vast chasms open, ejecting lava(...)


      • Most of the water on the surface of the planet becomes gas. A major portion of it escapes into space along with the gods know how much of the atmosphere.




      And so on.






      share|improve this answer











      $endgroup$














      • $begingroup$
        In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
        $endgroup$
        – Dalila
        7 hours ago











      • $begingroup$
        @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
        $endgroup$
        – Renan
        7 hours ago






      • 1




        $begingroup$
        keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
        $endgroup$
        – John
        4 hours ago















      7














      $begingroup$

      Estimates for the mass of the Chicxulub impactor that offed the dinosaurs range from 1015 and 4.6 $times$ 1017 kilograms.



      The hydrosphere's mass is currently estimated to be around 1.4 $times$ 1021 kilograms. That is like 10,000 Chicxulubs in terms of orders of magnitude, if we use the upper bound for Chic's mass. Might be more like 100,000 dino-killing asteroids hitting at once, maybe 1,000,000.



      For the record, the mass of the hydrosphere is also just one order of magnitude less than that of the Moon (at about 7 $times$ 1022 kg).



      The good news is since you are starting with a completely dry planet there is nothing to kill.



      The bad news is that the impact will have so much energy that most of that water will become gaseous. It will also be awkwardly hot. The atmosphere and the water will be so hot that a lot of that water and a lot of any atmosphere you had will escape to space.



      In the end the world's mountains will have been smoothed to different degrees due to strong, hot-steam winds happening during the months or years it will take for the planet to cool down. In the end you will have an Earth with shallower oceans and a thinner atmosphere. Maybe some life can develop there.




      I just remembered something. The megacomet in question is not as massive as the Moon, but it will be coming much faster than the Moon would if it stopped in its tracks. Which reminds me of this other question:



      No! Not the moon!



      It's about what would happen if the Moon hits us. Consider the effects described in there but with less severity. For example:




      • The impact is also enough to cause ripples on what is left of the crust, tearing it apart. A significant portion of the surface is destroyed; vast chasms open, ejecting lava(...)


      • Most of the water on the surface of the planet becomes gas. A major portion of it escapes into space along with the gods know how much of the atmosphere.




      And so on.






      share|improve this answer











      $endgroup$














      • $begingroup$
        In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
        $endgroup$
        – Dalila
        7 hours ago











      • $begingroup$
        @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
        $endgroup$
        – Renan
        7 hours ago






      • 1




        $begingroup$
        keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
        $endgroup$
        – John
        4 hours ago













      7














      7










      7







      $begingroup$

      Estimates for the mass of the Chicxulub impactor that offed the dinosaurs range from 1015 and 4.6 $times$ 1017 kilograms.



      The hydrosphere's mass is currently estimated to be around 1.4 $times$ 1021 kilograms. That is like 10,000 Chicxulubs in terms of orders of magnitude, if we use the upper bound for Chic's mass. Might be more like 100,000 dino-killing asteroids hitting at once, maybe 1,000,000.



      For the record, the mass of the hydrosphere is also just one order of magnitude less than that of the Moon (at about 7 $times$ 1022 kg).



      The good news is since you are starting with a completely dry planet there is nothing to kill.



      The bad news is that the impact will have so much energy that most of that water will become gaseous. It will also be awkwardly hot. The atmosphere and the water will be so hot that a lot of that water and a lot of any atmosphere you had will escape to space.



      In the end the world's mountains will have been smoothed to different degrees due to strong, hot-steam winds happening during the months or years it will take for the planet to cool down. In the end you will have an Earth with shallower oceans and a thinner atmosphere. Maybe some life can develop there.




      I just remembered something. The megacomet in question is not as massive as the Moon, but it will be coming much faster than the Moon would if it stopped in its tracks. Which reminds me of this other question:



      No! Not the moon!



      It's about what would happen if the Moon hits us. Consider the effects described in there but with less severity. For example:




      • The impact is also enough to cause ripples on what is left of the crust, tearing it apart. A significant portion of the surface is destroyed; vast chasms open, ejecting lava(...)


      • Most of the water on the surface of the planet becomes gas. A major portion of it escapes into space along with the gods know how much of the atmosphere.




      And so on.






      share|improve this answer











      $endgroup$



      Estimates for the mass of the Chicxulub impactor that offed the dinosaurs range from 1015 and 4.6 $times$ 1017 kilograms.



