Why does an inductor oppose the change in current (magnetic field)?How does an inductor store magnetic energy?Rate of change of current in an InductorWhy do Capacitor Inductor circuits Oscillate instead of reaching equilibrium?Magnetic field effect on inductorsAt $t=0$ the voltage across the Inductor will immediately jump to battery voltage. Why?If an inductor has current flowing in only one direction, does the magnetic field still vary directions?Energy stored in the magnetic fieldMagnetic field around an Inductor?Confusion in understanding the behavior of inductor in RL circuit with DC sourceHow is the rate of current change in an inductor present in a circuit maintained / decreased?
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Why does an inductor oppose the change in current (magnetic field)?
How does an inductor store magnetic energy?Rate of change of current in an InductorWhy do Capacitor Inductor circuits Oscillate instead of reaching equilibrium?Magnetic field effect on inductorsAt $t=0$ the voltage across the Inductor will immediately jump to battery voltage. Why?If an inductor has current flowing in only one direction, does the magnetic field still vary directions?Energy stored in the magnetic fieldMagnetic field around an Inductor?Confusion in understanding the behavior of inductor in RL circuit with DC sourceHow is the rate of current change in an inductor present in a circuit maintained / decreased?
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May I get a physical interpretation on this question? What is happening in the inductor when the current is running through it and what is physically happening when the current starts changing?
electromagnetism
New contributor
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add a comment |
$begingroup$
May I get a physical interpretation on this question? What is happening in the inductor when the current is running through it and what is physically happening when the current starts changing?
electromagnetism
New contributor
$endgroup$
add a comment |
$begingroup$
May I get a physical interpretation on this question? What is happening in the inductor when the current is running through it and what is physically happening when the current starts changing?
electromagnetism
New contributor
$endgroup$
May I get a physical interpretation on this question? What is happening in the inductor when the current is running through it and what is physically happening when the current starts changing?
electromagnetism
electromagnetism
New contributor
New contributor
New contributor
asked 8 hours ago
Yiyang ZhiYiyang Zhi
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3 Answers
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$begingroup$
What is happening in the inductor when the current is running through
it and what is physically happening when the current starts changing?
In order to explain what is physically happening it might be helpful to consider the mechanical analogue of kinetic energy and the inertia of mass. The analogy is not exact, but it may hopefully give you a physical "feel" for what's going on, that is not so easy to feel with electrical concepts.
As @niels nielson pointed out an inductor with a constant current produces a magnetic field. That magnetic field represents stored energy in the inductor, in this case, in the form of kinetic energy. (A capacitor has stored energy in the electric field between the plates and, in that case, the stored energy is electrical potential energy).
Now think of a mass moving at constant velocity and having kinetic energy. It will resist any attempt to slow it down (reduce its kinetic energy) or speed it up (increase its kinetic energy) analogous to an inductor resisting any attempt to change its current (and thereby changing the kinetic energy of its magnetic field). The mass has inertia. The inertia (to current change) of an inductor is analogous to the inertia (to velocity change) of the mass. The analogy can be seen when one compares faradays law of induction.
$$V_L(t)=LfracdI(t)dt$$
With Newtons's second law of motion
$$F=Mfracdv(t)dt$$
Very roughly speaking, we can consider:
- Voltage as the analogue of force
- Inductance as the analogue of mass
- Velocity as the analogue of current.
The diagram below shows other mechanical analogues for resistance and capacitance.
I would like to stress that inductance is not mass, velocity is not current, and voltage is not force. The analogy is simply intended to help you get some feel as to what is going on.
Hope it helps
$endgroup$
add a comment |
$begingroup$
Here is one way of looking at this.
We start with an inductor that has a steady current flowing through it from a power source. Because of this, there is a magnetic field extending into space surrounding the inductor.
Now we attempt to cut off the flow of current through the inductor, by switching off the source. At the instant the current goes off, the magnetic field begins to collapse around the inductor, which induces a current flow in the inductor in the same direction as our original current. The quicker the field collapses, the greater the induced current flow- and we observe a big fat spark jumping across the switch terminals as they move apart.
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert.
$endgroup$
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
add a comment |
$begingroup$
In classical electromagnetic theory, the effect works like this. The laws of physics dictate that whenever you have an electric current (i.e. charge in motion), there must be an associated magnetic field with it.
Now, those same laws also say that electromagnetic fields, of which purely magnetic fields are a special case, contain energy. By conservation of energy, that energy has to come from somewhere, if it wasn't there before, and it has to go somewhere as well, if it is there now but won't be later.
So now consider what happens when you initiate an electric current. By the first principle, there must be a magnetic field. By the second, this field represents energy, and that energy has to be sourced. Since you cannot have a current without this magnetic field, then that means it has to take energy to cause the current, and thus the power source you are using has to do work.
