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What is the difference between a translation and a Galilean transformation?

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What is the difference between a translation and a Galilean transformation?


time invariance for “Translations” versus “Galilean transformations”Lorentz and Galilean transformationWhat does a Galilean transformation actually mean?What is the Galilean transformation of the EM field?Galilean TransformationVelocity of light in Galilean transformationWhy isn't scaling space and time considered the 11th dimension of the Galilean group?






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What is the difference between a translation and a Galilean transformation?










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    What is the difference between a translation and a Galilean transformation?










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      8








      8





      $begingroup$


      What is the difference between a translation and a Galilean transformation?










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      $endgroup$




      What is the difference between a translation and a Galilean transformation?







      newtonian-mechanics inertial-frames definition galilean-relativity






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      edited 44 mins ago









      knzhou

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          4 Answers
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          active

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          8














          $begingroup$

          In a Galilean transformation:
          $$
          x’=x-V_x t,qquad y’=y-V_yt, ,qquad z’=z-V_z t, ,qquad t’=t
          $$

          whereas in (spatial) translation
          $$
          x’=x-r_x, ,qquad y’=y-r_y, ,qquad z’=z-r_z, ,qquad t’=t, .
          $$

          The Galilean transformation depends explicitly on the relative velocity $vec V$ and the time $t$: for different $t$’s you add a different vector $vec V t$, whereas the simple translation adds a fixed time-independent vector $vec r$ to each coordinate.



          Since the bit you add in the Galilean transformation is time-dependent, it affects how velocities transform:
          $$
          vec v’=vec v-vec V
          $$

          whereas, for a simple translation, $vec v’=vec v$ since there is no time-dependence on the shift in position.






          share|cite|improve this answer











          $endgroup$






















            4














            $begingroup$

            A Galilean transformation is a translation per unit time: whereas a translation just displaces all space by some vector, a Galilean transformation displaces space by some vector that is different at different moments in time. More precisely, it depends linearly on time.



            If you've encountered spacetime diagrams before: on an (x, t) spacetime diagram, a translation would just be shifting the whole of the diagram to the right or to the left, whereas a Galilean transformation involves skewing the diagram.






            share|cite|improve this answer








            New contributor



            Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$






















              3














              $begingroup$

              A Galilean transformation (or “Galilean boost”) is a change to a second inertial reference frame that is moving with constant velocity relative to the first one, but where the origin and axes align, so there is no translation at $t=0$ and no rotation at any time.



              Imagine a bicyclist passing by you. His frame is boosted from yours. Yours is boosted from his, in the opposite direction.



              Galilean boosts are the Newtonian equivalent of Lorentz boosts in Special Relativity.



              In a translation, the frames do not have any relative motion. They just have different origins (but aligned axes).






              share|cite|improve this answer











              $endgroup$






















                0














                $begingroup$

                A galilean boost changes your reference frame. A translation only changes your position in the same reference frame.






                share|cite|improve this answer









                $endgroup$

















                  Your Answer








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                  4 Answers
                  4






                  active

                  oldest

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                  4 Answers
                  4






                  active

                  oldest

                  votes









                  active

                  oldest

                  votes






                  active

                  oldest

                  votes









                  8














                  $begingroup$

                  In a Galilean transformation:
                  $$
                  x’=x-V_x t,qquad y’=y-V_yt, ,qquad z’=z-V_z t, ,qquad t’=t
                  $$

                  whereas in (spatial) translation
                  $$
                  x’=x-r_x, ,qquad y’=y-r_y, ,qquad z’=z-r_z, ,qquad t’=t, .
                  $$

                  The Galilean transformation depends explicitly on the relative velocity $vec V$ and the time $t$: for different $t$’s you add a different vector $vec V t$, whereas the simple translation adds a fixed time-independent vector $vec r$ to each coordinate.



                  Since the bit you add in the Galilean transformation is time-dependent, it affects how velocities transform:
                  $$
                  vec v’=vec v-vec V
                  $$

                  whereas, for a simple translation, $vec v’=vec v$ since there is no time-dependence on the shift in position.






                  share|cite|improve this answer











                  $endgroup$



















                    8














                    $begingroup$

                    In a Galilean transformation:
                    $$
                    x’=x-V_x t,qquad y’=y-V_yt, ,qquad z’=z-V_z t, ,qquad t’=t
                    $$

                    whereas in (spatial) translation
                    $$
                    x’=x-r_x, ,qquad y’=y-r_y, ,qquad z’=z-r_z, ,qquad t’=t, .
                    $$

                    The Galilean transformation depends explicitly on the relative velocity $vec V$ and the time $t$: for different $t$’s you add a different vector $vec V t$, whereas the simple translation adds a fixed time-independent vector $vec r$ to each coordinate.



