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If a specific mass of air is polluted, will the pollution stick with it?


Are there any high-resolution urban CO2 concentration data sets?How do tree roots mitigate pollution in general? Diagram preferredHow do current pollution levels in Los Angeles compare to the 1970s?How can I test the Air Quality?Why is the Earth's shadow blue?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


Let us say a car pollutes 1m3 of air. Is that pollution attached to that specific air mass or will it fall to the ground or take its own path through the air, independent of the air it first polluted?



And how far can it travel, typically?










share|improve this question









New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$







  • 2




    $begingroup$
    Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
    $endgroup$
    – Erik
    9 hours ago










  • $begingroup$
    There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
    $endgroup$
    – Friddy
    8 hours ago










  • $begingroup$
    @Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
    $endgroup$
    – Spencer
    7 hours ago

















3












$begingroup$


Let us say a car pollutes 1m3 of air. Is that pollution attached to that specific air mass or will it fall to the ground or take its own path through the air, independent of the air it first polluted?



And how far can it travel, typically?










share|improve this question









New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$







  • 2




    $begingroup$
    Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
    $endgroup$
    – Erik
    9 hours ago










  • $begingroup$
    There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
    $endgroup$
    – Friddy
    8 hours ago










  • $begingroup$
    @Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
    $endgroup$
    – Spencer
    7 hours ago













3












3








3





$begingroup$


Let us say a car pollutes 1m3 of air. Is that pollution attached to that specific air mass or will it fall to the ground or take its own path through the air, independent of the air it first polluted?



And how far can it travel, typically?










share|improve this question









New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




Let us say a car pollutes 1m3 of air. Is that pollution attached to that specific air mass or will it fall to the ground or take its own path through the air, independent of the air it first polluted?



And how far can it travel, typically?







pollution air






share|improve this question









New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 7 hours ago









Ash

2,2482 silver badges18 bronze badges




2,2482 silver badges18 bronze badges






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asked 9 hours ago









Dagfinn A. MorkDagfinn A. Mork

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161 bronze badge




New contributor



Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Dagfinn A. Mork is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









  • 2




    $begingroup$
    Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
    $endgroup$
    – Erik
    9 hours ago










  • $begingroup$
    There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
    $endgroup$
    – Friddy
    8 hours ago










  • $begingroup$
    @Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
    $endgroup$
    – Spencer
    7 hours ago












  • 2




    $begingroup$
    Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
    $endgroup$
    – Erik
    9 hours ago










  • $begingroup$
    There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
    $endgroup$
    – Friddy
    8 hours ago










  • $begingroup$
    @Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
    $endgroup$
    – Spencer
    7 hours ago







2




2




$begingroup$
Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
$endgroup$
– Erik
9 hours ago




$begingroup$
Pour yourself a cup o' tea, and add some drops of milk. What happens to the milk? Why would air and gaseous pollutants behave differently?
$endgroup$
– Erik
9 hours ago












$begingroup$
There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
$endgroup$
– Friddy
8 hours ago




$begingroup$
There will be dispersion reducing the concentration of all the pollutants. The particulates will drop out depending on their size and type. Some will be scrubbed out of the air by rain, and some will react with components of the atmosphere. Overall you will see the pollutants follow along with the airmass, but as you move away from the source of the pollution the concentration will diminish. A atmospheric scientist should be able to give you a better answer.
$endgroup$
– Friddy
8 hours ago












$begingroup$
@Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
$endgroup$
– Spencer
7 hours ago




$begingroup$
@Erik en.m.wikipedia.org/wiki/Inversion_(meteorology)
$endgroup$
– Spencer
7 hours ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

Air is a fluid, as such it tends to mix and concentrations, of anything, tend to disperse into the wider volume. Erik's cup of tea metaphor is pretty accurate, currents of air will pull apart your exemplar 1m3 and disperse the pollutants therein, the heavier particulate, which is mainly soot, water droplets from combustion, and unburned fuel, will full to the ground fairly quickly. Finer particulate and reactive gases like nitrogen and sulfur oxides will react with water to form acids and fall back to earth with the next rain storm. The exception to this general rule of mixing occurs when there is an inversion layer that puts a "lid" on vertical circulation in a particular area causing a build up of pollutants which often results in smog formation.






share|improve this answer









$endgroup$




















    3












    $begingroup$

    Like many of my answers on this Stack Exchange, the answer is yes and no. Part of it depends on the pollutant itself. Let's call the mass by it's technical term, a parcel. There are a couple things that can change the pollution level of the parcel, other than the source (a car in your example):



    • Chemical reactions between the pollutant, the parcel, light, and water vapor.