Likewise, when the power source is withdrawn, the magnetic field begins to falter, and its energy has to go somewhere. That energy goes now into keeping the current flowing for longer.
Moreover, you should be able to see then that any and all circuit elements have inductance, not just "inductors", and it is impossible to avoid, because to do so you would need to have a current without establishing any magnetic field. "Inductors" are simply components specially designed to exaggerate the effect.
$endgroup$
add a comment |
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3 Answers
3
active
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3 Answers
3
active
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active
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$begingroup$
What is happening in the inductor when the current is running through
it and what is physically happening when the current starts changing?
In order to explain what is physically happening it might be helpful to consider the mechanical analogue of kinetic energy and the inertia of mass. The analogy is not exact, but it may hopefully give you a physical "feel" for what's going on, that is not so easy to feel with electrical concepts.
As @niels nielson pointed out an inductor with a constant current produces a magnetic field. That magnetic field represents stored energy in the inductor, in this case, in the form of kinetic energy. (A capacitor has stored energy in the electric field between the plates and, in that case, the stored energy is electrical potential energy).
Now think of a mass moving at constant velocity and having kinetic energy. It will resist any attempt to slow it down (reduce its kinetic energy) or speed it up (increase its kinetic energy) analogous to an inductor resisting any attempt to change its current (and thereby changing the kinetic energy of its magnetic field). The mass has inertia. The inertia (to current change) of an inductor is analogous to the inertia (to velocity change) of the mass. The analogy can be seen when one compares faradays law of induction.
$$V_L(t)=LfracdI(t)dt$$
With Newtons's second law of motion
$$F=Mfracdv(t)dt$$
Very roughly speaking, we can consider:
- Voltage as the analogue of force
- Inductance as the analogue of mass
- Velocity as the analogue of current.
The diagram below shows other mechanical analogues for resistance and capacitance.
I would like to stress that inductance is not mass, velocity is not current, and voltage is not force. The analogy is simply intended to help you get some feel as to what is going on.
Hope it helps
$endgroup$
add a comment |
$begingroup$
What is happening in the inductor when the current is running through
it and what is physically happening when the current starts changing?
In order to explain what is physically happening it might be helpful to consider the mechanical analogue of kinetic energy and the inertia of mass. The analogy is not exact, but it may hopefully give you a physical "feel" for what's going on, that is not so easy to feel with electrical concepts.
As @niels nielson pointed out an inductor with a constant current produces a magnetic field. That magnetic field represents stored energy in the inductor, in this case, in the form of kinetic energy. (A capacitor has stored energy in the electric field between the plates and, in that case, the stored energy is electrical potential energy).
Now think of a mass moving at constant velocity and having kinetic energy. It will resist any attempt to slow it down (reduce its kinetic energy) or speed it up (increase its kinetic energy) analogous to an inductor resisting any attempt to change its current (and thereby changing the kinetic energy of its magnetic field). The mass has inertia. The inertia (to current change) of an inductor is analogous to the inertia (to velocity change) of the mass. The analogy can be seen when one compares faradays law of induction.
$$V_L(t)=LfracdI(t)dt$$
With Newtons's second law of motion
$$F=Mfracdv(t)dt$$
Very roughly speaking, we can consider:
- Voltage as the analogue of force
- Inductance as the analogue of mass
- Velocity as the analogue of current.
The diagram below shows other mechanical analogues for resistance and capacitance.
I would like to stress that inductance is not mass, velocity is not current, and voltage is not force. The analogy is simply intended to help you get some feel as to what is going on.
Hope it helps
$endgroup$
add a comment |
$begingroup$
What is happening in the inductor when the current is running through
it and what is physically happening when the current starts changing?
In order to explain what is physically happening it might be helpful to consider the mechanical analogue of kinetic energy and the inertia of mass. The analogy is not exact, but it may hopefully give you a physical "feel" for what's going on, that is not so easy to feel with electrical concepts.
As @niels nielson pointed out an inductor with a constant current produces a magnetic field. That magnetic field represents stored energy in the inductor, in this case, in the form of kinetic energy. (A capacitor has stored energy in the electric field between the plates and, in that case, the stored energy is electrical potential energy).
Now think of a mass moving at constant velocity and having kinetic energy. It will resist any attempt to slow it down (reduce its kinetic energy) or speed it up (increase its kinetic energy) analogous to an inductor resisting any attempt to change its current (and thereby changing the kinetic energy of its magnetic field). The mass has inertia. The inertia (to current change) of an inductor is analogous to the inertia (to velocity change) of the mass. The analogy can be seen when one compares faradays law of induction.
$$V_L(t)=LfracdI(t)dt$$
With Newtons's second law of motion
$$F=Mfracdv(t)dt$$
Very roughly speaking, we can consider:
- Voltage as the analogue of force
- Inductance as the analogue of mass
- Velocity as the analogue of current.
