Where or how can I find what interfaces an out of the box Apex class implements?Test Queueable Apex: Methods defined as TestMethod do not support Web service callouts, test skippedHitting system limits with my testClassThe Apex class 'ParkLocator' does not appear to be calling the SOAP endpointREST integration and testTest class is creating ApexAsyncJob recordsattempt to de-reference null object in test classTesting future callout methodHow to deserialize into interface type when concrete type is unknownUsing ApexMocks for a class that implements Queueable InterfaceHow to test Database.Error piece code in the Scheduled job (Apex class implements Schedulable)
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Where or how can I find what interfaces an out of the box Apex class implements?
Test Queueable Apex: Methods defined as TestMethod do not support Web service callouts, test skippedHitting system limits with my testClassThe Apex class 'ParkLocator' does not appear to be calling the SOAP endpointREST integration and testTest class is creating ApexAsyncJob recordsattempt to de-reference null object in test classTesting future callout methodHow to deserialize into interface type when concrete type is unknownUsing ApexMocks for a class that implements Queueable InterfaceHow to test Database.Error piece code in the Scheduled job (Apex class implements Schedulable)
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Is there a method of discovering (or a place to look up) all of the interfaces that an out of the box Salesforce class (Like LoginHistory) implements?
The reason I ask:
I'm attempting to test a method which interacts with a LoginHistory object that's passed in as a parameter. The method accesses the UserId and LoginTime fields on the object. Salesforce won't allow me to new up this object and assign values to these properties for my test. If the object's class implements an interface, I think I could create a mock object from it use it instead for this testing.
Is there a better solution to my problem?
apex unit-test class interface apexmock
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
add a comment |
Is there a method of discovering (or a place to look up) all of the interfaces that an out of the box Salesforce class (Like LoginHistory) implements?
The reason I ask:
I'm attempting to test a method which interacts with a LoginHistory object that's passed in as a parameter. The method accesses the UserId and LoginTime fields on the object. Salesforce won't allow me to new up this object and assign values to these properties for my test. If the object's class implements an interface, I think I could create a mock object from it use it instead for this testing.
Is there a better solution to my problem?
apex unit-test class interface apexmock
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
add a comment |
Is there a method of discovering (or a place to look up) all of the interfaces that an out of the box Salesforce class (Like LoginHistory) implements?
The reason I ask:
I'm attempting to test a method which interacts with a LoginHistory object that's passed in as a parameter. The method accesses the UserId and LoginTime fields on the object. Salesforce won't allow me to new up this object and assign values to these properties for my test. If the object's class implements an interface, I think I could create a mock object from it use it instead for this testing.
Is there a better solution to my problem?
apex unit-test class interface apexmock
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
Is there a method of discovering (or a place to look up) all of the interfaces that an out of the box Salesforce class (Like LoginHistory) implements?
The reason I ask:
I'm attempting to test a method which interacts with a LoginHistory object that's passed in as a parameter. The method accesses the UserId and LoginTime fields on the object. Salesforce won't allow me to new up this object and assign values to these properties for my test. If the object's class implements an interface, I think I could create a mock object from it use it instead for this testing.
Is there a better solution to my problem?
apex unit-test class interface apexmock
apex unit-test class interface apexmock
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
asked 10 hours ago
SF1DevSF1Dev
4535 silver badges19 bronze badges
4535 silver badges19 bronze badges
add a comment |
add a comment |
1 Answer
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sObject classes don't implement interfaces at all. Unfortunately, that won't be a viable solution here.
One very common solution to this issue (needing to create an object and populate non-writeable fields) is JSON deserialization. It's viable here; an example:
LoginHistory l;
l = (LoginHistory)JSON.deserialize(
'"UserId": "'+UserInfo.getUserId()+'", "LoginTime": ' + JSON.serialize(DateTime.now()) + '',
LoginHistory.class
);
System.debug(l);
This works for a wide variety of objects you cannot otherwise construct or populate, although it might require some experimentation to get it just right. The pattern is the same: you construct some JSON string representing the object's properties and deserialize it, giving the class of the desired object.
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
add a comment |
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1 Answer
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1 Answer
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votes
sObject classes don't implement interfaces at all. Unfortunately, that won't be a viable solution here.
One very common solution to this issue (needing to create an object and populate non-writeable fields) is JSON deserialization. It's viable here; an example:
LoginHistory l;
l = (LoginHistory)JSON.deserialize(
'"UserId": "'+UserInfo.getUserId()+'", "LoginTime": ' + JSON.serialize(DateTime.now()) + '',
LoginHistory.class
);
System.debug(l);
This works for a wide variety of objects you cannot otherwise construct or populate, although it might require some experimentation to get it just right. The pattern is the same: you construct some JSON string representing the object's properties and deserialize it, giving the class of the desired object.
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
add a comment |
sObject classes don't implement interfaces at all. Unfortunately, that won't be a viable solution here.
One very common solution to this issue (needing to create an object and populate non-writeable fields) is JSON deserialization. It's viable here; an example:
LoginHistory l;
l = (LoginHistory)JSON.deserialize(
'"UserId": "'+UserInfo.getUserId()+'", "LoginTime": ' + JSON.serialize(DateTime.now()) + '',
LoginHistory.class
);
System.debug(l);
This works for a wide variety of objects you cannot otherwise construct or populate, although it might require some experimentation to get it just right. The pattern is the same: you construct some JSON string representing the object's properties and deserialize it, giving the class of the desired object.
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
add a comment |
sObject classes don't implement interfaces at all. Unfortunately, that won't be a viable solution here.
One very common solution to this issue (needing to create an object and populate non-writeable fields) is JSON deserialization. It's viable here; an example:
LoginHistory l;
l = (LoginHistory)JSON.deserialize(
'"UserId": "'+UserInfo.getUserId()+'", "LoginTime": ' + JSON.serialize(DateTime.now()) + '',
LoginHistory.class
);
System.debug(l);
This works for a wide variety of objects you cannot otherwise construct or populate, although it might require some experimentation to get it just right. The pattern is the same: you construct some JSON string representing the object's properties and deserialize it, giving the class of the desired object.
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
sObject classes don't implement interfaces at all. Unfortunately, that won't be a viable solution here.
One very common solution to this issue (needing to create an object and populate non-writeable fields) is JSON deserialization. It's viable here; an example:
LoginHistory l;
l = (LoginHistory)JSON.deserialize(
'"UserId": "'+UserInfo.getUserId()+'", "LoginTime": ' + JSON.serialize(DateTime.now()) + '',
LoginHistory.class
);
System.debug(l);
This works for a wide variety of objects you cannot otherwise construct or populate, although it might require some experimentation to get it just right. The pattern is the same: you construct some JSON string representing the object's properties and deserialize it, giving the class of the desired object.
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
answered 9 hours ago
David Reed♦David Reed
47.2k8 gold badges27 silver badges65 bronze badges
47.2k8 gold badges27 silver badges65 bronze badges
add a comment |
add a comment |
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