      The hydrosphere's mass is currently estimated to be around 1.4 $times$ 1021 kilograms. That is like 10,000 Chicxulubs in terms of orders of magnitude, if we use the upper bound for Chic's mass. Might be more like 100,000 dino-killing asteroids hitting at once, maybe 1,000,000.



      For the record, the mass of the hydrosphere is also just one order of magnitude less than that of the Moon (at about 7 $times$ 1022 kg).



      The good news is since you are starting with a completely dry planet there is nothing to kill.



      The bad news is that the impact will have so much energy that most of that water will become gaseous. It will also be awkwardly hot. The atmosphere and the water will be so hot that a lot of that water and a lot of any atmosphere you had will escape to space.



      In the end the world's mountains will have been smoothed to different degrees due to strong, hot-steam winds happening during the months or years it will take for the planet to cool down. In the end you will have an Earth with shallower oceans and a thinner atmosphere. Maybe some life can develop there.




      I just remembered something. The megacomet in question is not as massive as the Moon, but it will be coming much faster than the Moon would if it stopped in its tracks. Which reminds me of this other question:



      No! Not the moon!



      It's about what would happen if the Moon hits us. Consider the effects described in there but with less severity. For example:




      • The impact is also enough to cause ripples on what is left of the crust, tearing it apart. A significant portion of the surface is destroyed; vast chasms open, ejecting lava(...)


      • Most of the water on the surface of the planet becomes gas. A major portion of it escapes into space along with the gods know how much of the atmosphere.




      And so on.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 7 hours ago

























      answered 7 hours ago









      RenanRenan

      69k21 gold badges156 silver badges333 bronze badges




      69k21 gold badges156 silver badges333 bronze badges














      • $begingroup$
        In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
        $endgroup$
        – Dalila
        7 hours ago











      • $begingroup$
        @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
        $endgroup$
        – Renan
        7 hours ago






      • 1




        $begingroup$
        keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
        $endgroup$
        – John
        4 hours ago
















      • $begingroup$
        In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
        $endgroup$
        – Dalila
        7 hours ago











      • $begingroup$
        @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
        $endgroup$
        – Renan
        7 hours ago






      • 1




        $begingroup$
        keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
        $endgroup$
        – John
        4 hours ago















      $begingroup$
      In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
      $endgroup$
      – Dalila
      7 hours ago





      $begingroup$
      In regards to the water boiling back off in to space, is there any equilibrium point where a larger impactor (so more water to spare) wold leave Earth with the same water content as present after the boil-off is done? Or would the extra energy from the extra mass just boil off even more of it, leaving Earth with even less water, instead of more?
      $endgroup$
      – Dalila
      7 hours ago













      $begingroup$
      @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
      $endgroup$
      – Renan
      7 hours ago




      $begingroup$
      @Dalila I have neither the math nor the physics in me to find that out, but I think if there is an equilibrium point, it's for something less massive than the megacomet I imagined when typing my answer.
      $endgroup$
      – Renan
      7 hours ago




      1




      1




      $begingroup$
      keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
      $endgroup$
      – John
      4 hours ago




      $begingroup$
      keep in mind your mega comet is going to eject a lot of rock too, so you need a more massive earth to start with as well.
      $endgroup$
      – John
      4 hours ago













      6














      $begingroup$

      So, lets say there's about $1.8*10^21$kg of water on the surface of the earth (this excludes hydrates and stuff in the mantle, but the surface stuff seems like the bit most likely to be deposited by impacts after earth's formation).



      Given the density of ice, $2750kg/m^3$, that much water would form a solid sphere about 545.5km in radius. That's Quite Big, by the way... the Chixulub impactor that kicked off the Cretaceous-Paleogene extinction event wasn't likely to have been bigger than 81km across. It is at least smaller than the Theia impact believed to have created our moon, which was believed to have been about 6000km across. There are theories suggesting that much of the Earth's water did arrive during the Theia impact. I won't go into the Theia impact here, but instead consider only a single delivery of ice, probably after the moon was formed and the Hadean era ended (otherwise subsequent bombardments might have blown the water away into space).



      Lets assume it is hitting crystalline rock, there being no water or sedimentary minerals on a waterless world. You can now throw these handy figures and assumptions into the Earth Impact Effects Program. I picked a conservative impact velocity of 11km/s (it is a bit unlikely for it to be lower than this, and at this speed it is more likely that some of the delivered water will stay) and a 45 degree impact angle (other angles don't make much difference, which isn't entirely surprising). Summary for those of you too lazy to follow the link and fill in the form for yourself:



      • Initial crater 283km deep, 800km across. Given that Earth's crust is no more than 90km deep, that means the mantle is very definitely exposed. The hole will fill in with ejecta, of which there is quite a lot... it'll end up about 3km deep.