The diagram below shows other mechanical analogues for resistance and capacitance.
I would like to stress that inductance is not mass, velocity is not current, and voltage is not force. The analogy is simply intended to help you get some feel as to what is going on.
Hope it helps
$endgroup$
What is happening in the inductor when the current is running through
it and what is physically happening when the current starts changing?
In order to explain what is physically happening it might be helpful to consider the mechanical analogue of kinetic energy and the inertia of mass. The analogy is not exact, but it may hopefully give you a physical "feel" for what's going on, that is not so easy to feel with electrical concepts.
As @niels nielson pointed out an inductor with a constant current produces a magnetic field. That magnetic field represents stored energy in the inductor, in this case, in the form of kinetic energy. (A capacitor has stored energy in the electric field between the plates and, in that case, the stored energy is electrical potential energy).
Now think of a mass moving at constant velocity and having kinetic energy. It will resist any attempt to slow it down (reduce its kinetic energy) or speed it up (increase its kinetic energy) analogous to an inductor resisting any attempt to change its current (and thereby changing the kinetic energy of its magnetic field). The mass has inertia. The inertia (to current change) of an inductor is analogous to the inertia (to velocity change) of the mass. The analogy can be seen when one compares faradays law of induction.
$$V_L(t)=LfracdI(t)dt$$
With Newtons's second law of motion
$$F=Mfracdv(t)dt$$
Very roughly speaking, we can consider:
- Voltage as the analogue of force
- Inductance as the analogue of mass
- Velocity as the analogue of current.
The diagram below shows other mechanical analogues for resistance and capacitance.
I would like to stress that inductance is not mass, velocity is not current, and voltage is not force. The analogy is simply intended to help you get some feel as to what is going on.
Hope it helps
edited 16 mins ago
answered 3 hours ago
Bob DBob D
11.2k3 gold badges10 silver badges35 bronze badges
11.2k3 gold badges10 silver badges35 bronze badges
add a comment |
add a comment |
$begingroup$
Here is one way of looking at this.
We start with an inductor that has a steady current flowing through it from a power source. Because of this, there is a magnetic field extending into space surrounding the inductor.
Now we attempt to cut off the flow of current through the inductor, by switching off the source. At the instant the current goes off, the magnetic field begins to collapse around the inductor, which induces a current flow in the inductor in the same direction as our original current. The quicker the field collapses, the greater the induced current flow- and we observe a big fat spark jumping across the switch terminals as they move apart.
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert.
$endgroup$
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
add a comment |
$begingroup$
Here is one way of looking at this.
We start with an inductor that has a steady current flowing through it from a power source. Because of this, there is a magnetic field extending into space surrounding the inductor.
Now we attempt to cut off the flow of current through the inductor, by switching off the source. At the instant the current goes off, the magnetic field begins to collapse around the inductor, which induces a current flow in the inductor in the same direction as our original current. The quicker the field collapses, the greater the induced current flow- and we observe a big fat spark jumping across the switch terminals as they move apart.
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert.
$endgroup$
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
add a comment |
$begingroup$
Here is one way of looking at this.
We start with an inductor that has a steady current flowing through it from a power source. Because of this, there is a magnetic field extending into space surrounding the inductor.
Now we attempt to cut off the flow of current through the inductor, by switching off the source. At the instant the current goes off, the magnetic field begins to collapse around the inductor, which induces a current flow in the inductor in the same direction as our original current. The quicker the field collapses, the greater the induced current flow- and we observe a big fat spark jumping across the switch terminals as they move apart.
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert.
$endgroup$
Here is one way of looking at this.
We start with an inductor that has a steady current flowing through it from a power source. Because of this, there is a magnetic field extending into space surrounding the inductor.
Now we attempt to cut off the flow of current through the inductor, by switching off the source. At the instant the current goes off, the magnetic field begins to collapse around the inductor, which induces a current flow in the inductor in the same direction as our original current. The quicker the field collapses, the greater the induced current flow- and we observe a big fat spark jumping across the switch terminals as they move apart.
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert.
answered 5 hours ago
niels nielsenniels nielsen
24.5k5 gold badges33 silver badges69 bronze badges
24.5k5 gold badges33 silver badges69 bronze badges
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
add a comment |
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
We conclude that the current flow in the inductor really wants to keep flowing, and the inductor "fights" any change in the magnitude of the current flow we try to assert. But doesn't the OP want to know why this itself happens, not how we know it does happen?
$endgroup$
– Aaron Stevens
4 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
$begingroup$
I left out the d(i)/dt terminology because I did not think he was at that level. What I was shooting for was the idea that the field collapse drives the current and tries to maintain its flow. My usual way of explaining this is to move into the mechanical analogue and represent inductance as a mass but I thought that might not be suitable.