    • Diffusion (the parcel gets all stretched and mixes with surrounding parcels as well as the molecules slowly migrating)

    • Deposition (if the pollutant is an aerosol, it could be falling from gravity or be taken up by rain. If it is a gas, it could be reacting with aerosols or the surface of the earth).

    Let's put this into math!
    $$fracDchiDt=S+R_prod-R_sink-D-F$$
    where $chi$ is the concentration of the pollutant, $S$ is the source, $R_prod$ is the chemical reactions that produce the pollutant, $R_sink$ is the chemical reactions that destroy the pollutant, $D$ is deposition, and $F$ is diffusion.



    How far does this polluted mass travel? Well, that is complicated, as the parcel is immediately stretched and contorted. But an actual answer can be computed. Provided that there is no additional source, the pollutant should be reduced drastically by the equation $$tau=fracchiR_sink+D+F$$, where $tau$ stands for lifetime. How far will it travel? Well, let's say the wind speed is $v$, which has dimensions of length per time. $tau$ is a time scale. So we can say that the pollutant will be drastically reduced by $vtimestau$ distance downwind.



    Carbon monoxide is a toxic gas that has a lifetime of 1-2 months. So given a wind speed of about 5 m s$^-1$, it may travel 26,297 kilometers. Carbon dioxide, which is also a pollutant from cars, has a lifetime of 35-95 years, so it can travel 14989539 kilometers. Given that the diameter of the earth is 8000 kilometers, you can see why the pollution just spreads over the face of the earth.



    Nitrogen monoxide is also a pollutant emitted by cars. However, it is rapidly oxidized and has a lifetime of a few seconds. So it may only travel a few meters.






    share|improve this answer









    $endgroup$















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4












      $begingroup$

      Air is a fluid, as such it tends to mix and concentrations, of anything, tend to disperse into the wider volume. Erik's cup of tea metaphor is pretty accurate, currents of air will pull apart your exemplar 1m3 and disperse the pollutants therein, the heavier particulate, which is mainly soot, water droplets from combustion, and unburned fuel, will full to the ground fairly quickly. Finer particulate and reactive gases like nitrogen and sulfur oxides will react with water to form acids and fall back to earth with the next rain storm. The exception to this general rule of mixing occurs when there is an inversion layer that puts a "lid" on vertical circulation in a particular area causing a build up of pollutants which often results in smog formation.






      share|improve this answer









      $endgroup$

















        4












        $begingroup$

        Air is a fluid, as such it tends to mix and concentrations, of anything, tend to disperse into the wider volume. Erik's cup of tea metaphor is pretty accurate, currents of air will pull apart your exemplar 1m3 and disperse the pollutants therein, the heavier particulate, which is mainly soot, water droplets from combustion, and unburned fuel, will full to the ground fairly quickly. Finer particulate and reactive gases like nitrogen and sulfur oxides will react with water to form acids and fall back to earth with the next rain storm. The exception to this general rule of mixing occurs when there is an inversion layer that puts a "lid" on vertical circulation in a particular area causing a build up of pollutants which often results in smog formation.






        share|improve this answer









        $endgroup$















          4












          4








          4





          $begingroup$

          Air is a fluid, as such it tends to mix and concentrations, of anything, tend to disperse into the wider volume. Erik's cup of tea metaphor is pretty accurate, currents of air will pull apart your exemplar 1m3 and disperse the pollutants therein, the heavier particulate, which is mainly soot, water droplets from combustion, and unburned fuel, will full to the ground fairly quickly. Finer particulate and reactive gases like nitrogen and sulfur oxides will react with water to form acids and fall back to earth with the next rain storm. The exception to this general rule of mixing occurs when there is an inversion layer that puts a "lid" on vertical circulation in a particular area causing a build up of pollutants which often results in smog formation.