      • Final crater diameter: 1920km, once the surrounding land has finished falling into the initial hole. This is bigger than the biggest hypothesised impact structures ever found, MAPCIS.

      • Despite the impact energy being measure in exatonnes, the calculator doesn't suggest that you'll get a really interesting superheated fireball as the impactor vapourises. I'm slightly dubious on this, but as I'm not an expert on banging rocks together and the authors of the application are, I'll defer to them. Certainly, the behaviour of objects undergoing a hypervelocity collision is unintuitive. This increases the chance that some of the water will actually survive the impact and stay put.

      • Debris from the impact (like, lumps of the stuff, not just dust) will fall over 5000km from ground zero.

      The sedate impact velocity is required to minimise the chances of massive post-impact heating. Hopefully the impact pressures are low enough (relatively speaking) and the energy release spread out over a long enough period of time that what you get is a huge explosion of rock and steam that boils and buries an area larger than North America, rather than a multi-thousand-degree fireball that propels debris out of earth's orbit and generates large quantities of light gases that can escape the atmosphere. If the latter occurred, you'd need to deliver even more water, and then the impact energies would be even higher and more volatiles would be lost... and so on. You can see why many smaller impacts are preferred.






      share|improve this answer











      $endgroup$



















        6














        $begingroup$

        So, lets say there's about $1.8*10^21$kg of water on the surface of the earth (this excludes hydrates and stuff in the mantle, but the surface stuff seems like the bit most likely to be deposited by impacts after earth's formation).



        Given the density of ice, $2750kg/m^3$, that much water would form a solid sphere about 545.5km in radius. That's Quite Big, by the way... the Chixulub impactor that kicked off the Cretaceous-Paleogene extinction event wasn't likely to have been bigger than 81km across. It is at least smaller than the Theia impact believed to have created our moon, which was believed to have been about 6000km across. There are theories suggesting that much of the Earth's water did arrive during the Theia impact. I won't go into the Theia impact here, but instead consider only a single delivery of ice, probably after the moon was formed and the Hadean era ended (otherwise subsequent bombardments might have blown the water away into space).



        Lets assume it is hitting crystalline rock, there being no water or sedimentary minerals on a waterless world. You can now throw these handy figures and assumptions into the Earth Impact Effects Program. I picked a conservative impact velocity of 11km/s (it is a bit unlikely for it to be lower than this, and at this speed it is more likely that some of the delivered water will stay) and a 45 degree impact angle (other angles don't make much difference, which isn't entirely surprising). Summary for those of you too lazy to follow the link and fill in the form for yourself:



        • Initial crater 283km deep, 800km across. Given that Earth's crust is no more than 90km deep, that means the mantle is very definitely exposed. The hole will fill in with ejecta, of which there is quite a lot... it'll end up about 3km deep.

        • Final crater diameter: 1920km, once the surrounding land has finished falling into the initial hole. This is bigger than the biggest hypothesised impact structures ever found, MAPCIS.

        • Despite the impact energy being measure in exatonnes, the calculator doesn't suggest that you'll get a really interesting superheated fireball as the impactor vapourises. I'm slightly dubious on this, but as I'm not an expert on banging rocks together and the authors of the application are, I'll defer to them. Certainly, the behaviour of objects undergoing a hypervelocity collision is unintuitive. This increases the chance that some of the water will actually survive the impact and stay put.

        • Debris from the impact (like, lumps of the stuff, not just dust) will fall over 5000km from ground zero.

        The sedate impact velocity is required to minimise the chances of massive post-impact heating. Hopefully the impact pressures are low enough (relatively speaking) and the energy release spread out over a long enough period of time that what you get is a huge explosion of rock and steam that boils and buries an area larger than North America, rather than a multi-thousand-degree fireball that propels debris out of earth's orbit and generates large quantities of light gases that can escape the atmosphere. If the latter occurred, you'd need to deliver even more water, and then the impact energies would be even higher and more volatiles would be lost... and so on. You can see why many smaller impacts are preferred.






        share|improve this answer











        $endgroup$

















          6














          6










          6







          $begingroup$

          So, lets say there's about $1.8*10^21$kg of water on the surface of the earth (this excludes hydrates and stuff in the mantle, but the surface stuff seems like the bit most likely to be deposited by impacts after earth's formation).



