Possible nonclassical ion from a bicyclic system8a-methyl-1,2,3,4,4a,8a-hexahydronaphthalen-4a-ylium carbocation rearrangementRearrangement of 8a-ethyl-1,3,4,8a-tetrahydronaphthalen-4a(2H)-olHydrolysis of 4-chloro-3,3-dimethylbut-1-ene forms which products much faster than primary alkyl halides?Comparison of rate of dehydration of primary, secondary & tertiary alcohols on cyclohexaneIs this reaction of 4-chloro-1,1-dimethylcyclohexane SN1, SN2, E1, or E2?Why can't a nucleophile attack the intermediate of an electrophilic aromatic substitution?Is a sequence of two Wagner-Meerwein rearrangements possible?Ring expansion in the reaction of (hydroxymethyl)cyclobutane and HBrIn the addition of HBr to isoprene why does the less stable carbocation form?How is more than one pinacolone is possible?Does rearrangement occur in Friedel Crafts alkylation or not?Is rearrangement possible in cyclic bromonium ion?

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Possible nonclassical ion from a bicyclic system


8a-methyl-1,2,3,4,4a,8a-hexahydronaphthalen-4a-ylium carbocation rearrangementRearrangement of 8a-ethyl-1,3,4,8a-tetrahydronaphthalen-4a(2H)-olHydrolysis of 4-chloro-3,3-dimethylbut-1-ene forms which products much faster than primary alkyl halides?Comparison of rate of dehydration of primary, secondary & tertiary alcohols on cyclohexaneIs this reaction of 4-chloro-1,1-dimethylcyclohexane SN1, SN2, E1, or E2?Why can't a nucleophile attack the intermediate of an electrophilic aromatic substitution?Is a sequence of two Wagner-Meerwein rearrangements possible?Ring expansion in the reaction of (hydroxymethyl)cyclobutane and HBrIn the addition of HBr to isoprene why does the less stable carbocation form?How is more than one pinacolone is possible?Does rearrangement occur in Friedel Crafts alkylation or not?Is rearrangement possible in cyclic bromonium ion?













2












$begingroup$


In this question a bicycling alcohol is reacted with acid to make what appears to be a tertiary carbocation, and the OP asked whether it could become aromatic. The given answer suggests it could be, but only if a nonclassical ion is formed. So, does that happen?



The substrate is 8a-methyl-1,3,4,8a-tetrahydronaphthalen-4a(2⁠H)-ol.










share|improve this question











$endgroup$











  • $begingroup$
    Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
    $endgroup$
    – Oscar Lanzi
    3 hours ago















2












$begingroup$


In this question a bicycling alcohol is reacted with acid to make what appears to be a tertiary carbocation, and the OP asked whether it could become aromatic. The given answer suggests it could be, but only if a nonclassical ion is formed. So, does that happen?



The substrate is 8a-methyl-1,3,4,8a-tetrahydronaphthalen-4a(2⁠H)-ol.










share|improve this question











$endgroup$











  • $begingroup$
    Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
    $endgroup$
    – Oscar Lanzi
    3 hours ago













2












2








2





$begingroup$


In this question a bicycling alcohol is reacted with acid to make what appears to be a tertiary carbocation, and the OP asked whether it could become aromatic. The given answer suggests it could be, but only if a nonclassical ion is formed. So, does that happen?



The substrate is 8a-methyl-1,3,4,8a-tetrahydronaphthalen-4a(2⁠H)-ol.










share|improve this question











$endgroup$




In this question a bicycling alcohol is reacted with acid to make what appears to be a tertiary carbocation, and the OP asked whether it could become aromatic. The given answer suggests it could be, but only if a nonclassical ion is formed. So, does that happen?



The substrate is 8a-methyl-1,3,4,8a-tetrahydronaphthalen-4a(2⁠H)-ol.







organic-chemistry carbocation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago







Oscar Lanzi

















asked 9 hours ago









Oscar LanziOscar Lanzi

17k12853




17k12853











  • $begingroup$
    Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
    $endgroup$
    – Oscar Lanzi
    3 hours ago
















  • $begingroup$
    Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
    $endgroup$
    – Oscar Lanzi
    3 hours ago















$begingroup$
Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
$endgroup$
– Oscar Lanzi
3 hours ago




$begingroup$
Thanks for getting the name. IUPAC convention confuses me more than actual chemistry!
$endgroup$
– Oscar Lanzi
3 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

I don't think it is necessary to consider a mechanism with a nonclassical carbocation. It would undergo normal rearrangement with a 1,2-methide shift within the same ring. See the mechanism I posted in previous question you were directing to:



Rearrangement to Aromatic



Answer to this question would support for my mechanism.