          share|improve this answer









          $endgroup$



          Air is a fluid, as such it tends to mix and concentrations, of anything, tend to disperse into the wider volume. Erik's cup of tea metaphor is pretty accurate, currents of air will pull apart your exemplar 1m3 and disperse the pollutants therein, the heavier particulate, which is mainly soot, water droplets from combustion, and unburned fuel, will full to the ground fairly quickly. Finer particulate and reactive gases like nitrogen and sulfur oxides will react with water to form acids and fall back to earth with the next rain storm. The exception to this general rule of mixing occurs when there is an inversion layer that puts a "lid" on vertical circulation in a particular area causing a build up of pollutants which often results in smog formation.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 6 hours ago









          AshAsh

          2,2482 silver badges18 bronze badges




          2,2482 silver badges18 bronze badges























              3












              $begingroup$

              Like many of my answers on this Stack Exchange, the answer is yes and no. Part of it depends on the pollutant itself. Let's call the mass by it's technical term, a parcel. There are a couple things that can change the pollution level of the parcel, other than the source (a car in your example):



              • Chemical reactions between the pollutant, the parcel, light, and water vapor.

              • Diffusion (the parcel gets all stretched and mixes with surrounding parcels as well as the molecules slowly migrating)

              • Deposition (if the pollutant is an aerosol, it could be falling from gravity or be taken up by rain. If it is a gas, it could be reacting with aerosols or the surface of the earth).

              Let's put this into math!
              $$fracDchiDt=S+R_prod-R_sink-D-F$$
              where $chi$ is the concentration of the pollutant, $S$ is the source, $R_prod$ is the chemical reactions that produce the pollutant, $R_sink$ is the chemical reactions that destroy the pollutant, $D$ is deposition, and $F$ is diffusion.



              How far does this polluted mass travel? Well, that is complicated, as the parcel is immediately stretched and contorted. But an actual answer can be computed. Provided that there is no additional source, the pollutant should be reduced drastically by the equation $$tau=fracchiR_sink+D+F$$, where $tau$ stands for lifetime. How far will it travel? Well, let's say the wind speed is $v$, which has dimensions of length per time. $tau$ is a time scale. So we can say that the pollutant will be drastically reduced by $vtimestau$ distance downwind.



              Carbon monoxide is a toxic gas that has a lifetime of 1-2 months. So given a wind speed of about 5 m s$^-1$, it may travel 26,297 kilometers. Carbon dioxide, which is also a pollutant from cars, has a lifetime of 35-95 years, so it can travel 14989539 kilometers. Given that the diameter of the earth is 8000 kilometers, you can see why the pollution just spreads over the face of the earth.



              Nitrogen monoxide is also a pollutant emitted by cars. However, it is rapidly oxidized and has a lifetime of a few seconds. So it may only travel a few meters.






              share|improve this answer









              $endgroup$

















                3












                $begingroup$

                Like many of my answers on this Stack Exchange, the answer is yes and no. Part of it depends on the pollutant itself. Let's call the mass by it's technical term, a parcel. There are a couple things that can change the pollution level of the parcel, other than the source (a car in your example):



                • Chemical reactions between the pollutant, the parcel, light, and water vapor.

                • Diffusion (the parcel gets all stretched and mixes with surrounding parcels as well as the molecules slowly migrating)

                • Deposition (if the pollutant is an aerosol, it could be falling from gravity or be taken up by rain. If it is a gas, it could be reacting with aerosols or the surface of the earth).

                Let's put this into math!
                $$fracDchiDt=S+R_prod-R_sink-D-F$$
                where $chi$ is the concentration of the pollutant, $S$ is the source, $R_prod$ is the chemical reactions that produce the pollutant, $R_sink$ is the chemical reactions that destroy the pollutant, $D$ is deposition, and $F$ is diffusion.



                How far does this polluted mass travel? Well, that is complicated, as the parcel is immediately stretched and contorted. But an actual answer can be computed. Provided that there is no additional source, the pollutant should be reduced drastically by the equation $$tau=fracchiR_sink+D+F$$, where $tau$ stands for lifetime. How far will it travel? Well, let's say the wind speed is $v$, which has dimensions of length per time. $tau$ is a time scale. So we can say that the pollutant will be drastically reduced by $vtimestau$ distance downwind.



                Carbon monoxide is a toxic gas that has a lifetime of 1-2 months. So given a wind speed of about 5 m s$^-1$, it may travel 26,297 kilometers. Carbon dioxide, which is also a pollutant from cars, has a lifetime of 35-95 years, so it can travel 14989539 kilometers. Given that the diameter of the earth is 8000 kilometers, you can see why the pollution just spreads over the face of the earth.