          Given the density of ice, $2750kg/m^3$, that much water would form a solid sphere about 545.5km in radius. That's Quite Big, by the way... the Chixulub impactor that kicked off the Cretaceous-Paleogene extinction event wasn't likely to have been bigger than 81km across. It is at least smaller than the Theia impact believed to have created our moon, which was believed to have been about 6000km across. There are theories suggesting that much of the Earth's water did arrive during the Theia impact. I won't go into the Theia impact here, but instead consider only a single delivery of ice, probably after the moon was formed and the Hadean era ended (otherwise subsequent bombardments might have blown the water away into space).



          Lets assume it is hitting crystalline rock, there being no water or sedimentary minerals on a waterless world. You can now throw these handy figures and assumptions into the Earth Impact Effects Program. I picked a conservative impact velocity of 11km/s (it is a bit unlikely for it to be lower than this, and at this speed it is more likely that some of the delivered water will stay) and a 45 degree impact angle (other angles don't make much difference, which isn't entirely surprising). Summary for those of you too lazy to follow the link and fill in the form for yourself:



          • Initial crater 283km deep, 800km across. Given that Earth's crust is no more than 90km deep, that means the mantle is very definitely exposed. The hole will fill in with ejecta, of which there is quite a lot... it'll end up about 3km deep.

          • Final crater diameter: 1920km, once the surrounding land has finished falling into the initial hole. This is bigger than the biggest hypothesised impact structures ever found, MAPCIS.

          • Despite the impact energy being measure in exatonnes, the calculator doesn't suggest that you'll get a really interesting superheated fireball as the impactor vapourises. I'm slightly dubious on this, but as I'm not an expert on banging rocks together and the authors of the application are, I'll defer to them. Certainly, the behaviour of objects undergoing a hypervelocity collision is unintuitive. This increases the chance that some of the water will actually survive the impact and stay put.

          • Debris from the impact (like, lumps of the stuff, not just dust) will fall over 5000km from ground zero.

          The sedate impact velocity is required to minimise the chances of massive post-impact heating. Hopefully the impact pressures are low enough (relatively speaking) and the energy release spread out over a long enough period of time that what you get is a huge explosion of rock and steam that boils and buries an area larger than North America, rather than a multi-thousand-degree fireball that propels debris out of earth's orbit and generates large quantities of light gases that can escape the atmosphere. If the latter occurred, you'd need to deliver even more water, and then the impact energies would be even higher and more volatiles would be lost... and so on. You can see why many smaller impacts are preferred.






          share|improve this answer











          $endgroup$



          So, lets say there's about $1.8*10^21$kg of water on the surface of the earth (this excludes hydrates and stuff in the mantle, but the surface stuff seems like the bit most likely to be deposited by impacts after earth's formation).



          Given the density of ice, $2750kg/m^3$, that much water would form a solid sphere about 545.5km in radius. That's Quite Big, by the way... the Chixulub impactor that kicked off the Cretaceous-Paleogene extinction event wasn't likely to have been bigger than 81km across. It is at least smaller than the Theia impact believed to have created our moon, which was believed to have been about 6000km across. There are theories suggesting that much of the Earth's water did arrive during the Theia impact. I won't go into the Theia impact here, but instead consider only a single delivery of ice, probably after the moon was formed and the Hadean era ended (otherwise subsequent bombardments might have blown the water away into space).



          Lets assume it is hitting crystalline rock, there being no water or sedimentary minerals on a waterless world. You can now throw these handy figures and assumptions into the Earth Impact Effects Program. I picked a conservative impact velocity of 11km/s (it is a bit unlikely for it to be lower than this, and at this speed it is more likely that some of the delivered water will stay) and a 45 degree impact angle (other angles don't make much difference, which isn't entirely surprising). Summary for those of you too lazy to follow the link and fill in the form for yourself:



          • Initial crater 283km deep, 800km across. Given that Earth's crust is no more than 90km deep, that means the mantle is very definitely exposed. The hole will fill in with ejecta, of which there is quite a lot... it'll end up about 3km deep.

          • Final crater diameter: 1920km, once the surrounding land has finished falling into the initial hole. This is bigger than the biggest hypothesised impact structures ever found, MAPCIS.

