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The differences amongst f[x_], f[x__], and f[x___]
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The differences amongst f[x_], f[x__], and f[x___]
What are the use cases for different scoping constructs?Open and search Documentation-CenterWhat is the difference between Reduce and Solve?Functions that remember their valuesWays to access lists inside listsWhy is the Spherical Bessel Function acting strangely at this point?What is the relationship between Thread and MapThreadBad performance of Integrate (and WolframAlpha) for an Integral of Bessel function of the first kind: Version 11 edit
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$begingroup$
This is probably very elementary but I have not used the following and I cannot find anything online, and I was unable to find something here.
Can someone explain to me the differences amongst
f[x_]:=, f[x__]:=, f[x___]:=
and maybe give some practical examples so I can see the differences?
functions special-functions documentation
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
$endgroup$
add a comment
|
$begingroup$
This is probably very elementary but I have not used the following and I cannot find anything online, and I was unable to find something here.
Can someone explain to me the differences amongst
f[x_]:=, f[x__]:=, f[x___]:=
and maybe give some practical examples so I can see the differences?
functions special-functions documentation
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
$endgroup$
4
$begingroup$
Considerg1[x_]:= x,g2[x__]:= x, andg3[x___]:=xand compareg1[],g1[5]andg1[5,6](similarly forg2andg3).
$endgroup$
– kglr
8 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
3
$begingroup$
Konstantinos, seeBlank (_),BlankSequence (__)andBlankNullSequence (___)in the docs for more details.g1requires a single argument; sog1[]andg1[2,3]both return unevaluated.g2requires 1 or more arguments sog2[]returnsg2[]; and ...
$endgroup$
– kglr
7 hours ago
1
$begingroup$
...g3expects 0 or more arguments sog3[]evaluates to,g3[1,2,3]gives1,2,3andg3[1,2,3](one argument which is the list1,2,3) gives1,2,3etc.
$endgroup$
– kglr
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago
add a comment
|
$begingroup$
This is probably very elementary but I have not used the following and I cannot find anything online, and I was unable to find something here.
Can someone explain to me the differences amongst
f[x_]:=, f[x__]:=, f[x___]:=
and maybe give some practical examples so I can see the differences?
functions special-functions documentation
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
$endgroup$
This is probably very elementary but I have not used the following and I cannot find anything online, and I was unable to find something here.
Can someone explain to me the differences amongst
f[x_]:=, f[x__]:=, f[x___]:=
and maybe give some practical examples so I can see the differences?
functions special-functions documentation
functions special-functions documentation
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
asked 8 hours ago
KonstantinosKonstantinos
8631 gold badge5 silver badges14 bronze badges
8631 gold badge5 silver badges14 bronze badges
4
$begingroup$
Considerg1[x_]:= x,g2[x__]:= x, andg3[x___]:=xand compareg1[],g1[5]andg1[5,6](similarly forg2andg3).
$endgroup$
– kglr
8 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
3
$begingroup$
Konstantinos, seeBlank (_),BlankSequence (__)andBlankNullSequence (___)in the docs for more details.g1requires a single argument; sog1[]andg1[2,3]both return unevaluated.g2requires 1 or more arguments sog2[]returnsg2[]; and ...
$endgroup$
– kglr
7 hours ago
1
$begingroup$
...g3expects 0 or more arguments sog3[]evaluates to,g3[1,2,3]gives1,2,3andg3[1,2,3](one argument which is the list1,2,3) gives1,2,3etc.
$endgroup$
– kglr
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago
add a comment
|
4
$begingroup$
Considerg1[x_]:= x,g2[x__]:= x, andg3[x___]:=xand compareg1[],g1[5]andg1[5,6](similarly forg2andg3).
$endgroup$
– kglr
8 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
3
$begingroup$
Konstantinos, seeBlank (_),BlankSequence (__)andBlankNullSequence (___)in the docs for more details.g1requires a single argument; sog1[]andg1[2,3]both return unevaluated.g2requires 1 or more arguments sog2[]returnsg2[]; and ...