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    So the answer seems to be "No". Fair enough.
    $endgroup$
    – Oscar Lanzi
    3 hours ago


















2












$begingroup$

While there are examples of 1,2-methide shifts, this question has an uncanny resemblance to the dienone-phenol rearrangement whose mechanism was first elucidated by Woodward and Singh in 1950. Dienone 1 under acidic conditions undergoes rearrangement to phenol 6 and not, based on earlier speculation, to phenol 4. The direct 1,2-methide shift (2b --> 3) does not occur but rather the reaction proceeds through the spiro carbocation 5. continued

enter image description here


Applying this approach to the carbocation 7 generated from the alcohol in this question, spiro carbocation 8 forms the predicted tetrahydronaphthalene 10. One way to distinguish between the two mechanisms is via a labeling experiment. All of the carbon label in 7 will retain its location as the red star in 10 if the 1,2-methyl shift mechanism applies. The spiro mechanism will partition the label ~50:50 between the two ring benzylic carbons. For related studies, see reference 2.


1) R. B. Woodward and T. Singh, J. Am. Chem. Soc., 1950, 72, 494.

2) A. J. Waring, J. H. Zaidi and J. W. Pilkington, J. Chem. Soc, Perkin Transactions I, 1981, 1454.






share|improve this answer









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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    I don't think it is necessary to consider a mechanism with a nonclassical carbocation. It would undergo normal rearrangement with a 1,2-methide shift within the same ring. See the mechanism I posted in previous question you were directing to:



    Rearrangement to Aromatic



    Answer to this question would support for my mechanism.






    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      So the answer seems to be "No". Fair enough.
      $endgroup$
      – Oscar Lanzi
      3 hours ago















    3












    $begingroup$

    I don't think it is necessary to consider a mechanism with a nonclassical carbocation. It would undergo normal rearrangement with a 1,2-methide shift within the same ring. See the mechanism I posted in previous question you were directing to:



    Rearrangement to Aromatic



    Answer to this question would support for my mechanism.






    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      So the answer seems to be "No". Fair enough.
      $endgroup$
      – Oscar Lanzi
      3 hours ago













    3












    3








    3





    $begingroup$

    I don't think it is necessary to consider a mechanism with a nonclassical carbocation. It would undergo normal rearrangement with a 1,2-methide shift within the same ring. See the mechanism I posted in previous question you were directing to:



    Rearrangement to Aromatic



    Answer to this question would support for my mechanism.






    share|improve this answer











    $endgroup$



    I don't think it is necessary to consider a mechanism with a nonclassical carbocation. It would undergo normal rearrangement with a 1,2-methide shift within the same ring. See the mechanism I posted in previous question you were directing to:



    Rearrangement to Aromatic



    Answer to this question would support for my mechanism.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 5 hours ago

























    answered 6 hours ago









    Mathew MahindaratneMathew Mahindaratne

    8,2991131




    8,2991131







    • 1




      $begingroup$
      So the answer seems to be "No". Fair enough.
      $endgroup$
      – Oscar Lanzi
      3 hours ago












    • 1




      $begingroup$
      So the answer seems to be "No". Fair enough.
      $endgroup$
      – Oscar Lanzi
      3 hours ago







    1




    1




    $begingroup$
    So the answer seems to be "No". Fair enough.
    $endgroup$
    – Oscar Lanzi
    3 hours ago




    $begingroup$
    So the answer seems to be "No". Fair enough.
    $endgroup$
    – Oscar Lanzi
    3 hours ago











    2












    $begingroup$

    While there are examples of 1,2-methide shifts, this question has an uncanny resemblance to the dienone-phenol rearrangement whose mechanism was first elucidated by Woodward and Singh in 1950. Dienone 1 under acidic conditions undergoes rearrangement to phenol 6 and not, based on earlier speculation, to phenol 4. The direct 1,2-methide shift (2b --> 3) does not occur but rather the reaction proceeds through the spiro carbocation 5. continued

    enter image description here


    Applying this approach to the carbocation 7 generated from the alcohol in this question, spiro carbocation 8 forms the predicted tetrahydronaphthalene 10. One way to distinguish between the two mechanisms is via a labeling experiment. All of the carbon label in 7 will retain its location as the red star in 10 if the 1,2-methyl shift mechanism applies. The spiro mechanism will partition the label ~50:50 between the two ring benzylic carbons. For related studies, see reference 2.