                Nitrogen monoxide is also a pollutant emitted by cars. However, it is rapidly oxidized and has a lifetime of a few seconds. So it may only travel a few meters.






                share|improve this answer









                $endgroup$















                  3












                  3








                  3





                  $begingroup$

                  Like many of my answers on this Stack Exchange, the answer is yes and no. Part of it depends on the pollutant itself. Let's call the mass by it's technical term, a parcel. There are a couple things that can change the pollution level of the parcel, other than the source (a car in your example):



                  • Chemical reactions between the pollutant, the parcel, light, and water vapor.

                  • Diffusion (the parcel gets all stretched and mixes with surrounding parcels as well as the molecules slowly migrating)

                  • Deposition (if the pollutant is an aerosol, it could be falling from gravity or be taken up by rain. If it is a gas, it could be reacting with aerosols or the surface of the earth).

                  Let's put this into math!
                  $$fracDchiDt=S+R_prod-R_sink-D-F$$
                  where $chi$ is the concentration of the pollutant, $S$ is the source, $R_prod$ is the chemical reactions that produce the pollutant, $R_sink$ is the chemical reactions that destroy the pollutant, $D$ is deposition, and $F$ is diffusion.



                  How far does this polluted mass travel? Well, that is complicated, as the parcel is immediately stretched and contorted. But an actual answer can be computed. Provided that there is no additional source, the pollutant should be reduced drastically by the equation $$tau=fracchiR_sink+D+F$$, where $tau$ stands for lifetime. How far will it travel? Well, let's say the wind speed is $v$, which has dimensions of length per time. $tau$ is a time scale. So we can say that the pollutant will be drastically reduced by $vtimestau$ distance downwind.



                  Carbon monoxide is a toxic gas that has a lifetime of 1-2 months. So given a wind speed of about 5 m s$^-1$, it may travel 26,297 kilometers. Carbon dioxide, which is also a pollutant from cars, has a lifetime of 35-95 years, so it can travel 14989539 kilometers. Given that the diameter of the earth is 8000 kilometers, you can see why the pollution just spreads over the face of the earth.



                  Nitrogen monoxide is also a pollutant emitted by cars. However, it is rapidly oxidized and has a lifetime of a few seconds. So it may only travel a few meters.






                  share|improve this answer









                  $endgroup$



                  Like many of my answers on this Stack Exchange, the answer is yes and no. Part of it depends on the pollutant itself. Let's call the mass by it's technical term, a parcel. There are a couple things that can change the pollution level of the parcel, other than the source (a car in your example):



                  • Chemical reactions between the pollutant, the parcel, light, and water vapor.

                  • Diffusion (the parcel gets all stretched and mixes with surrounding parcels as well as the molecules slowly migrating)

                  • Deposition (if the pollutant is an aerosol, it could be falling from gravity or be taken up by rain. If it is a gas, it could be reacting with aerosols or the surface of the earth).

                  Let's put this into math!
                  $$fracDchiDt=S+R_prod-R_sink-D-F$$
                  where $chi$ is the concentration of the pollutant, $S$ is the source, $R_prod$ is the chemical reactions that produce the pollutant, $R_sink$ is the chemical reactions that destroy the pollutant, $D$ is deposition, and $F$ is diffusion.



                  How far does this polluted mass travel? Well, that is complicated, as the parcel is immediately stretched and contorted. But an actual answer can be computed. Provided that there is no additional source, the pollutant should be reduced drastically by the equation $$tau=fracchiR_sink+D+F$$, where $tau$ stands for lifetime. How far will it travel? Well, let's say the wind speed is $v$, which has dimensions of length per time. $tau$ is a time scale. So we can say that the pollutant will be drastically reduced by $vtimestau$ distance downwind.



                  Carbon monoxide is a toxic gas that has a lifetime of 1-2 months. So given a wind speed of about 5 m s$^-1$, it may travel 26,297 kilometers. Carbon dioxide, which is also a pollutant from cars, has a lifetime of 35-95 years, so it can travel 14989539 kilometers. Given that the diameter of the earth is 8000 kilometers, you can see why the pollution just spreads over the face of the earth.



                  Nitrogen monoxide is also a pollutant emitted by cars. However, it is rapidly oxidized and has a lifetime of a few seconds. So it may only travel a few meters.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 6 hours ago









                  BarocliniCplusplusBarocliniCplusplus

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