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Best model for precedence constraints within scheduling problem


Symmetry-breaking ILP constraints for square binary matrixDealing with non-overlapping constraintsConditional Controls in MIP ModelsAssignment Problem with Decreasing CostsHow to formulate this scheduling problem efficiently?How to reformulate (linearize/convexify) a budgeted assignment problem?What is this type of scheduling problem called?The rationale to improve MTZ?













8












$begingroup$


Suppose I'm modeling a problem where I want to compute the start time bucket for some jobs. All time buckets have equal duration. There are some additional constraints involved but I also have to model some precedence constraints for certain jobs.

Due to the rest of the model I have to use binary variables $s_jt$ that are 1 if job $jin J$ starts in time bucket $tin T$. Suppose I furthermore have a set $P$ of tuples of jobs $(j_1, j_2)in Psubset Jtimes J$ for which the second has to start after the first is finished. Each job $j$ has duration $d_j$, i.e the number of time buckets that are needed to finish the job.



My question is how to model the precedence constraint using the above variables (plus maybe some additional ones) in the most efficient and/or effective way. Meaning I'm interested in the smallest formulation but also in the formulation that gives the tightest bound, respectively the fastest solving times when solved with a MIP solver.










share|improve this question









$endgroup$


















    8












    $begingroup$


    Suppose I'm modeling a problem where I want to compute the start time bucket for some jobs. All time buckets have equal duration. There are some additional constraints involved but I also have to model some precedence constraints for certain jobs.

    Due to the rest of the model I have to use binary variables $s_jt$ that are 1 if job $jin J$ starts in time bucket $tin T$. Suppose I furthermore have a set $P$ of tuples of jobs $(j_1, j_2)in Psubset Jtimes J$ for which the second has to start after the first is finished. Each job $j$ has duration $d_j$, i.e the number of time buckets that are needed to finish the job.



    My question is how to model the precedence constraint using the above variables (plus maybe some additional ones) in the most efficient and/or effective way. Meaning I'm interested in the smallest formulation but also in the formulation that gives the tightest bound, respectively the fastest solving times when solved with a MIP solver.










    share|improve this question









    $endgroup$
















      8












      8








      8





      $begingroup$


      Suppose I'm modeling a problem where I want to compute the start time bucket for some jobs. All time buckets have equal duration. There are some additional constraints involved but I also have to model some precedence constraints for certain jobs.

      Due to the rest of the model I have to use binary variables $s_jt$ that are 1 if job $jin J$ starts in time bucket $tin T$. Suppose I furthermore have a set $P$ of tuples of jobs $(j_1, j_2)in Psubset Jtimes J$ for which the second has to start after the first is finished. Each job $j$ has duration $d_j$, i.e the number of time buckets that are needed to finish the job.



      My question is how to model the precedence constraint using the above variables (plus maybe some additional ones) in the most efficient and/or effective way. Meaning I'm interested in the smallest formulation but also in the formulation that gives the tightest bound, respectively the fastest solving times when solved with a MIP solver.










      share|improve this question









      $endgroup$




      Suppose I'm modeling a problem where I want to compute the start time bucket for some jobs. All time buckets have equal duration. There are some additional constraints involved but I also have to model some precedence constraints for certain jobs.

      Due to the rest of the model I have to use binary variables $s_jt$ that are 1 if job $jin J$ starts in time bucket $tin T$. Suppose I furthermore have a set $P$ of tuples of jobs $(j_1, j_2)in Psubset Jtimes J$ for which the second has to start after the first is finished. Each job $j$ has duration $d_j$, i.e the number of time buckets that are needed to finish the job.



      My question is how to model the precedence constraint using the above variables (plus maybe some additional ones) in the most efficient and/or effective way. Meaning I'm interested in the smallest formulation but also in the formulation that gives the tightest bound, respectively the fastest solving times when solved with a MIP solver.







      mixed-integer-programming modeling scheduling






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 8 hours ago









      JakobSJakobS

      1,2363 silver badges18 bronze badges




      1,2363 silver badges18 bronze badges























          2 Answers
          2






          active

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          7












          $begingroup$

          Can you change the meaning of your variables? A classic trick when you have a lot of precedences is to use the by formulation.