$endgroup$
– kglr
7 hours ago
1
$begingroup$
...g3expects 0 or more arguments sog3[]evaluates to,g3[1,2,3]gives1,2,3andg3[1,2,3](one argument which is the list1,2,3) gives1,2,3etc.
$endgroup$
– kglr
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago
4
4
$begingroup$
Consider
g1[x_]:= x, g2[x__]:= x, and g3[x___]:=x and compare g1[], g1[5] and g1[5,6] (similarly for g2 and g3).$endgroup$
– kglr
8 hours ago
$begingroup$
Consider
g1[x_]:= x, g2[x__]:= x, and g3[x___]:=x and compare g1[], g1[5] and g1[5,6] (similarly for g2 and g3).$endgroup$
– kglr
8 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
3
3
$begingroup$
Konstantinos, see
Blank (_), BlankSequence (__) and BlankNullSequence (___) in the docs for more details. g1 requires a single argument; so g1[] and g1[2,3] both return unevaluated. g2 requires 1 or more arguments so g2[] returns g2[]; and ...$endgroup$
– kglr
7 hours ago
$begingroup$
Konstantinos, see
Blank (_), BlankSequence (__) and BlankNullSequence (___) in the docs for more details. g1 requires a single argument; so g1[] and g1[2,3] both return unevaluated. g2 requires 1 or more arguments so g2[] returns g2[]; and ...$endgroup$
– kglr
7 hours ago
1
1
$begingroup$
...
g3 expects 0 or more arguments so g3[] evaluates to g3[1,2,3] gives 1,2,3and g3[1,2,3] (one argument which is the list 1,2,3) gives 1,2,3 etc.$endgroup$
– kglr
7 hours ago
$begingroup$
...
g3 expects 0 or more arguments so g3[] evaluates to g3[1,2,3] gives 1,2,3and g3[1,2,3] (one argument which is the list 1,2,3) gives 1,2,3 etc.$endgroup$
– kglr
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago
add a comment
|
1 Answer
1
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oldest
votes
$begingroup$
_ matches one thing.
__ matches one or more things.
___ matches zero or more things.
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
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1 Answer
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1 Answer
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active
oldest
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$begingroup$
_ matches one thing.
__ matches one or more things.
___ matches zero or more things.
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
$endgroup$
add a comment
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$begingroup$
_ matches one thing.
__ matches one or more things.
___ matches zero or more things.
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
$endgroup$
add a comment
|
$begingroup$
_ matches one thing.
__ matches one or more things.
___ matches zero or more things.
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
$endgroup$
_ matches one thing.
__ matches one or more things.
___ matches zero or more things.
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
answered 7 hours ago
John DotyJohn Doty
8,9361 gold badge14 silver badges27 bronze badges
8,9361 gold badge14 silver badges27 bronze badges
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4
$begingroup$
Consider
g1[x_]:= x,g2[x__]:= x, andg3[x___]:=xand compareg1[],g1[5]andg1[5,6](similarly forg2andg3).$endgroup$
– kglr
8 hours ago
$begingroup$
Thank you for the comment. Some more questions. When I tried g3[5, 6, 7] it gave me 5,6,7 which is what I expected from the general pattern. However, g2[5, 6, 7] also gives the same result, so I am not sure what's the difference. Also g1[], g2[], just give back the same while g3[] gives back . Could you explain a bit more thoroughly? Am I missing something?
$endgroup$
– Konstantinos
7 hours ago
3
$begingroup$
Konstantinos, see
Blank (_),BlankSequence (__)andBlankNullSequence (___)in the docs for more details.g1requires a single argument; sog1[]andg1[2,3]both return unevaluated.g2requires 1 or more arguments sog2[]returnsg2[]; and ...$endgroup$
– kglr
7 hours ago
1
$begingroup$
...
g3expects 0 or more arguments sog3[]evaluates to,g3[1,2,3]gives1,2,3andg3[1,2,3](one argument which is the list1,2,3) gives1,2,3etc.$endgroup$
– kglr
7 hours ago
$begingroup$
Thanks a lot once more. I did not know how to find these online. I was trying something like f[__] Mathematica and nothing was popping up.
$endgroup$
– Konstantinos
7 hours ago