          • Despite the impact energy being measure in exatonnes, the calculator doesn't suggest that you'll get a really interesting superheated fireball as the impactor vapourises. I'm slightly dubious on this, but as I'm not an expert on banging rocks together and the authors of the application are, I'll defer to them. Certainly, the behaviour of objects undergoing a hypervelocity collision is unintuitive. This increases the chance that some of the water will actually survive the impact and stay put.

          • Debris from the impact (like, lumps of the stuff, not just dust) will fall over 5000km from ground zero.

          The sedate impact velocity is required to minimise the chances of massive post-impact heating. Hopefully the impact pressures are low enough (relatively speaking) and the energy release spread out over a long enough period of time that what you get is a huge explosion of rock and steam that boils and buries an area larger than North America, rather than a multi-thousand-degree fireball that propels debris out of earth's orbit and generates large quantities of light gases that can escape the atmosphere. If the latter occurred, you'd need to deliver even more water, and then the impact energies would be even higher and more volatiles would be lost... and so on. You can see why many smaller impacts are preferred.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 4 hours ago

























          answered 7 hours ago









          Starfish PrimeStarfish Prime

          14.9k32 silver badges69 bronze badges




          14.9k32 silver badges69 bronze badges
























              4














              $begingroup$

              If you want to have the total hydrosphere being delivered on a single impact, let's first check the mass




              The total mass of Earth's hydrosphere is about $1.4 cdot 10^18$ tonnes




              That means $1.4 cdot 10^21$ kg.



              As references, Mimas has a mass of $3 cdot 10^19$ kg, while Enceladus has a mass of $1.0 cdot 10^20$ kg.



              That's a major impact. As a consequence of the impact, most of the water would be vaporized, and such a vast amount of vapor in the Earth atmosphere would be bad: it would mean a huge greenhouse effect, probably turning the planet into a twin Venus.



              Just based on the mass it's impossible to estimate the angle of impact, while the impact velocity would be at least in the order of 10 km/s.






              share|improve this answer











              $endgroup$



















                4














                $begingroup$

                If you want to have the total hydrosphere being delivered on a single impact, let's first check the mass




                The total mass of Earth's hydrosphere is about $1.4 cdot 10^18$ tonnes




                That means $1.4 cdot 10^21$ kg.



                As references, Mimas has a mass of $3 cdot 10^19$ kg, while Enceladus has a mass of $1.0 cdot 10^20$ kg.



                That's a major impact. As a consequence of the impact, most of the water would be vaporized, and such a vast amount of vapor in the Earth atmosphere would be bad: it would mean a huge greenhouse effect, probably turning the planet into a twin Venus.



                Just based on the mass it's impossible to estimate the angle of impact, while the impact velocity would be at least in the order of 10 km/s.






                share|improve this answer











                $endgroup$

















                  4














                  4










                  4







                  $begingroup$

                  If you want to have the total hydrosphere being delivered on a single impact, let's first check the mass




                  The total mass of Earth's hydrosphere is about $1.4 cdot 10^18$ tonnes




                  That means $1.4 cdot 10^21$ kg.



                  As references, Mimas has a mass of $3 cdot 10^19$ kg, while Enceladus has a mass of $1.0 cdot 10^20$ kg.



                  That's a major impact. As a consequence of the impact, most of the water would be vaporized, and such a vast amount of vapor in the Earth atmosphere would be bad: it would mean a huge greenhouse effect, probably turning the planet into a twin Venus.



                  Just based on the mass it's impossible to estimate the angle of impact, while the impact velocity would be at least in the order of 10 km/s.






                  share|improve this answer











                  $endgroup$



                  If you want to have the total hydrosphere being delivered on a single impact, let's first check the mass




                  The total mass of Earth's hydrosphere is about $1.4 cdot 10^18$ tonnes




                  That means $1.4 cdot 10^21$ kg.



                  As references, Mimas has a mass of $3 cdot 10^19$ kg, while Enceladus has a mass of $1.0 cdot 10^20$ kg.



                  That's a major impact. As a consequence of the impact, most of the water would be vaporized, and such a vast amount of vapor in the Earth atmosphere would be bad: it would mean a huge greenhouse effect, probably turning the planet into a twin Venus.



                  Just based on the mass it's impossible to estimate the angle of impact, while the impact velocity would be at least in the order of 10 km/s.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 7 hours ago

























                  answered 7 hours ago









                  L.DutchL.Dutch

                  114k35 gold badges263 silver badges545 bronze badges




                  114k35 gold badges263 silver badges545 bronze badges































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