    1) R. B. Woodward and T. Singh, J. Am. Chem. Soc., 1950, 72, 494.

    2) A. J. Waring, J. H. Zaidi and J. W. Pilkington, J. Chem. Soc, Perkin Transactions I, 1981, 1454.






    share|improve this answer









    $endgroup$

















      2












      $begingroup$

      While there are examples of 1,2-methide shifts, this question has an uncanny resemblance to the dienone-phenol rearrangement whose mechanism was first elucidated by Woodward and Singh in 1950. Dienone 1 under acidic conditions undergoes rearrangement to phenol 6 and not, based on earlier speculation, to phenol 4. The direct 1,2-methide shift (2b --> 3) does not occur but rather the reaction proceeds through the spiro carbocation 5. continued

      enter image description here


      Applying this approach to the carbocation 7 generated from the alcohol in this question, spiro carbocation 8 forms the predicted tetrahydronaphthalene 10. One way to distinguish between the two mechanisms is via a labeling experiment. All of the carbon label in 7 will retain its location as the red star in 10 if the 1,2-methyl shift mechanism applies. The spiro mechanism will partition the label ~50:50 between the two ring benzylic carbons. For related studies, see reference 2.


      1) R. B. Woodward and T. Singh, J. Am. Chem. Soc., 1950, 72, 494.

      2) A. J. Waring, J. H. Zaidi and J. W. Pilkington, J. Chem. Soc, Perkin Transactions I, 1981, 1454.






      share|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        While there are examples of 1,2-methide shifts, this question has an uncanny resemblance to the dienone-phenol rearrangement whose mechanism was first elucidated by Woodward and Singh in 1950. Dienone 1 under acidic conditions undergoes rearrangement to phenol 6 and not, based on earlier speculation, to phenol 4. The direct 1,2-methide shift (2b --> 3) does not occur but rather the reaction proceeds through the spiro carbocation 5. continued

        enter image description here


        Applying this approach to the carbocation 7 generated from the alcohol in this question, spiro carbocation 8 forms the predicted tetrahydronaphthalene 10. One way to distinguish between the two mechanisms is via a labeling experiment. All of the carbon label in 7 will retain its location as the red star in 10 if the 1,2-methyl shift mechanism applies. The spiro mechanism will partition the label ~50:50 between the two ring benzylic carbons. For related studies, see reference 2.


        1) R. B. Woodward and T. Singh, J. Am. Chem. Soc., 1950, 72, 494.

        2) A. J. Waring, J. H. Zaidi and J. W. Pilkington, J. Chem. Soc, Perkin Transactions I, 1981, 1454.






        share|improve this answer









        $endgroup$



        While there are examples of 1,2-methide shifts, this question has an uncanny resemblance to the dienone-phenol rearrangement whose mechanism was first elucidated by Woodward and Singh in 1950. Dienone 1 under acidic conditions undergoes rearrangement to phenol 6 and not, based on earlier speculation, to phenol 4. The direct 1,2-methide shift (2b --> 3) does not occur but rather the reaction proceeds through the spiro carbocation 5. continued

        enter image description here


        Applying this approach to the carbocation 7 generated from the alcohol in this question, spiro carbocation 8 forms the predicted tetrahydronaphthalene 10. One way to distinguish between the two mechanisms is via a labeling experiment. All of the carbon label in 7 will retain its location as the red star in 10 if the 1,2-methyl shift mechanism applies. The spiro mechanism will partition the label ~50:50 between the two ring benzylic carbons. For related studies, see reference 2.


        1) R. B. Woodward and T. Singh, J. Am. Chem. Soc., 1950, 72, 494.

        2) A. J. Waring, J. H. Zaidi and J. W. Pilkington, J. Chem. Soc, Perkin Transactions I, 1981, 1454.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 hours ago









        user55119user55119

        4,51711242




        4,51711242



























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