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Why do balloons get cold when they deflate?


Why does cold metal seem colder than cold air?Why do I feel cold air in the shower?Does a room aerate faster when it's cold outside?Work needed to pump the balloonsWhy does cold air feel even colder when you are moving through it quickly?Letting air out of a balloonThe Official Equation for the relationship between the Volume of a balloon and time






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5












$begingroup$


When I deflate balloons by cutting one end and letting the air out, why does the surface of the balloon feel cooler?



Thanks,










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$endgroup$




















    5












    $begingroup$


    When I deflate balloons by cutting one end and letting the air out, why does the surface of the balloon feel cooler?



    Thanks,










    share|cite|improve this question









    $endgroup$
















      5












      5








      5


      1



      $begingroup$


      When I deflate balloons by cutting one end and letting the air out, why does the surface of the balloon feel cooler?



      Thanks,










      share|cite|improve this question









      $endgroup$




      When I deflate balloons by cutting one end and letting the air out, why does the surface of the balloon feel cooler?



      Thanks,







      thermodynamics






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 8 hours ago









      Shuheng ZhengShuheng Zheng

      2682 silver badges10 bronze badges




      2682 silver badges10 bronze badges























          1 Answer
          1






          active

          oldest

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          5












          $begingroup$

          A piece of rubber can act as a refrigerator of sorts, as follows:



          If you take a piece of rubber and stretch it out, the molecular chains are pulled out in tension and the kinks in them get straightened out. they are now stiffer, and whatever frequency at which they were originally vibrating will go up slightly- and this means the rubber is now warmer by a tiny amount, as if it were a parcel of gas which you have compressed.



          If you maintain the stretch while the heat leaves the rubber, eventually the rubber assumes the temperature of its surroundings- like the parcel of compressed gas would, if stored in a thermally conductive container under pressure.



          Then, if you suddenly release the tension on the rubber band, its molecules relax back to their slack state and their vibrational frequency drops down a tiny bit- which means its temperature drops below ambient- just as if you released the pressure on that parcel of compressed gas and allowed it to expand.



          This effect can be demonstrated with a rubber band, as follows: Hold the band with both hands and press it against your lip to sense its temperature. Now pull the band out tight with your hands and hold it there for 10 seconds. Then quickly bring your hands together so the rubber band goes slack and immediately press it against your lip again. You will detect that it is now cooler.






          share|cite|improve this answer









          $endgroup$














          • $begingroup$
            That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
            $endgroup$
            – Gert
            7 hours ago










          • $begingroup$
            Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
            $endgroup$
            – niels nielsen
            6 hours ago










          • $begingroup$
            Yes, I believe you are correct. Ta
            $endgroup$
            – Gert
            4 hours ago













          Your Answer








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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          5












          $begingroup$

          A piece of rubber can act as a refrigerator of sorts, as follows:



          If you take a piece of rubber and stretch it out, the molecular chains are pulled out in tension and the kinks in them get straightened out. they are now stiffer, and whatever frequency at which they were originally vibrating will go up slightly- and this means the rubber is now warmer by a tiny amount, as if it were a parcel of gas which you have compressed.



          If you maintain the stretch while the heat leaves the rubber, eventually the rubber assumes the temperature of its surroundings- like the parcel of compressed gas would, if stored in a thermally conductive container under pressure.



          Then, if you suddenly release the tension on the rubber band, its molecules relax back to their slack state and their vibrational frequency drops down a tiny bit- which means its temperature drops below ambient- just as if you released the pressure on that parcel of compressed gas and allowed it to expand.



          This effect can be demonstrated with a rubber band, as follows: Hold the band with both hands and press it against your lip to sense its temperature. Now pull the band out tight with your hands and hold it there for 10 seconds. Then quickly bring your hands together so the rubber band goes slack and immediately press it against your lip again. You will detect that it is now cooler.






          share|cite|improve this answer









          $endgroup$














          • $begingroup$
            That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
            $endgroup$
            – Gert
            7 hours ago










          • $begingroup$
            Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
            $endgroup$
            – niels nielsen
            6 hours ago










          • $begingroup$
            Yes, I believe you are correct. Ta
            $endgroup$
            – Gert
            4 hours ago















          5












          $begingroup$

          A piece of rubber can act as a refrigerator of sorts, as follows:



          If you take a piece of rubber and stretch it out, the molecular chains are pulled out in tension and the kinks in them get straightened out. they are now stiffer, and whatever frequency at which they were originally vibrating will go up slightly- and this means the rubber is now warmer by a tiny amount, as if it were a parcel of gas which you have compressed.



          If you maintain the stretch while the heat leaves the rubber, eventually the rubber assumes the temperature of its surroundings- like the parcel of compressed gas would, if stored in a thermally conductive container under pressure.



