Mechanism of Acid HydrolysisAcid-catalyzed hydrolysis of diphenyl malonateAcid catalyzed hydrolysis of esterAlkaline Ester Hydrolysis Reactionselective hydrolysis problemHydrolysis of an esterWeak acid and weak base salt hydrolysisWhich mechanism is not seen during hydrolysis of esters?Acid hydrolysis of ethyl acetateAcid hydrolysis of ethyl acetate usesHydrolysis under basic medium

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Extracting data from Plot



Mechanism of Acid Hydrolysis


Acid-catalyzed hydrolysis of diphenyl malonateAcid catalyzed hydrolysis of esterAlkaline Ester Hydrolysis Reactionselective hydrolysis problemHydrolysis of an esterWeak acid and weak base salt hydrolysisWhich mechanism is not seen during hydrolysis of esters?Acid hydrolysis of ethyl acetateAcid hydrolysis of ethyl acetate usesHydrolysis under basic medium













2












$begingroup$


I wanted to ask a question about acid catalysed hydrolysis.



I learnt in an introductory course to Physical Organic Chemistry that there are different ways that an ester can be hydrolysed acidically:




$ceA_AC1$
$ceA_AC2$
$ceA_AL1$
$ceA_AL2$




There are different ways that esters can be hydrolysed:
– catalysis by acids (A) or bases (B)
– cleavage of acyl-oxy (AC) or alkyl-oxy (AL) bonds
– the molecularity of the key step (1 or 2).



Using Acids (A) there are 4 different ways to hydrolyse an ester using acid catalysis:




$ceA_AC1$ Cleavage of Acyl-Oxy Bond Unimolecular
$ceA_AC2$ Cleavage of Acyl-Oxy Bond Dimolecular
$ceA_AL1$ Cleavage of Alkyl-Oxy Bond Unimolecular
$ceA_AL2$ Cleavage of Alkyl-Oxy Bond Dimolecular




An explanation can be found here.



But consider this question, with the marking scheme given below:
enter image description here



Our professor did not mention anything regarding how to choose which type of hydrolysis takes place. From this question, he states and goes further onto mention that either $ceA_AC1$ or $ceA_AC2$ can take place, but no other.



I'm looking at these structures and thinking



Why can't $ceA_AL1$ or $ceA_AL2$ take place for these two? Why must it be the two given in them marking scheme?










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
    $endgroup$
    – Karl
    8 hours ago










  • $begingroup$
    @Karl Edit made. Reference added.
    $endgroup$
    – vik1245
    8 hours ago






  • 2




    $begingroup$
    +1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
    $endgroup$
    – Karl
    7 hours ago










  • $begingroup$
    @Karl edited it further so now it appears in the introduction rather than the end!
    $endgroup$
    – vik1245
    7 hours ago















2












$begingroup$


I wanted to ask a question about acid catalysed hydrolysis.



I learnt in an introductory course to Physical Organic Chemistry that there are different ways that an ester can be hydrolysed acidically:




$ceA_AC1$
$ceA_AC2$
$ceA_AL1$
$ceA_AL2$




There are different ways that esters can be hydrolysed:
– catalysis by acids (A) or bases (B)
– cleavage of acyl-oxy (AC) or alkyl-oxy (AL) bonds
– the molecularity of the key step (1 or 2).



Using Acids (A) there are 4 different ways to hydrolyse an ester using acid catalysis:




$ceA_AC1$ Cleavage of Acyl-Oxy Bond Unimolecular
$ceA_AC2$ Cleavage of Acyl-Oxy Bond Dimolecular
$ceA_AL1$ Cleavage of Alkyl-Oxy Bond Unimolecular
$ceA_AL2$ Cleavage of Alkyl-Oxy Bond Dimolecular




An explanation can be found here.



But consider this question, with the marking scheme given below:
enter image description here



Our professor did not mention anything regarding how to choose which type of hydrolysis takes place. From this question, he states and goes further onto mention that either $ceA_AC1$ or $ceA_AC2$ can take place, but no other.