          Let $s'_jt$ be 1 if job $j$ starts by time $t$ (i.e. at time $t$ or before). In that case, your precedence constraint can be formulated as
          $$s'_j_2,t leq s'_j_1,t-d_1$$



          Notice that you can do a change of variables ($s_j,1=s'_j,1$ and $s_j,t =s'_j,t-s'_j,t-1$) to write the remaining constraints with these new variables. You also need to add constraints $s'_j,tleq s'_j,t+1$.



          This usually provide a very tight bound, specially if the number of precedence constraints is very large and the additional constraints are just a few (see [1]).






          share|improve this answer











          $endgroup$














          • $begingroup$
            Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
            $endgroup$
            – JakobS
            7 hours ago










          • $begingroup$
            Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
            $endgroup$
            – Borelian
            7 hours ago











          • $begingroup$
            Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
            $endgroup$
            – JakobS
            7 hours ago


















          5












          $begingroup$

          A straightforward formulation that suffices is to impose conflict constraints of the form $$s_j_1,t_1+s_j_2,t_2le 1$$ if $t_1+d_1>t_2$, but you can strengthen that to $$sum_tge t_1s_j_1,t+sum_tle t_2s_j_2,tle 1.$$






          share|improve this answer









          $endgroup$

















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            2 Answers
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            active

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            active

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            active

            oldest

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            7












            $begingroup$

            Can you change the meaning of your variables? A classic trick when you have a lot of precedences is to use the by formulation.



            Let $s'_jt$ be 1 if job $j$ starts by time $t$ (i.e. at time $t$ or before). In that case, your precedence constraint can be formulated as
            $$s'_j_2,t leq s'_j_1,t-d_1$$



            Notice that you can do a change of variables ($s_j,1=s'_j,1$ and $s_j,t =s'_j,t-s'_j,t-1$) to write the remaining constraints with these new variables. You also need to add constraints $s'_j,tleq s'_j,t+1$.



            This usually provide a very tight bound, specially if the number of precedence constraints is very large and the additional constraints are just a few (see [1]).






            share|improve this answer











            $endgroup$














            • $begingroup$
              Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
              $endgroup$
              – JakobS
              7 hours ago










            • $begingroup$
              Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
              $endgroup$
              – Borelian
              7 hours ago











            • $begingroup$
              Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
              $endgroup$
              – JakobS
              7 hours ago















            7












            $begingroup$

            Can you change the meaning of your variables? A classic trick when you have a lot of precedences is to use the by formulation.



            Let $s'_jt$ be 1 if job $j$ starts by time $t$ (i.e. at time $t$ or before). In that case, your precedence constraint can be formulated as
            $$s'_j_2,t leq s'_j_1,t-d_1$$



            Notice that you can do a change of variables ($s_j,1=s'_j,1$ and $s_j,t =s'_j,t-s'_j,t-1$) to write the remaining constraints with these new variables. You also need to add constraints $s'_j,tleq s'_j,t+1$.



            This usually provide a very tight bound, specially if the number of precedence constraints is very large and the additional constraints are just a few (see [1]).






            share|improve this answer











            $endgroup$














            • $begingroup$
              Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
              $endgroup$
              – JakobS
              7 hours ago










            • $begingroup$
              Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
              $endgroup$
              – Borelian
              7 hours ago











            • $begingroup$
              Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
              $endgroup$
              – JakobS
              7 hours ago













            7












            7








            7





            $begingroup$

            Can you change the meaning of your variables? A classic trick when you have a lot of precedences is to use the by formulation.



            Let $s'_jt$ be 1 if job $j$ starts by time $t$ (i.e. at time $t$ or before). In that case, your precedence constraint can be formulated as
            $$s'_j_2,t leq s'_j_1,t-d_1$$



            Notice that you can do a change of variables ($s_j,1=s'_j,1$ and $s_j,t =s'_j,t-s'_j,t-1$) to write the remaining constraints with these new variables. You also need to add constraints $s'_j,tleq s'_j,t+1$.