          Then, if you suddenly release the tension on the rubber band, its molecules relax back to their slack state and their vibrational frequency drops down a tiny bit- which means its temperature drops below ambient- just as if you released the pressure on that parcel of compressed gas and allowed it to expand.



          This effect can be demonstrated with a rubber band, as follows: Hold the band with both hands and press it against your lip to sense its temperature. Now pull the band out tight with your hands and hold it there for 10 seconds. Then quickly bring your hands together so the rubber band goes slack and immediately press it against your lip again. You will detect that it is now cooler.






          share|cite|improve this answer









          $endgroup$














          • $begingroup$
            That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
            $endgroup$
            – Gert
            7 hours ago










          • $begingroup$
            Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
            $endgroup$
            – niels nielsen
            6 hours ago










          • $begingroup$
            Yes, I believe you are correct. Ta
            $endgroup$
            – Gert
            4 hours ago













          5












          5








          5





          $begingroup$

          A piece of rubber can act as a refrigerator of sorts, as follows:



          If you take a piece of rubber and stretch it out, the molecular chains are pulled out in tension and the kinks in them get straightened out. they are now stiffer, and whatever frequency at which they were originally vibrating will go up slightly- and this means the rubber is now warmer by a tiny amount, as if it were a parcel of gas which you have compressed.



          If you maintain the stretch while the heat leaves the rubber, eventually the rubber assumes the temperature of its surroundings- like the parcel of compressed gas would, if stored in a thermally conductive container under pressure.



          Then, if you suddenly release the tension on the rubber band, its molecules relax back to their slack state and their vibrational frequency drops down a tiny bit- which means its temperature drops below ambient- just as if you released the pressure on that parcel of compressed gas and allowed it to expand.



          This effect can be demonstrated with a rubber band, as follows: Hold the band with both hands and press it against your lip to sense its temperature. Now pull the band out tight with your hands and hold it there for 10 seconds. Then quickly bring your hands together so the rubber band goes slack and immediately press it against your lip again. You will detect that it is now cooler.






          share|cite|improve this answer









          $endgroup$



          A piece of rubber can act as a refrigerator of sorts, as follows:



          If you take a piece of rubber and stretch it out, the molecular chains are pulled out in tension and the kinks in them get straightened out. they are now stiffer, and whatever frequency at which they were originally vibrating will go up slightly- and this means the rubber is now warmer by a tiny amount, as if it were a parcel of gas which you have compressed.



          If you maintain the stretch while the heat leaves the rubber, eventually the rubber assumes the temperature of its surroundings- like the parcel of compressed gas would, if stored in a thermally conductive container under pressure.



          Then, if you suddenly release the tension on the rubber band, its molecules relax back to their slack state and their vibrational frequency drops down a tiny bit- which means its temperature drops below ambient- just as if you released the pressure on that parcel of compressed gas and allowed it to expand.



          This effect can be demonstrated with a rubber band, as follows: Hold the band with both hands and press it against your lip to sense its temperature. Now pull the band out tight with your hands and hold it there for 10 seconds. Then quickly bring your hands together so the rubber band goes slack and immediately press it against your lip again. You will detect that it is now cooler.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 8 hours ago









          niels nielsenniels nielsen

          24.8k5 gold badges33 silver badges69 bronze badges




          24.8k5 gold badges33 silver badges69 bronze badges














          • $begingroup$
            That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
            $endgroup$
            – Gert
            7 hours ago










          • $begingroup$
            Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
            $endgroup$
            – niels nielsen
            6 hours ago










          • $begingroup$
            Yes, I believe you are correct. Ta
            $endgroup$
            – Gert
            4 hours ago
















          • $begingroup$
            That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
            $endgroup$
            – Gert
            7 hours ago










          • $begingroup$
            Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
            $endgroup$
            – niels nielsen
            6 hours ago










          • $begingroup$
            Yes, I believe you are correct. Ta
            $endgroup$
            – Gert
            4 hours ago















          $begingroup$
          That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
          $endgroup$
          – Gert
          7 hours ago




          $begingroup$
          That effect is very real and well documented. But how do we know for sure the air inside, which undergoes a quasi-isobaric expansion, does not drop also in temperature a bit?
          $endgroup$
          – Gert
          7 hours ago












          $begingroup$
          Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
          $endgroup$
          – niels nielsen
          6 hours ago




          $begingroup$
          Because its pressure remains almost constant as the balloon contracts. The air expansion occurs not in the body of the balloon itself, but in the neck of the balloon near its outlet.
          $endgroup$
          – niels nielsen
          6 hours ago












          $begingroup$
          Yes, I believe you are correct. Ta
          $endgroup$
          – Gert
          4 hours ago




          $begingroup$
          Yes, I believe you are correct. Ta
          $endgroup$
          – Gert
          4 hours ago

















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