I'm looking at these structures and thinking



Why can't $ceA_AL1$ or $ceA_AL2$ take place for these two? Why must it be the two given in them marking scheme?










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
    $endgroup$
    – Karl
    8 hours ago










  • $begingroup$
    @Karl Edit made. Reference added.
    $endgroup$
    – vik1245
    8 hours ago






  • 2




    $begingroup$
    +1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
    $endgroup$
    – Karl
    7 hours ago










  • $begingroup$
    @Karl edited it further so now it appears in the introduction rather than the end!
    $endgroup$
    – vik1245
    7 hours ago













2












2








2


1



$begingroup$


I wanted to ask a question about acid catalysed hydrolysis.



I learnt in an introductory course to Physical Organic Chemistry that there are different ways that an ester can be hydrolysed acidically:




$ceA_AC1$
$ceA_AC2$
$ceA_AL1$
$ceA_AL2$




There are different ways that esters can be hydrolysed:
– catalysis by acids (A) or bases (B)
– cleavage of acyl-oxy (AC) or alkyl-oxy (AL) bonds
– the molecularity of the key step (1 or 2).



Using Acids (A) there are 4 different ways to hydrolyse an ester using acid catalysis:




$ceA_AC1$ Cleavage of Acyl-Oxy Bond Unimolecular
$ceA_AC2$ Cleavage of Acyl-Oxy Bond Dimolecular
$ceA_AL1$ Cleavage of Alkyl-Oxy Bond Unimolecular
$ceA_AL2$ Cleavage of Alkyl-Oxy Bond Dimolecular




An explanation can be found here.



But consider this question, with the marking scheme given below:
enter image description here



Our professor did not mention anything regarding how to choose which type of hydrolysis takes place. From this question, he states and goes further onto mention that either $ceA_AC1$ or $ceA_AC2$ can take place, but no other.



I'm looking at these structures and thinking



Why can't $ceA_AL1$ or $ceA_AL2$ take place for these two? Why must it be the two given in them marking scheme?










share|improve this question











$endgroup$




I wanted to ask a question about acid catalysed hydrolysis.



I learnt in an introductory course to Physical Organic Chemistry that there are different ways that an ester can be hydrolysed acidically:




$ceA_AC1$
$ceA_AC2$
$ceA_AL1$
$ceA_AL2$




There are different ways that esters can be hydrolysed:
– catalysis by acids (A) or bases (B)
– cleavage of acyl-oxy (AC) or alkyl-oxy (AL) bonds
– the molecularity of the key step (1 or 2).



Using Acids (A) there are 4 different ways to hydrolyse an ester using acid catalysis:




$ceA_AC1$ Cleavage of Acyl-Oxy Bond Unimolecular
$ceA_AC2$ Cleavage of Acyl-Oxy Bond Dimolecular
$ceA_AL1$ Cleavage of Alkyl-Oxy Bond Unimolecular
$ceA_AL2$ Cleavage of Alkyl-Oxy Bond Dimolecular




An explanation can be found here.



But consider this question, with the marking scheme given below:
enter image description here



Our professor did not mention anything regarding how to choose which type of hydrolysis takes place. From this question, he states and goes further onto mention that either $ceA_AC1$ or $ceA_AC2$ can take place, but no other.



I'm looking at these structures and thinking



Why can't $ceA_AL1$ or $ceA_AL2$ take place for these two? Why must it be the two given in them marking scheme?







hydrolysis esters






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago







vik1245

















asked 8 hours ago









vik1245vik1245

347115




347115







  • 1




    $begingroup$
    Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
    $endgroup$
    – Karl
    8 hours ago










  • $begingroup$
    @Karl Edit made. Reference added.
    $endgroup$
    – vik1245
    8 hours ago






  • 2




    $begingroup$
    +1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
    $endgroup$
    – Karl
    7 hours ago










  • $begingroup$
    @Karl edited it further so now it appears in the introduction rather than the end!
    $endgroup$
    – vik1245
    7 hours ago












  • 1




    $begingroup$
    Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
    $endgroup$
    – Karl
    8 hours ago