            This usually provide a very tight bound, specially if the number of precedence constraints is very large and the additional constraints are just a few (see [1]).






            share|improve this answer











            $endgroup$



            Can you change the meaning of your variables? A classic trick when you have a lot of precedences is to use the by formulation.



            Let $s'_jt$ be 1 if job $j$ starts by time $t$ (i.e. at time $t$ or before). In that case, your precedence constraint can be formulated as
            $$s'_j_2,t leq s'_j_1,t-d_1$$



            Notice that you can do a change of variables ($s_j,1=s'_j,1$ and $s_j,t =s'_j,t-s'_j,t-1$) to write the remaining constraints with these new variables. You also need to add constraints $s'_j,tleq s'_j,t+1$.



            This usually provide a very tight bound, specially if the number of precedence constraints is very large and the additional constraints are just a few (see [1]).







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 7 hours ago

























            answered 7 hours ago









            BorelianBorelian

            1916 bronze badges




            1916 bronze badges














            • $begingroup$
              Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
              $endgroup$
              – JakobS
              7 hours ago










            • $begingroup$
              Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
              $endgroup$
              – Borelian
              7 hours ago











            • $begingroup$
              Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
              $endgroup$
              – JakobS
              7 hours ago
















            • $begingroup$
              Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
              $endgroup$
              – JakobS
              7 hours ago










            • $begingroup$
              Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
              $endgroup$
              – Borelian
              7 hours ago











            • $begingroup$
              Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
              $endgroup$
              – JakobS
              7 hours ago















            $begingroup$
            Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
            $endgroup$
            – JakobS
            7 hours ago




            $begingroup$
            Hi @Borelian, unfortunately this will not work due to the other constraints that I have. But nice to know nonetheless... Might be helpful for other similar problems.
            $endgroup$
            – JakobS
            7 hours ago












            $begingroup$
            Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
            $endgroup$
            – Borelian
            7 hours ago





            $begingroup$
            Yes @jakobs, but note that you can do a change of variables $s_j,t =s'_j,t-s'_j,t-1$ and use the same original constraints but with more terms..
            $endgroup$
            – Borelian
            7 hours ago













            $begingroup$
            Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
            $endgroup$
            – JakobS
            7 hours ago




            $begingroup$
            Ah nice! Did not see that. Can you add this to your answer? It would make it more self-contained...
            $endgroup$
            – JakobS
            7 hours ago











            5












            $begingroup$

            A straightforward formulation that suffices is to impose conflict constraints of the form $$s_j_1,t_1+s_j_2,t_2le 1$$ if $t_1+d_1>t_2$, but you can strengthen that to $$sum_tge t_1s_j_1,t+sum_tle t_2s_j_2,tle 1.$$






            share|improve this answer









            $endgroup$



















              5












              $begingroup$

              A straightforward formulation that suffices is to impose conflict constraints of the form $$s_j_1,t_1+s_j_2,t_2le 1$$ if $t_1+d_1>t_2$, but you can strengthen that to $$sum_tge t_1s_j_1,t+sum_tle t_2s_j_2,tle 1.$$






              share|improve this answer









              $endgroup$

















                5












                5








                5





                $begingroup$

                A straightforward formulation that suffices is to impose conflict constraints of the form $$s_j_1,t_1+s_j_2,t_2le 1$$ if $t_1+d_1>t_2$, but you can strengthen that to $$sum_tge t_1s_j_1,t+sum_tle t_2s_j_2,tle 1.$$






                share|improve this answer









                $endgroup$



                A straightforward formulation that suffices is to impose conflict constraints of the form $$s_j_1,t_1+s_j_2,t_2le 1$$ if $t_1+d_1>t_2$, but you can strengthen that to $$sum_tge t_1s_j_1,t+sum_tle t_2s_j_2,tle 1.$$







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 8 hours ago









                Rob PrattRob Pratt

                1,0221 silver badge10 bronze badges




                1,0221 silver badge10 bronze badges






























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