$endgroup$
– niels nielsen
3 hours ago
add a comment |
$begingroup$
In classical electromagnetic theory, the effect works like this. The laws of physics dictate that whenever you have an electric current (i.e. charge in motion), there must be an associated magnetic field with it.
Now, those same laws also say that electromagnetic fields, of which purely magnetic fields are a special case, contain energy. By conservation of energy, that energy has to come from somewhere, if it wasn't there before, and it has to go somewhere as well, if it is there now but won't be later.
So now consider what happens when you initiate an electric current. By the first principle, there must be a magnetic field. By the second, this field represents energy, and that energy has to be sourced. Since you cannot have a current without this magnetic field, then that means it has to take energy to cause the current, and thus the power source you are using has to do work.
Likewise, when the power source is withdrawn, the magnetic field begins to falter, and its energy has to go somewhere. That energy goes now into keeping the current flowing for longer.
Moreover, you should be able to see then that any and all circuit elements have inductance, not just "inductors", and it is impossible to avoid, because to do so you would need to have a current without establishing any magnetic field. "Inductors" are simply components specially designed to exaggerate the effect.
$endgroup$
add a comment |
$begingroup$
In classical electromagnetic theory, the effect works like this. The laws of physics dictate that whenever you have an electric current (i.e. charge in motion), there must be an associated magnetic field with it.
Now, those same laws also say that electromagnetic fields, of which purely magnetic fields are a special case, contain energy. By conservation of energy, that energy has to come from somewhere, if it wasn't there before, and it has to go somewhere as well, if it is there now but won't be later.
So now consider what happens when you initiate an electric current. By the first principle, there must be a magnetic field. By the second, this field represents energy, and that energy has to be sourced. Since you cannot have a current without this magnetic field, then that means it has to take energy to cause the current, and thus the power source you are using has to do work.
Likewise, when the power source is withdrawn, the magnetic field begins to falter, and its energy has to go somewhere. That energy goes now into keeping the current flowing for longer.
Moreover, you should be able to see then that any and all circuit elements have inductance, not just "inductors", and it is impossible to avoid, because to do so you would need to have a current without establishing any magnetic field. "Inductors" are simply components specially designed to exaggerate the effect.
$endgroup$
add a comment |
$begingroup$
In classical electromagnetic theory, the effect works like this. The laws of physics dictate that whenever you have an electric current (i.e. charge in motion), there must be an associated magnetic field with it.
Now, those same laws also say that electromagnetic fields, of which purely magnetic fields are a special case, contain energy. By conservation of energy, that energy has to come from somewhere, if it wasn't there before, and it has to go somewhere as well, if it is there now but won't be later.
So now consider what happens when you initiate an electric current. By the first principle, there must be a magnetic field. By the second, this field represents energy, and that energy has to be sourced. Since you cannot have a current without this magnetic field, then that means it has to take energy to cause the current, and thus the power source you are using has to do work.
Likewise, when the power source is withdrawn, the magnetic field begins to falter, and its energy has to go somewhere. That energy goes now into keeping the current flowing for longer.
Moreover, you should be able to see then that any and all circuit elements have inductance, not just "inductors", and it is impossible to avoid, because to do so you would need to have a current without establishing any magnetic field. "Inductors" are simply components specially designed to exaggerate the effect.
$endgroup$
In classical electromagnetic theory, the effect works like this. The laws of physics dictate that whenever you have an electric current (i.e. charge in motion), there must be an associated magnetic field with it.
Now, those same laws also say that electromagnetic fields, of which purely magnetic fields are a special case, contain energy. By conservation of energy, that energy has to come from somewhere, if it wasn't there before, and it has to go somewhere as well, if it is there now but won't be later.
So now consider what happens when you initiate an electric current. By the first principle, there must be a magnetic field. By the second, this field represents energy, and that energy has to be sourced. Since you cannot have a current without this magnetic field, then that means it has to take energy to cause the current, and thus the power source you are using has to do work.
Likewise, when the power source is withdrawn, the magnetic field begins to falter, and its energy has to go somewhere. That energy goes now into keeping the current flowing for longer.
Moreover, you should be able to see then that any and all circuit elements have inductance, not just "inductors", and it is impossible to avoid, because to do so you would need to have a current without establishing any magnetic field. "Inductors" are simply components specially designed to exaggerate the effect.
answered 2 hours ago
The_SympathizerThe_Sympathizer
6,31012 silver badges30 bronze badges
6,31012 silver badges30 bronze badges
add a comment |
add a comment |
Yiyang Zhi is a new contributor. Be nice, and check out our Code of Conduct.
Yiyang Zhi is a new contributor. Be nice, and check out our Code of Conduct.
Yiyang Zhi is a new contributor. Be nice, and check out our Code of Conduct.
Yiyang Zhi is a new contributor. Be nice, and check out our Code of Conduct.
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