  • $begingroup$
    @Karl Edit made. Reference added.
    $endgroup$
    – vik1245
    8 hours ago






  • 2




    $begingroup$
    +1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
    $endgroup$
    – Karl
    7 hours ago










  • $begingroup$
    @Karl edited it further so now it appears in the introduction rather than the end!
    $endgroup$
    – vik1245
    7 hours ago







1




1




$begingroup$
Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
$endgroup$
– Karl
8 hours ago




$begingroup$
Perhaps you could explain in a few words what those mechanisms mean, or provide a reference. I think that's not too widely known.
$endgroup$
– Karl
8 hours ago












$begingroup$
@Karl Edit made. Reference added.
$endgroup$
– vik1245
8 hours ago




$begingroup$
@Karl Edit made. Reference added.
$endgroup$
– vik1245
8 hours ago




2




2




$begingroup$
+1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
$endgroup$
– Karl
7 hours ago




$begingroup$
+1 , but I wouldn't add this as a P.S. People have a short attention span, they read five lines, find they don't get it, and move on. ;-)
$endgroup$
– Karl
7 hours ago












$begingroup$
@Karl edited it further so now it appears in the introduction rather than the end!
$endgroup$
– vik1245
7 hours ago




$begingroup$
@Karl edited it further so now it appears in the introduction rather than the end!
$endgroup$
– vik1245
7 hours ago










1 Answer
1






active

oldest

votes


















1












$begingroup$

You should have read your explanation material more carefully! It clearly states that $A_AL2$ has not even been observed in acid hydrolysis due to water being a poor nucleophile in an $S_N2$ process. As for $A_AL1$, that only happens when the esterified radical can leave as a stable carbocation which, in this case methyl is a very very unstable carbocation.






share|improve this answer








New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$












  • $begingroup$
    Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
    $endgroup$
    – vik1245
    7 hours ago











Your Answer








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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

You should have read your explanation material more carefully! It clearly states that $A_AL2$ has not even been observed in acid hydrolysis due to water being a poor nucleophile in an $S_N2$ process. As for $A_AL1$, that only happens when the esterified radical can leave as a stable carbocation which, in this case methyl is a very very unstable carbocation.






share|improve this answer








New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$












  • $begingroup$
    Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
    $endgroup$
    – vik1245
    7 hours ago















1












$begingroup$

You should have read your explanation material more carefully! It clearly states that $A_AL2$ has not even been observed in acid hydrolysis due to water being a poor nucleophile in an $S_N2$ process. As for $A_AL1$, that only happens when the esterified radical can leave as a stable carbocation which, in this case methyl is a very very unstable carbocation.






share|improve this answer








New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$












  • $begingroup$
    Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
    $endgroup$
    – vik1245
    7 hours ago













1












1








1





$begingroup$

You should have read your explanation material more carefully! It clearly states that $A_AL2$ has not even been observed in acid hydrolysis due to water being a poor nucleophile in an $S_N2$ process. As for $A_AL1$, that only happens when the esterified radical can leave as a stable carbocation which, in this case methyl is a very very unstable carbocation.






share|improve this answer








New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$



You should have read your explanation material more carefully! It clearly states that $A_AL2$ has not even been observed in acid hydrolysis due to water being a poor nucleophile in an $S_N2$ process. As for $A_AL1$, that only happens when the esterified radical can leave as a stable carbocation which, in this case methyl is a very very unstable carbocation.







share|improve this answer








New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this answer



share|improve this answer






New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








answered 7 hours ago









Valentin LupuValentin Lupu

662




662




New contributor



Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Valentin Lupu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • $begingroup$
    Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
    $endgroup$
    – vik1245
    7 hours ago
















  • $begingroup$
    Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
    $endgroup$
    – vik1245
    7 hours ago















$begingroup$
Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
$endgroup$
– vik1245
7 hours ago




$begingroup$
Well if I am such a fool then I will learn today! Thanks very much this isn't actually my material but I read it so fast I couldn't actually make the point clear to myself! My apologies!
$endgroup$
– vik1245
7 hours ago

















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