                    Since the bit you add in the Galilean transformation is time-dependent, it affects how velocities transform:
                    $$
                    vec v’=vec v-vec V
                    $$

                    whereas, for a simple translation, $vec v’=vec v$ since there is no time-dependence on the shift in position.






                    share|cite|improve this answer











                    $endgroup$

















                      8














                      8










                      8







                      $begingroup$

                      In a Galilean transformation:
                      $$
                      x’=x-V_x t,qquad y’=y-V_yt, ,qquad z’=z-V_z t, ,qquad t’=t
                      $$

                      whereas in (spatial) translation
                      $$
                      x’=x-r_x, ,qquad y’=y-r_y, ,qquad z’=z-r_z, ,qquad t’=t, .
                      $$

                      The Galilean transformation depends explicitly on the relative velocity $vec V$ and the time $t$: for different $t$’s you add a different vector $vec V t$, whereas the simple translation adds a fixed time-independent vector $vec r$ to each coordinate.



                      Since the bit you add in the Galilean transformation is time-dependent, it affects how velocities transform:
                      $$
                      vec v’=vec v-vec V
                      $$

                      whereas, for a simple translation, $vec v’=vec v$ since there is no time-dependence on the shift in position.






                      share|cite|improve this answer











                      $endgroup$



                      In a Galilean transformation:
                      $$
                      x’=x-V_x t,qquad y’=y-V_yt, ,qquad z’=z-V_z t, ,qquad t’=t
                      $$

                      whereas in (spatial) translation
                      $$
                      x’=x-r_x, ,qquad y’=y-r_y, ,qquad z’=z-r_z, ,qquad t’=t, .
                      $$

                      The Galilean transformation depends explicitly on the relative velocity $vec V$ and the time $t$: for different $t$’s you add a different vector $vec V t$, whereas the simple translation adds a fixed time-independent vector $vec r$ to each coordinate.



                      Since the bit you add in the Galilean transformation is time-dependent, it affects how velocities transform:
                      $$
                      vec v’=vec v-vec V
                      $$

                      whereas, for a simple translation, $vec v’=vec v$ since there is no time-dependence on the shift in position.







                      share|cite|improve this answer














                      share|cite|improve this answer



                      share|cite|improve this answer








                      edited 20 hours ago

























                      answered 23 hours ago









                      ZeroTheHeroZeroTheHero

                      22.8k5 gold badges35 silver badges71 bronze badges




                      22.8k5 gold badges35 silver badges71 bronze badges


























                          4














                          $begingroup$

                          A Galilean transformation is a translation per unit time: whereas a translation just displaces all space by some vector, a Galilean transformation displaces space by some vector that is different at different moments in time. More precisely, it depends linearly on time.



                          If you've encountered spacetime diagrams before: on an (x, t) spacetime diagram, a translation would just be shifting the whole of the diagram to the right or to the left, whereas a Galilean transformation involves skewing the diagram.






                          share|cite|improve this answer








                          New contributor



                          Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.





                          $endgroup$



















                            4














                            $begingroup$

                            A Galilean transformation is a translation per unit time: whereas a translation just displaces all space by some vector, a Galilean transformation displaces space by some vector that is different at different moments in time. More precisely, it depends linearly on time.



                            If you've encountered spacetime diagrams before: on an (x, t) spacetime diagram, a translation would just be shifting the whole of the diagram to the right or to the left, whereas a Galilean transformation involves skewing the diagram.






                            share|cite|improve this answer








                            New contributor



                            Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.





                            $endgroup$

















                              4














                              4










                              4







                              $begingroup$

                              A Galilean transformation is a translation per unit time: whereas a translation just displaces all space by some vector, a Galilean transformation displaces space by some vector that is different at different moments in time. More precisely, it depends linearly on time.



                              If you've encountered spacetime diagrams before: on an (x, t) spacetime diagram, a translation would just be shifting the whole of the diagram to the right or to the left, whereas a Galilean transformation involves skewing the diagram.






                              share|cite|improve this answer








                              New contributor



                              Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





                              $endgroup$



                              A Galilean transformation is a translation per unit time: whereas a translation just displaces all space by some vector, a Galilean transformation displaces space by some vector that is different at different moments in time. More precisely, it depends linearly on time.



                              If you've encountered spacetime diagrams before: on an (x, t) spacetime diagram, a translation would just be shifting the whole of the diagram to the right or to the left, whereas a Galilean transformation involves skewing the diagram.







                              share|cite|improve this answer








                              New contributor



                              Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.








                              share|cite|improve this answer



                              share|cite|improve this answer






                              New contributor



                              Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.








                              answered yesterday









                              MovpasdMovpasd

                              513 bronze badges




                              513 bronze badges




                              New contributor



                              Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.




                              New contributor




                              Movpasd is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.


























                                  3














                                  $begingroup$

                                  A Galilean transformation (or “Galilean boost”) is a change to a second inertial reference frame that is moving with constant velocity relative to the first one, but where the origin and axes align, so there is no translation at $t=0$ and no rotation at any time.



                                  Imagine a bicyclist passing by you. His frame is boosted from yours. Yours is boosted from his, in the opposite direction.



                                  Galilean boosts are the Newtonian equivalent of Lorentz boosts in Special Relativity.



                                  In a translation, the frames do not have any relative motion. They just have different origins (but aligned axes).






                                  share|cite|improve this answer











                                  $endgroup$



















                                    3














                                    $begingroup$

                                    A Galilean transformation (or “Galilean boost”) is a change to a second inertial reference frame that is moving with constant velocity relative to the first one, but where the origin and axes align, so there is no translation at $t=0$ and no rotation at any time.



                                    Imagine a bicyclist passing by you. His frame is boosted from yours. Yours is boosted from his, in the opposite direction.



                                    Galilean boosts are the Newtonian equivalent of Lorentz boosts in Special Relativity.



                                    In a translation, the frames do not have any relative motion. They just have different origins (but aligned axes).






                                    share|cite|improve this answer











                                    $endgroup$

















                                      3














                                      3










                                      3







                                      $begingroup$

                                      A Galilean transformation (or “Galilean boost”) is a change to a second inertial reference frame that is moving with constant velocity relative to the first one, but where the origin and axes align, so there is no translation at $t=0$ and no rotation at any time.



                                      Imagine a bicyclist passing by you. His frame is boosted from yours. Yours is boosted from his, in the opposite direction.



                                      Galilean boosts are the Newtonian equivalent of Lorentz boosts in Special Relativity.



                                      In a translation, the frames do not have any relative motion. They just have different origins (but aligned axes).






                                      share|cite|improve this answer











                                      $endgroup$



                                      A Galilean transformation (or “Galilean boost”) is a change to a second inertial reference frame that is moving with constant velocity relative to the first one, but where the origin and axes align, so there is no translation at $t=0$ and no rotation at any time.



                                      Imagine a bicyclist passing by you. His frame is boosted from yours. Yours is boosted from his, in the opposite direction.



                                      Galilean boosts are the Newtonian equivalent of Lorentz boosts in Special Relativity.



                                      In a translation, the frames do not have any relative motion. They just have different origins (but aligned axes).







                                      share|cite|improve this answer














                                      share|cite|improve this answer



                                      share|cite|improve this answer








                                      edited 22 hours ago

























                                      answered yesterday









                                      G. SmithG. Smith

                                      22k1 gold badge40 silver badges74 bronze badges




                                      22k1 gold badge40 silver badges74 bronze badges
























                                          0














                                          $begingroup$

                                          A galilean boost changes your reference frame. A translation only changes your position in the same reference frame.






                                          share|cite|improve this answer









                                          $endgroup$



















                                            0














                                            $begingroup$

                                            A galilean boost changes your reference frame. A translation only changes your position in the same reference frame.






                                            share|cite|improve this answer









                                            $endgroup$

















                                              0














                                              0










                                              0







                                              $begingroup$

                                              A galilean boost changes your reference frame. A translation only changes your position in the same reference frame.






                                              share|cite|improve this answer









                                              $endgroup$



                                              A galilean boost changes your reference frame. A translation only changes your position in the same reference frame.







                                              share|cite|improve this answer












                                              share|cite|improve this answer



                                              share|cite|improve this answer










                                              answered 21 hours ago









                                              my2ctsmy2cts

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                                              7,8152 gold badges7 silver badges23 bronze badges































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